Which statement would indicate the presence of an acid?
It tastes bitter..
It does not react with active metals.
It reacts with active metals to form a gas.
It does not change the color of litmus paper

Answer:

81.65 g CO2

Explanation:

Answer:

Cell is defined as the smallest unit or basic unit of life.

the smallest part of a living thing that can carry out the activities needed for life. Basically the unit of all forms of life.

Explanation:

hope this helps in anyway :)

Answer:

It will become a red giant

Explanation:

When the sun runs out of its hydrogen fuel and the hydrogen atoms are combined together to make helium atoms, it expands into a red giant, which is made up of helium atoms and gases.

Answer:

0.192 mol N₂O

Explanation:

Step 1: Write the balanced equation

NH₄NO₃(aq) ⇒ N₂O(g) + 2 H₂O(l)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of NH₄NO₃ to N₂O is 1:1.

Step 3: Calculate the number of moles of N₂O formed upon complete reaction of 0.192 moles of NH₄NO₃

We will use the previously established molar ratio.

0.192 mol NH₄NO₃ × 1 mol N₂O/1 mol NH₄NO₃ = 0.192 mol N₂O

Answer:

5.01 x 10^-6 M

Explanation:

PH= -log [H+]

[H+] = 10^-PH

Answer:

The molecules in gasoline (octane, the chemical formula shown) contain chemical energy. This energy is transformed into kinetic energy that allows a car to race on a racetrack.

B.

Delta G is negative and Delta S is positive.

Answer:

0.001 g

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 5730 years

Original amount (N₀) = 144 g

Time (t) = 100,000 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 5730 years

Time (t) = 100,000 years

Number of half-lives (n) =?

n = t / t½

n = 100,000 / 5730

n ≈ 17

Finally, we shall determine the amount remaining. This can be obtained as follow:

Original amount (N₀) = 144 g

Number of half-lives (n) = 17

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2¹⁷ × 144

N = 1/131072 × 144

N = 0.000007 × 144

N ≈ 0.001 g

Thus, the amount remaining after 100000 years is 0.001 g

We know that, at STP, one mole of a gas occupies 22.4 L of volume

we'll use the same principle to solve this problem

Converting given volume to Liters:

We know that 1 m³ = 1000 L

So, 20000 m³ = (20000)*(1000) L = 2 * 10⁷ L

Converting Liters to moles:

As mentioned above, at STP, one mole occupies 22.4 Liters

Number of moles in 2 * 10⁷ L = 2 * 10⁷ / 22.4

Number of moles = 8.9 * 10⁵ moles

Converting moles to number of particles:

We know that 1 mole contains 6.022 * 10²³ molecules

So, 8.9 * 10⁵ moles contain [(8.9 * 10⁵) * (6.022 * 10²³)] molecules

Number of molecules = 53.6 * 10²⁸ molecules

In proper scientific notation:

Number of molecules = 5.36 * 10²⁹ molecules

Answer:

it contains 0.599 g i hope it helps

Answer:

D

Explanation:

Answer:

When blood is too basic, carbonic acid can ionize to bicarbonate and H+ ions, adding H+ ions to the blood.

When blood becomes too acidic, bicarbonate combines with extra H+ ions to form carbonic acid, removing H+ ions from the blood.

Carbonic acid can raise or lower the pH of blood.

Explanation:

A buffer is a solution that resists changes to its pH when small quantities of acids or bases are added to it. The human blood serves as a buffer as it contains a buffer of carbonic acid (H2CO3) and bicarbonate anion (HCO3-) which serves to maintain blood pH between 7.35 and 7.45. Other buffering systems in blood exist such as the Hydrogen ion and oxygen gas which affects oxygen binding to haemoglobin, however the carbonic-acid-bicarbonate buffer is the most important buffer for maintaining acid-base balance in the blood.

