When Rutherford performed his experiment, only 1 in 20,000 alpha particles bounced straight back or were
deflected greatly. The rest went straight through the gold foil.
a What does this indicate about the probability of actually hitting anything?

Explanation:

The self-ionization of water (also autoionization of water, and autodissociation of water) is an ionization reaction in pure water or in an aqueous solution, in which a water molecule, H2O, deprotonates (loses the nucleus of one of its hydrogen atoms) to become a hydroxide ion, OH−. The hydrogen nucleus, H+, immediately protonates another water molecule to form hydronium, H3O+. It is an example of autoprotolysis, and exemplifies the amphoteric nature of water

Animation of the self-ionization of water

Chemically pure water has an electrical conductivity of 0.055 μS/cm. According to the theories of Svante Arrhenius, this must be due to the presence of ions. The ions are produced by the water self-ionization reaction, which applies to pure water and any aqueous solution:

H2O + H2O ⇌ H3O+ + OH−

Expressed with chemical activities a, instead of concentrations, the thermodynamic equilibrium constant for the water ionization reaction is:

{\displaystyle K_{\rm {eq}}={\frac {a_{\rm {H_{3}O^{+}}}\cdot a_{\rm {OH^{-}}}}{a_{\rm {H_{2}O}}^{2}}}}

which is numerically equal to the more traditional thermodynamic equilibrium constant written as:

{\displaystyle K_{\rm {eq}}={\frac {a_{\rm {H^{+}}}\cdot a_{\rm {OH^{-}}}}{a_{\rm {H_{2}O}}}}}

under the assumption that the sum of the chemical potentials of H+ and H3O+ is formally equal to twice the chemical potential of H2O at the same temperature and pressure.[1]

Because most acid–base solutions are typically very dilute, the activity of water is generally approximated as being equal to unity, which allows the ionic product of water to be expressed as:[2]

{\displaystyle K_{\rm {eq}}\approx a_{\rm {H_{3}O^{+}}}\cdot a_{\rm {OH^{-}}}}

In dilute aqueous solutions, the activities of solutes (dissolved species such as ions) are approximately equal to their concentrations. Thus, the ionization constant, dissociation constant, self-ionization constant, water ion-product constant or ionic product of water, symbolized by Kw, may be given by:

{\displaystyle K_{\rm {w}}=[{\rm {H_{3}O^{+}}}][{\rm {OH^{-}}}]}

where [H3O+] is the molarity (≈ molar concentration)[3] of hydrogen or hydronium ion, and [OH−] is the concentration of hydroxide ion. When the equilibrium constant is written as a product of concentrations (as opposed to activities) it is necessary to make corrections to the value of {\displaystyle K_{\rm {w}}} depending on ionic strength and other factors (see below).[4]

At 25 °C and zero ionic strength, Kw is equal to 1.0×10−14. Note that as with all equilibrium constants, the result is dimensionless because the concentration is in fact a concentration relative to the standard state, which for H+ and OH− are both defined to be 1 molal (or nearly 1 molar). For many practical purposes, the molal (mol solute/kg water) and molar (mol solute/L solution) concentrations can be considered as nearly equal at ambient temperature and pressure if the solution density remains close to one (i.e., sufficiently diluted solutions and negligible effect of temperature changes). The main advantage of the molal concentration unit (mol/kg water) is to result in stable and robust concentration values which are independent of the solution density and volume changes (density depending on the water salinity (ionic strength), temperature and pressure); therefore, molality is the preferred unit used in thermodynamic calculations or in precise or less-usual conditions, e.g., for seawater with a density significantly different from that of pure water,[3] or at elevated temperatures, like those prevailing in thermal power plants.

We can also define pKw {\displaystyle \equiv } −log10 Kw (which is approximately 14 at 25 °C). This is analogous to the notations pH and pKa for an acid dissociation constant, where the symbol p denotes a cologarithm. The logarithmic form of the equilibrium constant equation is pKw = pH + pOH.

Explanation:

Factors which determine how fast a solute will dissolve are as follows.

1). Surface area of dissolving particles - More is the surface area of dissolving particles available more it will come in contact with high number of particles. As a result, more interaction causes more collision between particles due to which more solute will dissolve in solvent.

2). Stirring - More stirring in a solution will lead to more number of collisions between the particles. Hence, more solute particles will dissolve in it.

3). Temperature - More is the temperature provided to solution more will be kinetic energy of its particles. This causes more collisions and therefore, more dissolution of solute particles in the solvent will take place.

Explanation:

Mike drives his car 60 km in 55minutes. What is its average speed in kilometers per hour ? A train travels 120 km in 2 hours and 30 .

l love my life an I am happy with it

Answer:

silicon

Explanation:

because silicon has 14 electrons and protons

Answer:

Sulphide ion(S-²) has a -2 charge

Ammonium (NH4+¹) has a +1 charge

When Exchange of Radicals Occur..

The compound formed is

(NH4)2S.

OPTION A IS YOUR ANSWER!

Answer:

NH4)2S

So it is A

Explanation:

Answer:

Calcium (Ca) - will lose electrons

Sulfur (S) - will gain electrons

Carbon (C) could lose or gain electrons

Neon (Ne) Does not gain or lose electrons

Answer:

The correct solution is "3.6975 M".

Explanation:

The given values are:

Volume of solution,

V = 23.2 mL

Density,

D = 1.42 g/mL

Final volume,

= 200 mL

or,

= 0.2 L

Now,

The mass will be:

= [tex]D\times V[/tex]

= [tex]1.42\times 23.1[/tex]

= [tex]32.802 \ g[/tex]

Mass of HNO₃ will be:

= [tex]\frac{32.802}{0.704}[/tex]

= [tex]46.59375 \ g[/tex]

Mol of HNO₃ will be:

= [tex]\frac{mass}{MW}[/tex]

= [tex]\frac{46.59375}{63}[/tex]

= [tex]0.7395 \ mol[/tex]

hence,

The concentration will be:

= [tex]\frac{mol \ of \ HNO_3}{final \ V}[/tex]

= [tex]\frac{0.7395}{0.2}[/tex]

= [tex]3.6975 \ M[/tex]

Answer:

See explanation

Explanation:

The molecular equation shows all the compounds involved in the reaction.

The molecular equation is as follows;

2NaF(aq) + Pb(NO3)2(aq) -------> PbF2(s) + 2NaNO3(aq)

The complete ionic equation shows all the ions involved in the reaction

The complete ionic equation;

2Na^+(aq) + 2F^-(aq) + Pb^2+(aq) + 2NO3^-(aq) -------->PbF(s) + 2Na^+(aq) +2NO3^-(aq)

The net Ionic equation shows the ions that actually participated in the reaction

The net ionic equation is;

2F^-(aq) + Pb^2+(aq)--------> PbF(s)

Answer: Aluminum, because it allows heat to flow easily.

Have a nice day!

Answer: third energy level

Explanation: In a sodium atom, the highest-energy principal energy level containing electrons is the third energy level, and that energy level contains one electron.

Answer:

[tex]m_X=66.4385amu[/tex]

Explanation:

Hello there!

In this case, according to the given information for this problem, it turns out possible for us to calculate the average atomic mass of the element by multiplying the mass of each isotope by its percent abundance and then add up the results, just as shown below:

[tex]65.3410amu*0.3187=20.8242amu\\\\66.9519amu*0.6813=45.6143amu\\\\m_X=20.8242amu+45.6143amu\\\\m_X=66.4385amu[/tex]

Regards!

Answer:

30 hot dogs

Explanation:

It is given that :

There are 4 packets of eight wieners, i.e. 4 x 8 = 32 wieners

There are 3 bags of ten buns, i.e. 3 x 10 = 30 buns

One hot dogs need 1 bun and 1 wiener to make a hot dog.

There are 30 buns, so 30 hot dogs can be made out by using all the 30 buns and the 30 wieners out of the 32 wieners.

Therefore, 30 hot dogs.

And the number of extra wieners left = 32 - 30 = 2 wieners.

Answer:

Mars and Orbital code saber and the alien

Answer:

See Explanation

Explanation:

A fission reaction is a chain reaction. The neutrons that are produced in one reaction leads to further chain reaction in the system.

If one neutron initiates fission that leads to the production of two other neutrons,two more new reactions are initiated.

If these reactions each produce one neutron, then another two new reactions are initiated. This makes a total of four new reactions from the two fission events described.

A total of four neutrons is produced from the two fission events.

Answer:

If one neutron initiates a fission event that produces two neutrons in the products, how many new reactions can now be initiated?

2

If each of the neutrons produced in the first fission event then initiates a fission event that produces one neutron in the products, how many new reactions can now be initiated by each neutron?

1

How many neutrons in total were produced by the two fission events described?

4

Explanation:

Got it correct on Edge.

could you theoretically cook methamphetamine? just wonderkng.

Answer:

sorry don't know the answer!!!

Answer:

just look at what row the element is in. The lower the row, the bigger the radius

Explanation:

Answer:

"22.73 atm" is the correct answer.

Explanation:

Given:

Solubility,

[tex]S_1=0.66 \ g/L[/tex]

[tex]S_2=1.5 \ g/L[/tex]

Pressure,

[tex]P_1=10.0 \ atm[/tex]

[tex]P_2=?[/tex]

By using Henry's law,

⇒ [tex]\frac{S_1}{P_1} =\frac{S_2}{P_2}[/tex]

or,

⇒ [tex]P_2=\frac{S_2 P_1}{S_1}[/tex]

By putting the values, we get

⇒      [tex]=\frac{1.5\times 10.0}{0.66}[/tex]

⇒      [tex]=\frac{15}{0.66}[/tex]

⇒      [tex]=22.73\ atm[/tex]

Answer:

[tex]yes[/tex]

Explanation:

Iodine is present in salt which makes it salty:)

Answer:

Nitrogen molecule (N2)

The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.

The total number of electrons present in the nitrogen molecule (N2) is 14.

In order to maximize energy, these 14 electrons can be accommodated in the different molecular orbitals.

N2: KK'(σ2s)2 (σ*2s)2 (π2Px)2 (π2py)2 (σ2pz)2

Here (σ1s)2 (σ*1s)2 part of the configuration is abbreviated as KK’, which denotes the K shells of the two atoms. In calculating bond order, we can ignore KK’, as it includes two bonding and two antibonding electrons.

The bond order of N2can be calculated as follows:

Here, Nb = 10 and Na = 4

Bond order = (Nb−Na) /2

B.O = (10−4)/2

B.O = 3

So your answer should be C3.

Answer: Silver bromide

Explanation: AgNO3 + KBr — AgBr + KNO3

Answer:

5.9 g

Explanation:

Step 1: Write the balanced reaction for the photosynthesis

6 CO₂ + 6 H₂O ⇒ C₆H₁₂O₆ + 6 O₂

Step 2: Calculate the moles of CO₂

We have 5.0 L of CO₂ at 32 °C (305 K) and 750 mmHg. We can calculate the moles of CO₂ using the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 750 mmHg × 5.0 L/(62.4 mmHg.L/mol.K) × 305 K = 0.20 mol

Step 3: Calculate the moles of C₆H₁₂O₆ produced from 0.20 moles of CO₂

The molar ratio of CO₂ to C₆H₁₂O₆ is 6:1. The moles of C₆H₁₂O₆ produced are 1/6 × 0.20 mol = 0.033 mol

Step 4: Calculate the mass corresponding to 0.033 moles of C₆H₁₂O₆

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

0.033 mol × 180.16 g/mol = 5.9 g

Answer:

80%

Explanation:

Water is essential for all the body functions like digestion

We should drink water so that we will have a healthy body

Stay safe and healthy :)

Answer:

1. Ferric sulfate - Fe2(SO4)3

2. Strontium oxalate – SrC2O4

3. Chromic acid – CrO3

4. Nickel (III) carbonate – NiCO3

5. Silver bromate – AgBrO3

6. Dinitrogen difluoride - N2H2

7. Magnesium molybdate – MgMoO4

8. Sodium hydrogen phosphate - Na2PO4

Answer:

circulatory and excretory

Answer:

Hi, there your answer is A. As the frequency of a wave increases, the shorter its wavelength is.

Explanation:

When frequency increases, wavelength decreases.

Hope this Helps :)

Today, as part of the series of posts on soils, we are going to look at ‘soil texture’. Soil forms the basis for all life but it’s important to know about its mineral constitution as well as its biological profile.

Texture refers to the ‘feel’ of the soil. This is affected by the constituent materials found within it, specifically sand, silt and clay particles. A coarse sand will feel gritty but a wet clay will feel heavy and sticky. The texture of a soil has a direct impact on the way the soil reacts to certain environmental conditions – for example, towards drought or heavy rain (with sandy soils more freely draining).

There is a big difference in the size of the different particles.

Coarse sand = diameter 2-0.2mm

Fine sand = diameter 0.2-0.02mm

Silt = diameter 0.02-0.002mm

Clay = diameter less than 0.002mm

Note how the clay particles are much smaller than the sand particles – this is important as it means the total surface area of a clay soil is much greater and so the capacity to hold water is also much greater.

Between the sand, silt and clay particles there are lots of pores. In fact a soil as a whole is generally 45% mineral, 5% organic matter (depending on the soil) and 50% pore space through which air and water can pass.

Sand –

Made up of weathered primary rock minerals.

The particles are irregular in outline.

They are large and so do not pack together easily.

Large pore spaces in between.

Air gets in very easily and water flows rapidly through it.

Silt –

Light energy travels in the form of waves.