Which object has the most gravitational potential energy?
O A. A 5 kg book at a height of 2 m
B. A 8 kg book at a height of 2 m
C. An 8 kg book at a height of 3 m
D. An 5 kg book at a height of 3 m
help pls

Answers

Answer 1

Answer: An 8 kg book at a height of 3 m has the most gravitational potential energy.

Explanation:

Gravitational potential energy is the product of mass of object, height of object and gravitational field.

So, formula to calculate gravitational potential energy is as follows.

U = mgh

where,

m = mass of object

g = gravitational field = [tex]9.81 m/s^{2}[/tex]

h = height of object

(A) m = 5 kg and h = 2m

Therefore, its gravitational potential energy is calculated as follows.

[tex]U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 2 m\\= 98.1 J (1 J = kg m^{2}/s^{2})[/tex]

(B) m = 8 kg and h = 2 m

Therefore, its gravitational potential energy is calculated as follows.

[tex]U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 2 m\\= 156.96 J (1 J = kg m^{2}/s^{2})[/tex]

(C) m = 8 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

[tex]U = mgh\\= 8 kg \times 9.81 m/s^{2} \times 3 m\\= 235.44 J (1 J = kg m^{2}/s^{2})[/tex]

(D) m = 5 kg and h = 3 m

Therefore, its gravitational potential energy is calculated as follows.

[tex]U = mgh\\= 5 kg \times 9.81 m/s^{2} \times 3 m\\= 147.15 J (1 J = kg m^{2}/s^{2})[/tex]

Thus, we can conclude that an 8 kg book at a height of 3 m has the most gravitational potential energy.


Related Questions

If a spider can travel 3.5 meters in 25 minutes, how fast can they go?

Answers

they can go 7.5 meters in 25 minutes

Explain what resonance is and give one example of a destructive outcome of resonance. Also give one example of a non-destructive outcome of resonance. Use details to support your answer.

Answers

Answer:

resonance is when a body is made to vibrate with the frequency of another body without touching it.

Explanation:

example of destructive: soldiers matching on a bridge unanimously can make the bridge collapse.

Answer:hi

i like ears

and lemon

and poetry

Explanation:

Instead of changing the the frequency you can change the tension to produce the next higher harmonic. What percentage of the tension would produce the next higher harmonic?

Answers

Answer:

  [tex]\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2[/tex]

Explanation:

This is a string resonance exercise, the wavelengths in a string held at the ends is

          λ = 2L₀ / n

where n is an integer

the speed of the wave is

           v = λ f

            f = v /λ

the speed of the wave is given by the characteristics of the medium (string)

           v = [tex]\sqrt{\frac{T}{\mu } }[/tex]

we substitute  

            f = [tex]\frac{n}{2L_o} \ \sqrt{\frac{T}{\mu } }[/tex]

to obtain the following harmonic we change n → n + 1

            f’ =  [tex]\frac{n+1}{2L_o} \ \sqrt{\frac{T_o}{\mu } }[/tex]

In this case, it tells us to change the tension to obtain the same frequency.

            f ’= \frac{n}{2L_o} \  \sqrt{\frac{T}{\mu } }

how the two frequencies are equal

         [tex]\frac{n+1}{2L_o} \sqrt{\frac{T_o}{ \mu } } = \frac{n}{2L_o} \sqrt{\frac{T}{\mu } }[/tex]

           (n + 1) [tex]\sqrt{T_o}[/tex] = n [tex]\sqrt{T}[/tex]

             [tex]\frac{T}{T_o} = ( \frac{n+1}{n} )^2[/tex]

             [tex]\frac{T}{T_o} = ( 1 + \frac{1}{n} )^2[/tex]

this is the relationship of the voltages to obtain the following harmonic,

Help pleaseeeeee!!! I really need it today :)

Answers

Answer:

i'd say 1kg-----5m-----5kg but im not to sure

Explanation:

Question 5 of 10
Which of the following best describes a property of water?
O A. Dissolving very few substances
B. Remaining liquid over a narrow range of temperatures
C. Having low surface tension
D. Requiring a lot of energy to change temperature

Answers

Answer:

B

Explanation:

water do not have a solid shape and that makes it take to shape of a container etc

Answer:

D. Requiring a lot of energy to change temperature

Explanation:

because im right n ur wrong

g A ball is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. The ball rises to a height equal to the asteroid's radius and then falls straight down toward the surface of the asteroid. What forces, if any, act on the ball while it is on the way up

Answers

Answer:

Only a decreasing gravitational force that acts downward

Explanation:

The gravitational force is the gravitational pull which attract a mass of smaller size by the mass of a bigger size.  It is the force which attract two masses close to each other.

