what was the physical property used by mendleev in creating his periodic table.​

Answers

Answer 1

Answer:

melting point and boiling point


Related Questions

earthquakes are most common

Answers

Answer:

Most earthquakes occur along the edge of the oceanic and continental plates.

Explanation:

And if your question is for the country then it will be Japan

Neil Bohr's model of the atom suggested that electrons are found in distinct paths. Question 11 options: True False

Answers

Answer:

true

Explanation:

Copper slowly reacts with oxygenIs this a physical or chemical change?

Answers

Answer:CHEMICAL

Explanation:

it cannot go back to its original state and it reacts.

What is the hydrogen ion concentration of a solution with pH 5.60?

Answers

Answer:options

Explanation:

What should the ^14_6C content (in percent of y0) of a fossilized tree that is claimed to be 3000 years old?

Answers

Answer:

The current mass fraction of [tex]^{14}_{6} C[/tex] should be approximately 68.8 percent.

Explanation:

[tex]^{14}_{6} C[/tex] is a radioactive isotope with a halflife of 5568 years. The decay of any radioisotope is modelled after the following ordinary differential equation:

[tex]\frac{dm}{dt} = -\frac{m}{\tau}[/tex]

Where:

[tex]m[/tex] - Current mass of the isotope, measured in grams.

[tex]\tau[/tex] - Time constant, measured in years.

The solution of this equation is of the form:

[tex]m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }[/tex]

Where:

[tex]t[/tex] - Time, measured in years.

[tex]m_{o}[/tex] - Initial mass of the isotope, measured in grams.

The time constant can be found as a function of halflife ([tex]t_{1/2}[/tex]):

[tex]\tau = \frac{t_{1/2}}{\ln 2}[/tex]

If [tex]t_{1/2} = 5568\,yrs[/tex] and [tex]t = 3000\,yrs[/tex], the mass fraction of [tex]^{14}_{6} C[/tex] is:

[tex]\tau = \frac{5568\,yrs}{\ln 2}[/tex]

[tex]\tau \approx 8032.926\,yrs[/tex]

[tex]\frac{m(3000\,yrs)}{m_{o}} = e^{-\frac{3000\,yrs}{8032.926\,yrs} }[/tex]

[tex]\frac{m(3000\,yrs)}{m_{o}} \approx 0.688[/tex]

The current mass fraction of [tex]^{14}_{6} C[/tex] should be approximately 68.8 percent.

Which of the following statements would be the hypothesis most easily tested? a) Oak trees grow tallest between temperatures of 10 and 40 degrees Celsius. b) All organisms are made of cells c) An invertebrate is an animal without a backbone or an internal skeleton d) If life were to exist on another planet, that life would also be composed of carbon compounds.

Answers

Answer: a) Oak trees grow tallest between temperatures of 10 and 40 degrees

Explanation:

This hypothesis is specific, can be tested (though perhaps not easily), and is well set up.

Hope this helps! :)

A student was asked to separate a mixture of chemicals. The weight of each component within the mixture is as follows: potassium bromide 2.53g and 0.760g barium sulfate. What is the percentage of barium sulfate within the mixture?

Answers

Answer:

a

Explanation:

f

The percentage of barium sulphate within the mixture is 23.1 %.

We have a mixture of barium sulfate and potassium bromide.

We have to determine the percentage of barium sulfate within the mixture.

What is a Mixture ?

A mixture is a material made up of two or more different chemical substances which are not chemically bonded to one another.

According to the question -

Mass of barium sulfate = 0.760 g

Total mass of mixture = 0.760 + 2.53 = 3.29 g

Therefore, the percentage of barium sulfate within the mixture -

0.760/3.29 x 100 = 23.1 %

Hence, the percentage of barium sulphate within the mixture is 23.1 %.

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Jia observes that adding a solution of sodium hydroxide to a clear liquid turns the liquid pink. She makes a hypothesis about why the liquid changed color. Which characteristic is least important for her hypothesis to have?

Answers

The question is incomplete, the complete question is;

Jia observes that adding a solution of sodium hydroxide to a clear liquid turns the liquid pink. She makes a hypothesis about why the liquid changed color.

Which characteristic is least important for her hypothesis to have?

A)ability to be tested

B)based on the opinion of her classmates

C)ability to be proven incorrect

D)based on her current knowledge

Answer:

B)based on the opinion of her classmates

Explanation:

A hypothesis is a supposition or tentative explanation put forward based on minimal evidence. It sometimes sets the pace for further investigation.