A buffer solution is made up of an acid and its conjugate base or a base and its conjugate acid. For carbonic acid-bicarbonate buffer, carbonic acid serves as the acid while bicarbonate serves as the base. When a little quantity of a base as hydroxide ions is added to a buffer, the acid reacts with it and remove it from the solution. On the other hand, when a little quantity of an acid as hydrogen ions are added to a buffer, the conjugate base reacts with it and remove it from the solution, thus keeping the pH of the solution fairly constant.

In the carbonic acid-bicarbonate buffer:

When blood is too basic, carbonic acid can ionize to bicarbonate and H+ ions, adding H+ ions to the blood.

When blood becomes too acidic, bicarbonate combines with extra H+ ions to form carbonic acid, removing H+ ions from the blood.

Thus, carbonic acid can raise or lower the pH of blood.

Carbonic acid work to maintain blood pH as follows:

This means that, carbonic acid works to maintain blood pH as follows:

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Answer:

WHERE ARE THE CHOICES?

PLEASE MAKE SURE THAT YOUR QUESTION IS RIGHT BEFORE POSTING IT シ︎

Change of state of matter is not  an indication that a chemical change has taken place.

Matter is a substance which is made up of various types of particles  which occupy space and have inertia . All living things and objects  are made up of various types of particles  that occupy space and have inertia .

Depending on temperature and other factors matter is able to exist in different phases. Most common of which are solid, liquid and gas. Matter can exist in more than one state depending on the temperature and pressure .

State of matter can be changed  by heating or cooling and even by changing the applied pressure.When a state changes matter does not break rather its state changes though its chemical composition remains same.

Physical characteristics of matter are shape, color, size and temperature. Every matter is made up of elements which  cannot be broken down further by ordinary chemical reactions.

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Answer: [tex]K_{eq}[/tex] at  the temperature of the experiment is 0.56.

Explanation:

Moles of  [tex]CO[/tex] = 0.35 mole

Moles of  [tex]H_2O[/tex] = 0.40 mole

Volume of solution = 1.00 L

Initial concentration of [tex]CO[/tex] = [tex]\frac{0.35mol}{1.00L}=0.35M[/tex]

Initial concentration of [tex]H_2O[/tex] = [tex]\frac{0.40mol}{1.00L}=0.40M[/tex]

Equilibrium concentration of [tex]CO[/tex] = [tex]\frac{0.19mol}{1.00L}=0.19M[/tex]

The given balanced equilibrium reaction is,

                      [tex]CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)[/tex]

Initial conc.          0.35 M         0.40 M                  0 M        0M

    At eqm. conc.     (0.35-x) M   (0.40-x) M   (x) M      (x) M

Given:  (0.35-x) = 0.19

x= 0.16 M

The expression for equilibrium constant for this reaction will be,

[tex]K_{eq}=\frac{[CO_2]\times [H_2]}{[CO]\times [H_2O]}[/tex]  

Now put all the given values in this expression, we get :

[tex]K_{eq}=\frac{0.16\times 0.16}{(0.35-0.16)\times (0.40-0.16)}[/tex]

[tex]K_{eq}=\frac{0.16\times 0.16}{(0.19)\times (0.24)}=0.56[/tex]

Thus [tex]K_{eq}[/tex] at  the temperature of the experiment is 0.56.

Answer:

HERE

Explanation:

Question:

Does anyone know if this is positive,negative or neutral?

Answer:

Netarual

Explanation:

I but the Images down below

Answer:

2.475 mol of O2  formed.

Explanation:

Given 1.65 moles of KClO3 as the target amount in the reactant, used the coefficient of the balanced chemical reaction involved to determine the number of moles of O2 molecules formed.

x mole of  O2   = 1.65 mol  KClO3 x [(3 mol O2)/ (2 mol KClO3)] = 2.475 mol of O2

x mole of  O2 formed  = 2.475 mol of O2

Answer: 41.0

Explanation: When you multiply the two numbers you get 41 but you need to have the same amount of significant numbers as the number in the problem with the least significant numbers. I hope this helps

When the switch is closed, electrons flow from the solid magnesium electrode, Mg(s) to solid silver electrode, Ag(s).

