What Mass of glucose is
needed to prepare 235mL of 22% w/v glucose?

Answers

Answer 1

Answer: 8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution. 8 grams of glucose are needed to prepare 400.Oct 6, 2017

Answer 2

Answer:

8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution. 8 grams of glucose are needed to prepare 400

Explanation:


Related Questions

how much carbon is in CO2 if the sample contains 48 g of oxygen remember the ratio of carbon to oxygen is 12 g of 32 g
18g
24g
12g
20g

Answers

Answer: 24g

Explanation:

Explain the term mole ratio in your own words When would you use this term ?

Answers

Answer:

A mole ratio is ​the ratio between the amounts in moles of any two compounds involved in a chemical reaction.

Mole ratios are used as conversion factors between products and reactants in many chemistry problems.

Explanation:

During a solar eclipse, explain what would an observer
on the Moon see on the surface of the Earth?

Answers

Answer:

It getting darker

Explanation:

This is because the light isn't hitting the earth as much, making it darker. They might also see more city lights than before. Hope this helps! plz mark as brainliest!

How many grams of carbon disulfide will be produced if .012
kg of sulfur reacts with carbon?

Answers

Answer:

14.25g

Explination:

I found this answer on quizlet titled, "Chem Quizlet" by jamie_barbara

what is similar between emission like spectrum and absorption line spectrum?

Answers

The main difference between the two is that emission spectrum has different colored lines in the spectrum, an absorption spectrum has dark colored lines in the spectrum.

write the molecular formula of sodium nitroprusside.​

Answers

Answer:

Explanation: Sodium Nitroprusside, whose molecular formula is  • 2H2O, and whose molecular weight is 297.95. Dry sodium nitroprusside is a reddish-brown powder, soluble in water.

Use average bond enthalpies (linked above) to calculate the enthalpy change for the following gas-phase reaction. CO(g) + Cl2(g) COCl2(g) To analyze the reaction, first draw Lew To analyze the reaction, first draw Lewis structures for all reactant and product molecules. ΔHreaction = ------ kJ Draw the reaction using separate sketchers for each species. Separate multiple reactants and/or products using the + sign from the drop-down arrow. Separate reactants from products using the → symbol from the drop-down menu. Remember to include nonbonding valence electrons in your Lewis structures. To analyze the reaction, first draw Lewis structures for all reactant and product molecules. Draw the reaction using separate sketchers for each species. Separate multiple reactants and/or products using the + sign from the drop-down arrow. Separate reactants from products using the → symbol from the drop-down menu. Remember to include nonbonding valence electrons in your Lewis structures. To analyze the reaction, first draw Lewis structures for all reactant and product molecules. Draw the reaction using separate sketchers for each species. Separate multiple reactants and/or products using the + sign from the drop-down arrow. Separate reactants from products using the → symbol from the drop-down menu. Remember to include nonbonding valence electrons in your Lewis structures.

Answers

Answer:

ΔHreaction (KJ) =  - 78 KJ

The value may vary in relation to the source of the bond enthalpy data.

 Bond enthalpies used  (From a table of bond enthalpies )

Bond           KJ/ mol

C≡O           1080

C-Cl            330

C=O           741

Cl-Cl           243

Explanation:

                         CO(g) + Cl2(g)  →    COCl2(g)

1) Lewis structures

Valence electrons

C     4

O     6

Cl     7

Reactants

CO(g)

In the case of CO, carbon has a negative charge and oxygen a positive charge.

Cl2(g)

Products

COCl2(g)

_______________________

ΔHreaction (KJ) = ∑ n* ΔH ( reactants) - ∑ n* ΔH (product)

ΔHreaction (KJ) =   (ΔHC≡O +   ΔHCl-Cl)  - ( ΔHC=O  + 2* ΔHC-Cl)

Replacing the values

ΔHreaction (KJ) =   (1080 +  243)  - ( 741 + 2* 330)

ΔHreaction (KJ) = 1323 -  1401

                          =  - 78 KJ

The strength of an acid is affected by the polarity of the bond connected to the acidic hydrogen. The more highly polarized this bond, the more easily the hydrogen is ionized. Electronegative atoms or groups of atoms present in the structure of an acid can act to withdraw electrons and produce additional polarization. Two common groups of acids to which this principle can be applied are oxoacids and carboxylic acids. In the latter group, the length of the hydrocarbon chain in a carboxylic acid has very little effect on acid strength Longer chains may slightly diminish acidity. Bases act as hydrogen ion acceptors because of the unshared electron pass in their structure. Any group present in a base that withdraws electrons makes these electron pairs less available to accept a hydrogen ion. In contrast, any group that can act as an electron donating group such as hydrocarbon groups (usually represented as II) can increase the base strength. Thus, the addition of electronegative atoms or groups of atoms to the structure of a base decreases the base strength and electron donating groups increase base strength. Many common weak bases are derivatives of ammonia, in which H atom(s) of NH_2 are replaced with other groups.
Arrange the following oxoacids in order of decreasing acid strength. Rank from strongest to weakest acid.
1. HBrO
2. HClO
3. HClO2
4. HClO3

Answers

Answer:

The answer is "[tex]\bold{HClO_3 > HClO_2 >HClO > HBrO}[/tex]"

Explanation:

We arrange oxoacids to decrease the intensity of acids in this question. Or we may conclude all this from strongest to weakest acids they order oxoacids, that's why above given order is correct.