Hypothesis is always based on empirical observation and not on popular opinion, hence the opinion of Jia's classmates is least important in Jia's formulation of a hypothesis.

Answer:

B) based on the opinion of her classmates

Explanation:

edge 2023

a knowledge of life science is essential for botanists, forest technicians ,park rangers and health care workers true or false

Answers

Answer: True

Explanation:

I took the test

Answer:

T

Explanation:

Trust i took the test :p

4.731 * 10 ^ - 7 / 5.7 * 10 ^ 3 express in scientific notation

Answers

Answer:

8.3 × 10¯¹¹

Explanation:

4.731×10¯⁷ ÷ 5.7×10³

The above expression can be simplified as follow:

4.731×10¯⁷ ÷ 5.7×10³

Recall

a^m ÷ a^n = a^(m – n)

4.731×10¯⁷ ÷ 5.7×10³ = (4.731 ÷5.7) × 10^(–7 – 3)

4.731×10¯⁷ ÷ 5.7×10³ = 0.83 × 10¯¹⁰

4.731×10¯⁷ ÷ 5.7×10³ = 8.3×10¯¹ × 10¯¹⁰

Recall

a^m × a^n = a^(m + n)

8.3×10¯¹ × 10¯¹⁰ = 8.3 × 10^(–1 + –10)

8.3×10¯¹ × 10¯¹⁰ = 8.3 × 10^(–1 – 10)

8.3×10¯¹ × 10¯¹⁰ = 8.3 × 10¯¹¹

Therefore,

4.731×10¯⁷ ÷ 5.7×10³ = 8.3 × 10¯¹¹

An unknown element X has the following isotopes: ²⁵X (80.5% abundant) and ²⁷X (19.5% abundant). What is the average atomic mass in amu of X?

Answers

Answer:

25.4 amu

Explanation:

Step 1: Given data

Mass of the isotope ²⁵X (m²⁵X): 25 amuAbundance of the isotope ²⁵X (ab²⁵X): 80.5 % = 0.805Mass of the isotope ²⁷X (m²⁷X): 27 amuAbundance of the isotope ²⁷X (ab²⁷X): 19.5% = 0.195

Step 2: Calculate the average atomic mass of X

We will use the following expression.

m = m²⁵X × ab²⁵X + m²⁷X × ab²⁷X

m = 25 amu × 0.805 + 27 amu × 0.195

m = 25.4 amu

Which of the following is true about critical analysis of promotional claims?

a. It is necessary because consumers generally do not need to purchase goods.

b. Advertisements intend to mislead consumers about the goods they portray.

c. It prevents consumers from purchasing unnecessary goods.

d. It is essential because advertisements always contain false information.

Answers

Answer:

Which of the following is true about critical analysis of promotional claims?

a.  It is necessary because consumers generally do not need to purchase goods.

b.  Advertisements intend to mislead consumers about the goods they portray.

c.  It prevents consumers from purchasing unnecessary goods. Is Correct

d.  It is essential because advertisements always contain false information.

Critical analysis is an important aspect of the evaluation of the needs and demands. It is an integrated part of promotional claims to prevent unnecessary purchasing. Thus, option c is correct.

What is a promotional claim?

The promotional event is used in advertising to characterize the benefits and advantages of the services and products so as to persuade consumers and customers to buy the services and goods. The advertisements use claims to attract audiences.

It is a marketing strategy to increase sales and attract customers by offering various deals and services. The critical analysis of the promotional claim must be done to avoid the unnecessary purchasing of the goods and services by the consumers.

Therefore, option c. the unnecessary buying of the goods can be prevented by critical analysis.

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Determine the number of significant figures in each of the following measurements:________.
(a) 0.0000003 cm
(b) 2901 g
(c) 40.2 g
(d) 56 mL

Answers

Answer:

(a) 1.

(b) 4.

(c) 3.

(d) 2.

Explanation:

Hello,

(a) In this case, we do no take into account the zero digits before the first nonzero digit which is three, therefore it has one significant figure.

(b) In this case, we consider all the given figures since they are all after the first nonzero digit, therefore it has four significant figures.

(c) In this case, we consider all the given figures since they are all after the first nonzero digit including the decimal place, therefore it has three significant figures.

(d) In this case, we consider all the given figures since they are all after the first nonzero digit, therefore it has two significant figures.