Electronegativity of metals refers to the ability of the atoms of metallic elements to attract electrons from the other metallic elements.

Electronegativity increases down the activity series.

Silver (Ag) will have more tendency to attract electron more than magnesium (Mg).

Thus, when the switch is closed, electrons flow from the solid magnesium electrode, Mg(s) to solid silver electrode, Ag(s).

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Answer:

A. The rate constant decreases

Explanation:

i took the quiz on a pex and it was correct

Answer:

can not be determined

Explanation:

because when I tried to calculate it it didn't give me the answer options that was in the pic so it's definitely C

Answer:

1 watt is conduned by you ok

Answer:

0.0102 L or 10.2 mL

Explanation:

From the question given above, the following data were obtained:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole / Volume

With the above formula, we can obtain the volume as follow:

Molarity = 0.250 M

Mole = 0.00255 mole

Volume =?

Molarity = mole / Volume

0.250 = 0.00255 / volume

Cross multiply

0.250 × volume = 0.00255

Divide both side by 0.250

Volume = 0.00255 / 0.250

Volume = 0.0102 L

Covert 0.0102 L to mL.

1 L = 1000 mL

Therefore,

0.0102 L = 0.0102 L × 1000 / 1 L

0.0102 L = 10.2 mL

Thus, the volume is 0.0102 L or 10.2 mL

Answer:

no problem hey I will help you

Answer:

a chemical which promotes a chemical reaction

and sppeds up that reaction.

Answer:

The final concentration of the Randyne in grams per milliliter = 0.011 g/mL

Explanation:

As we know

C1V1 = C2V2

C1 and C2 = concentration of solution 1 and 2 respectively

V1 and V2 = Volume of solution 1 and 2 respectively

Substituting the given values, we get -

[tex]50 * 15 = X * (15+50)\\X = 11.54[/tex] mg/mL

The final concentration of the Randyne in grams per milliliter = 0.011 g/mL

The final concentration of the Randyne in this solution is 0.01 g /mL.

It is very important to know the dilution methods in a chemistry lab. The dilution from the stock solution can be prepared by using the formula,

[tex]C_1V_1 = C_2V_2[/tex]

Where,

[tex]C_1[/tex]- concentration of the stock solution

[tex]V_1[/tex] - the volume of the stock solution

[tex]C_2[/tex] - concentration of the diluted solution

[tex]V_2[/tex] - the volume of diluted solution

Put the values in the formula,

[tex]50 \times 15 = C_2 \times 75 \\\\C_2 = \dfrac {750}{75 }\\\\C_2 = 10{\rm \ mg/mL \ \ \ or} \\\\ C_2 = 0.01 \rm \ g/mL[/tex]

Therefore, the final concentration of the Randyne in this solution is 0.01 g /mL.

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Answer:

1

Explanation:

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Answer:

Percent dissociated = 3.92%

Explanation:

The equilibrium of the weak acid, HA, is:

HA ⇄ H⁺ + A⁻

Where Ka = 8x10⁻⁴ is: [H⁺] [A⁻] / [HA]

As both H⁺ and A⁻ comes from the same equilibrium we can write the concentrations of the species as follows:

[H⁺] = X

[A⁻] = X

[HA] = 0.50M - X

Where X is reaction coordinate

Replacing:

8x10⁻⁴ = X² / 0.50-X

4x10⁻⁴ - 8x10⁻⁴X - X² = 0

Solving for X:

X = -0.02M. False solution. There is no negative concentrations

X = 0.0196M. Right solution.

Replacing:

[A⁻] = 0.0196M

Percent of the acid that is dissociated is:

[A⁻] / [HA]₀ * 100

[HA]₀ is its initial concentration = 0.50M

0.0196M / 0.50M * 100