In 2-3 sentences, explain how objects in our solar system planets acquired the mass to become planets.

Answers

The sun contained 99% of the available matter and the rest matter formed smaller clumps inside the spinning disk. These clumps gained enough mass which lead to their gravity shaping them into spheres becoming planets.

What are planets?

A planet can be described as a large, rounded astronomical body that is neither a star nor its remnant. The theory of planet formation is the nebular hypothesis, which tells that an interstellar cloud collapses out of a nebula to generate a young protostar orbited by a protoplanetary disk.

The planet grows in this disk by the accumulation of material driven by gravity and this process is known as accretion. Our solar system has at least eight planets that rotate around an axis tilted with respect to its orbital pole.

All planets possess an atmosphere, although that of Mercury is tenuous.  The Solar System planets create magnetic fields apart from Venus and Mars, and all planets except Venus and Mercury have natural satellites.

Learn more about planets, here:

https://brainly.com/question/15268075

#SPJ2

which of the following human activities are not related to an increase in global temperature

Answers

list the activities pls

You are given 19.2 liters of H3PO4. How many moles do you have?

Answers

Answer:

Explanation:

Do a quick conversion: 1 grams H3PO4 = 0.010204583427424 mole using the molecular. How many grams H3PO4 in 1 mol?  You can view more details on each measurement unit: molecular weight of H3PO4 or mol This. The formula weight is simply the weight in atomic mass units of all the atoms in a given formula.

PbSO4 has a Ksp = 1.3 * 10-8 (mol/L)2.

I will mark brainliest if you answer all three questions. Thank you so so so much!!!

Answers

i. The dissolution of PbSO₄ in water entails its ionizing into its constituent ions:

[tex]\mathrm{PbSO_{4}}(aq) \rightleftharpoons \mathrm{Pb^{2+}}(aq)+\mathrm{SO_4^{2-}}(aq).[/tex]

---

ii. Given the dissolution of some substance

[tex]xA{(s)} \rightleftharpoons yB{(aq)} + zC{(aq)}[/tex],

the Ksp, or the solubility product constant, of the preceding equation takes the general form

[tex]K_{sp} = [B]^y [C]^z[/tex].

The concentrations of pure solids (like substance A) and liquids are excluded from the equilibrium expression.

So, given our dissociation equation in question i., our Ksp expression would be written as:

[tex]K_{sp} = \mathrm{[Pb^{2+}] [SO_4^{2-}]}[/tex].

---

iii. Presumably, what we're being asked for here is the molar solubility of PbSO4 (at the standard 25 °C, as Ksp is temperature dependent). We have all the information needed to calculate the molar solubility. Since the Ksp tells us the ratio of equilibrium concentrations of PbSO4 in solution, we can consider either [Pb2+] or [SO4^2-] as equivalent to our molar solubility (since the concentration of either ion is the extent to which solid PbSO4 will dissociate or dissolve in water).

We know that Ksp = [Pb2+][SO4^2-], and we are given the value of the Ksp of for PbSO4 as 1.3 × 10⁻⁸. Since the molar ratio between the two ions are the same, we can use an equivalent variable to represent both:

[tex]1.3 \times 10^{-8} = s \times s = s^2 \\s = \sqrt{1.3 \times 10^{-8}} = 1.14 \times 10^{-4} \text{ mol/L}.[/tex]

So, the molar solubility of PbSO4 is 1.1 × 10⁻⁴ mol/L. The answer is given to two significant figures since the Ksp is given to two significant figures.


A blend or combination of genetic material of the parents.
Question 2
What do variations of inherited traits between parent and offspring arise from?

Answers

Answer:

Variations of inherited traits between parent and offspring arise from genetic differences that result from the subset of chromosomes (and therefore genes) inherited.

Explanation:

What is created when an acid is mixed with a base?

Answers

Answer:

If you mix equal amounts of a strong acid and a strong base, the two chemicals essentially cancel each other out and produce a salt and water. Mixing equal amounts of a strong acid with a strong base also produces a neutral pH (pH = 7) solution.

