Complete Question
What mass of aluminum has a total nuclear charge of 2.9 C?
Aluminum has atomic number 13. Suppose the aluminum is all of the isotope with 14 neutrons.
Answer:
The mass is [tex]T_m = 6.252 *10^{-5}\ g[/tex]
Explanation:
From the question we are told that
The total nuclear charge is [tex]q = 2.9 \ C[/tex]
The atomic number is [tex]u = 13[/tex]
The number of neutron is [tex]k = 14[/tex]
Generally the number of positive charge is mathematically represented as
[tex]N = \frac{q}{p}[/tex]
here p is the charge on a single proton with value [tex]p = 1.60*10^{-19} \ C[/tex]
So
[tex]N = \frac{2.9}{1.60*10^{-19}}[/tex]
=> [tex]N = 1.813*10^{19} \ protons[/tex]
Now since 1 atom contains 13 proton
The number of atoms present is
[tex]a = \frac{1.813*10^{19}}{13}[/tex]
[tex]a = 1.395 *10^{18} \ atoms[/tex]
Then the number of moles present is mathematically represented as
[tex]n = \frac{a}{N_k}[/tex]
Where N_k is the Boltzmann constant with value
[tex]N_k = 6.023*10^{23}[/tex]
So
[tex]n = \frac{1.395 *10^{18}}{ 6.023*10^{23}}[/tex]
[tex]n = 2.315 *10^{-6}\ moles[/tex]
Generally one mole of aluminum is equal to 27 g
So
The total mass of aluminum is
[tex]T_m = n * 27[/tex]
=> [tex]T_m = 2.315 *10^{-6} * 27[/tex]
=> [tex]T_m = 6.252 *10^{-5}\ g[/tex]
supposed the Kingfisher Dives with an average speed of 4.6 m / s for 1.4 seconds before hitting the water. What is the height from which the bird dove
Answer:
h = 1.07 m
Explanation:
It is given that,
The average sped of the kingfisher, v = 4.6 m/s
Time, t = 1.4 s
Final speed, v = 0 (as it hits the water)
We need to find the height from which the bird dove. Let the height is h. According to the conservation of energy.
[tex]mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(4.6)^2}{2\times 9.8}\\\\h=1.07\ m[/tex]
So, the bird dove from a height of 1.07 m.
When measuring the diameter of a cylinder the following measurements are obtained.
16.4 millimeters
16.8 millimeters
16.9 millimeters
16.6 millimeters
16.8 millimeters
Find the percent uncertainty in the measurements.
(Keep 2 decimal places in the percentage.)
Answer:
a. 1.80 %
b. 0.60 %
c. 1.20 %
d. 0.60 %
e. 0.60 %
Explanation:
In order to calculate percent uncertainties in each case, we forst need to calculate the average value:
Average Diameter = (16.4 mm + 16.8 mm + 16.9 mm + 16.6 mm +16.8 mm)/5
Average Diameter = 16.7 mm
Now, the formula for percent uncertainty is:
% Uncertainty = (Uncertainty/Average) * 100 %
where,
Uncertainty = |Value - Average|
For Each Case:
a. 16.4 mm:
Uncertainty = |16.4 mm - 16.7 mm| = 0.3 mm
Therefore,
% Uncertainty = (0.3 mm/16.7 mm) * 100%
% Uncertainty = 1.80 %
b. 16.8 mm:
Uncertainty = |16.8 mm - 16.7 mm| = 0.1 mm
Therefore,
% Uncertainty = (0.1 mm/16.7 mm) * 100%
% Uncertainty = 0.60 %
c. 16.4 mm:
Uncertainty = |16.9 mm - 16.7 mm| = 0.2 mm
Therefore,
% Uncertainty = (0.2 mm/16.7 mm) * 100%
% Uncertainty = 1.20 %
d. 16.6 mm:
Uncertainty = |16.6 mm - 16.7 mm| = 0.1 mm
Therefore,
% Uncertainty = (0.1 mm/16.7 mm) * 100%
% Uncertainty = 0.60 %
e. 16.8 mm:
Uncertainty = |16.8 mm - 16.7 mm| = 0.3 mm
Therefore,
% Uncertainty = (0.1 mm/16.7 mm) * 100%
% Uncertainty = 0.60 %
What unit is time usually measured in?
