Which state has the most fixed shape?
O A. Gas
O B. Solid
O C. Liquid
O D. Plasma

Explanation:

we know that

v = m/d

or; v=1kg/800kgm^3

or; v=0. 00125m

The turning moment the balloon produces about the pivot on the ruler is 0.0096 N-m.

The force that can cause an object to rotate along an axis is measured as torque. In linear kinematics, force is what drives an object's acceleration. Similar to this, an angular acceleration is brought on by torque. As a result, torque can be thought of as the rotational counterpart to force. The axis of rotation is a straight line about which an item rotates.

Weight of the balloon and carbon di oxide: w = 0.06 N.

Distance from pivot: d = 16 cm = 0.16 m.

The length of the ruler pivoted at the center = 100 cm = 1 m.

Hence,  the turning moment the balloon produces about the pivot on the ruler = wd = 0.06 × 0.16 N-m = 0.0096 N-m.

So, the turning moment the balloon  is 0.0096 N-m.

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Answer:

7)  λ = 0.5 m,  8)  f = 4.8 10¹⁴ Hz

Explanation:

The speed of an electromagnetic wave is

          c = λ f

where c is the speed of light in vacuum c = 3 10⁸ m / s

7) indicate the frequency f = 6.0 10⁸ Hz

we do not know the wavelength

         λ = c / f

we calculate

        λ = 3 10⁸ / 6.0 10⁸

        λ = 0.5 m

8) indicate the wavelength  λ = 6.25 10-7 m

we do not know the frequency

         f = c / λ

we calculate

        f = 3 10⁸ / 6.25 10⁻⁷

        f = 0.48 10¹⁵ Hz

        f = 4.8 10¹⁴ Hz

Answer:

Explanation:

V = I * R

V = 4 * 12.1 = 48.4 v

Answer:

A ball rolling down the slope.

A bicycle rider is riding the bicycle on tthe slope where both pedals are engaged.

Answer:

[tex]k.e = \frac{1}{2} m {v}^{2} \\ {v}^{2} = {u}^{2} + 2gs \\ {v}^{2} = 0 + (2 \times 9.8 \times 15) \\ v = 17.1 \: m {s}^{ - 1} \\ k.e = \frac{1}{2} \times m \times {17.1}^{2} \\ = 147m \: joules \\ m \: is \: mass[/tex]

Kinetic energy of the rock just before hitting the water is 147m joules where m is the mass of the object.

The kinetic energy of an object is defined as the energy it possesses due to its motion. It is the work required to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains the kinetic energy as long as its momentum does not change.

It is directly proportional to the mass of the object and the square of its velocity:[tex]K.E. = 1/2 mv^2[/tex].

Where, m= mass of the object

v= velocity

So if the units of mass are in kilograms and the units of velocity are meters per second, then kinetic energy has units of kilogram-meter squared per second squared.

For above given information,

[tex]K.E= 1/2 mv^2\\v^2= u^2 + 2gs\\ \\v^2= 0+ (2* 9.8*15)\\v^2= 294 m/s\\So, K.E. = 1/2 m* 294 m/s\\K.E.= 147m joules[/tex]

Thus, Kinetic energy of the rock just before hitting the water is 147m joules where m is the mass of the object.

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Answer:

the answer to the question is mitosis

Answer:

a. V_y = 50m/s and V_x = 86.6m/s

b. d_x = 173.2m

c. d_y = 80.38m

Explanation:

V_x = 100m/s*cos(30°)

V_x = 86.6m/s

V_y = 100m/s*sin(30°)

V_y = 50m/s

D_x = v_x*t

d_x = 86.6m/s*2s

d_x = 173.2m

v_f = 50m/s+(-9.81m/s²)*2s

v_f = 30.38m/s

d_y = .5*(30.38m/s+50m/s)*2s

d_y = 80.38m

Answer:

A Couple in a bicycle is usually generated by the gravitational force and the corresponding reaction forces of the floor. A couple is a force which encourages or prevents a body turning in motion.

The wheels help in the movement and motion of the bicycle from point A to B. The chain which connects different parts help in the rotation of the bicycle wheels through the movement of the pedals by the legs

Answer:

a

Explanation:

because it's need someone moving it so it can move somewhere else

Answer:

The speed she must have at point 3 is approximately 21.72 m/s

Explanation:

The given parameters are;

The radius of the track, r = 3.25 m

The speed with which the driver goes past point 1, v₁ = 20.2 m/s

Let, 'm', represent the mass of the driver and the car, and let v₃ represent the velocity at point 3, based on the diagram and solution method from a similar question online, we have;

At point 1, The net force, [tex]F_{NET} = F_N - F_g[/tex]

The net force, [tex]F_{NET}[/tex], is the centrifugal force, therefore;

[tex]F_{NET} = \dfrac{m \cdot v_1^2}{r}[/tex]

[tex]F_g[/tex] = The force of gravity on the car (the weight of the car) = m·g

[tex]F_N_1[/tex] = The normal reaction at point 1

Therefore, we have;

[tex]F_{NET} = \dfrac{m \cdot v_1^2}{r} = F_N_1 - F_g = F_N_1 - m \cdot g[/tex]

[tex]F_N_1= \dfrac{m \cdot v_1^2}{r} + m \cdot g = m\cdot \left(\dfrac{ v_1^2}{r} + g \right)[/tex]

[tex]F_N_1 = m\cdot \left(\dfrac{ v_1^2}{r} + g \right)[/tex]

At point 3, The net force, [tex]F_{NET} = F_N_3 + F_g[/tex]

Where;

