Write the equation of the line in fully simplified slope-intercept form.

Answer:

(a)  $897.72:  26 yr

     $1526.49:  10 yr

(b)  See below.

(c)  x = 705

     more, $705, longer it will take

Step-by-step explanation:

Given equation:

[tex]t=16.708 \ln \left(\dfrac{x}{x-705}\right)[/tex]

where:

[tex]\begin{aligned}x=897.72 \implies t& =16.708 \ln \left(\dfrac{897.72}{897.72-705}\right)\\& =16.708 \ln \left(4.65815691...\right)\\&=16.708(1.53861985...)\\&=25.70726...\\&=26\; \rm years\end{aligned}[/tex]

[tex]\begin{aligned}x=1526.49 \implies t& =16.708 \ln \left(\dfrac{1526.49}{1526.49-705}\right)\\& =16.708 \ln \left(1.85819669...\right)\\& =16.708(0.619606496...)\\&=10.352385...\\&=10 \; \rm years\end{aligned}[/tex]

To approximate the total amounts paid (in dollars) over the term of the mortgage, multiply the monthly payment by the term.

Please note I have provided two calculations per monthly payment:

(1) by using the exact term, and (2) using the rounded term from part (a).

[tex]\implies \$897.72 \times 25.7072605... \times 12 =\$276935.06[/tex]

[tex]\implies \$897.72 \times 26 \times 12=\$280088.64[/tex]

[tex]\implies \$1526.49 \times 10.3523853... \times 12=\$189633.75[/tex]

[tex]\implies \$1526.49 \times 10 \times 12 =\$183178.80[/tex]

To calculate the amount of interest costs (in dollars) in each case, subtract $150,000 from the total amounts paid:

[tex]\$897.72\implies 276935.06-150000=\$126935.06[/tex]

[tex]\$897.72 \implies 280088.64-150000=\$130088.64[/tex]

[tex]\$1526.49 \implies 189633.75-150000=\$39633.75[/tex]

[tex]\$1526.49\implies 183178.80-150000=\$33178.80[/tex]

The natural logarithm of a negative number cannot be taken.

Therefore, x > 705.

So the vertical asymptote for the model is:

The monthly payment must be more than $705, and the closer to this value the payment is, the longer it will take to pay off the mortgage.

Answer:

Prove that for any x0∈X and any r>0, the open ball Br(xo) is open. My attempt: Let y∈Br(x0). By definition, d(y,x0)<r

Step-by-step explanation:

Prove that for any x0∈X and any r>0, the open ball Br(xo) is open. My attempt: Let y∈Br(x0). By definition, d(y,x0)<r

The correct interpretation of the confidence interval is: "We are 95% confident that between 50.6% and 55.4% of California adult residents say that marijuana should be legal." (Option A)

The confidence interval represents the range of values within which we are 95% confident that the true population parameter (in this case, the percentage of California adult residents who say that marijuana should be legal) lies. It is specific to the population of California adult residents that was surveyed, and cannot be generalized to other states or to all American adults.

Therefore, Option A is the correct answer that we are 95% confident that between 50.6% and 55.4% of California adult residents say that marijuana should be legal.

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The confidence interval denotes the range of values within which we are 95% certain that the true population parameter (in this case, the proportion of adult Californians who support marijuana legalization) resides. It cannot be extrapolated to adults in other states or to all Americans as a whole because it is specific to the demographic of adult inhabitants of California who were polled.

Accordingly, Option A is the right response, and we are 95% certain that between 50.6% and 55.4% of adult inhabitants of California agree that marijuana should be legal.

Answer:

f(g(-1)) = -8

Step-by-step explanation:

⭐ The two equations we are given are:

This problem is an example of composite functions.

⭐What are composite functions?

First, we have to compute the value for the 2nd function you see. The 2nd function is inside f(x), and it is g(-1).

Essentially, we have to find the corresponding y-value for when x = -1 in g(x)

[tex]g(-1) = 2(-1) + 5[/tex]

[tex]g(-1) = 3[/tex]

Next, take this value and substitute it as the x-value for f(x).

[tex]f(3) = 1-x^2[/tex]

Now we have to find the y-value for f(x) for when x = 3.

[tex]f(3) = 1 -3^2[/tex]

⚠️⚠️⚠️!!! CAUTION !!! ⚠️⚠️⚠️

Some people may make the mistake of computing f(3) like this:

[tex]f(3) = 1 - 3^2[/tex]

[tex]f(3) = 1+9\\f(3) = 10[/tex]

This is wrong because only 3 is being squared, not -3. Make sure to read the equations you are given carefully to avoid mistakes like this.

[tex]f(3) = 1-3^2\\f(3) = 1-9\\f(3) = -8[/tex]

∴ f(g(-1)) = -8

The number of small rooms reserved is 4.

