Answer:
Resolve the vectors:
F1 = 30 cos 30 i + 30 sin 30 j = 26 i + 15 j
F2 = 80 cos 135 i + 80 sin 135 j = -56.6 i + 56,6 j
F1 + F2 = (26 - 56.6) i + (15 + 56.6) j = -30.6 i + 71.6 j
The offsetting force would be
F3 = 30.6 i - 71.6 j
The magnitude of this vector is (30.6^2 + 71.6^2)^1/2 = 77.9
cos theta 3 = 30.6 / 77.9 = 66.9 deg
Check:
77.9 * sin 66.9 = 71.6 agreeing in magnitude with F3
Now we need the quadrant of the offsetting vector
sin theta 3 = - cos theta 3 = +
This occurs in the fourth quadrant and theta 3 = 360 - 66.9 = 293.1 deg
Leverrier predicted that an invisible planet was pulling the planet Uranus off its predicted course around the sun. Likewise, human beings are pulled off course by the invisible forces of their ____________.
Human beings are pulled off course as a result of the invisible forces of the unconscious.
According to Leverrier, he stated that an invisible planet was pulling the planet Uranus off its predicted course around the sun.
In such a way, human beings are pulled off course by the invisible forces of their unconscious minds. The unconscious minds of people control the thoughts of people.
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The c-c sigma bond in acetylene is formed by the overlap of which two orbitals.
Answer:When carbon atom tends to form single bonds then its hybridization is , when carbon atom tends to form double bond then its hybridization is and when a carbon atom is attached to a triple bond or with two double bonds then its hydridization is sp.
For example, in HCN molecule there is a triple existing between the carbon and nitrogen atom.
So, hybridization of carbon in this molecules is sp. Moreover, nitrogen atom is also attached via triple bond and it also has a lone pair of electrons. Hence, the hybridization of nitrogen atom is also sp.
Thus, we can conclude that s and p type of orbitals overlap to form the sigma bond between C and N in H−C≡N:
Explanation:
The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32. 50 N/m, is 0. 640 J. Find by how much is the spring is compressed.
The spring in the dart gun is compressed by 0.16 m
From the question given above, the following data were obtained:
Spring constant (K) = 50 N/m
Potential Energy (PE) = 0.640 J
Compression (e) =?The compression experience by the spring can be obtained as follow:
PE = ½ke²
0.64 = ½ × 50 × e²
0.64 = 25 × e²
Divide both side by 25
e² = 0.64 / 25
Take the square root of both side
e = √(0.64 / 25)
e = 0.16 m
Therefore, the spring is compressed by 0.16 m
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What is the disappearance of a wave into a medium.
A. Signal
B. Amplitude
C. Absorption
D. Transmission
Answer:
Absorption
Explanation:
the disappearance of an EM wave into the medium. scattering – the spreading out of light rays in all directions because particles reflect and absorb the light.
if you were planning to escape from someone and you were tied to a chair what would you do
A child, m = 25. 0 kg, swings from a rope, l = 9. 43 m, which hangs above water, d = 1. 9 m, when vertical. The child is h = 4. 8 m above the water when she begins to swing.
The velocity at the bottom of the swing is [tex]\mathbf{v= \sqrt{2gh -2gd}}[/tex]. The time it took the child to reach the river is 0.62 seconds.
The objective of this question is to determine:
The expression for the velocity of the child at the bottom of the swing.Suppose the child lets go at the bottom of the swing, how long does she take to reach the river at t seconds.At the bottom of the swing, there is an equal change in both the Kinetic energy as well as the potential energy and the expression can be computed as:
[tex]\mathbf{\dfrac{1}{2}mv^2 = mg (h -d)}[/tex]
[tex]\mathbf{\dfrac{v^2}{2}= g (h -d)}[/tex]
[tex]\mathbf{v^2= 2gh -2gd}[/tex]
[tex]\mathbf{v= \sqrt{2gh -2gd}}[/tex]
According to the second equation of motion;
[tex]\mathbf{S = ut +\dfrac{1}{2}at^2}[/tex]
where;
distance s = d = 1.9 macceleration due to gravity = 9.8 m/s²initial velocity (u) = 0∴
[tex]\mathbf{1.9 = 0(t) +\dfrac{1}{2}(9.8) t^2}[/tex]
[tex]\mathbf{1.9 = \dfrac{1}{2}(9.8) t^2}[/tex]
[tex]\mathbf{t^2 =\dfrac{1.9\times 2}{9.8} }}[/tex]
[tex]\mathbf{t = \sqrt{\dfrac{1.9\times2}{9.8}}}[/tex]
[tex]\mathbf{t =0.62 \ s}[/tex]
Therefore, we can conclude that the velocity at the bottom of the swing is [tex]\mathbf{v= \sqrt{2gh -2gd}}[/tex]. The time it took the child to reach the river is 0.62 seconds.
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Which is the force that results from use of a machine?
O a. input force
Oc. input work
Ob. output force
Od. output work
Answer:
D. Output force
Explanation:
The input force is the effort used to run the machine and this results in an output force.
