The optical storage media has greatest storage capacity is Single-layer, single-sided Blu-ray disc.
What is the Blu-ray disc.
A Blu-ray disc can store the most information compared to other types of optical discs. A one-sided Blu-ray disc can store around 25 GB of information.
Dual-layer or double-sided discs are discs that have two layers or two sides, which allows them to store more information. New Blu-ray discs with 20 layers can store up to 500 GB of data. Small DVDs can save about 4. 7 GB of data. A DVD that has two layers or can be played on both sides can store up to 8. 5 GB of data. If it is both dual-layer and double-sided, it can hold up to 17 GB of data.
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What is the effect when one part of a system changes? A. The entire system changes or could stop working. B. The closed-loop system becomes an open-loop system. C. The open-loop system becomes a closed-loop system. D. The larger system is not affected.
Answer:
c is the answer hope you get it right
The effect when one part of a system changes C. The open-loop system becomes a closed-loop system.
Systemic change is generally understood to require adjustments or transformations in the policies, practices, power dynamics, social norms or mindsets that underlie the societal issue at stake. It often involves the collaboration of a diverse set of players and can take place on a local, national or global level.
How does a systemic change happen?All systems organize individual pieces into some sort of interrelated whole. Put simply, systemic change occurs when change reaches all or most parts of a system, thus affecting the general behavior of the entire system.
Why is systems change important?A systems-change approach is more appropriate for problems that are complex, unpredictable, and context-dependent. For example, the challenge of inadequate access to educational opportunities for children from low-income neighborhoods cannot be addressed with a straightforward, logistical fix.
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This is a glitch ?
Answer:
I think no...Brainly might not allow unique text's.
Answer:
dunno???
Explanation:
Write a program that demonstrates how various exceptions are caught with catch(Exception exception). This time define classes ExceptionA (which inherits from class Exception) and ExceptionB (which inherits from class ExceptionA). In your program, create try blocks that throw exceptions of types ExceptionA, ExceptionB, NullPointerException and IOException. All exceptions should be caught with catch blocks specifying type Exception.
Answer:
Sorry mate I tried but I got it wrong!
Explanation:
Sorry again
Define a class Complex to represent complex numbers. All complex numbers are of the form x + yi, where x and y are real numbers, real numbers being all those numbers which are positive, negative, or zero.
Answer:
The program in C++ is as follows:
#include<bits/stdc++.h>
using namespace std;
class Complex {
public:
int rl, im;
Complex(){ }
Complex(int Real, int Imaginary){
rl = Real; im = Imaginary;
}
};
int main(){
int real, imag;
cout<<"Real: "; cin>>real;
cout<<"Imaginary: "; cin>>imag;
Complex ComplexNum(real, imag);
cout<<"Result : "<< ComplexNum.rl<<" + "<<ComplexNum.im<<"i"<<endl;
}
Explanation:
See attachment for explanation
web analytics can tell you many things about your online performance, but what can analytics tools not tell you
Answer:
The answer is below
Explanation:
While web analytics such as Góogle analysts is known to help online marketers to map out a clear strategy and thereby improve their outreach, there are still some specific things the current web analytics can not do for the user. For example:
1. Web Analytics can’t accurately track leads
2. Web Analytics can’t track lead quality
3. Web Analytics can’t track the full customer journey
4. Web Analytics can’t highlight the true impact of payment.
Ling has configured a delegate for her calendar and would like to ensure that the delegate is aware of their permissions. Which option should she configure?
Delegate can see my private Items
Tasks > Editor
Inbox > None
Automatically send a message to delegate summarizing these permissions
Answer:
Tasks>Editor (B)
Explanation:
I just did the test
Answer:
Tasks > Editor
Explanation:
Did the test
Imagine that you are helping to build a store management system for a fast food restaurant. Given the following lists, write a program that asks the user for a product name. Next, find out if the restaurant sells that item and report the status to the user. Allow the user to continue to inquire about product names until they elect to quit the program.
Answer:
The program in python is as follows:
def checkstatus(food,foodlists):
if food in foodlists:
return "Available"
else:
return "Not Available"
foodlists = ["Burger","Spaghetti","Potato","Lasagna","Chicken"]
for i in range(len(foodlists)):
foodlists[i] = foodlists[i]. lower()
food = input("Food (Q to quit): ").lower()
while food != "q":
print("Status: ",checkstatus(food,foodlists))
food = input("Food (Q to quit): ").lower()
Explanation:
The program uses function.