Regards.

What is the volume of a sample of mercury having a mass of 1.0 kg if the density of mercury is 13.5g/cm3?

Answers

Answer:

volume = 74.07 cm³

Explanation:

The volume of a substance given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{Density} [/tex]

From the question

Density = 13.5 g/cm³

We must first convert the mass from kg to g

1kg = 1000 g

mass of mercury = 1000 g

Substitute the values into the above formula and solve

That's

[tex]volume = \frac{1000}{13.5} [/tex]

We have the final answer as

volume = 74.07 cm³

Hope this helps you

PLEASE HELP WILL GIVE BRAINLIEST!!!
How is a light bulb related to radiation?
A. The light emitted by a light bulb is a form of radiation that occurs when the filament heats up and its thermal emission gains enough energy to move into the visible spectrum.
B. Light bulbs do not have anything to do with radiation.
C. As light is emitted from the filament, the energy in the metal is replaced as lightbulbs absorb background radiation. This prevents the filament from burning out quickly but the radiation cannot be used as power so electricity is still required for the lightbulb to work.
D. A light bulb emits radiation when its filament is burned out and can longer emit light. This makes it important to remove dead lightbulbs as soon as they wear out.

Answers

Answer:

The light emitted by a light bulb is a form of radiation that occurs when the filament heats up and its thermal emission gains enough energy to move into the visible spectrum.

Explanation:

Light bulbs contain a filament which is heated up electrically. When this filament is heated up,energy in the form of heat is imparted to the electrons in the filament.

This thermal excitation of electrons ultimately leads to emission of light in the viable spectrum. This light is now radiated through a light bulb.

which of the following is an example of a combustion reaction ?
A. photosynthesis in plants
B. cellular respiration in humans
C. mixing of vinegar and baking soda
D. release of carbon dioxide on heating limestone

Answers

Answer:

D. release of carbon dioxide on heating limestone

Answer:

The guy up there is wrong cause i literally just took this test and the answer is B. cellular respiration in humans

Explanation:

The solar wind is made up of ions, mostly protons, flowing out from the Sun at about 400 km/s. Near Earth, each cubic kilometer of interplanetary
space contains, on average, 6 x 10^15 solar-wind ions.

How many miles of ions are in a cubic kilometer of near- Earth space?

Answers

Answer:

There are [tex]6\times 10^{12}[/tex] miles of ions in a cubic kilometer of near-Earth space.

Explanation:

In this context, we must be clear on stating that words miles is a synonym for thousands. In other words, the question may be rewritten to this form: How many thousand of ions are in a cubic kilometer of near-Earth space? In engineering notation, a thousand is represented by:

[tex]x = 10^{3}[/tex]

As we know the average quantity of solar-wind ions in a cubic kilometer of interplanetary space near Earth, we need to make quick conversion to determine the quantity of miles of ions by this formula:

[tex]y = n\cdot 10^{-3}[/tex]

Where:

[tex]n[/tex] - Quantity of solar-wind ions, measured in units.

[tex]y[/tex] - Quantity of solar-wind ions, measured in thousands (or miles).

If we know that [tex]n = 6\times 10^{15}\,units[/tex], then:

[tex]y = (6\times 10^{15}\,units)\cdot \left(10^{-3}\,\frac{miles}{unit} \right)[/tex]

[tex]y = 6\times 10^{12}\,miles[/tex]

There are [tex]6\times 10^{12}[/tex] miles of ions in a cubic kilometer of near-Earth space.

Complete each of the definitions with the appropriate phrase. Precision means that ___________measurements are close to____________ Accuracy means that___________ measurements are close to_____________

Answers

Answer:

Precision means that independent measurements are close to each other.

Accuracy means that independent measurements are close to a known or accepted value.

Explanation:

Accuracy refers to how close the measurements of a measurement system are to the true value while precision refers to how close the measurements are to each other. In other words, accuracy is the closeness of the value of one or more independent measurements to a true value, and precision is the closeness of two or more values ​​of several measurements to each other.

Both are independent of each other, that is to say that the results in the values ​​of a measurement can be precise and not exact, and vice versa.

So:

Precision means that independent measurements are close to each other.

Accuracy means that independent measurements are close to a known or accepted value.