In the context, when a ball is tossed up from the surface of an asteroid that have no atmosphere, the ball rises up and then falls back to the surface of the asteroid. The ball falls back because the gravitational pull of the asteroid pulls back the ball to its surface. Thus a decreasing gravitational force acts on the ball in the downward direction while the ball is in its way up.  

what is the light synthesis ?​

Answers

Answer:

Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. ... During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.

Explanation:

thank me later

Photosynthesis is a process through which plants and other organisms transform light energy into chemical energy, which is then released to power the organism's metabolic activities through cellular respiration.


Two identical particles each of mass M and charge Q are placed a certain distance apart. If they are in equilibrium
under mutual gravitational and electric force then calculate the order of Q/M in SI units.

Answers

Answer:

 Q / m = 8.61 10⁻¹¹ C / kg

Explanation:

For this exercise we use the gravitational force of attraction

           

     [tex]F_g = G \frac{m_1m_2}{r^2}[/tex]

the electric force

     [tex]F_e = k \frac{q1q2}{r^2}[/tex]

indicate that the two forces are equal

     G m₁ m₂ / r² = k q₁ q₂ / r²

they also say that the two masses are equal and the two charges are equal

     G m² = k Q²

     Q / m =  [tex]\sqrt{\frac{G}{k} }[/tex]

we calculate

      Q / m = [tex]\sqrt{\frac{6.67 \ 10^{-11} }{8.99 \ 10^9} }[/tex]

      Q / m = [tex]\sqrt{ 0.7419 \ 10 ^{-20}}[/tex]

       Q / m = 0.861 10⁻¹⁰

       Q / m = 8.61 10⁻¹¹ C / kg

Describe the Compton Effect​

Answers

Compton scattering, discovered by Arthur Holly Compton, is the scattering of a photon after an interaction with a charged particle, usually an electron. If it results in a decrease in energy of the photon, it is called the Compton effect. Part of the energy of the photon is transferred to the recoiling electron.

Consider a solid sphere and a solid disk with the same radius and the same mass. Explain why the solid disk has a greater moment of inertia than the solid sphere, even though it has the same overall mass and radius.

Answers

Answer:

Explanation:

In a Solid sphere; the moment of inertia around its geometrical axis can be expressed by using the formula:

[tex]\mathtt{I_s = \dfrac{2}{5} M_s R^2_s}[/tex]

For the solid disk; the moment of inertia around the central axis is:

[tex]\mathtt{I_D= \dfrac{1}{2}M_DR_D^2}[/tex]

Suppose [tex]M_D = M_S[/tex]; then we can say both to be equal to M

As well as [tex]R_D = R_S[/tex]; then that too can be equal to R

Now;

[tex]\mathtt{I_s = \dfrac{2}{5} M R^2} --- (1)[/tex]

[tex]\mathtt{I_D= \dfrac{1}{2}MR^2}---(2)[/tex]

Multiplying equation (1) by 2, followed by dividing it by 2; we have:

[tex]\mathtt{I_s= \dfrac{2}{5}MR^2} \times \dfrac{2}{2}[/tex]

[tex]I_s = \dfrac{4}{5} \times \dfrac{1}{2}MR^2 \\ \\ I_s = \dfrac{4}{5}\times I_D \\ \\ I_s > I_D[/tex]

An electric field has a positive test charge of 5.00 C placed in it. The force on the test charge is
6.000 N. The magnitude of the electric field at the location of the test charge is
o 30.0 NVC
0 1.20 N/C
0 120, NVC
O 3.00 N/C
01.02 N/C

Answers

Answer:

yes

Explanation:

this means the answer is yes

A battery has an EMF of 12 Volts, internal resistance of 0.5 Ohms, and its terminal voltage is measured to be 13 Volts. The battery is ________ and has a current of ____ Amps passing through.

Answers

Answer:

The battery is charging and has a current of 2Amps passing through.

Explanation:

Given;

EMF of the battery, E = 12 V

internal resistance, r = 0.5 ohms

terminal voltage of the battery, ΔV = 13 volts

When the terminal voltage is greater than the EMF of the battery, the battery is being charged, allowing currents to pass in a reverse direction.

ΔV = E - Ir

ΔV - E = -Ir

13 - 12 = -0.5I

1 = -0.5I

I = 1 / -0.5

I = -2 A

The negative sign indicates the reverse direction of the current.

Therefore, the battery is charging and has a current of 2Amps passing through.

PLEASE HELPPPPPPP!!!!!!!!!!

Answers

Answer:

F' = 800 N

Explanation:

The electrical force between charges is 400 N.

The electrical force between two charges is given by :

[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]

If q₁' = 2q₁, new force becomes,

[tex]F'=k\dfrac{q_1'q_2'}{r^2}\\\\F'=k\dfrac{2q_1\times q_2}{r^2}\\\\F'=2\times F\\\\F'=2\times 400\\\\F'=800\ N[/tex]

So, the new force becomes 800 N.

When using Fleming's Left Hand Rule to determine the direction of the force on an electron moving in a magnetic field, the velocity vector (V) is represented by the direction of your ___________.

thumb

index finger

middle finger

None of the above

Answers

thumb


If the forefinger represents the direction of the field and the second finger represents that of the current, then thumb gives the direction of the force.

pls solve this:

if u solve this, I will surely mark u as brilliant

Answers

Answer: The frequency of a pendulum is [tex]0.2 s^{-1}[/tex].

Explanation:

Time period is defined as the time required to produce complete wave.

As we know that the frequency and time are inversely proportional to each other.

That means,

[tex]\nu =\frac{1}{T}[/tex]

Where,

[tex]\nu[/tex] is frequency of pendulum

T is time period

Given:

Time period = 5 seconds

Now putting all the given values in the above formula, we get the frequency of the pendulum.

[tex]\nu =\frac{1}{T}\\\\\nu =\frac{1}{5s}\\\\\nu =0.2s^{-1}[/tex]

Therefore, the frequency of a pendulum is [tex]0.2 s^{-1}[/tex].

Will mark Brainliest!
All elements on the periodic table are neutral because they have the same number of electrons as what other particle?
A. Protons
B. Photons
C. Atomic mass
D. Neutrons​

Answers

I think it’s A protons .. hope this helps
A) protons.

hope this helps :)

Objects 1 and 2 attract each other with a electrostatic force
of 72.0 units. If the distance separating Objects 1 and 2 is
tripled, then the new electrostatic force will be _units.

Answers

Answer:

8 units

Explanation:

From the question given above, the following data were obtained:

Initial force (F₁) = 72 units

Initial distance apart (r₁) = r

Final distance apart (r₂) = tripled = 3r

Final force (F₂) =.?

The final force between the two objects can be obtained by using the following formula:

F₁r₁² = F₂r₂²

72 × r² = F₂ × (3r)²

72r² = F₂ × 9r²

Divide both side by 9r²

F₂ = 72r² / 9r²

F₂ = 8 units

Therefore, the final force between the two objects is 8 units

compare the time period of two pendulums of length 4m and 9m​

Answers

area= length × length

area = 4m × 9m

ans 36

The answer is 45-54

What is the essential concept of the photon theory of light?​

Answers

Answer:

Cause it gives us internet

a force in the opposite direction
of the motion

Answers

forces: forces applied to an object in opposite directions that are not equal in size. Unbalanced forces result in a change in motion. friction: the force that opposes the motion or tendency toward motion of two objects that are in contact.

The number of proton is equal to the number of _____ in an atom​

Answers

Answer:

THE NUMBER OF PROTON IS EQUAL TO THE NUMBER OF ATOMIC NUMBER(Z) IN AN ATOM

Explanation:

PLZ MARK ME BRAINLIEST

Answer:

Explanation:

The number of proton is equal to the number of electron in an atom.

Explain how you would have to change the experimental set-up (electric field strength, drift chamber length, and/or buf

Answers

Answer:

Please find the complete question in the attached file.

Explanation:

In this statement, the weak electromagnetic field that has been used when with the range of resistance to start measuring the mobility of even an ion with both the counter-charge utilization as well as the DC is the potential for using so that we can always obtain a desired electrical field and modify the drift chamber lengthy and gas pressures buffered.

II. Magnetic fields Magnets and magnetic fields EM 115 We have observed that magnets interact even when they are not in direct contact. In electrostatics we used the idea of an electric field to account for the interaction between charges that were separated from one another. For magnetic interactions, we similarly define a magnetic field. A. Obtain a compass from a tutorial instructor. I. Use the compass to explore the region around a bar magnet. Describe the behavior of the compass needle both near the poles of the magnet and in the region between the poles.

Answers

Solution :

We all know that a bar magnet have two poles, the north pole and the south pole. These poles interacts with each other. The ends of the magnets having similar poles will push each other away while the poles with like charges will pull each others towards it.

The compass needle is also a magnet having south polarity as well as north polarity. When the compass needle is close to the bar magnet, it is opposite to the poles or along the poles. The compass needle shows the direction or is pointed towards the north. So when the compass needle is placed near the north pole of the bar magnet, the pointer of the compass needle points towards the north, i.e. it gets deflected because of he like charges. And when it is placed near the south pole of the magnet, it gets attracted towards it and is pointed towards the pole.

Now as we move the compass needle from the poles to the region that is between the poles, the compass needle pointer points towards the north direction every time. It show a deflection always. If we place the magnetic lines, we will see that the magnetic lines will exit from the north poles and enters the south pole of the bar magnet.  

A mass m, which is connected to a spring of spring constant k, is released from x = A to perform
a simple harmonic motion. Another mass 2m, which is connected to another spring of the same
spring constant k, is also released from x = A to perform a simple harmonic motion. Compare the
values of total mechanical energy stored in these two spring-mass systems.

Answers

No entiendo inglés ....

That light has a dual nature is referring to light: having energy and momentum. having high- or low-energy photons. acting as waves and particles. undergoing pair production.

Answers

Answer:

Option C, acting as waves and particles

Explanation:

Light has dual nature  because it acts both as a wave and particle. It has high energy particle i.e photons and it also behave as an electromagnetic wave. This property of light is studied under the quantum mechanics. Einstein also proved that light is a stream of photons possessing both electrical and magnetic properties.

Hence, option C is correct

According to Newton's second law, how are mass and acceleration related?
A. They are directly proportional to each other
B. They are inversely proportional to each other

Answers

Answer:

B. They are inversely proportional to each other

[tex] \frac{momentum}{time} = force \\ \\ \frac{mass \times velocity}{time} = force \\ \\ \frac{mass \times velocity}{time} = mass \times acceleration[/tex]

Question
1 point
An object of mass 8.0 kg is falling vertically through the air. The drag force acting on the object is 60N. What is the best estimate of the acceleration of
the object?


Answers

Answer:

here's the pdf for it

IB QuestionbankExplanation:

The decibel level of the sound of a subway train was measured at 92 dB. Find the intensity in watts per square meter (W/m2). (Give your answer in scientific notation, correct to one decimal place.)

Answers

Answer:

I = 1.58 x 10⁻³ watt/m²

Explanation:

Here, we will use the following formula:

[tex]\beta = 10\ log_{10}(\frac{I}{I_o})[/tex]

where,

β = decibel level = 92 dB

I = Intenisty of sound in watt/m² = ?

I₀ = reference intensity = 10⁻¹² watt/m²

Therefore,

[tex]92\ dB =10\ log_{10}(\frac{I}{10^{-12}\ watt/m^2} )\\\\[/tex]

[tex]10^{9.2} = \frac{I}{10^{-12}}\ watt/m^2\\\\I = (1.58\ x\ 10^9)(10^{-12}\ watt/m^2)[/tex]

I = 1.58 x 10⁻³ watt/m²

A Carnot engine with an efficiency of 30% operates with a high-temperature reservoir at 188oC and exhausts 2000 J of heat each cycle. What are (a) the heat input per cycle and (b) the Celcius temperature of the low-temperature reservoir

Answers

Answer:

a) The heat input per cycle is 2857.143 joules.

b) The temperature of the low-temperature reservoir is 49.655 °C.

Explanation:

a) The efficiency of the Carnot engine is defined by the following formula:

[tex]\eta_{th} = 1-\frac{T_{L}}{T_{H}} = 1 - \frac{Q_{L}}{Q_{H}}[/tex] (1)

Where:

[tex]T_{L}[/tex] - Low temperature reservoir, in Kelvin.

[tex]T_{H}[/tex] - High temperature reservoir, in Kelvin.

[tex]Q_{L}[/tex]  - Heat output, in joules.

[tex]Q_{H}[/tex] - Heat input, in joules.

[tex]\eta_{th }[/tex] - Engine efficiency, no unit.

If we know that [tex]\eta_{th} = 0.3[/tex] and [tex]Q_{L} = 2000\,J[/tex], the heat input of the Carnot engine is:

[tex]\eta_{th} = 1 - \frac{Q_{L}}{Q_{H}}[/tex]

[tex]\frac{Q_{L}}{Q_{H}} = 1 - \eta_{th}[/tex]

[tex]Q_{H} = \frac{Q_{L}}{1-\eta_{th}}[/tex]

[tex]Q_{H} = \frac{2000\,J}{1-0.3}[/tex]

[tex]Q_{H} = 2857.143\,J[/tex]

The heat input per cycle is 2857.143 joules.

b) If we know that [tex]T_{H} = 461.15\,K[/tex] and [tex]\eta_{th} = 0.3[/tex], then the temperature of the low-temperature reservoir:

[tex]\eta_{th} = 1 - \frac{T_{L}}{T_{H}}[/tex]

[tex]\frac{T_{L}}{T_{H}} = 1 - \eta_{th}[/tex]

[tex]T_{L} = T_{H}\cdot (1-\eta_{th})[/tex]

[tex]T_{L} = (461.15\,K)\cdot (1-0.3)[/tex]

[tex]T_{L} = 322.805\,K[/tex]

[tex]T_{L} = 49.655\,^{\circ}C[/tex]

The temperature of the low-temperature reservoir is 49.655 °C.

Last stage of a medium mass star

Answers

White Dwarf Stage

This ring is called a planetary nebula. when the last of the helium atoms in the core are fused into carbon atoms, the medium size star begins to die. Gravity causes the last of the star's matter to collapse inward and compact. This is the white dwarf stage.

the last stage of a medium mass star is the white dwarf stage
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