Calcium sulfate is ionic or covalent bond

Answers

Answer:

The Lewis structure for the sulfate ion consists of a central sulfur atom with four single bonds to oxygen atoms. This yields the expected total of 32 electrons. Since the sulfur atom started with six valence electrons, two of the S-O bonds are coordinate covalent.

Explanation:

Then that means it has both.

Which of these is a disadvantage of wind energy?
a. it is renewable.
0
b. it reduces greenhouse gas emissions.
0
c. it is abundant.
0
d. it reduces bird and bat populations

Answers

The answer is D... It reduces bird and bat population.

Answer: d

Explanation: took the test got it right

Write a word equation and a skeleton equation for the chemical reaction.
A. Solid iron reacts with aqueous copper(ii) nitrate to produce solid copper and aqueous iron(ii) nitrate.

Answers

That guy is a hacker beware!^

How many hydrogen atoms are present in H2SO4+H2O?

Answers

Four hydrogen atoms






Help me pls I put 49 point( every single point that I have) pls help me

Answers

Answer:

see below

Explanation:

1)  chem rxn    compound   molecule   covalent   ions    ionic

2) 2 hydrogen  one oxygen       H2O    covalent

3) is always liq

Write a net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and phosphoric acid are combined. Assume excess base. I WILL REPORT YOU I YOU POST A LINK AS AN ANSWER!

Answers

The complete reaction for potassium hydroxide (KOH) and phosphoric acid (H3PO4) would yield products of water (H2O) and potassium phosphate (K3PO4).

3 KOH + H3PO4 ---> K3PO4 + 3 H2O

The net ionic equation would be obtained when you express the compounds in their ionic forms and eliminating the spectator ions. Spectator ions are the ions that appear in the reactant and product side. They do not actively participate the in the reaction.

3 K+ + 3 OH- + H3PO4  --->  3K+ + PO4^3- + 3 H2O

H3PO4 is a weak acid so it does not dissociate. H2O is not an ionic compound so it also does not dissociate. Therefore, the spectator ion is the potassium ion K+. The net ionic reaction is

3 OH- + 3 H3PO4  ---> PO4^3- + 3 H2O

6621.5 kJ of heat is required to convert a 20.5 g sample of
aluminum from the solid to liquid phase. What is the heat of
fusion of aluminum in kJ/g?
kJ/g

Answers

Answer:

323 kJ/g

Explanation:

ck-12 said it was correct

What does H2o mean in chemistry?

Answers

Water (chemical formula: H2O) is a transparent fluid which forms the world's streams, lakes, oceans and rain, and is the major constituent of the fluids of organisms. As a chemical compound, a water molecule contains one oxygen and two hydrogen atoms that are connected by covalent bonds.

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer:

Water (chemical formula: H2O) is a transparent fluid which forms the world's streams, lakes, oceans and rain, and is the major constituent of the fluids of organisms. As a chemical compound, a water molecule contains one oxygen and two hydrogen atoms that are connected by covalent bonds.

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

2 C4H10 + 13O2 -------> 8CO2 + 10H2O
a) What is the mole ratio between butane and oxygen gas?
b) What is the mole ratio between water and oxygen gas?
c) How many moles of water formed?
d) How many moles of butane burned?
e) How many grams of butane burned?
f) How much oxygen was used up in moles?
g) How much oxygen was used up in grams?

Answers

Answer:

A. 2 : 13

B. 10 : 13

C. 10 moles of water, H₂O.

D. 2 moles of butane, C₄H₁₀

E. 116 g of butane, C₄H₁₀

F. 13 moles of oxygen, O₂

G. 416 g of oxygen, O₂

Explanation:

The equation for the reaction is given below:

2C₄H₁₀ + 13O₂ —> 8CO₂ + 10H₂O

A. Determination of the mole ratio between butane and oxygen gas.

Mole of butane, C₄H₁₀ = 2 moles

Mole of oxygen, O₂ = 13 moles

Mole ratio of butane and oxygen = 2 : 13

B. Determination of the mole ratio between water and oxygen gas

Mole of the water, H₂O = 10 moles

Mole of oxygen, O₂ = 13 moles

Mole ratio of water and oxygen = 10 : 13

C. Determination of the moles of water formed.

From the balanced equation above,

10 moles water, H₂O were produced.

D. Determination of the moles of butane burned.

From the balanced equation above,

2 moles of butane, C₄H₁₀ were burned.

E. Determination of the mass of butane burned.

Molar mass of C₄H₁₀ = (12×4) + (10×1)

= 48 + 10 = 58 g/mol

Mole of C₄H₁₀ = 2 moles

Mass of C₄H₁₀ =?

Mass = mole × molar mass

Mass of C₄H₁₀ = 2 × 58

Mass of C₄H₁₀ = 116 g

Thus, 116 g of butane, C₄H₁₀ were burned.