1. What is the name of the covalent compound CCl4?2. What is the name of the covalent compound N2O5?

Answers

The first one, is like methane (CH4) but with 4 chlorine atoms. So tetrachloromethane. (Tetra is the Greek prefix for ‘four’)
The second one is a compound that consists of covalent bonds. This means that you should work with prefixes. This results in dinitrogenpent(a)oxide.

The name of the covalent compound CCl₄  is carbon tetracloride while that of N₂O₅ is dinitrogen pentoxide.

What is a covalent compound?

Covalent compound has a covalent  bond which  is defined as a type of bond which is formed by the mutual sharing of electrons to form electron pairs between the two atoms.These electron pairs are called as bonding pairs or shared pair of electrons.

Due to the sharing of valence electrons , the atoms are able to achieve a stable electronic configuration . Covalent bonding involves many types of interactions like σ bonding,π bonding ,metal-to-metal bonding ,etc.

Sigma bonds are the strongest covalent bonds while the pi bonds are weaker covalent bonds .Covalent bonds are affected by electronegativities of the atoms present in the molecules.Compounds having covalent bonds have lower melting points as compared to those with ionic bonds.

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Give the names of the cation in each of the following compounds: a. CuS b. Ag2SO4 c. Al(ClO3)3 d. CO(OH)2 e. PbCO3.

Answers

Answer:

a. Cu2+  (Copper (II) ion )   b. 2Ag+ ( Silver ion)  c. Al3+ (Aluminium (III) ion)  d. Co2+  ( Cobalt (II) ion)   e. Pb2+ ( Lead (II) ion )

Explanation:

Cations are positively charged ions.

In the question given;

CuS , known as Copper (ii) Sulphide, has Cu2+ (Copper (II) ion ) as the Cation.

Ag2SO4, Known as Silver Sulfate, has 2Ag+ ( Silver ion) as the Cation.

Al(ClO3)3, known as Aluminium Chlorate, has Al3+ (Aluminium (III) ion), as the Cation.

Co(OH)2, known as Cobalt(II) Hydroxide, has Co2+ ( Cobalt (II) ion) , as the Cation.

PbCO3, known as Lead(II) Carbonate, has Pb2+ ( Lead (II) ion ), as the Cation.

Calculate the volume, in milliliters, of a 0.470 M KOH solution that should be added to 5.250 g of HEPES (MW = 238.306 g/mol, pKa = 7.56) to give a p

Answers

Answer:

17.13mL

Explanation:

Complete question:

to give a pH of 7.32.

Hepes is a weak acid. When HEPES reacts with KOH its conjugate base, HEPES⁻ is produced:

HEPES + KOH → HEPES⁻

Now when you have in solution both the weak acid and conjugate base a buffer is produced. The equation that relates pKa and pH of a buffer is H-H equation:

pH = pKa + log [HEPES⁻] / [HEPES]

Where [] could be taken as the moles of each specie.

Replacing:

7.32 = 7.56 + log [HEPES⁻] / [HEPES]

-0.24 = log [HEPES⁻] / [HEPES]

0.57544 =  [HEPES⁻] / [HEPES] (1)

Now, moles of 5.250g of HEPES is:

Mass HEPES:

5.250g * (1mol / 238.306g) = 0.02203 moles HEPES.

That means:

0.02203 moles = [HEPES⁻] + [HEPES] (2)

Replacing (2) in (1):

0.57544 =  0.02203 moles - [HEPES] / [HEPES]

0.57544[HEPES] =  0.02203 moles - [HEPES]

1.57544[HEPES] = 0.02203 moles

[HEPES] = 0.01398 moles HEPES.

And [HEPES⁻] = 0.02203 moles - 0.01398 moles =

0.00805 moles of HEPES⁻

As HEPES⁻ is produced from HEPES and KOH, if we add 0.0805 moles of KOH, we will have in solution 0.00805 moles of HEPES⁻ and 0.01398 moles of HEPES.

To obtain 0.00805 moles of KOH from a 0.470M KOH, you need to add:

0.00805 moles KOH * (1L / 0.470mol) = 0.01713L of 0.470M KOH =

17.13mL

Use the pop-up menus to label the following statements as either True of False.
1. Hypochlorous acid is an oxidizing agent.
2. Concentrated acetic acid is corrosive.
3. Methylene chloride is flammable.
4. Methylene chloride is a probable human carcinogen.
5. Pipets that contain only water can be disposed of in the trash.