A penny is dropped from the top of a tower. It hits the ground below after 2.5 s. How tall was the tower?
A. 24,5m
B. 3.92m
C. 30.6m
D. 60m
Answer:
C. 30.6m
Explanation:
To find the height of the tower, we are to use Newtons law of motion to solve this problem. Since the penny is falling from the top of the tower, it is acted by the acceleration due to gravity. The formula to be used is:
[tex]H=ut+\frac{1}{2}gt^2[/tex]
Where H is the height of the tower, t is the time taken to hit the ground, u is the initial velocity and g is the acceleration due to gravity.
Given that, t = 2.5 s, g =9.8 m/s², u = 0 m/s (at the top of tower)
[tex]H=ut+\frac{1}{2}gt^2\\\\H=0(2.5)+ \frac{1}{2}(9.8)(2.5)^2\\\\H=30.6\ m[/tex]
Someone plans to float a small, totally absorbing sphere 0.518 m above an isotropic point source of light, so that the upward radiation force from the light matches the downward gravitational force on the sphere. The sphere's density is 22.2 g/cm3, and its radius is 2.12 mm. (a) What power would be required of the light source
Answer:
Explanation:
From the question we are told that
The height is [tex]h = 0.518 \ m[/tex]
The sphere density is [tex]\rho = 22.2g/cm^3 = \frac{22.2 }{1000} * 1*10^{6} = 22200 kg/m^3[/tex]
The radius is [tex]r = 2.12 \ mm =0.00212 \ m[/tex]
Generally the power required is mathematically represented as
[tex]P = \frac{16 * \pi * \rho * r * g * h^2 * c }{3}[/tex]
substituting values
[tex]P = \frac{16 * 3.142 * 22200 * 0.00212 * 9.8 * 0.518^2 * 3.0*10^{8}}{ 3}[/tex]
[tex]P = 6.22*10^{11} \ W[/tex]
A small plane flies at a speed of 102 km/h in still air. Suppose the wind blows out from the west (with the air moving east) at a speed of 46 km/h.A) In what direction must the pilot head her plane to move directly north across land?B) How long does it take her to reach a point 300 km directly north of her srarting point?
Answer:
2.68 hours
Explanation:
A.) Suppose the wind blows out from the west (with the air moving east). The pilot should then head her plane to northwest direction to move directly north.
B.) Given that plane flies at a speed of 102 km/h in still air. And the wind blows out from the west (with the air moving east) at a speed of 46 km/h.
The plan resultant speed can be calculated by using pythagorean theorem.
Resultant Speed = Sqrt( 102^2 + 46^2 )
Resultant Speed = Sqrt( 12520)
Resultant speed = 111.89 km/h
From the definition of speed,
Speed = distance/time
Where distance = 300 km
Substitute the resultant speed and the distance into the formula.
111.89 = 300/time
Time = 300/111.89
Time = 2.68 hours
Therefore, it take her 2.68 hours to reach a point 300 km directly north of her srarting point
What is the magnite of the net displacement of the mouse?
Complete Question
A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?
Answer:
The values is [tex]s = 7.49 \ m[/tex]
Explanation:
From the question we are told that
The distance it travels eastward is [tex]x = 5.0 \ m[/tex]
The distance it travel towards the southeast is [tex]l = 3.0\ m[/tex]
The distance it travel towards the south is [tex]z = 1 \ m[/tex]
Let x-axis be east
y-axis south
z-axis into the ground
The angle made between east and south is [tex]\theta = 45^o[/tex]
The displacement toward x-axis is
[tex]x = 5 + 3cos(45)[/tex]
[tex]x = 7.12[/tex]
The displacement toward the y-axis is
[tex]y = 3 * sin (45)[/tex]
[tex]y = 2.123[/tex]
Now the overall displacement of the rat is mathematically evaluated as
[tex]s = \sqrt{7.12^2 + 2.12^2 + 1^2}[/tex]
[tex]s = 7.49 \ m[/tex]
A 68 kg deer has a momentum of 952 kg∙m/s. What is its velocity?
