write a pair of equal angles which are supplementary

Answers

Answer 1

Step-by-step explanation:

msjshshshsheueueue6636363636363636663673737328292920101pqplqlamzmzbzbxbdjsksow8e8eurhdbxbxvftdyrueioeowpqpqlalajdhddgzg xbnnxmcmxMlqlqpqw


Related Questions

Point N is between M and R. If MN = 25 in, and NR = 12 in, then what is the length of MR?

Answers

Add MN and NR together.
25 + 12 = 37. Make sure to add the word units on the end if it’s not multiple choice.

Mr. Green's lawn mower holds 600 milliliters of gasoline in the tank. He just filled his 6 liter gas can at the station. How many times will he be able to fill his lawn mower tank from the gas can?

Answers

Answer:

10 times.

Step-by-step explanation:

Since 1 liter = 1000 milliliters, we can say that 600 milliliters is equal to 0.6 liters because 600/1000 = 0.6

Since the gas can holds 6 liters, and the lawn mower holds 0.6 liters, 6/0.6 = 10.

So, he can fill his lawn mower 10 times with the gas can

Mr Green can fill his lawn 10 times

the first step is to convert the milliliters to liters

600 milliliters to liters

= 600/1000

= 0.6 liters

the number of times can be calculated as follows

= 6/0.6

= 10

hence it will take Mr. Green  10 times to fill his lawn mower

please see the link below for more information

https://brainly.com/question/632986?referrer=searchResults

What is 4/q as a decimal

Answers

Answer:

what is the value of q?

Step-by-step explanation:

If the​ cost, C​, for manufacturing x units of a certain product is given by C=x2+10x+45, find the number of units manufactured at a cost of $ 10,020.

Answers

Answer: 95 units.

Step-by-step explanation:

The cost of making x units is:

C(x) = x^2 + 10*x + 45.

Now, if the cost is $10,020, then we can solve this for x as:

C(x) = 10,020 = x^2 + 10*x + 45

x^2 + 10*x + 45 - 10,020 = 0

x^2 + 10*x - 9,975 = 0

Now, remember that for a quadratic equation:

a*x^2 + b*x + c = 0

the solutions are:

[tex]x = \frac{-b +-\sqrt{b^2 - 4*a*c} }{2*a}[/tex]

In this case the solutions are:

x = [tex]x = \frac{-10 +-\sqrt{10^2 - 4*1*(-9,975)} }{2*1} = \frac{-10 +- 200}{2}[/tex]

Then we have two solutions, one for each sign:

x = (-10 -200)/2 = -110

x = (-10 + 200)/2 = 95

Here we must choose the positive option, as x represents a positive quaintity.

Then the number of units manufactured is 95.

What is 3X to the second power plus 4X -3+ negative 4X to the second power minus 2X -4 in polynomial form

Answers

Answer:

The polynomial form of the expression is: 25·X² + 2·X + 2.

Step-by-step explanation:

The expression that can be formed using the provided data is:

[tex](3X)^{2}+(4X-3)+(-4X)^{2}-(2X-4)[/tex]

Simplify the expression to get a result in polynomial form as follows:

[tex](3X)^{2}+(4X-3)+(-4X)^{2}-(2X-4)[/tex]

[tex]=9X^{2}+4X-3+16X^{2}-2X+5\\\\=(9+16)X^{2}+(4-2)X+(5-3)\\\\=25X^{2}+2X+2[/tex]

Thus, the polynomial form of the expression is: 25·X² + 2·X + 2.

unit rate 232 miles in 4 hours​

Answers

Answer:

58 miles per hour

Step-by-step explanation:

leave a heart please :D

Find sets of three consecutive odd integers whose sum is between 100 and 115

Answers

Answer:

33, 35, 37

Step-by-step explanation:

Consecutive: in a row

Odd: any number not evenly divisible by 2

Integers: Whole numbers

Sum: the answer to an addition problem

So, 100 is close to 30*3, so start there and move on. It has to be a little more, so start at 31, 33, and 35, but it's only 99, so you need something a little more. Check 33, 35, and 37 to be sure, and you've got your answer!

It is 60 Celsius on the crust of a volcano. What is this number in Kelvin?

Answers

Answer:

333.15 Kelvin (K)

Step-by-step explanation:

When you convert from Celsius to Kelvin, you add 273.15

60 C + 273.15 = 333.15 K

So, that is the answer. Hope this helps!

Answer:

333.15 Kelvin (333 rounded)

Step-by-step explanation:

You must add 273.15.

60 + 273.15 = 333.15.

The answer is 333.15 (333 rounded.)

what is the constant for -9x^3+12p+6

Answers

6 is the constant in that equation. The answer is 6 because it is the only number that is not attached to a variable.

A constant is any numbers in an equation that don't have any variable connected to it.

-9x^3 and 12p are not constants since they are connected to variables.