Answers

Answer:

1 True

2. True

3. True

4. True

5. False

Explanation:

1. Hypochlorous acid (HOCl)  is a weak acid that forms when chlorine dissolves in water, and is partially dissociated, forming hypochlorite. HOCl is considered a strong oxidizing agent responsible for the killing action of germs in chlorine solutions.

2. Acetic acid is also known as ethanoic acid. It has a distinctive sour taste and pungent smell, and is generally considered a weak acid. in a concentrated form, acetic acid can be corrosive.

3/4 . Methylene chloride is an organochloride compound with the formula CH2Cl2. It is  a colorless, volatile liquid with a moderately sweet aroma is widely used as a solvent. It is normally stable, non-flammable and non-explosive when mixed with air at temperatures below 100 °C, but its vapor is flammable only when present in relatively high concentrations of about 14% to 22% in air. Research shows that it is very much possibly carcinogenic, and it has been linked to cancer of the lungs, liver, pancreas, breast cancer and salivary gland cancer in laboratory animals.

5. Laboratory and medical waste are not to be disposed in the trash with regular wastes, as they are potentially toxic. Special disposal methods and agencies exists to take away such wastes.

Categorize each property as either physical or chemical.
Physical Properties
Chemical Properties
melting point
color
density
flammability
corrosiveness
electrical
reactivity with acids
hardness

Answers

Answer:

Physical properties are the properties of a substance that can observed and measured without altering the identity of the substance. Examples of physical properties according to the above question are color, hardness, malleability, electrical conductivity, density, melting point.

Chemical properties on the other hand are the properties of a substance that describes the ability of the substance to undergo chemical reactions based on its composition. Examples include reactivity with acids, flammability.

In other words, to identity a chemical property of a substance we check its ability to be change into a different state via chemical reaction. Rusting of iron is a good example of chemical property.

So therefore, categorizing the properties we have;

Physical properties                                             Chemical Properties

Melting point                                                                Flammability

Color                                                                        Reactivity with acids

Density                                                                       Corrosiveness

Electrical conductivity

Hardness

Answer:

Physical: Melting Point, Color, Conductivity, Boiling Point

Chemical: Susceptibility to rust, flammability

Explanation:

What will be the charge of the ion formed from each of these atoms ?
Si14, As33, Mg12, Rb37, F9, Ge32, Sn50

Answers

Answer:

Si14- Si^4+

As33- As^3-

Mg12- Mg^2+

Rb37- Rb^+

F9- F^-

Ge32- Ge^4+

Sn50- Sn^2+, Sn^4+

Explanation:

The elements shown in the answer have their common ions written beside them.

Silicon mostly forms positive ions in oxyacids and complex ions. Arsenic mostly forms its anion. Magnesium forms only the +2cation just as rubidium only forms the +1 cation. The fluoride ion is F^- while tin may for a +2*or +4 cation. Germanium usually forms the +4 cation.

graph results on a grid x 0, 10, 20, 30, 40, 50, 60, 70 and y 0,2,6,15,6,3,1,0

Answers

You should be able to graph this quiet easily, even online, look it up on desmos

Billy is running at a rate of 8 m/s West he ran a total distance of 400 m how long does it take him to complete the distance

Answers

Answer:

50 Seconds

Explanation:

400 Divided By 8 Is 50

Answer:

50

Explanation:

Its 50 because 400/8=50

Which of the following options correctly describe physical and chemical properties? A- A phase change always occurs when a physical property is measured B- When a chemical property is measured, the substance being observed is converted to a different substance or interacts with another substance. C- A chemical property of a substance can be observed without changing its composition or interacting with another substance. D- A physical property can be observed without a chemical reaction.

Answers

Answer:

The correct options are B and D

Explanation:

A physical property is a property (of any substance) that can be observed without the substance undergoing any change in identity nor does it require a chemical reaction to determine. For example, colour and size are physical properties that are part of the identity of a substance and can/must be observed without a substance undergoing any change or chemical reaction. This explanation makes option A wrong and option D right.

A chemical property of a substance is the property that relies on the ability of that substance to undergo a chemical reaction/interaction with another substance to form a new/different substance. For example, ability of a substance to react with an acid (to form a different substance) is a chemical property. This explanation makes option C wrong and option B correct.