The number of large rooms reserved is 8.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

We have,

Small rooms are denoted as S.

Large rooms are denoted as L.

Now,

We will make two equations.
L = 2S _____(1)

8L + 6S = 88 ______(2)

Putting (1) in (2) we get,

8L + 6S = 88

8 x (2S) + 6S = 88

16S + 6S = 88

22S = 88

S = 88/22

S = 8/2

S = 4

Now,

Putting S = 4 in (1) we get,

L = 2 x 4

L = 8

Thus,

The number of small rooms and large rooms reserved is 4 and 8.

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The histogram that best represents the distribution of job applications for graduating seniors is given as follows:

a. Histogram III.

An histogram shows the number of times that each observation appears in a data-set.

Data on college graduates suggests that most will send out a large number of applications before getting their first job, hence the left bins on the histogram should have small numbers, while the right bins on the histogram should have greater numbers.

The only histogram that follows this pattern is Histogram III, hence option A gives the histogram that best represents the distribution of job applications for graduating seniors.

The histograms are given by the image shown at the end of the answer.

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To solve the given system of equations using elimination, we can add the two equations together to eliminate one of the variables. Doing this, we get 3x + 9y + (-10x - 6y) = 33 + (-14), which simplifies to -7x + 3y = 19. We can then solve for y by dividing both sides of the equation by 3, giving us y = 19/3 = 6.33. We can substitute this value for y in either of the original equations to solve for x. For example, if we substitute 6.33 for y in the first equation, we get 3x + 9 * 6.33 = 33, which simplifies to 3x = 3.67. Dividing both sides of the equation by 3, we get x = 1.22. Therefore, the solution of the system is (1.22, 6.33), which is approximately (1, 6). The answer choice that is closest to this solution is (d) (-1, 4). Thus, the solution of the system is (-1, 4).

With the help of Linear relationships The difference in the rate of change between the two containers is 1/5 gallon per minute.

what is Linear relationships?

A statistical word used to express a straight-line relationship between two variables is a linear relationship (or linear association). Graphs and mathematical equations of the form y = mx + b can both be used to represent linear relationships. In everyday life, linear relationships are quite prevalent.

Given:

Volume of water in each container.

To find:

Difference in the rate of change.

Solution:

Take any two points on container 1.

Let the points are (10, 2) and (20, 4).

m = (y2 - y1) / ( x2 - x1 )

   = ( 4 - 2 ) / ( 20 - 10 )

   = 2/ 10

   = 1/ 5

Rate of change for container 1 is .

Take any two points on container 2.

Let the points are (5, 2) and (10, 4).

m = (y2 - y1) / ( x2 - x1 )

   = ( 4 - 2 ) / ( 10 - 5)

   = 2 / 5

Rate of change for container 2 is 2/5

Difference = (2 /5 ) - ( 1/ 5 )

                  = 1 / 5  

Hence, The difference in the rate of change between the two containers is 1/5 gallon per minute.

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The slope of the line is 7/9

It is important to note that the equation of a line is represented as;

y = mx + c

Where;

The formula for calculating the slope of a line is expressed as;

Slope, m = y₂ - y₁/x₂ - x₁

Now, let's substitute the values into the formula from the points given we have;

Slope, m =1 -(-6)/ -3 - (-6)

expand the bracket

Slope, m = 1 + 6/ 3 + 6

add the values

Slope, m = 7/9

Hence, the value is 7/9

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Answer:

22

There are 22 multiples that end in 22.

Answer:

Initial balance 500, compounds 4 times at an interest rate of 15%

Step-by-step explanation:

Initial balance 500, compounds 4 times at an interest rate of 15%

No, A is not defective.

The rank–nullity theorem is a theorem in linear algebra, which asserts that the dimension of the domain of a linear map is the sum of its rank (the dimension of its image) and its nullity (the dimension of its kernel).

Given here  A be a 4 x 4 matrix and let λ be an eigenvalue of multiplicity 3 and rank 1, then by rank nullity theorem we have

    Rank(A-λI) + Nullity((A-λI) =4

⇒dimN(N-λI) = Nullity(A-λI)

⇒dimN(N-λI) = 4 - Rank(A-λI)

⇒dimN(N-λI)  = 4-1

⇒dimN(N-λI) = 3

Therefore 3 linearly independent eigenvectors belong to eigenvalue λ. Since λ is an eigenvalue of multiplicity 3, this ensures that there is a different eigenvalue different from λ. Along with 3 linearly independent eigenvectors in the eigenspace of λ, this gives us 4 linearly independent eigenvectors in the matrix A. Now we An n × n matrix A is diagonalizable if and only if A has n linearly independent eigenvectors. Thus A is nondefective

Hence, matrix A is not defective.

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Answer: Pythagorean triplets.