[tex]F_{N3}[/tex] = The normal reaction at point 3

Therefore;

[tex]F_N_3= F_{NET} - F_g = \dfrac{m \cdot v_3^2}{r} - m \cdot g = m\cdot \left(\dfrac{ v_3^2}{r} - g \right)[/tex]

For the normal force to be the same, we get;

[tex]F_{N1} = F_{N3}[/tex]

Therefore;

[tex]m\cdot \left(\dfrac{ v_1^2}{r} + g \right) = m\cdot \left(\dfrac{ v_3^2}{r} - g \right)[/tex]

[tex]\left(\dfrac{ v_1^2}{r} + g \right) = \left(\dfrac{ v_3^2}{r} - g \right)[/tex]

[tex]v_3^2 = r \times \left(\dfrac{ v_1^2}{r} + g + g \right) = v_1^2 + 2\cdot g \cdot r[/tex]

[tex]v_3 = \sqrt{v_1^2 + 2\cdot g \cdot r}[/tex]

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

Therefore;

v₃ = √(20.2² + 2 × 9.81 × 3.25) ≈ 21.72 m/s

The speed she must have at point 3, so that the normal force at the top has the same magnitude as it did at the bottom, v₃ ≈ 21.72 m/s

Answer:

Velocidad final, V = 40 m/s

Explanation:

Dados los siguientes datos;

Aceleración = 5 m/s²

Velocidad inicial = 0 m/s (ya que comienza desde el reposo)

Tiempo = 8 segundos

Para encontrar la velocidad final, usaríamos la primera ecuación de movimiento;

[tex] V = U + at[/tex]

Dónde;

Sustituyendo en la fórmula, tenemos;

[tex] V = 0 + 5*8 [/tex]

[tex] V = 0 + 40 [/tex]

[tex] V = 40 [/tex]

Velocidad final, V = 40 m/s

Answer:

When an object falls, gravity pulls the object towards the ground and causes the object to accelerate by 9.8m/s each second. Regardless of mass, every object accelerates at the same rate (9.8m/s) when dropped unless there´s air resistance.  

Answer:

Work is ability if application of energy.

Such as pushing a wheel barrow through a distance ( Newton's third law )

Work is the ability to do something.

c- temperature

The speed of sound increases with increasing temperature .

Answer:

[tex]h=3.18\times 10^{-9}\ m[/tex]

Explanation:

Given that,

The volume of a drop, [tex]V=10^{-10}\ m^3[/tex]

The radius of the circular film, [tex]r=10^{-1}\ m[/tex]

We need to find the thickness of the film.

We know that,

Volume, [tex]V=\pi r^2 h[/tex]

So,

[tex]h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{10^{-10}}{\pi \times (10^{-1})^2}\\\\h=3.18\times 10^{-9}\ m[/tex]

So, the thickness of the file is equal to[tex]3.18\times 10^{-9}\ m[/tex].

If two vectors are represented both in magnitude and direction by the two adjacent sides of a triangle taken in an order, then their resultant is given by the third side taken in the reverse order.

Resultant vector :

                         R = sqrt of A^2 + B^2 + 2ABcosθ

given :

          A = 200 units

          B = 300 units

          θ = 30 degrees

∴ R = sqrt of 200^2 + 300^2 + 2(200)(300)cos35

the answer is 477.805656

Answer: Light ray X will eventually hit the borader

Explanation:

Answer:

mechanical advantage

Explanation:

i got it right on edge :)

Answer:

x = 1/2

Explanation:

5x/x + 2 = 3x/x + 1

do cross multiplication

(x + 2) * 3x = (x + 1) * 5x

3x^2 + 6x = 5x^2 + 5x

6x - 5x = 5x^2 - 3x^2

x = 2x^2

x/x^2 = 2

1/x = 2

1 = 2x

1/2 = x

Answer:ur mom

Explanation:because

Answer:

2.4 secs.

Explanation:

Current (A) = Charge (coulomb)/Time(sec)

We are looking for time. So:

Time (sec) = Charge (coulomb)/Current (A)

↓

12coulombs/5.0A = 2.4 secs

The voltage from one side of the battery all the way around to the other side of the battery is 12v .

If 4 of those volts show up across the circle-thing, then the rest of the 12v ... 8v ... Must show up across the set of parallel rectangles.

To get that answer, I subtracted the 4 from the 12.

Just like it says in choice-C.

Answer:

1200000 J

Explanation:

Applying,

W = Fdcos∅....................... Equation 1

Where W = Workdone, F = Force applied to pull the wagon, d = distance, ∅ = angle with the horizontal.

From the question,

Given: F = 2000 N, d = 0.75 miles = (0.75×1600) = 1200 m, ∅ = 60°

Substitute these values into equation 1

W = 2000×1200×cos60°

W = 2000×1200×0.5

W = 1200000 J

Hence the work done in pulling the wagon is 1200000 J

Answer:

592000 J

Explanation:

We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:

1 Pa = 1 Kg/ms²

Therefore,

3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²

Next, we shall determine the workdone.

Workdone is given by the following equation:

Workdone (Wd) = pressure (P) × change in volume (ΔV)

Wd = PΔV

With the above formula, the work done can be obtained as follow:

Pressure (P) = 3.7×10⁵ Kg/ms²

Change in volume (ΔV) = 1.6 m³

Workdone (Wd) =?

Wd = PΔV

Wd = 3.7×10⁵ × 1.6

Wd = 592000 Kgm²/s²

Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:

1 Kgm²/s² = 1 J

Therefore,

592000 Kgm²/s² = 592000 J

Therefore, the Workdone is 592000 J.