Given the ion C2O4-2- , what species would you expect to form with each of the following ions?1. K+ _____2. Cu2+_____3. Bi3+_____4. Pb4+______5. NH4+______6. H+______

Answers

Answer:

1. K₂C₂O₄

2. CuC₂O₄.

3. Bi₂(C₂O₄)₃

4. Pb(C₂O₄)₂.

5. (NH₄)₂C₂O₄

6. H₂C₂O₄

Explanation:

Hello,

In this case, since the oxidation states are exchanged according to the naming rules, the resulting species are shown below:

1. K₂C₂O₄

2. CuC₂O₄ (here, the +2 of copper and -2 of C₂O₄, are simplified).

3. Bi₂(C₂O₄)₃

4. Pb(C₂O₄)₂ (here, the +4 of lead and -2 of C₂O₄, are simplified).

5. (NH₄)₂C₂O₄

6. H₂C₂O₄

Regards.

What is the term for "anything that takes up space and has mass"?
O A. Electron
B. Water
O c. Matter
O D. Atom
SUBN

Answers

Everything that takes up space around us that has mass is matter. So the answer is MATTER.

A student measured the volume of water to be 18.5 ml; the actual volume was 17.5 ml. What was the % deviation

Answers

Answer:

+5.7%

Explanation:

18.5mL/17.5mL = 1.057 = 105.7% - 100% = 5.7%

Since the measured volume was higher, it is PLUS 5.7%

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If the main pump is started at 7 PM, when should the auxiliary pump be started so that the tanker is emptied by 10 PM? 1) 6,875 28In the problem above,(estimate: 6,875 28 as 6,000 + 30 = 200).After the first digit is placed in the hundreds place in the quotient and students havedivided, multiplied, subtracted, and compared, the student should bring down the 7.Now, estimate 1270 28 and perform a second division (repeat).1,270 28 is estimated as 1,200 + 30 = 40.Students then divide, multiply, subtract, and compare the remainder to the divisor,making sure it is smaller.Finally, perform 115 -28, by estimating, dividing, multiplying, subtracting, andcomparingAfter writing the remainder in the quotient, the division is complete.What is the Quotient? Answer: Read the passage from Emma by Jane Austen. Then write a careful analysis showing how this passage provides a characterization and evaluation of Emma more than of Harriet. You may emphasize whichever devices (e.g., tone, selection of detail, syntax, point of view) you find most significant.Passage:As Emma sat one morning, a note was brought from Mrs. Goddard requesting, in most respectful terms, to be allowed to bring Miss Smith with her; a most welcome request; for Miss Smith was a girl of seventeen, whom Emma knew very well by sight, and had long felt an interest in, on account of her beauty. A very gracious invitation was returned, and the evening no longer dreaded by the fair mistress of the mansion. Harriet Smith was the natural* daughter of somebody. Somebody had placed her, several years back, at Mrs. Goddard's school, and somebody had lately raised her from the condition of scholar to that of parlour boarder. This was all that was generally known of her history. She had no visible friends, but what had been acquired at Highbury, and was now just returned from a long visit in the country to some young ladies who had been at school there with her. She was a very pretty girl, and her beauty happened to be of a sort which Emma particularly admired. She was short, plump, and fair, with a fine bloom, blue eyes, light hair, regular features, and a look of great sweetness; and, before the end of the evening, Emma was as much pleased with her manners as her person, and quite determined to continue the acquaintance. She was not struck by anything remarkably clever in Miss Smith's conversation, but she found her altogether very engaging-not inconveniently shy, nor unwilling to talkand yet so far from pushing, showing so proper and becoming a deference, seeming so pleasantly grateful for being admitted to Hartfield, and so artlessly impressed by the appearance of everything in so superior a style to what she had been used to, that she must have good sense, and deserve encouragement. Encouragement should be given. Those soft blue eyes, and all those natural graces, should not be wasted on the inferior society of Highbury and its connections. The acquaintances she had already formed were unworthy of her. The friends from whom she had just parted, though very good sort of people, must be doing her harm. They were a family of the name of Martin, whom Emma well knew by character, as renting a large farm of Mr. Knightley, and residing in the parish of Donwell-very creditably, she believed; she knew Mr. Knightley thought highly of them; but they must be coarse and unpolished, and very unfit to be the intimates of a girl who wanted only a little more knowledge and elegance to be quite perfect. She would notice her; she would improve her; she would detach her from her bad acquaintances, and introduce her into good society; she would form her opinions and her manners. It would be an interesting, and certainly a very kind undertaking; highly becoming her own situation in life, her leisure, and powers.