6 is a constant because its not connected to any variable.

Best of Luck!

The perimeter of the rectangle and the triangle shown are the same. Write an equation to represent this situation, and solve for x. Then, find the perimeter of each shape.

Answers

Answer:

Step-by-step explanation:

Perimeter of a polygon = Sum of all sides of the polygon

Perimeter of the given rectangle = 2[(5x - 2) + (3x - 0.5)]

                                                      = 2[8x - 2.5]

                                                      = (16x - 5)

Perimeter of the given triangle = (2x + 3) + (2x + 3) + (10x - 5)

                                                   = 14x + 1

Since perimeter of the rectangle and triangle are same, equation will be

(16x - 5) = (14x + 1)

16x - 14x = 5 + 1

2x = 6

x = 3

Perimeter = (16x - 5)

                 = 48 - 5

                 = 43 units

A farmland is 30cm long and 15cm wild what is the area of the farmland

Answers

The answer is 450cm

5. Find the base of the triangle if its area is 48 sq. in and its height is 16 in. 10 points none of the options 9 in O 12 in 6 in​

Answers

Answer:

The answer is 6 in

Step-by-step explanation:

Area of a triangle is given by

[tex] A = \frac{1}{2} bh[/tex]

where b is the base

h is the height

From the question

A = 48 sq. in

h = 16 in.

Substitute the values into the above formula and solve for the base

That's

[tex]48 = \frac{1}{2} 16b \\ 48 = 8b \\ \frac{8b}{8} = \frac{48}{8} [/tex]

We have the final answer as

6 in

Hope this helps you

i need help finding the range​

Answers

Answer:

I think it's -1, 4. But i'm not a 100% sure.

Step-by-step explanation:

Answer:

To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

Step-by-step explanation:

This is how you solve for Range; I can't view the image on my chromebook.

If it takes 10 seconds to hear thunder when lightning is 4 miles away, determine how far away the lightning is when it takes 6 seconds to hear the thunder. miles

Answers

Answer:

2.4 miles.

Step-by-step explanation:

10sec = 4 miles.......what abt.....

6 sec =  ??

cross multiply:

6sec × 4miles ÷ 10 sec= 2.4miles

in geometry why do we use 3.14 rather than 3.14159??

Answers

Answer:

3.14 is the simplified version (approximate) to π

Its simpler to use.

Suppose you have 20 coins that total $3.00. Some coins are nickels and some are quarters. Which of the following pairs of equations would you use to find out how many of each coin you have?

Answers

Answer:

Step-by-step explanation:

n + q = 20

.05n + .25q = 3.00

5n + 25q = 300

 n + q = 20

5n + 25q = 300

-5n - 5q = -100

20q = 200

q = 10 quarters

n + 10 = 20

n = 10 nickels

(10 nickels, 10 quarters)

If m 8 =22, m 7=31, and m EAD=102 find m 9

Answers

S is the answer

Step-by-step explanation:

Let 3+4+8+9+13+14+18+___ 40 terms=S

3. Given: a+b=12 and ab=9
Use (a + b)2 to find a² +bº. (Do not solve for a and b individually)

Answers

Answer:

a²+b²=126

Step-by-step explanation:

(a+b)²=a²+b²+2ab

(12)²=a²+b²+2×9

144=a²+b²+18

a²+b²=144-18=126

HELP WILL GIVE BRAILEST AND WILL GIVE 50 POINTS!!!!! (also please tell me how you did it!) Simplify and Solve: 12x + 8 < 116

Answers

Answer:

Step-by-step explanation:

1. isolate the variable   subtract both sides by 8                   (12x+8-8<116-8)  

2. Divide both sides by twelve                                               (12x/12<116-8/12)                                            

3. Simplify                                                                                 (x<108/12)      

4. Answer                                                                   (x<9)                                                        

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                                                                                                                                                                                   

Step 1: Subtract 8 from both sides.

=12x+8−8<116−8

=12x<108

Step 2: Divide both sides by 12.

[tex] \frac{12x}{12} < \frac{108}{12} [/tex]

Answer

x<9

5/8-(1/4) to the 2 power

Answers

Answer:

0.5625

Step-by-step explanation:

Dose every positive real number

also have both a positive and negative cube root?

Answers

Answer:

Any real number will have only one real cube root. Hence the technicalities associated with the principal root do not apply.

Step-by-step explanation:

x+a=3/4 I don't know how to solve this and I need someone to help explain it to me.