Jade has a refractive index of 1.61. If light approaches the gem at an angle of 80.0°, what is the angle of refraction?
Calculate the index of refraction of a material if the angle of incidence is 60° and the angle of refraction is 50°
Answer using calculations & full work and thoughts shown.
From Snell's law, the angle of refraction is 38 degree approximately and the index of refraction is 1.13
The given refractive index is 1.61
If light approaches the gem at an angle of 80.0°, that means the angle of incidence is 80.0°
To calculate the angle of refraction, we will use Snell's law which state that:
n = sin i / sin r
where n = refractive index
Substitute all the parameters into the formula
1.61 = sin 80 / sin r
make sin r the subject of formula
sin r = sin 80 / 1.61
sin r = 0.611
r = [tex]Sin^{-1}[/tex](0.611)
r = 37.7
r = 38 degree (Approximately)
We will use the same formula to calculate the index of refraction of a material if the angle of incidence is 60° and the angle of refraction is 50°. That is,
n = sin i / sin R
Where n = index of refraction
i = Incidence
R = refraction
Substitute all the parameters to the formula
n = sin 60 / sin 50
n = 0.866 / 0.766
n = 1.13
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How long would it take a 500 w electric motor to do 150,000 j of work
Explanation:
300 second = 5 minutes
details
500 watts = 500 joules per second
Time = (1.50 x 10^5 joules)/(5 x 10^2 joules per second) = .3 x 10^3 seconds =300 second
If you eat cheese are you 1 percent cheese?
Answer:
No. Exactly what you eat doesn’t make up your internal structure.
:)
Answer:
Explanation:
Light cheeses are less than 20 %, low fat cheeses are 20 to 30%, fat cheeses are 50 to 60%, double-cream cheeses are at least 60% and triple-cream cheeses are at least 75 %.
The wave height is equal to twice the _____.wave period wave height wave amplitude wave velocity wavelength
The wave height is equal to twice the amplitude of the wave.
The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.
The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.
Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.
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At what tension, in newtons, must the D-string must be stretched in order for it to be properly tuned
The fundamental frequency, wavelength of the wave, and mass per unit
length of the string, determines the tension in the string.
The tension to which the D-string must be tuned is approximately 19.718 NewtonsReasons:
From a similar question, we have;
Fundamental frequency, f₁ = 146.8 Hz
Oscillating length on the D-string, λ₁ = 0.61 m
Mass of the string = 1.5 × 10⁻³ kg.
We have;
[tex]\displaystyle f_1 \cdot \lambda _1 =\mathbf{ \sqrt{\frac{T}{m/L} }}[/tex]
Therefore;
[tex]\displaystyle T = \mathbf{\frac{f_1^2 \cdot \lambda _1^2 \cdot m }{L}}[/tex]
Which gives;
[tex]\displaystyle T = \frac{146.8^2 \times 0.61^2 \times 1.5 \times 10^{-3} }{0.61 } \approx \mathbf{19.718}[/tex]
The tension to which the D-string must be tuned, T ≈ 19.718 Newtons
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The parameters given in a similar question obtained online are;
The fundamental frequency of the tone, f₁ = 146.8 Hz
The oscillating length on the D-string, λ₁ = 0.61 m
The mass of the string = 1.5 × 10⁻³ kg.
What is a thought experiment?
Answer:
A thought experiment is an experiment carried out only in the imagination
Explanation:
What is a net force on an object that has a mass of 20.0 kg, an applied force of 100 n moving on a surface with a friction coefficient of 0.21?
The net force on the object as described is; 58.84N
Two forces acting on the object are;
The applied force and the frictional force.In essence; the frictional force can be evaluated as;
Frictional force; = coefficient × Weight of object.Frictional force = 0.21 × 20 × 9.8.Frictional force = 41.16NThe Net force = Applied force - frictional forceNet force = 100 - 41.16NNet Force = 58.84 N.
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What acceleration occurs if the friction force in #4 is now 4N?
The acceleration of the 20 N force is 6.67 m/s^2. The acceleration of the 4N force is 1.33 m/s^2.
What is force?We define the force that acts on a body as that which is able to cause an acceleration or that which is able to change the direction of an object. Recall that from the Newton first law, an object would continue in its state of rest or uniform motion unless the object is acted upon by an external force.
Now the frictional force is the force that tends to resist the motion of two surfaces that are in contact. Owing to the fact that it is a resistive force its direction is always opposite the force that seeks to move the object forward.
Now;
F = ma
a = F/m
a = 20 N/3Kg
a = 6.67 m/s^2
If the force is 4N;
a = F/m
a = 4N/3Kg
a = 1.33 m/s^2
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Missing parts;
How would you calculate the acceleration if you push with a 20 N horizontal force on a 3 kg block on a horizontal friction-free air table? What is the acceleration if the friction force is 4 N?
How much force is required to move a tractor 60m, when using 250J of work?