All we need to do is divide the momentum and weight to find the velocity:
v = m / w
Solve using the values we are given.
v = 952/68 = 14 m/s
Best of Luck!
Lightning occurs when there is a flow of electric charge (principally electrons) between the ground and a thundercloud. The maximum rate of charge flow in a lightning bolt is about 20,000 C/s this lasts for 100 μs or less.1. How much charge flows between the ground and the cloud in this time? (Q= ? C)2. How many electrons flow during this time? (n_e = ?)
Answer:
a
The charge is [tex]Q = 2.0*10^8 \ C[/tex]
b
The number of electrons [tex]N = 1.25 *10^{27} \ electrons[/tex]
Explanation:
From the question we are told that
The maximum rate of charge flow is [tex]\frac{dq}{dt} = I = 20000 \ C/s[/tex]
Here I means current
The time interval is [tex]t=100 \mu s = 100*10^{-6}[/tex]
Generally the amount of charge is mathematically represented as
[tex]Q = \frac{I}{t}[/tex]
=> [tex]Q = \frac{20000}{ 100*10^{-6}}[/tex]
=> [tex]Q = 2.0*10^8 \ C[/tex]
The number of electrons that flow during that time is evaluated as
[tex]N = \frac{Q}{e}[/tex]
Here e is the charge on a single electron with value [tex]e= 1.60*10^{-19} \ C[/tex]
So
[tex]N = \frac{2.0*10^8}{ 1.60*10^{-19}}[/tex]
[tex]N = 1.25 *10^{27} \ electrons[/tex]
A kayak on a lake is moving at a constant speed of 4.1 m/s in a direction 41.6° north of west. After 10 min, find the following.(a) how far west the kayak has traveled km (b) how far north the kayak has traveled km
Given :
A kayak on a lake is moving at a constant speed of 4.1 m/s in a direction 41.6° north of west.
To Find :
After 10 min :
(a) how far west the kayak has traveled km.
(b) how far north the kayak has traveled km.
Solution :
a) Time taken in seconds :
[tex]t=10\times 60 \ s = 600\ s[/tex] .
Distance travelled in 600 s is :
[tex]D=s\times t\\\\D=4.1\times 600\ m\\\\D=2460\ m[/tex]
Distance in km is :
[tex]D=\dfrac{2460}{1000}=2.46\ km[/tex]
b) Now , distance from the north is given by :
[tex]d=D\times sin\ 41.6^o\\\\d=2.46 \times sin\ 41.6^o\\\\d=1.63\ km[/tex]
Hence , this is the required solution .
if the earth stops rotating the Apparent value of g on its surface will
Answer:
If the earth stops rotating the apparent weight will increase at most of the places because the upward component of the centrifugal force due to rotation will disappear.
If the velocity of a proton is straight up (thumb pointing up) then RHR2 shows that the force points to the left. What would the direction of the force be if the velocity were
Answer:
a) to the right
b) up
c) down
d) there will be no force on the proton
e) there will be no force on the proton
Explanation:
The complete question is
If the velocity of a proton is straight up(thumb pointing up) then RHR2 (right hand rule) shows that the force points to the left. What would the direction of the force be if the velocity were a)down, b)to the right, c)to the left, d)into the page, and e)out of the page?
The right hand rule for a positive charge states that...
Hold the thumb of the right hand at right angle to the rest of the fingers, and the rest of the fingers parallel to one another, and pointing away from the body. If the thumb shows the velocity of a positive charge in a magnetic field, and the fingers all point in the direction of the magnetic field, then the palm will push in the direction of the force on the positive charge (proton).
From this, we can deduce from the original statement about this proton that the direction of the field is into the screen of this computer. with that field direction held constant, we can work out that
a) if the thumb point down, the force will be to the right
b) if the thumb points to the right, the force will be upwards
c) if the thumb points to the left, the force is downwards
d) if the thumb points into the page, then there will be no force on the proton since the proton must travel perpendicularly to the magnetic field for a force to be induced on it
e) explanation is the same as foe option d.
What is the velocity during the first 4 seconds?
Answer:
6?
Explanation:
Answer:
did you get the answer bc I think its -3
Explanation:
Which dartboard represents high accuracy and low precision?
