Hello may any of you help me with these two equations I’m having a little hard time thank you =10 points
Answer:
a. 10.08
b. 0.0576
GIVING BRAINIEST IF CORRECT!!!
Mr. Cohen just got a pool and decided to fill it up using a hose. After a half hour, the pool is filled 1/15 of the way. How much will the pool be filled after 6 hours?
A. 4/5 full
B. 1/30 full
C. 2/5 full
Answer:
C. 2/5 full
Step-by-step explanation:
[tex]\frac{1}{\frac{1}{15} } :\frac{6}{y}[/tex]
y · 1 = 1/15 · 6
y = 0.4
[tex]y=\frac{2}{5}[/tex]
A triangle PQR is right angled at R, with PQ=80cm and R=60cm. find QR?
pythagorus theorem
Answer:
Solution given:
A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm
and
base[b]PR=60cm.
perpendicular [P]= QR
by using Pythagoras law
h²=p²+b²
80²=QR²+60²
QR²=80²-60²
QR=[tex]\sqrt{2800}[/tex]
QR=20[tex]\sqrt{7}[/tex]=52.9=53cm
QR=53cm.
help help i need help with my math
Answer:
13
Step-by-step explanation:
Answer:
13
Step-by-step explanation:
48-[(2^2+3)x5]
48-[(4+3)x5]
48-[(7)x5]
48-[35]
13
Maggie has 7 bills, all tens and twenties, that
total $100 in value. Find the number of tens, x, and
the number of twenties, y, that Maggie has.
Answer:
4 tens, 3 twenties
Step-by-step explanation:
4 tens ($40) and 3 ($60) twenties work. I’m sorry I don’t have a formula for it though.
Find the equation of the axis of symmetry of the following parabola algebraically.
y=x^2-12x+34
Find the range of the given data below:
7, 10, 12, 11, 12, 10, 11, 13, 17, 13
Ans: 10
Answer: 10
Step-by-step explanation:
Arranged data
7,10,10,11,11,12,12,13,13,17
Range= Highest value - Lowest Vlue
Highest value=17
Lowest value =7
Range=17-7
Range=10
Answer:
[tex]Answer: 10
Step-by-step explanation:
Arranged data
7,10,10,11,11,12,12,13,13,17
Range= Highest value - Lowest Vlue
Highest value=17
Lowest value =7
Range=17-7
Range=10 [/tex]
hope it is helpful to you
If point D is placed on `bar(AC)`, how will the measure of `/_DAB` relate to the measure of `/_CAB` ?
Answer:
m`/_DAB` will be equal to m`/_CAB`.
Step-by-step explanation:
Correct on edmentum.
An isosceles triangle has base angles that each measure 42°. Which equation can be used to find z, the measure of the third angle of this isosceles triangle in degrees? \
Answer:
42 + 42 + z = 180
Step-by-step explanation:
Note that:
Base angles in an isosceles triangle are equal in measure.
The sum of angles in a triangle is 180°.
Thus, the equation would be
42 + 42 + z = 180
Someone please help me out!!
Answer:
4/ 5
cos A = AB/ AC
= 24/ 30
= 4/ 5
that is option A
Someone help me answer this pls
Answer:
y>-2x-3
Step-by-step explanation:
I think, not sure.
easy algebra question below first correct answer gets brainliest
Answer:
using pythagoras theorem
h^2=p^2+b^2
h^2=12^2+9^2
h^2=144+81
h^2=225
h=[tex]\sqrt{225}[/tex]
h=15
Step-by-step explanation:
please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Answer:
[tex]1017.9ft ^{3} [/tex]
Step-by-step explanation:
[tex]volume \: of \: cylinder \\ v = \pi \times r {}^{2} \times h \\ = \pi \times 9^2 \times 4 \\ = 1017.9[/tex]
hi! i’ll give brainliest please help
Answer:
third option mechanical weathering
Step-by-step explanation:
in mechanical weathering it breaks the rock into smaller pieces . these smaller pieces are just like the bigger rock , just smaller .
A motorboat travels 9 miles downstream (with the current) in 30 minutes. The return trip upstream (against the current) takes 90 minutes.
Given :
A motorboat travels 9 miles downstream (with the current) in 30 minutes.
The return trip upstream (against the current) takes 90 minutes.
To Find :
The speed of stream and motorboat.