F. Determination of the number of mole of oxygen used.

From the balanced equation above,

13 moles of oxygen, O₂ were used.

G. Determination of the mass of oxygen used.

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ = 13 moles

Mass of O₂ =?

Mass = mole × molar mass

Mass of O₂ = 13 × 32

Mass of O₂ = 416 g

Thus, 416 g of oxygen, O₂ were used.

How did you spend your Easter?

Answers

Answer:

I didn't do anything, we don't celebrate lol I hope you had fun though!

Explanation:

pls help with 1 question (15 ponts)
What happens in the circulatory system?

Answers

It is made of blood vessels that carry blood towards and away from the heart, it also carries oxygen, nutrients and hormones to cells and removes waste like carbon dioxide

Can someone help me I am stuck on this question it would mean the world if u helped me =) have a nice day!

Answers

Answer:

C: Plants mostly need air, water and sunlight to grow

Explanation:

The following solutions are prepared by dissolving the requisite amount of solute in water to obtain the desired concentrations. Rank the solutions according to their respective osmotic pressures in decreasing order assuming the complete dissociation of ionic compounds. Rank from highest to lowest osmotic pressure. To rank items as equivalent, overlap them.
A. 1 M MgCl2
B. 1 M KCI
C. 1 M C12
D. H22011
1. Highest osmotic pressure
2. Lowest osmotic pressure

Answers

Answer: 1. Highest osmotic pressure : 1 M [tex]MgCl_2[/tex]

2. Lowest osmotic pressure:  1 M [tex]C_{12}H_{22}O_{11}[/tex]

Explanation:

[tex]\pi=i\times C\times R\times T[/tex]

[tex]\pi[/tex]= osmotic pressure

i = Van'T Hoff factor  

C = concentration  

T = Temperature  

1. For 1M [tex]MgCl_2[/tex]  

, i= 3 as it is a electrolyte and dissociate to give 3 ions.

[tex]MgCl_2\rightarrow Mg^{2+}+2Cl^{-}[/tex]  

2. For 1 M [tex]KCl[/tex]

, i= 2 as it is a electrolyte and dissociate to give 2 ions.

[tex]KCl\rightarrow K^{+}+Cl^{-}[/tex]

3. For  1M [tex]C_{12}H_{22}O_{11}[/tex]

, i= 1 as it is a non electrolyte and do not dissociate.  

Thus as vant hoff factor is highest for [tex]MgCl_2[/tex] thus osmotic pressure is highest for 1 M [tex]MgCl_2[/tex]

And as vant hoff factor is lowest for [tex]C_{12}H_{22}O_{11}[/tex] thus osmotic pressure is lowest for  1 M [tex]C_{12}H_{22}O_{11}[/tex]

Calculate the number of nickel atoms in a 5-cent coin of mass 0.942g if it was made of an alloy consisting of 75% copper and 25% nickel.

Answers

Answer:

2.41x10²¹ atoms

Explanation:

First we calculate the mass of nickel in the coin, using the given mass and percent composition:

0.942 g * 25/100 = 0.2355 g Ni

Then we convert 0.2355 grams of nickel to moles, using its molar mass:

0.2355 g Ni ÷ 58.69 g/mol = 0.004 mol

Finally we convert moles into number of atoms, using Avogadro's number:

0.004 mol * 6.023x10²³ atoms/mol = 2.41x10²¹ atoms

At 2000 ∘C the equilibrium constant for the reaction 2NO(g)⇌N2(g)+O2(g) is Kc=2.4×103. If the initial concentration of NO is 0.175 M , what is the equilibrium concentration of N2?

Answers

Answer:

[tex][N_2]=0.0866M[/tex]

Explanation:

Hello there!

In this case, in agreement to the chemical reaction, it is possible for us to figure out the equilibrium concentration of the N2 product, via an ICE table plugged in the equilibrium expression:

[tex]Kc=\frac{[N_2][O_2]}{[NO]^2}\\\\2.4x10^3=\frac{x*x}{(0.175-2x)^2}[/tex]

In such a way, when solving for x via quadratic equation or just a solver, it is possible to obtain:

[tex]x_1=0.0866M\\\\x_2=0.0884M[/tex]

In such a way, since the root 0.0884 M produce a negative concentration of NO (0.175-2*0.0884=-0.0018M), we infer that the correct root is 0.0866 M; therefore, the concentration of N2 at equilibrium is equal to x:

[tex][N_2]=x=0.0866M[/tex]

Best regards!

Suppose that Laser A were to shine a beam of light straight into the left side of Prism A, and Laser B were to shine an identical beam of light straight into the left side of Prism B. Which prism would refract the light more? (Assume the sides of the two prisms are sloped the same.)

Answers

Answer:

Prism B

Explanation:

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