Step-by-step explanation:

not sure but this is the triangle that helps at all.

The students corresponding to those 200 numbers would beasked to participate in the survey.

What is corresponding ?

Having or participating in the same relationship (such as kind, degree, position, correspondence, or function) especially with regard to the same or like wholes (such as geometric figures or sets) corresponding parts of similar triangles. : related, accompanying.

Have given,

a) The administrators could number an alphabetical list of students from 1 to 2,500.Then use a random number generator from a calculator or computer to generate 200 unique random numbers from 1 to2,500.(if you don’t say “unique”, then say “ignoring repeats”)The students corresponding to those 200 numbers would beasked to participate in the survey.

b) One advantage is that stratified random sampling guarantees that each of the school-level strata will have some representation, because it is possible that a simple random sample would miss one or more of the strata completely.(NOTE: It is NOT sufficient to say that a stratified sample “makes it MORELIKELY that all school-levels are represented in the sample”… the student must state that stratifying by school level GUARANTEES or ENSURES that all school levels are represented in the sample.)

The students corresponding to those 200 numbers would beasked to participate in the survey.

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The answers are a) FR = 365 N b) u = 70.8° d and c) (MR)O = 2364 N m (counterclockwise)

When an object is subject to several forces, the resultant force is the force that alone produces the same acceleration as all those forces.

Given is a figure, we need to find equivalent resultant force and couple moment at point O

Equivalent Resultant Force And Couple Moment At O.

+→ (FR)x = ΣFx; (FR)x = 600 cos 60° - 455(12 / 13)

= -120 N = 120 N ←

+ ↑ (FR)y = ΣFy; (FR)y = 455(5/13) - 600 sin 60° = -344.62 N = 344.62 N ↓

As indicated in Fig (attached)

a) FR = √F(R)x²+F(R)y²

= √2120² + 344.62² = 364.91 N = 365 N

And

b) θ = tan-1{(FR)y / (FR)x}

= tan-1 {344.62/120}

= 70.80°

Also,

c) a+(MR)O = ΣMO; (MR)O = 455(12/13)(2) + 600 cos 60° (0.75) + 600 sin 60° (2.5)

= 2364.04 N m

= 2364 N m (counterclockwise)

Hence, The answers are a) FR = 365 N b) u = 70.8° d and c) (MR)O = 2364 N m (counterclockwise)

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Ss, variance and the standard deviation for the population of scores is 2.83 and 8 respectively

What is standard deviation and variance?

Standard deviation is a measure of the distribution of statistical data, whereas variance is a measure of how data points differ from the mean. The fundamental distinction between the two is that although the variance is expressed in squared units, the standard deviation is expressed in the same units as the data's mean.

Given,

SS = 40

Variance = 10

Standard Deviation = 3.16

Using Population Variance Formula :

= [tex]\frac{1}{n}[/tex]∑( x-xbar)²  where i is 1

For the complete solution see the attachment of table

sum ( x - x bar)² = 40

so, variance = 40/5

= 8

standard deviation = [tex]\sqrt{8}[/tex]

= 2.83

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Answer:  2x-4

Step-by-step explanation:

Answer:

solution

you must multiply a difference of x and 2 which is. >{x-2}

mathematical

4 x {x-2}

The point on the line 3x + y = 8 that is closest to the point (-3, 1) is (1.8, 2.6).

Quadratic equations are equations of the form a x² + b x + c = 0 where a, b and c are real numbers.

Given line is,

3x + y = 8 ⇒ y = -3x + 8

So we have any point (x, -3x + 8).

We have to find a point (x, -3x + 8) such that distance of this point from (-3, 1) is minimum.

Distance between (-3, 1) and (x, -3x + 8) = √[(x - -3)² + (-3x + 8 - 1)²]

                                                                  = √[(x + 3)² + (-3x + 7)²]

                                                                  = √(x² + 6x + 9 + 9x² - 42x + 49)

                                                                  = √(10x² - 36x + 58)

So the distance between (-3, 1) and (x, -3x + 8) is √(10x² - 36x + 58) should be minimum.

We minimize the function f(x) = 10x² - 36x + 58.

A quadratic function represents the equation of a parabola.

Coefficient of x² is positive, so parabola opens upward. So we will be having the minimum value.

Minimum value at the point x = -b / 2a for the quadratic equation a x² + b x + c.

Minimum value is at x = - (-36) / (2 × 10) = 36/20 = 9/5 = 1.8.

To find the y coordinate,

y = -3x + 8 = 2.6

So the required point is (1.8, 2.6).

Hence the point on the line closest to the point (-3, 1) is (1.8, 2.6)

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The Equation of line is y= 16.1x + 210. 8.

The approximate price by 2025 is 452.3.