Solution :
Let, speed of stream is u and speed of motorboat is v.
Now, we know distance is same in both case.
Distance( downstream ) = speed × time
[tex]9 = ( v +u ) \times 0.5\\\\v + u = 18[/tex]....1)
Distance( upstream ) = speed × time
[tex]9 = ( v- u ) \times 1.5\\\\v-u = 6[/tex]....2)
Solving equation 1 and 2 , we get :
v = 12 miles/hour and u = 6 miles/hour
Hence, this is the required solution.
Answer:
The speed of the stream is 6 mph, and the speed of the boat is 12 mph.
Step-by-step explanation:
Downstream:
9 miles in 30 minutes (0.5 hour).
9 mi / 0.5 h = 18 mph
Upstream:
9 miles in 90 minutes (1.5 h).
9 mi / 1.5 h = 6 mph
Let s = speed of stream.
The speed of the stream adds to the speed of the boat downstream and is subtracted fromt he speed of the boat upstream.
Let speed of boat be b.
b + s = 18
b - s = 6
Add the equations.
2b = 24
b = 12
b + s = 18
12 + s = 18
s = 6
The speed of the stream is 6 mph, and the speed of the boat is 12 mph.
What is the first quartile and third quartile of this data set: 34, 34, 36, 39, 50, 41, 45, 47, 40?
Answer:
http://web.mnstate.edu/peil/MDEV102/U4/S36/S363.htmlStep-by-step explanation:
Answer:
First quartile: 35
Third Quartile: 46
Step-by-step explanation:
solve: (x-3)(x+2)=0
answers:
3 and 2
3 and -2
-3 and -2
none of the choices are correct
Answer:
x=3 x=-2
Step-by-step explanation:
(x-3)(x+2)=0
Using the zero product property
x-3 =0 x+2 =0
x=3 x=-2
Answer:
3 and -2
Step-by-step explanation:
x -3 =0
x= 3
x+2 =0
x= -2
two rational numbers between 2/3 and 5/3
Answer:
1.333333333333 or 4/3
the volume of a large aquarium is 210 ft. it is 5 ft wide and 6 ft high. what is the length of the aquarium?
Answer:
7
Step-by-step explanation:
210=5×6×x
x is length of aquarium.
210÷(5×6)=7
$/sqrt{9}$
Triangle JKL is similar to triangle MNO. Find the measure of side MN. Figures are
not drawn to scale.
L
O
2
J
K
1.4
M
N
0
Answer:
4.2
Step-by-step explanation:
If they're similar, the fraction between their sides need to be equal, so do this:
2/1.4 = 6/MN
6•1.4/2 = MN
MN = 4.2
The first number in a pattern is 8. Each following number is found by subtracting 9 from the previous
number
What is the fifth number in the pattern?
Answer:
8,-1,-9,-18,-27,-36
and so on i would think it would be -27
Step-by-step explanation:
Answer:
-28
Step-by-step explanation:
other answer off by one
Find the area of the shaded segment VB and length of VB
Answer:
Area of length Vb = 25 square units
Area of segment Vb = 26 square units
Step-by-step explanation:
Area of length Vb = theta/360 * 2πr
Area of length Vb = 120/360 * 2*3.14 * 12
Area of length Vb = 1/3 * 75.36
Area of length Vb = 25 square units
Ares of length Vb is 25.1 sq. units
Area of shaded portion = Area of sector VUB - Area of triangle VUB
Area of sector VUB = theta/360 * πr²
Area of sector VUB = 120/360 * 3.14*144
Area of sector VUB = 1/3 * 452.16
Area of sector VUB =150.72
Area of triangle VUB = r²sintheta
Area of sector VUB = = 12²sin 120
Area of sector VUB = = 144(0.8660)
Area of sector VUB = 124.71
Area of the shaded segment = 150.72 - 124.71
Area of the shaded segment = 26.01
Area of the shaded segment = 26 sq. unitsAnswer:
Area of length Vb = 25 square units
Area of segment Vb = 26 square units
Step-by-step explanation:
Area of length Vb = theta/360 * 2πr
Area of length Vb = 120/360 * 2*3.14 * 12
Area of length Vb = 1/3 * 75.36
Area of length Vb = 25 square units
Ares of length Vb is 25.1 sq. units
Area of shaded portion = Area of sector VUB - Area of triangle VUB
Area of sector VUB = theta/360 * πr²
Area of sector VUB = 120/360 * 3.14*144
Area of sector VUB = 1/3 * 452.16
Area of sector VUB =150.72
Area of triangle VUB = r²sintheta
Area of sector VUB = = 12²sin 120
Area of sector VUB = = 144(0.8660)
Area of sector VUB = 124.71
Area of the shaded segment = 150.72 - 124.71
Area of the shaded segment = 26.01
Area of the shaded segment = 26 sq. units
I NEED HELP FAST WILL GIVE BRAINLIEST #1 AND IF YOU CAN #2
Answer:
Ok
Step-by-step explanation:
So,
simplify
[tex] \sqrt{12} [/tex]
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]\huge\boxed{2\sqrt{3}}[/tex]
»»————- ★ ————-««
Here’s why:
[tex]\boxed{\text{Simplifying the square root of 12}}\\\\\rightarrow\sqrt{12}\\\\\text{4 can be factored out of 12.}\\\\\rightarrow\sqrt{4(3)}\\\\\text{Two '2's can be factored out of 4.}\\\\\rightarrow\sqrt{2*2*3}\\\\\rightarrow\sqrt{2^2(3)}\\\\\text{Pulling out the terms from under the radical...}\\\\\rightarrow\boxed{2\sqrt{3}}[/tex]
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
A ball is launched from a platform. The equation for the ball's height h at time t seconds after launch is h(t)= -16t^2+153.6t +393.12, where h is in feet. What is the initial height of the ball before launch?
Answer:
The initial height of the ball before launch is 393.12 feet.
Step-by-step explanation:
The ball's height ([tex]h[/tex]), in feet, as a function of time ([tex]t[/tex]), in seconds, is represented by [tex]h(t) = -16\cdot t^{2}+153.6\cdot t + 393.12[/tex]. The initial height of the ball before launch is the height of the ball evaluated at [tex]t = 0\,s[/tex]:
[tex]h(0) = -16\cdot (0)^{2}+153.6\cdot (0) + 393.12[/tex]
[tex]h(0) = 393.12\,ft[/tex]
The initial height of the ball before launch is 393.12 feet.
Rosa is a secretary. She works Monday to Friday every week. If she worked a total of 44.5
hours this week, and her regular pay is $11.46 per hour, what is Rosa’s regular pay?
Answer:
$509.97 is Rosa's regular pay
is each pair of lines parallel perpendicular or neither
Answer:
perpendicular, parallel, neither, parallel
Solve the expression for a=12 , b=6 and c=3
Answer:
48
Step-by-step explanation:
[tex]a = 12, \ b = 6, \ c = 3\\\\b^2 - c^2 + (a+ b+c) = 6^2 - 3^2 + (12 +6+3) = 36-9+21 = 48[/tex]
Answer:
2-12+(++)
b^{2}-1c^{2}+(a+b+c)
b2−1c2+(a+b+c)
Simplify: 1
Eliminate redundant parentheses
2−12+(++)
b^{2}-1c^{2}+(a+b+c)
b2−1c2+(a+b+c)
2−12+++
b^{2}-1c^{2}+a+b+c
b2−1c2+a+b+c
Solution: 2−12+++
b^{2}-1c^{2}+a+b+c
b2−1c2+a+b+c
1/2x9
step by step please
[tex]4.5[/tex] ✅
Step-by-step explanation:
[tex] \frac{1}{2} \times 9 \\ = \frac{1 \times 9}{2} \\ = \frac{9}{2} \\ = 4.5[/tex]
[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]
A population of 350 animals has a growth rate of 5% each year. Write an exponential function to model this situation.
Given:
The population of animals = 350
Growth rate = 5% each year.
To find:
The exponential function to model this situation.
Solution:
The general exponential growth model is:
[tex]f(t)=a(1+r)^t[/tex]
Where, a is the initial value, r is the growth rate in decimal and t is the time period.
Substituting [tex]a=350, r=0.05[/tex] in the above formula, we get
[tex]f(t)=350(1+0.05)^t[/tex]
[tex]f(t)=350(1.05)^t[/tex]
Therefore, the required exponential function is [tex]f(t)=350(1.05)^t[/tex], where f(t) is the number of animals after t years.