A small mailbag is released from a helicopter that is descending steadily at 1.20 m/s. (a) After 5.00 s, what is the speed of the mailbag?
Answer:
50.2m/s
Explanation:
Using first equation of motion we have
V= u+gt
V= final speed
U= initial speed
So v = 1.2m/s + 9.8(5s)
50.2m/s
What is the electric field produced by this charge at point P, which is on the x-axis, 9.83 mm from the origin
Given :
Distance of point P from the origin is , d = 9.83 mm .
To Find :
The electric field produced by this charge at point P , if charge is placed at origin .
Solution :
Let , charge on origin is q .
Electric field at point P is given by :
[tex]E=\dfrac{kq}{r^2}[/tex] ..... ( 1 )
Here , k is constant , [tex]k=9\times 10^{9}\ N \ m^2/C^2[/tex] .
Putting value of k and r in above equation , we get :
[tex]E=\dfrac{q\times 9\times 10^9}{(9.83\times 10^{-3})^2}\ N/C\\\\E=(9.31\times 10^{13})q\ N/C[/tex]
Hence , this is the required solution .
1. A car travels at 55 km/h for 6.0 hours. How far does it travel?
Answer:
330 km
55*6= 330 km. An easy formula for this is multiplying time with speed.
Explanation:
330 kilometros
55 * 6 = 330 km. Una fórmula fácil para esto es multiplicar el tiempo por la velocidad.
Answer:330 km
Explanation:55*6= 330 km. An easy formula for this is multiplying time with speed.
Which of the following is the BEST example of increasing the intensity of a workout? A. running one mile further than normal B. running one mile faster than normal C. running one mile more every other workout D. jogging for three miles Please select the best answer from the choices provided. A B C D
Answer:
B. Running one mile faster than normal
Explanation:
Just took the quiz, good luck ❤
The best example of increasing the intensity of a workout is running one file faster than normal. Hence, option B is correct.
What is an Exercise?Exercise is a physical activity for the body that improves or preserves physical fitness as well as general health and wellness.
It is done for a variety of objectives, such as support growth and enhance strength, needs to better and also the cardiovascular system, refine sports skills, maintain or lose weight, improve health, or just for fun. Many people like to work outside where they may interact, gather in groups, and enhance their physical and emotional well-being.
The amount of advised exercise for health benefits varies on the objective, the style of activity, and the age of the individual. Exercise is better for you than not at all, even if it is only a little.
Therefore, the best example of increasing the intensity of workout or exercise by running one mile faster than normal.
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The main functions of the skin are:
ОА.
To protect the human body from foreign bodies from the outside environment.
ОВ.
A sensory organ for the brain.
Ос.
Shock absorption
OD
All of the above
Reset
Next
Answer:To protect the human body from foreign bodies from the outside environment.
Explanation:
according to the law , naturalized amrican citizens
What is the direction of the magnetic field around a wire carrying a current perpendicularly into this page
Answer:
Clockwise direction
Explanation:
In a case of a wire carrying a current, the right hand rule is used.
The thumb in the direction of current while the finger curl around in the direction of the magnetic field.
The right hand rule applies to a current in a straight line wire.
If the direction a wire carrying a current perpendicularly into this page, the direction of the magnetic field will be in a clockwise direction .
what distance is traveled by a police car that moves at a constant speed of 1.5 km/min for 5.0 min?
Answer:
7.5 meters
Explanation:
Answer:
7.5 kilometers
Explanation:
The distance can be found by multiplying the speed by the time.
[tex]d=s*t[/tex]
The car's speed is 1.5 kilometers per minute. It is traveling for 5.0, or 5 minutes. Therefore,
[tex]s= 1.5 km/min\\t=5 min[/tex]
Substitute the values into the formula.
[tex]d=1.5 km/min * 5 min[/tex]
Multiply. When you multiply, the minutes, or "min" will cancel each other out.
[tex]d= 1.5 km * 5[/tex]
[tex]d=7.5 km[/tex]
The distance the car travels is 7.5 kilometers.
If the kinetic energy of the ball decreases then the potential energy will____
Hey There!! ~
The answer to this is: Complete these sentences.
If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy is 15J.