The function is defines here. It accepts as input, a food item and a food list
def checkstatus(food,foodlists):
This check if the food is in the food lists
if food in foodlists:
Returns available, if true
return "Available"
Returns Not available, if otherwise
else:
return "Not Available"
The main begins here.
The food list is not given in the question. So, I assumed the following list
foodlists = ["Burger","Spaghetti","Potato","Lasagna","Chicken"]
This converts all items of the food list to lowercase
for i in range(len(foodlists)):
foodlists[i] = foodlists[i]. lower()
Prompt the user for food. When user inputs Q or q, the program exits
food = input("Food (Q to quit): ").lower()
This is repeated until the user quits
while food != "q":
Check and print the status of the food
print("Status: ",checkstatus(food,foodlists))
Prompt the user for another food
food = input("Food (Q to quit): ").lower()
what is descriptive research
Answer:
Descriptive research is used to describe characteristics of a population or phenomenon being studied. It does not answer questions about how/when/why the characteristics occurred. Rather it addresses the "what" question
What is output? public class MathRecursive { public static void myMathFunction(int a, int r, int counter) { int val; val = a*r; System.out.print(val+" "); if (counter > 4) { System.out.print("End"); } else { myMathFunction(val, r, counter + 1); } } public static void main (String [] args) { int mainNum1 = 1; int mainNum2 = 2; int ctr = 0; myMathFunction(mainNum1, mainNum2, ctr); } }
a) 2 4 8 16 32 End
b) 2 2 2 2 2
c) 2 4 8 16 32 64 End
d) 2 4 8 16 32
Answer:
The output of the program is:
2 4 8 16 32 64 End
Explanation:
See attachment for proper presentation of the program
The program uses recursion to determine its operations and outputs.
The function is defined as: myMathFunction(int a, int r, int counter)
It initially gets the following as its input from the main method
a= 1; r = 2; counter = 0
Its operation goes thus:
val = a*r; 1 * 2 = 2
Print val; Prints 2
if (counter > 4) { System.out.print("End"); } : Not true
else { myMathFunction(val, r, counter + 1); }: True
The value of counter is incremented by 1 and the function gets the following values:
a= 2; r = 2; counter = 1
val = a*r; 2 * 2 = 4
Print val; Prints 4
else { myMathFunction(val, r, counter + 1); }: True
The value of counter is incremented by 1 and the function gets the following values:
a= 4; r = 2; counter = 2
val = a*r; 4 * 2 = 8
Print val; Prints 8
else { myMathFunction(val, r, counter + 1); }: True
The value of counter is incremented by 1 and the function gets the following values:
a= 8; r = 2; counter = 3
val = a*r; 8 * 2 = 16
Print val; Prints 16
else { myMathFunction(val, r, counter + 1); }: True
The value of counter is incremented by 1 and the function gets the following values:
a= 16; r = 2; counter = 4
val = a*r; 16 * 2 = 32
Print val; Prints 32
else { myMathFunction(val, r, counter + 1); }: True
The value of counter is incremented by 1 and the function gets the following values:
a= 32; r = 2; counter = 5
val = a*r; 32 * 2 = 64
Print val; Prints 64
if (counter > 4) { System.out.print("End"); } : True
This prints "End"
So; the output of the program is:
2 4 8 16 32 64 End
4 reasons why users attach speakers
to their computers
Answer: we connected speakers with computers for listening voices or sound because the computer has not their own speaker. the purpose of speakers is to produce audio output that can be heard by the listener. Speakers are transducers that convert electromagnetic waves into sound waves. The speakers receive audio input from a device such as a computer or an audio receiver.
Explanation: Hope this helps!
Discusstheimportanceofbackingupdatainorganizations,pointingoutthebenefits
ofcloudbackupoption
Addition helps kids master the relationships between numbers and understand how quantities relate to one another. Even when kindergartners can't reliably answer addition problems or manipulate large numbers, basic addition skills give them a framework for mastering math in elementary schoo
How can the adoption of a data platform simplify data governance for an organization?
Answer:
by implementing models that predict compliance with data protection and data privacy policies.
Explanation:
A data platform is an IT system that helps an organization to organize, control and coordinate a large volume of data with the aim of making organizational systems faster and optimizing the decision-making process with effective strategic solutions for organizational success .
A database can simplify data governance for an organization by the fact that data is available to users determined by the organization itself, which increases the security and control of business-critical data.
help asapp!!!!!! give the technical name means (write the name in one word) . the feature of virus which copies itself..