Answer:
Work done,W= 250J
Displacement , s = 60
We know that, Work done = Force x displacement
i.e , W = Fxs
250 J = F x 60m
F = 250/60
=4.16 N
Hence , 4.16 N of Force is applied on the body.
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5. An acrobat, starting from rest, swings freely on a trapeze of
length 3.7 m (Figure 6). If the initial angle of the trapeze is
48°, use the law of conservation of energy to determine
(a) the acrobat's speed at the bottom of the swing
(b) the maximum height, relative to the initial position, to
which the acrobat can rise
The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;
a) The maximum speed is v = 4.89 m / s
b) The maximum height is h = 1.22 m
The energy conservation is one of the most fundamental principles of physics, stable that if there are no friction forces the mechanistic energy remains constant. Mechanical energy is the sum of the kinetic energy plus the potential energies.
Em = K + U
Let's write the energy in two points.
Starting point. Highest part of the oscillation
Em₀ = U = m g h
Final point. Lower part of the movement
[tex]Em_f[/tex] = K = ½ m v²
Energy is conserved.
Emo = [tex]Em_f[/tex]
m g h = ½ m v²
v² = 2 gh
Let's use trigonometry to find the height, see attached.
h = L - L cos θ
h = L (1- cos θ)
They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.
h = 3.7 (1- cos 48)
h = 1.22 m
this is the maximum height of the movement.
Let's calculate the velocity.
[tex]v= \sqrt{2 \ 9.8 \ 1.22}[/tex]
v = 4.89 m / s
In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;
a) The maximum speed is v = 4.89 m / s
b) The maximum height is h = 1.22 m
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A cyclist accelerates from 0m/s to 8m/s in 3 seconds.
Answer:
the rate of acceleration is 2.6666(and so on) if thats your question
Explanation:
I couldn't answer this question may someone please help me
Distance (s) =20 m
Initial velocity =0 m/s
g=10 m/s²
By using the formula:
v²= u²+ 2as
v²=0²+ 2×10×15
v²= 300
V= 10root over 3
[tex]10 \sqrt{3} [/tex]
For calculating time,
v= u+ at
10 root over 3 = 0+ 10t
10 root over= 10t
t = 1 root over 3
t = 1.73 s
[tex]1 \sqrt{3} [/tex]
The the stone will hit the ground with a velocity of 10 root over 3 m/s in 1 root over 3 sec.
The magnitude of vector A is 2.5 m and is directed towards east. The magnitude and direction of A /2 will be
The magnitude and direction of half of the given vector A is 1.25 m east.
The given parameters;
magnitude of vector A = 2.5 m eastA vector can be described with both magnitude and direction. The magnitude of the vector is the scalar or numeric representation of the vector.
When the scalar representation has direction, we term the quantity a vector quantity.
The magnitude of half of the given vector is calculated as follows;
[tex]\frac{A}{2} = \frac{2.5 \ m}{2} = 1.25 \ m\ east[/tex]
Thus, the magnitude and direction of half of the given vector A is 1.25 m east.
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The right to gather to advance some political or social cause is known as
Answer:
the first amendment
Explanation:
the first amendment to the United States constitution allows the freedoms concerning religion, expression, assembly, and the right to gather and petition.
PLS HELP ASAP it's just 2 questions and they are multiple choice!
I need help quickly pls
Answer:
Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:
Explanation:
5. How are electromagnetic waves similar to ocean waves?.
Answer:
Electromagnetic waves have crests and troughs similar to those of ocean waves. The distance between crests is the wavelength. The shortest wavelengths are just fractions of the size of an atom, while the longest wavelengths scientists currently study can be larger than the diameter of our planet!
Explanation:
hope it's helps u ...........!
Help help fast please first answer gets brainiest also needs to be clearly stated
a ball is thrown vertically up ward with a velocity of 25m/s. a/how fast was it moving after 2sec?
Answer:
12.5
Explanation:
given
distance=25
time=2sec
required
=speed
solution
=v=s/t
25/2
=12.5m/s
Suppose you were able to take measurements of current through the
resistor and voltage across the resistor. Your record of numerical values is written in a
tabular data below
Answer:
see attached
Explanation:
It will be easier to plot the data if you have grid lines to work with.
In the attached, we had to reverse the order of entries in the table, because the graphing program likes the independent variable listed first.
How far can a mother push a 20.0 kg baby carriage, using a force of 62 N, if she can only do 2920 J of work?
Please find attached photograph for your answer.
Hope it helps.
One thing I have to mention is that here we do not need to calculate the mass because the amount of force is already given.
Please do comment if you have any query.
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Imagine that a car is speeding down the highway and it hits a large bump in the road that forces it off the road. What would Newton call that object?
A.
a physical object
B.
a course interrupter
C.
an unbalanced force
D.
an unfortunate event
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
C. unbalanced force
Explanation:
it is called unbalanced force because it has changed direction of the moving object
How much would a 70 kg student weigh on Pluto? (massPluto = 1.25 x 1022 kg, radiusPluto = 1.20 x 106 m)
Answer: the weight would be 4.6 (I think i don’t know))
Explanation: