Which descriptions are true regarding different muscle types? Select four options.
Cardiac and skeletal muscles are striated.
Skeletal and smooth muscles are nonstriated.
Smooth and cardiac muscles are voluntary.
Heart and digestive muscles are involuntary muscles.
Smooth and skeletal muscles are involved in movement.
Cardiac muscles work to pump blood.

Answers

Answer 1

Answer:

1, 4, 5, 6

Explanation:

Answer 2

Answer:

1,4,5,6

Explanation:


Related Questions

For a 0.300 mol sample of helium gas in a 0.200 L container at 248K, will the pressure be greater if calculated with the ideal gas law or the van der Waals equation, and by roughly how much? (For He,a=0.0342L2atmmol2,b=0.0237 Lmol)

Answers

Answer:

It changes by roughly 1 atm.

Explanation:

Hello!

In this case, since the ideal gas equation differs from the van der Waals' one by the presence of the a and b parameters which correct the assumption of no interactions into the container, they are written as:

[tex]P=\frac{nRT}{V}\\\\P=\frac{RT}{v_m-b}-\frac{a}{v_m^2}[/tex]

Thus, the pressure via the ideal gas equation is:

[tex]P=\frac{0.300mol*0.082\frac{atm*L}{mol*K}*248K}{0.200L}=30.5atm[/tex]

And the pressure via the van der Waals equation, considering the molar volume (vm=0.200L/0.300L=0.667L/mol) is:

[tex]P=\frac{0.082\frac{atm*L}{mol*K}*248K}{0.667L/mol-0.0237L/mol}-\frac{0.0342atm*L^2/mol^2}{(0.667L/mol)^2}\\\\P=31.6atm-0.0769atm\\\\P=31.5atm[/tex]

It means that the pressure change by 1 atm, which is not a significant difference for helium.

The difference in pressure calculated by the two methods is 84 atm.

The ideal gas equation is given by

PV =nRT

From the data given in the question;

P = ?

V = 0.200 L

n =  0.300 mol

T = 248K

R = 0.082 atmLK-1Mol-1

P = nRT/V

P =  0.300 mol × 0.082 atmLK-1Mol-1  × 248K/0.200 L

P = 30.5 atm

From Van der Waals equation;

P = RT/V - b - a/V^2

P =  (0.082 × 248/0.200 - 0.0237)  - (0.0342/ 0.200^2)

P = 114.5 atm

The difference in pressure calculated by the two methods is;

114.5 atm -  30.5 atm = 84 atm

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QUESTION 24
Calculate [H 30+] of a solution with a pH of 2.14.

Answers

Answer:

The hydronium ion concentration can be found from the pH by the reverse of the mathematical operation employed to find the pH. [H3O+] = 10-pH or [H3O+] = antilog (- pH).

I hope what I just explained is enough .

A gas has a density of 1.57 g/L at 40.0 °C and 2.00 atm of pressure. What is the identity of the gas?

Answers

Answer:

Ne is the identity of the gas

How many micrograms of sodium chloride (to 2 decimal places) can be added to 527 mL of 0.00150 M silver nitrate before a precipitate forms? (Ksp = 1.80 x 10-10)

Answers

Answer:

use google

Explanation:

A solution of acetic acid is prepared in water by adding 11.1 g of sodium acetate to a volumetric flask and bringing the volume to 1.0 L with water. The final pH is measured to be 5.25. What are the concentrations of acetate and acetic acid in solution? (Assume that the temperature of the solution is 25 degrees Celsius)

Answers

Answer:

Molarity acetate: 0.1353M

Molarity acetic acid: 0.0418M

Explanation:

When in solution you have a weak acid (Acetic acid) and its conjugate base (sodium acetate) a buffer is produced. The pH of this buffer is obtained using the H-H equation:

pH = pKa + log [A⁻] / [HA]

Where pH is pH of the solution = 5.25

pKa is pKa of acetic buffer = 4.74

[A⁻] is molarity of acetate ion - Molar mass sodium acetate: 82.03g/mol-:

11.1g * (1mol / 82.03g) = 0.1353moles A⁻ / 1.0L = 0.1353M

And [HA] are moles of acetic acid.

Solving for HA:

5.25 = 4.74 + log [0.1353] / [HA]

0.51 =  log [0.1353] / [HA]

3.236 = [0.1353] / [HA]

[HA] = 0.1353M / 3.236

[HA] = 0.0418M

Show by calculation which process produces more energy per gram of material reacting

Answers

The answer is meaw meaw

Roughly how many water molecules are ionized at any given time in a sample of room-temperature water? a. one in a thousand b. one in a million c. one in a billion d. one in a trillion

Answers

Answer:

one in a billion

Explanation:

We have it known that Pure water is entirely made up of H2O molecules. Just 1 in 10⁹, that is a billion molecules are ionized when it is at room temperature.

The Ionization of water has this chemical equation:

H2O <--> H+ + OH-

When At equilibrium and at room temperature, we have the rate of forward reaction and the backward reaction to be very fast such that no water molecule would eventually remain ionized.

Therefore our answer is roughly one in a billion water.

A mixture of Xe, Kr and Ar has a total pressure of 6.70 atm. What is the mole fraction of Kr if the partial pressure of Xe is 1.60 atm and that of Ar is 2.80 atm.

Answers

Answer:

0.343

Explanation:

Step 1: Given data

Total pressure of the gaseous mixture (P): 6.70 atmPartial pressure of Xe (pXe): 1.60 atmPartial pressure of Ar (pAr): 2.80 atm

Step 2: Calculate the partial pressure of Kr

The total pressure of the mixture is equal to the sum of the partial pressures of the individual gases.

P = pXe + pAr + pKr

pKr = P - pXe - pAr

pKr = 6.70 atm - 1.60 atm - 2.80 atm

pKr = 2.30 atm

Step 3: Calculate the mole fraction of Kr

We will use the following expression.

X(Kr) = pKr/P

X(Kr) = 2.30 atm/6.70 atm

X(Kr) = 0.343

Considering the Dalton's partial pressure, the mole fraction of Kr is 0.34.

The pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

[tex]P_{T} =P_{1} +P_{2} +...+P_{n}[/tex] where n is the number of gases.

This relationship is due to the assumption that there are no attractive forces between the gases.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture.

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

[tex]P_{A} =x_{A} P_{T}[/tex]

In this case, you know:

Total pressure= 6.70 atm. Partial pressure of Xe is 1.60 atm. Partial pressure of Ar is 2.80 atm.

So, replacing in the Dalton's partial pressure law:

[tex]P_{T} =P_{Xe} +P_{Ar} +P_{Kr}[/tex]

6.70 atm= 1.60 atm + 2.80 atm + [tex]P_{Kr}[/tex]

6.70 atm- 1.60 atm- 2.80 atm= [tex]P_{Kr}[/tex]

2.30 atm=[tex]P_{Kr}[/tex]

Then: [tex]P_{Kr} =x_{Kr} P_{T}[/tex]

2.30 atm= [tex]x_{Kr}[/tex] 6.70 atm

[tex]x_{Kr}[/tex] =2.30 atm ÷6.70 atm

[tex]x_{Kr}[/tex] = 0.34  

In summary, the mole fraction of Kr is 0.34.

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Assume that the top of your head has a surface area of 25 cm x 25 cm. How many newtons of force push on your head at sea level? If you estimate this area to be 100 in2, what is the force in pounds?

Answers

Answer:

(a) 6332.812 N (b) 1469.59  pounds.

Explanation:

Given that,

The surface area of the top of yu head is 25 cm x 25 cm

Area = 625 cm² = 0.0625 m²

Atmospheric pressure on it is 101325 Pa.

(a) Pressure acting on an object is given by force acting per unit area. It can be written as :

[tex]P=\dfrac{F}{A}\\\\F=PA\\\\F=101325\ Pa\times 0.0625\ m^2\\\\F=6332.812\ N[/tex]

6332.812 N of force is acting on your head at sea level.

(b) If area, A = 100 in²

We know that,

1 atm = 14.6959 pounds/in²

[tex]P=\dfrac{F}{A}\\\\F=PA\\\\F=14.6959 \ \text{Pounds}/in^2\times 100\ in^2\\\\F=1469.59\ \text{pounds}[/tex]

So, the force is 1469.59  pounds.

A. The force required to push your head at sea level is 6332.8125 N

B. The force in pound is 1469.59 lb

A. Determination of the force required at sea level.

Pressure (P) = 101325 Nm²

Area (A) = 25 cm × 25 cm = 0.25 m × 0.25 m = 0.0625 m²

Force (F) =?

P = F / A

Cross multiply

F = PA

F = 101325 × 0.0625

F = 6332.8125 N

Therefore, the force required to push your head at sea level is 6332.8125 N

B. Determination of the force in pounds

Area (A) = 100 in²

Pressure (P) = 14.6959 pound / in²

Force (F) =?

F = PA

F = 14.6959 × 100

F = 1469.59 lb

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In substitution reactions, (CH3)3C-I reacts at the same rate with Br- and Cl- even though Br- is a more reactive nucleophile than Cl-. Why?A. (CH3)3C-Br reacts by SN1 mechanism whose rate is independent of nucleophile reactivity. B. (CH3)3C-Br reacts by SN2 mechanism and therefore all nucleophiles react at the same rate regardless of their reactivity. C. The t-butyl carbocation is so reactive, the measurable rate of it's reaction with different nucleophiles is imperceptible. D. The t-butyl group sterically hinders nucleophiles, making different nucleophiles appear to react at the same rate.

Answers

Answer:

A. (CH3)3C-I reacts by SN1 mechanism whose rate is independent of nucleophile reactivity.

Explanation:

We must recall that (CH3)3C-I is a tertiary alkyl halide. Tertiary alkyl halides preferentially undergo substitution reaction via SN1 mechanism.

In SN1 mechanism, the rate of reaction depends solely on the concentration of the alkyl halide (unimolecular mechanism) and is independent of the concentration of the nucleophile. As a result of this, both Br^- and Cl^- react at the same rate.

What is the ground-state electron configuration for the Mn4 ion and is it paramagnetic or diamagnetic?

Answers

Answer:

[Ar]3d4 is the ground-state electron configuration for the Mn4 ion

but i don't know whether it is paramagnetic or daimagnetic

What is the change in the internal energy of a system that does 100 joules of
work and absorbs 1,000 joules of heat?

Answers

Answer:900j

Explanation:

A car traveled 150 meters in 5 seconds, what was its speed? 1.
Pepper the dog traveled 100 meters in 10 seconds, what was Pepper’s speed? 2.
Tony drove his car 1000 meters in 2 minutes, what was the speed of the car? 3.
A bird is flying over New York at a speed of 10 miles per minute. It traveled at this speed for 20 minutes. How far did it fly? 4.



Answer Them all and get 25 points!!!!

Answers

Answer:

1.  car traveled 30 meters per second

2. pepper traveled 10 meters per second

3. tony drove around 500 meters per minute

4. the bird traveled 200 miles

Hope this helped!

1 .30
2.10
3.500
4.200

Would you want to build the wire for a cell phone charger out of nitrogen (N)? Why or why not? Be sure to explain how the properties and structure of nitrogen influence your decision.

Answers

Answer:

No

Explanation:

Nitrogen cannot be used to build the wire for a cell phone charger.

What are the elements used to build charger ?

Inside phone chargers is aluminum. Aluminum is used in phone chargers because it does a better job of conducting electricity than copper does. Bauxite is used to make aluminum. The crust of the earth contains aluminum.A phone charger is also made of tungsten. The wire's resistance is provided by tungsten. Wolframite make up tungsten. The crust of the Earth contains tungsten.Additionally, phone chargers contain gold. Because it is a conductor, gold is used in phone chargers. However, gold is also resistant to oxidation. Copper ores are used to make gold. Gold can be found everywhere on Earth and in its oceans.Silver is within your mobile charger. Silver conducts electricity. Silver is comprised of various minerals. Silver can be found free in nature at times, but it can also be found in copper, gold, and nickel.Phone chargers contain copper. Copper is also used to carry electric current.Chalcopyrite make up copper. Copper ore deposits can be found all over the world.Copper windings in a transformer are used to convert a 220 V input voltage into a 5 V operating output voltage in mobile phone chargers. The output voltage is greater than the input voltage if the secondary coil has more turns than the primary coil.Nitrogen (N), a nonmetallic element in the periodic table's Group 15 [Va] group. It is the most abundant element in Earth's atmosphere and a component of all living matter. It is a colorless, tasteless, and odorless gas. Nitrogen is used to shield motors, prevent oxidation and other chemical reactions, pressurize cable jackets, and more in the electrical industry.

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Please Help!!
Nitrogen gas can be prepared by passing ammonia over copper(II) oxide, and the other products are copper metal and water vapor. If a sample containing 3.58 moles of NH₃ is reacted with excess copper(II) oxide, how many grams of N₂ will be formed?

Answers

Mass of N₂ will be formed : 50.12 g

Further explanation

Reaction

2 NH₃(g) + 3 CuO(s) → N₂(g) + 3 Cu(s) + 3 H₂O(g)

moles NH₃ = 3.58

ratio mol NH₃ : mol N₂ = 2 : 1

so mol N₂ :

[tex]\tt \dfrac{1}{2}\times 3.58=1.79[/tex]

mass N₂ (MW=28 g/mol) :

[tex]\tt 1.79\times 28=50.12~g[/tex]

An organic thiol compound is 38.66% C, 9.73% H, and 51.61% S by mass. What is the empirical formula of this compound?

Answers

Answer:

Empirical formula is C₂H₆S

Explanation:

Given data:

Percentage of hydrogen = 9.73%

Percentage of carbon = 38.66%

Percentage of sulfur = 51.61%

Empirical formula = ?

Solution:

Number of gram atoms of H = 9.73 / 1.01 = 9.6

Number of gram atoms of S = 51.61 / 32 = 1.6

Number of gram atoms of C = 38.66 / 12 = 3.2

Atomic ratio:

             C                      :      H              :         S

           3.2/1.6               :     9.6/1.6       :       1.6/1.6

            2                      :        6             :        1

C : H : S = 2 : 6 : 1

Empirical formula is C₂H₆S.

if you are correct i will be sure to give your brainliest

Answers

Answer:

slow down speed updon't change1 will be the right answer

Answer:

Speeds up

Explanation:

A chemist prepares a solution of copper(II) sulfate by measuring out 17.2 of copper(II) sulfate into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's copper(II) sulfate solution.

Answers

Answer:

Concentration of the chemist's copper(II) sulfate solution is 0.43 mol/L

Note: The volume of the flask is assumed  to be 250 mL

Explanation:

Since the volume of the volumetric flask is not given, we assume the volume its volume to be 250 mL.

Mass of copper (ii) sulfate = 17.2 g; molar mass of copper (ii) sulfate = 160 g/mol

Concentration in mol/L = number of moles/volume in litres

Number of moles of copper (ii) sulfate = 17.2 g / 160 g/mol = 0.1075 moles

Volume of flask in litres = 250 mL/1000 mL * 1 L = 0.250 L

Concentration = 0.1075 moles / 0.250 L = 0.43 mol/L

Therefore, concentration of the chemist's copper(II) sulfate solution is 0.43 mol/L

Answer:

0.5000

Explanation:

We can measure the concentration of the copper sulfate solution as 1.000 mol/L. Since the tank contains one half liter, the solution contains 0.5000 moles of copper sulfate.

Which of these results in kinetic energy of an object?

Answers

Answer: B

Kinetic Energy is the energy possessed by the body due to "motion".

Answer:

B- motion

Explanation:

Correct on edge 2021

️️

Explain why water can take many different paths while moving though the water cycle

Answers

Answer:

the water cycle shows the continuous movement of water within the Earth and atmosphere. it is a complex system that includes many different processes. Beckley water evaporates into water vapor, condenses to form clouds, and precipitates back to Earth in the form of rain and snow. Water in different phases moved across the atmosphere. The Cove water flows across the land, into the ground, threw the ground. Groundwater moves into plants and evaporates from plants into the atmosphere. Solid ice and snow can turn directly into gas. It can also take place when water vapor becomes solid

Explanation:

hope this helps :]

Water can take different paths while moving through water   cycle because of it's unique property to exist in different phases.

What is water cycle?

Water cycle is one of the biogeochemical cycles which describes the movement of water above and below the surface of earth. Mass of water remains constant but it's mass in different forms varies as it exists in form of  glaciers, water and water vapor.

Water gets converted from one form to another by processes such as evaporation,transpiration, condensation,precipitation and surface run off.During this , water changes it's phases from liquid to vapor and solid . Ocean plays a major role in water cycle as it is a source of 86% global evaporation of water.

It involves change in energy leading to changes in temperature. When it evaporates,it takes energy from surroundings and while condensing, it releases energy in to the environment. The evaporation phase purifies the water and then replenishes land with freshwater.

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What color change is exhibited by phenolphthalein during a titration of aqueous acetic acid with aqueous sodium hydroxide ? a. colorless to pink b. pink to colorless c. no color change d. yellow to blue e blue to yellow

Answers

phenolphthalein during a titration

The color change exhibited by phenolphthalein during a titration of aqueous acetic acid with aqueous sodium hydroxide is pink to colorless.

An indicator is an organic dye which changes color in acidic, basic and neutral medium.

Phenolphthalein is an example of an indicator. When aqueous acetic acid is titrated against aqueous sodium hydroxide, the indicator may be added to the basic solution.

Phenolphthalein has a pink color in a basic medium. As the acid is added gradually, the solution turns colorless at end point.

Hence, the color change exhibited by phenolphthalein during a titration of aqueous acetic acid with aqueous sodium hydroxide is pink to colorless.

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Draw conclusion: The density of water is 1.0 g/mL, or 1.0 g/cm². Look at the data in your table. How can you use the density of an object to predict whether it will sink or float?

(Data is above)

PLEASE HELP ​

Answers

Answer:

work out if it's either going to sink or float

Explanation:

this can be carried out by calculating the numbers

Write the condensed electron configurations for the follow- ing atoms and indicate how many unpaired electrons each has: (a) Mg, (b) Ge, (c) Br, (d) V, (e) Y, (f) Lu.

Answers

Answer:

i think it is ge

Explanation:

Two or more than two atoms with different physical or chemical properties can not combine together to form an element. Therefore, the condensed electron configurations for the given element can be written as below.

What is element?

Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same.

The systematic distribution of electrons in the various atomic orbitals is called its electronic configuration. 1,2,3 represents the number of shells and s and represents the orbitals. The superscripts represents the number of electrons in each orbitals.

Electronic configuration of Mg   Ne 3s²

Electronic configuration of Ge   [Ar] 3d¹⁰ 4s² 4p²

Electronic configuration of Br    [Ar] 3d10 4s² 4p⁵

Electronic configuration of V     [Ar] 3d³ 4s²

Electronic configuration of  Y   [ Kr ]4d¹ 5s²

Electronic configuration of Lu     [Xe] 4f¹⁴ 5d¹6s²

Therefore, the condensed  electron configurations for the given element can be written as above.

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How many milliliters of a 0.266 M CsNO3 solution are required to make 150.0 mL of 0.075 M CsNO3 solution

Answers

Answer:

The required milliliters of CsNO3 in solution 1 = 42.29 mL

Explanation:

Given that:

The molarity of CsNO3 in solution 1 M₁= 0.266 M

The Volume of CsNO3 in solution 1 V₁  =   ???

The Volume of CsNO3 in solution 2 V₂ = 150.0 mL

The molarity of CsNO3 in solution 2 M₂= 0.075 M

By the application of the titrimetric concept:

M₁V₁ = M₂V₂

We have;

0.266 M ×  V₁  = 0.075 M × 150.0 mL

V₁  = ( 0.075 M × 150.0 mL ) / 0.266 M

V₁  = (11.25 / 0.266 ) mL

V₁  = 42.29 mL

Does a reaction occur when aqueous solutions of ammonium carbonate and chromium(III) nitrate are combined? yesno If a reaction does occur, write the net ionic equation. Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed leave it blank.

Answers

Answer:

3 CO₃²⁻(aq) + 2 Cr³⁺(aq) ⇒ Cr₂(CO₃)₃(s)

Explanation:

Let's consider the molecular equation that occurs when aqueous solutions of ammonium carbonate and chromium(III) nitrate are combined.

3 (NH₄)₂CO₃(aq) + 2 Cr(NO₃)₃(aq) ⇒ 6 NH₄NO₃(aq) + Cr₂(CO₃)₃(s)

The complete ionic equation includes all the ions and insoluble species.

6 NH₄⁺(aq) + 3 CO₃²⁻(aq) + 2 Cr³⁺(aq) + 6 NO₃⁻(aq) ⇒ 6 NH₄⁺(aq) + 6 NO₃⁻(aq) + Cr₂(CO₃)₃(s)

The net ionic equation includes only the ions that participate in the reaction and the insoluble species.

3 CO₃²⁻(aq) + 2 Cr³⁺(aq) ⇒ Cr₂(CO₃)₃(s)

Write the expression for the equilibrium constant Kp for the following reaction. (Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example, enter (PNH3)2 as (P NH3)2. If either the numerator or denominator is 1, please enter 1.) PCl5(g) ↔ PCl3(g) Cl2(g)

Answers

Answer and Explanation:

For the following balanced reaction:

PCl₅(g) ↔ PCl₃(g) + Cl₂(g)

We can see that all reactants and products are gases, so it is an homogeneous equilibrium. The expression for the equilibrium constant Kp can be written from the partial pressures (P) of reactants and products as follows:

[tex]Kp=\frac{(P PCl_{3})(P Cl_{2})}{(P PCl_{5})}[/tex]

Where PPCl₃ is the partial pressure of PCl₃ (reactant), PCl₂ is the partial pressure of Cl₂ (reactant) and PPCl₅ is the partial pressure of PCl₅ (product).

Answer the questions about the characteristics of the elements in group 2 (the alkaline earth metals).1. What happens when the elements in group 2 react with iodine? a. a salt is formed (MI_2) b. a salt is formed (MI) c. no reaction 2. How do they react with water? a. hydrogen gas is released b. oxygen is released 3. How do they react with oxygen? a. an oxide is formed (M_2 O) b. an oxide is formed (MO) c. no reaction 4. Which reacts the most vigorously? a. Ba b. Mg c. Ca d. Sr e. Ba 5. Which element in the group is the most metallic in character? a. Be b. Mg c. Ca d. Sr e. Ba

Answers

Answer:

Explanation:

1

When elements in group 2 react with Iodine, a salt MI_2 is formed

2

When they react with water, Hydrogen gas is released

3

When they react with Oxygen, an Oxide, MO is formed

4

The most vigorously reactive metal in group 2 is Barium, Ba. Reactivity increases as one moves downward in group 2

5

The most metallic element is Barium, Ba. This is because in the periodic table, metallic strength of metals increases as one moves down the table.

The thing that happens when the elements in group 2 react with iodine is:

A salt MI_2 is formed

The way these elements react with water is:

They form hydrogen gas  

The way they react with oxygen is:

They produce an Oxide, MO

The element which reacts the most vigorously  in group 2 is:

Barium, Ba. This is because their reactivity increases as one moves downward in group 2

The element in the group which is the most metallic in character is:

Barium, Ba. It is this way because of the changes in metallic strength as metals change positions in the table

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If 15.5 mL of 0.225 M aqueous magnesium chloride is added to 37.5 mL of 0.250 M aqueous lead(II) nitrate, then what mass of lead(II) chloride precipitates?A. 0.485 g.B. 0.971 g.C. 1.94 g.D. 3.888 g.E. 5.82 8 g.

Answers

Answer:

B. 0.971 g

Explanation:

When MgCl₂(aq) reacts with Pb(NO₃)₂(aq), PbCl₂(s) and Mg(NO₃)₂(aq) are produced:

MgCl₂(aq) + Pb(NO₃)₂(aq) →, PbCl₂(s) + Mg(NO₃)₂(aq)

Thus, we need to find imiting reactant finding moles of each reactant:

Moles MgCl₂:

15.5mL = 0.0155L * (0.225 mol / L) = 3.49x10⁻³ moles

Moles Pb(NO₃)₂:

37.5mL = 0.0375L * (0.250mol / L) = 9.38x10⁻³ moles

As the ratio of the reactants is 1:1, the moles of PbCl₂ are 3.48x10⁻³ moles.

We need to convert thes moles to mass using molar mass of PbCl₂ (278.1g/mol), thus:

3.48x10⁻³ moles * (278.1g/mol) =

0.968g of PbCl₂ are precipitate

Thus, right answer is:

B. 0.971 g

What is the Dependent variable?

Answers

Explanation:

Just like an independent variable, a dependent variable is exactly what it sounds like. It is something that depends on other factors. For example, a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it. Usually when you are looking for a relationship between two things you are trying to find out what makes the dependent variable change the way it does.

For the following reaction at equilibrium SO3(g) + NO(g) = SO2(g) + NO2(g)It is found that [SO2] = 0.70 M and [NO] = 1.20 M. Calculate the equilibrium constant for the readction knowing that the initial concentration were [SO3] = 2.55 M and [NO] = 1.90 M.

Answers

Answer:

[tex]K=0.14[/tex]

Explanation:

Hello!

In this case, for the undergoing chemical reaction, we can write the equilibrium expression via:

[tex]K=\frac{[SO_2][NO_2]}{[SO_3][NO]}[/tex]

Whereas the equilibrium concentration of both SO3 and NO are 2.55 M and 1.90 M respectively, it means that the extent of reaction [tex]x[/tex] is:

[tex]x=1.90M-1.20M=0.7M[/tex]

Because the equilibrium expression in terms of the reaction extent is:

[tex]K=\frac{x*x}{([SO_3]_0-x)([NO]_0-x)}[/tex]

It means that the concentration of SO3, NO, SO2 and NO2 at equilibrium are:

[tex][SO_3]=2.55M-0.70M=1.85M[/tex]

[tex][NO]=1.20M[/tex]

[tex][SO_2]=0.70M[/tex]

[tex][NO_2]=0.70M[/tex]

Thus, the equilibrium constant for such reaction is:

[tex]K=\frac{0.70*0.70}{1.85*1.90}\\\\K=0.14[/tex]

Best regards!

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