Answer:
if a computer is made out of many copies it can cause a virus with a definition of a tro Jan by a virus
Explanation:
what follows is a brief history of the computer virus and what the future holds for this once when a computer is made multiple copies of it's so several reducing malicious intent here but animal and prevade fit the definition of a Trojan buy viruses worms and Trojans paint the name Malwar as an umbrella term
Write a Python code that takes two sequences CATCGTCCT and CACCGACCG and prints the point mutations found when aligning the two sequences. Tip: you simply need to write a for loop to go over the length of the sequences, pick a letter from each position,and, compare the two sequences position by position for matches and report the mismatches.
Answer:
Following are the code to the given question:
def match_sequence(s1,s2):#Defining a method match_sequence that accepts two parameters
for l in range(len(s1)):#defining a loop that checks range of s1 value
if(s1[l] != s2[l]): # use if block to match each sequences
print('The sequence does not match at index: ',l+1)#print value with message
s1 = 'CATCGTCCT'#defining a string varible s1
s2 = 'CACCGACCG'#defining a string varible s1
match_sequence(s1,s2)#calling a method that prints its values
Output:
The sequence does not match at index: 3
The sequence does not match at index: 6
The sequence does not match at index: 9
Explanation:
In this code, a method "match_sequence" is declared that takes two string variable "s1 and s2" in its parameters, and inside the method, a loop is declared that checks the range of s1 value and use if block to match each sequence and use a print method that prints it values.
Outside the method, two string variables are declared that holds a string value that passes into the "match_sequence" method and calls it.
In the recursive function findMatch(), the first call is findMatch(array, 0, 4, key) . What are the remaining function calls to find the character 'e'?
public class FindMatch {
public static int findMatch(char array[], int low, int high, char key) {
if (high >= low) {
int mid = low + (high - low) / 2;
if (array[mid] == key) {
return mid;
}
if (array[mid] > key) {
return findMatch(array, low, mid, key);
}
else {
return findMatch(array, mid + 1, high, key);
}
}
return -1;
}
public static void main(String args[]){
char array[] = {'a','b','c','d','e'};
char key = 'e';
int result = findMatch(array, 0, 4, key);
if (result == -1) {
System.out.println("Element not found!");
}
else {
System.out.println("Element found at index: " + result);
}
}
}
a. (array, 2, 4, key) and (array, 3, 4, key)
b. (array, 2, 4, key), (array, 3, 4, key) and (array, 4, 4, key)
c. (array, 3, 4, key)
d. (array, 3, 4, key) and (array, 4, 4, key)
Answer:
The answer is "Option D".
Explanation:
In the given question "(array, 3, 4, key) and (array, 4, 4, key)", the element 'e' to also be searched is concentrated mostly on the right-hand side of the array since it is in the last place. This same middle value is 2 but findMatch(array, mid + 1 high, key) is labeled twice to move the center pointer to its last position, that is, so move that search item's 'e.'
An A record contains what
Answer:
IP address
Explanation:
An A record is actually an address record, which means it maps a fully qualified domain name (FQDN) to an IP address.
Answer:
IP adress. the person above me is correct
8. It is used to get qualitative data.
Answer:
please give me brainlist and follow
Explanation:
Qualitative data describes qualities or characteristics. It is collected using questionnaires, interviews, or observation, and frequently appears in narrative form. For example, it could be notes taken during a focus group on the quality of the food at Cafe Mac, or responses from an open-ended questionnaire.
unanswered questionl
¿ ? ¿ ? Whattttt ? ¿ ? ¿
Answer: What
Explanation:
places where computer are used
Answer:
Banks and financial.
Business.
Communication.
Defense and military.
Education.
Internet.
Medical.
Transportation.
etc..
Answer:
businesses, schools, colleges, medical offices, banks.
discuss five domains of Instructional technology
Answer:
Design, Development, Utilization, Management, and Evaluation.
combination of star topology and star topology can consider as hybrid?
Answer:
no
Explanation:
A hybrid topology is a type of network topology that uses two or more differing network topologies. These topologies can include a mix of bus topology, mesh topology, ring topology, star topology, and tree topology.
Means having a current knowledge and understanding of computer mobile devices the web and related technologies
Answer:
"Digital literacy" would be the appropriate solution.
Explanation:
Capable of navigating and understanding, evaluating as well as communicating on several digital channels, is determined as a Digital literacy.Throughout the same way, as media literacy requires the capability to recognize as well as appropriately construct publicity, digital literacy encompasses even ethical including socially responsible abilities.els
2.4
The SPCA receives an amount of R8 500 per annum from an undisclosed
donor. The amount has been growing at a rate of 7.5% per annum
IE
REQUIRED
Calculate how much the donor must have invested as a lump sum to be able
to continue with these payments indefinitely.