Answers

I think you should Subtract
a
a
from both sides of the equation.
x=3/4-a and that’s your answer

please someone help me to prove this...​

Answers

Answer:  see proof below

Step-by-step explanation:

Use the following Power Reducing Identities:

[tex]\cos^2 A = \dfrac{1}{2}(1 + \cos 2A)\\\\\sin^2 A = \dfrac{1}{2}(1 - \cos 2A)[/tex]

Use the following Product to Sum Identity:

[tex]\cos A\cdot \cos B=\dfrac{1}{2}\bigg[\cos(A+B)+\cos(A-B)\bigg][/tex]

Proof LHS → RHS

[tex]\text{LHS:}\qquad \qquad \qquad \cos^2\beta\cdot \sin^4\beta\\.\qquad \qquad \qquad =\cos^2\beta\cdot \sin^2\beta\cdot \sin^2 \beta[/tex]

[tex]\text{Power Reducing:}\qquad \dfrac{1}{2}\bigg(1+\cos 2\beta\bigg)\dfrac{1}{2}\bigg(1-\cos 2\beta\bigg)\dfrac{1}{2}\bigg(1-\cos 2\beta\bigg)\\\\\\.\qquad \qquad \qquad \quad =\dfrac{1}{8}(1+\cos 2\beta)(1-\cos 2\beta)(1-\cos 2\beta)[/tex]

[tex]\text{Expand:}\qquad \qquad \dfrac{1}{8}\bigg(1-\cos 2\beta-\cos^2 2\beta+\cos^3 2\beta\bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{8}\bigg(1-\cos 2\beta-\cos^2 2\beta+\cos^2 2\beta \cdot \cos \2\beta\bigg)[/tex]

[tex]\text{Power Reducing:}\qquad \dfrac{1}{8}\bigg(1-\cos 2\beta -\dfrac{1}{2}(1+\cos 4\beta)+\dfrac{1}{2}(1+\cos 4\beta)\cos 2\beta\bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{16}\bigg(2-2\cos 2\beta -1-\cos 4\beta +\cos 2\beta +\cos 4\beta \cdot \cos 2\beta \bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{16}\bigg(1-\cos 2\beta -\cos 4\beta+\cos 4\beta \cdot \cos 2\beta \bigg)[/tex]

[tex]\text{Product to Sum:}\quad \dfrac{1}{16}\bigg(1-\cos 2\beta -\cos 4\beta +\dfrac{1}{2}[\cos(4\beta+2\beta)+\cos (4\beta-2\beta)]\bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{32}\bigg(2-2\cos 2\beta -2\cos 4\beta +\cos 6\beta +\cos 2\beta\bigg)\\\\.\qquad \qquad \qquad =\dfrac{1}{32}\bigg(\cos 6\beta-2\cos 4\beta -\cos 2\beta +2 \bigg)[/tex]

[tex]\text{LHS=RHS:}\\ \dfrac{1}{32}\bigg(\cos 6\beta-2\cos 4\beta -\cos 2\beta +2 \bigg)=\dfrac{1}{32}\bigg(\cos 6\beta-2\cos 4\beta -\cos 2\beta +2 \bigg)[/tex]

Solve for a. 2z=4a/m +3

Answers

Answer:

               a = (2mz - 3m)/4

Step-by-step explanation:

2z = 4a/m +3

 -3        -3

2z - 3 = 4a/m

 ×m        ×m

(2z -3)m = 4a

     ÷4      ÷4

[(2z -3)m]/4 = a

a = (2mz - 3m)/4

The world's largest ocean, the Pacific ocean, has an area of about 200,000,000 km^(2) , which can be written as 2 x 10 ^(n) km^(2). What is n?​

Answers

n=8. All you have to do is count the amount of numbers after the 2 in 200,000,000. There are 8 numbers after the number 2 which makes n=8.

Answer:

n = 8

Step-by-step explanation:

:)

what should be added m(m-n) to get square ofm(m-n)

Answers

Answer: m²-mn

Explanation: multiply the letter outside the brackets by everything inside the brackets, so, m×m = m² and m×n = mn, altogether it is m²-mn.

what is 3,393 divided by 13

Answers

Answer:

261

I hope this helps!

please answer this quick
I need help​

Answers

Answer:

No, it is not a magic square.

Step-by-step explanation:

A magic square is when whatever way you add it from, it is always the same answer (the magic sum). As you can clearly tell, it doesn't add up to the same number.

It is not magic Square

Can someone please help to explain this?

Answers

Answer:

[tex]\frac{PQ}{DE}[/tex] = [tex]\frac{4}{6}[/tex]

Step-by-step explanation:

Given

Δ PQR ~ Δ DEF

Then the ratio of corresponding sides are equal

The corresponding letters in the names of the triangles gives the corresponding sides.

Thus PQ/DE, QR/EF, PQ/DF

In this case

[tex]\frac{PQ}{DE}[/tex] = [tex]\frac{4}{6}[/tex]

-5 - 1 =
please help me and it isnt -4

Answers

Answer:

the answer is -6

Step-by-step explanation:

if you have -5 and you take away another number, you end up with -6

Answer:

-6

Step-by-step explanation:

-5 - 1 ISNT -4

-5 + 1 IS -4

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