If the kinetic energy of the ball decreases, then the potential energy will Increase.
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[tex]ItsNobody[/tex]~
Hypothesis If an object rolls over _______________ (type of material), then it will _____________ (describe the prediction of distance it will travel)
Answer:
smooth
go far
Adolescents required fewer hours of physical activity than adults. True or False?
Answer:
Aerobic physical activity is better for the cardiovascular system than it is for strength endurance, while anaerobic physical activity is better at building strength endurance than it is at increasing cardiorespiratory fitness.
Therefore true
What is a primary source?
Answer:
provides a first hand account of an event or time period and are considered to be authoritative
Answer:
main source
Explanation:
farah claps his 600times in 60seconds. what is the friquency and periodb
Answer:
[tex]\huge\boxed{\sf Frequency = 10\ Hz}[/tex]
[tex]\huge\boxed{\sf Time\ Period = 0.1\ secs}[/tex]
Explanation:
Given:
No. of times = 600 times
Time = 60 seconds
Required:
Frequency = f = ?
Time Period = T = ?
Solution:
Frequency = No. of Times / TimeFrequency = 600 / 60
Frequency = 10 Hz
Time Period = 1 / FrequencyTime Period = 1 / 10
Time Period = 0.1 secs
A student releases a marble from the top of a ramp. The marble increases
speed while on the ramp then continues across the floor. The marble travels a
total of 160cm in 4.60s.
What was the marble's final speed?
cm/s
HELP PLEASE
Answer:
Vf = 69.56 cm/s
Explanation:
In order to find the final speed of the ramp, we will use the equations of motion. First we use second equation of motion to find out the acceleration of marble:
s = Vi t + (1/2)at²
where,
s = distance traveled = 160 cm
Vi = Initial Speed = 0 cm/s (since, marble starts from rest)
t = time interval = 4.6 s
a = acceleration = ?
Therefore,
160 cm = (0 cm/s)(4.6 s) + (1/2)(a)(4.6 s)²
a = (320 cm)/(4.6 s)²
a = 15.12 cm/s²
Now, we use first equation of motion:
Vf = Vi + at
Vf = 0 cm/s + (15.12 cm/s²)(4.6 s)
Vf = 69.56 cm/s
A woman leaning over the railing of a tall bridge accidentally drops her cell phone. If the bridge is 31.16 m high, how long will it take the phone to hit the river below the bridge?
Answer:
2.52 s
Explanation:
We can use equation of motion to solve this.
[tex]s \: = ut + \frac{1}{2} a {t}^{2} [/tex]
Assuming initial velocity to be 0 and no air resistance,
[tex] s \: = \frac{1}{2} a {t}^{2} \\ 31.16 = \frac{1}{2} (9.81) {t}^{2} \\ t = 2.52s[/tex]
The time of flight is 3.54 s.
What are equations of motion?There are three equation of motions that can be used when motion of the object is under constant acceleration and on a straight path.
They are listed below as:
[tex]v = u + at\\\\s = ut + \dfrac{1}{2} at^2\\\\v^2 = u^2 + 2as[/tex]
where the symbols have following meanings:
u = initial velocity of the considered object
v = final velocity of the object
a = acceleration of the object
s = distance traveled by the object in 't' time.
It is given that A woman leaning over the railing of a tall bridge accidentally drops her cell phone. If the bridge is 31.16 m high, then how long will it take the phone to hit the river below the bridge.
We can use equation of motion to solve this;
[tex]s = ut + \dfrac{1}{2} at^2[/tex]
where:
s = 31.16 m is the vertical displacement of the phone
u = 0 is the initial vertical velocity
Assuming initial velocity to be 0 and no air resistance,
[tex]s = 1/2 (9.8)(t)^2\\31.16 = 1/2 (9.8)(t)^2\\t = 2.52 s[/tex]
Hence, The time of flight is 3.54 s.
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You are driving your car at a speed of 19.0 m/s and you hit the brakes. The car accelerates at -3.50 m/s2. (a) How long does it take the car to cover 10.0 m? (b) What is the final velocity of the car? (show work)
Answer:
Time taken by car to cover 10m is 5.42 seconds and final velocity is 0m/s.