(2)
Answer:
ds2d2d2d2dd
Explanation:
PLS HELP SO I CAN PASS WILL GIVE BRAINLINESS AND 30 POINTS
Charlie Chaplin is know for developing
a
The Dramedy
b
Early Special Effects
c
Slap-Stick
d
The Prat-Fall
Question 2 (1 point)
Chaplin felt it was important for the audience to
a
turn off their cellphones during the movie.
b
believe the stunts were real by doing them himself.
c
escape from their problems by avoiding difficult topics.
d
have an emotional connection with the characters.
Question 3 (3 points)
Match the silent film with its modern influence
Column A
1.
Metropolis:
Metropolis
2.
The Kid:
The Kid
3.
Nosferatu:
Nosferatu
Column B
a.Freddy Kruger
b.The Simpsons
c.Sharknado
d.Star Wars
Question 4 (1 point)
How did Nosferatu change the Vampire cannon (story)?
a
Vampires are friendly
b
Vampires can be killed by sunlight
c
Vampires can become invisible
d
Vampires can be repelled by garlic
Question 5 (1 point)
Metropolis was the first film to
a
have religious undertones.
b
use special effects.
c
have humanoid robots.
d
use Gothic Imagery.
movies being the kid , nosferatu , and metropolis
Answer:
a
have religious undertones.
b
use special effects.
c
have humanoid robots.
d
use Gothic Imagery.
Explanation:
Write a C++ function for the following:
Suppose that Account class has a method called withdraw, which will be inherited by Checking and Savings class. The withdraw method will perform according to account type. So, the late bind is needed. Declare the withdraw method in Account class. The method should take a double input as withdraw amount and output true if the withdraw successfully and false if the withdraw unsuccessfully.
Solution :
class Account
[tex]$ \{ $[/tex]
public:
[tex]$\text{Account}()$[/tex];
double [tex]$\text{getBalance}$[/tex]();
void [tex]$\text{setBalance}$[/tex]();
[tex]$\text{bool withdraw}$[/tex](double bal);
[tex]$\text{private}:$[/tex]
double [tex]$\text{balance}$[/tex];
}:
[tex]$\text{Account}()$[/tex] {}
double [tex]$\text{getBalance}$[/tex]()
[tex]$ \{ $[/tex]
[tex]$\text{return balance}$[/tex];
}
void [tex]$\text{setBalance}$[/tex](double [tex]$\text{balance}$[/tex])
[tex]$ \{ $[/tex]
this.[tex]$\text{balance}$[/tex] = [tex]$\text{balance}$[/tex];
}
[tex]$\text{boolean}$[/tex] withdraw([tex]$\text{double bal}$[/tex])
[tex]$ \{ $[/tex]
if([tex]$\text{balance}$[/tex] >= bal)
[tex]$ \{ $[/tex]
[tex]$\text{balance}$[/tex] = [tex]$\text{balance}$[/tex] - bal;
[tex]$\text{return}$[/tex] true;
}
[tex]$\text{return}$[/tex] false;
}
}
The following Mic1 microcode excerpt shows support for a possible 7 bit opcode, 8 bit integer argument machine instruction (organized like the INSP instruction). This part of the microcode will be reached after the instruction opcode has been parsed and identified by earlier parts of the microcode and while the IR contains the complete instruction from memory (as usual for the IR).
100:a := band(smask, ir);
101:a := a + (-1); if n goto 0;
102:ac := lshift(ac); if n goto 104;
103:goto 101;
104:ac := ac + 1; goto 101;
If this possible instruction had a masm assembly pneumonic of XXXX , and was used in an assembly program as shown below:
.
.
LODD abc:
XXXX 7
HALT
.
.
abc: "lost"
What would the 16 bit content of the AC look like when we hit the HALT instruction?
a. 1 0 1 1 0 1 1 0 0 0 1 1 0 1 1 1
b. 0 1 1 0 1 1 1 1 0 1 1 0 1 1 0 0
c. 0 1 1 0 1 1 0 0 0 1 1 0 1 1 1 1
d. 0 0 1 1 0 1 1 1 1 0 1 1 0 1 1 0
Answer:
The answer is "Option A".
Explanation:
In the first 2 signatures in a string, the "ol" with both the "l" throughout the low byte environment is included, and so the initial bit layout becomes: Number of [tex]0 1 1 0 1 1 1 1 0 1 1 0 1 1 0 0[/tex] Its high 7 bits are moved to the lower 7 having come until the correct circular change of 7 is done:
[tex]0 1 1 0 1 1 1 1 0 1 1 0 1 1 0 0 \ \ \ to \ \ 1 0 1 1 0 1 1 0 0 0 1 1 0 1 1 1[/tex]
Simon has a folder that's just a little too large for his thumb drive. How can he make the folder smaller without deleting the contents? *
Answer:
Try zipping the folder.
Explanation:
This reduces the size of the content but doesn't make you delete anything.
Recall the binary search algorithm.1. Using the algorithm/algorithmic environment, give pseudocode using a for loop.AnswerMy algorithm for binary search using a for loop is given in Algorithm 1.Algorithm 1BinarySearchFor(A)[[XXX TODO:pseudocode here]]2. Using the algorithm/algorithmic environment, give pseudocode using a while loop.Answer[[XXX TODO:your answer here]]3. Using the algorithm/algorithmic environment, give pseudocode using recursion.Answer[[XXX TODO:your answer here]]4. What is the loop invariant of your second algorithm
Answer:
Following are the Pseudo Code to the given question:
Explanation:
Following are the pseudo-code by using the For loop:
Defines the A function (node, element)
The node is larger than 0.
if another value of the node equals its element
Loop Break
That element if node. value becomes lower than that
Node is node equivalent.
right
Using other nodes is node equivalent.
left
Node Return
If the node is vacant
print the Tree is empty
Following are the pseudo-code by using the while loop:
Defines the function A(node,element)
While this node is not zero.
if the value of the node equals the element
Loop Break
The element if node. value is lower than
Node is node equivalent.
right
Using other nodes is equivalent to an a.left node
Node Return
If the node is vacant
print Tree is empty
following are the Pseudo-code for recursion:
Set the function A (node, key)
If no root is the same as the root or no root.
return the root.
If the root value is lower than that of the quest for key return (root. right, key)
Return your lookup (root.left,key)
Write a c++ to read seven days in an array and print it
Explanation:
Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.
You will write code to manipulate strings using pointers but without using the string handling functions in string.h. Do not include string.h in your code. You will not get any points unless you use pointers throughout both parts.
You will read in two strings from a file cp4in_1.txt at a time (there will be 2n strings, and you will read them until EOF) and then do the following. You alternately take characters from the two strings and string them together and create a new string which you will store in a new string variable. You may assume that each string is no more than 20 characters long (not including the null terminator), but can be far less. You must use pointers. You may store each string in an array, but are not allowed to treat the string as a character array in the sense that you may not have statements like c[i] = a[i], but rather *c *a is allowed. You will not get any points unless you use pointers.
Example:
Input file output file
ABCDE APBQCRDSETFG
PQRSTFG arrow abcdefghijklmnopgrstuvwxyz
acegikmoqsuwyz
bdfhjlnprtvx
Solution :
#include [tex]$< \text{stdio.h} >$[/tex]
#include [tex]$< \text{stdlib.h} >$[/tex]
int [tex]$\text{main}()$[/tex]
{
[tex]$\text{FILE}$[/tex] *fp;
[tex]$\text{fp}$[/tex]=fopen("cp4in_1.txt","r");
char ch;
//while(1)
//{
while(!feof(fp))
{
char *[tex]$\text{s1}$[/tex],*[tex]$\text{s2}$[/tex],*[tex]$\text{s3}$[/tex];
[tex]$\text{s1}$[/tex] = (char*) [tex]$\text{malloc}$[/tex]([tex]$20$[/tex] * [tex]$\text{sizeof}$[/tex](char));
[tex]$\text{s2}$[/tex] = (char*) [tex]$\text{malloc}$[/tex]([tex]$20$[/tex] * [tex]$\text{sizeof}$[/tex](char));
[tex]$\text{s3}$[/tex] = (char*) [tex]$\text{malloc}$[/tex]([tex]$40$[/tex] * [tex]$\text{sizeof}$[/tex](char));
[tex]$\text{int i}$[/tex]=0,j=0,x,y;
while(1)
{
ch=getc(fp);
if(ch=='\n')
break;
*(s1+i)=ch;
i++;
}
while(1)
{
ch=getc(fp);
if(ch=='\n')
break;
*(s2+j)=ch;
j++;
}
for(x=0;x<i;x++)
{
*(s3+x)=*(s1+x);
}
for(y=0;y<j;x++,y++)
{
*(s3+x)=*(s2+y);
}
for(x=0;x<i+j;x++)
{
printf("%c",*(s3+x));
}
printf("\n");
getc(fp);
}
}