A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. Therefore, it is possible to write the change in y coordinate with respect to the change in x coordinate as,

m = Δy/Δx where, m is the slope

Given:

The points are (1, 226.9) and (4, 275.2).

So, Slope for line

m = ( 275.2- 226.9)/( 4-1)

m = 48.3/ 3

m= 16.1

Now, using the slope- intercept form

y= mx+ b

y = 16.1x + b

Now, x= 1 and y= 226.9

By, y = 16.1 + x

226.9 = 16.1(1)+ b

b= 210.8

So, the equation of line is y= 16.1x + 210. 8

Now,  x is the number of years since 2010 and by 2025

x= 2025 - 2010 = 15

Then, the approximate price by 2025

y= 16.1(15) + 210.8

y= 452.3

Hence, the approximate price by 2025 is 452.3.

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Answer: 177.8

Step-by-step explanation: To find the percent increase, we have to use this formula:

New value-old value/ old value x 100

So, following this formula, we would do 25-9, which, is 16, divided by 9. That would be 1.777... So now let's round that to 1.78, so 1.78 x 100 = 177.8. I hope this helped.

Answer:

1. A(t) = 65t + 700

2.B(t) = 40t + 900

3. High School A and High School B will both have 1,220 students in the 8th year

Step-by-step explanation:

1. The equation for the number of students in High School A represents a linear function.

⭐ What is a linear function?

Let's write the equation for High School A in the [tex]y = mx+b[/tex] format, known as slope-intercept form:

∴ High School A: [tex]y = 65x + 700[/tex]

2. Let's write the equation for High School B in the [tex]y = mx + b[/tex] format, known as slope-intercept form:

∴ High School B: [tex]y = 40x + 900[/tex]

3. To find at what year High School A and High School B will have the same number of students, we need to solve a system of linear equations.

⭐What is a system of linear equations?

For this problem, let's set both linear equations equal to each other to see at what point will the high school populations be the same.

[tex]A(t) = B(t)[/tex]

[tex]65t + 700 = 40t + 900[/tex]

[tex]25t = 200[/tex]

[tex]t = 8[/tex]

Now we know that in the 8th year, High School A will have the same population as High School B.

We need to find what the population will be in year 8.

Thus, substitute the value of t into one of the functions and solve.

I am choosing to substitute t into A(t), but you can also do B(t).

[tex]A(8) = 65(8) + 700[/tex]

[tex]A(8) = 520 + 700[/tex]

[tex]A(8) = 1,220[/tex]

⚠️!!! CAUTION !!! ⚠️

Some people may stop at this point and write that in the 8th year, both high schools will have a population of 1,220 students.

However, you should also substitute 8 into the other function you didn't substitute it into to make sure that 8 is correct.

[tex]B(8) = 40(8) + 900[/tex]

[tex]B(8) = 320 + 900[/tex]

[tex]B(8) = 1,220[/tex]

∴ In the 8th year, both high schools will have a population of 1,220 students.

The maximum height of the firework is; 387.78 ft

The time for which the firework is in the air before it explodes is; 1 second

We are given the function;

h = -(500/9)t² + (1000/3)t + 10

where;

h is height after time of t seconds

At height of zero, the firework would either be about to launch or when it has come down.

Thus, let us set h = 0 to find the times.

0 = -(500/9)t² + (1000/3)t + 10

Using quadratic equation calculator, we have;

t ≈ 2 seconds

Now the  firework explodes at the highest point which will be the mid point of where the launching started and the endpoint where it stopped.

This means time at midpoint = (0 + 2)/2 = 1 sec

It explodes after 1 second.

Thus maximum height at this time is;

h = -(500/9)(1)² + (1000/3)(1) + 10

h = 387.78 ft

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Answer:

1

Step-by-step explanation:

A)

[tex]( \sqrt{3 } - \sqrt{2} )( \sqrt{3} + \sqrt{2} )( \sqrt{5 } - \sqrt{4} )( \sqrt{5} + \sqrt{4} )....[/tex]

using difference of two squares

[tex]( \sqrt{a} + \sqrt{b} )(\sqrt{a} - \sqrt{b} ) = a - b[/tex]

we can rewrite the A) to 1×1×1×1.... so the answer would be 1

Answer:

x=5

Step-by-step explanation:

(Not sure how I was supposed to do the model..so I ended up doing it this way..)

3x-5=10

Add 5 on both sides and then you get

3x=15

divide both sides by 3 and then you get

x=5

(Hopefully you can see my model even if it's just a little...)
For the model I drew 3 rectangles and put an x inside each one of them. for the -5, I drew 5 squares with a minus symbol/sign inside. And then I put an equal sign beside and I drew 10 squares with nothing inside but you can draw positive signs in it to show that it's positive..

So basically mines was

3 rectangles with x inside -5 squares with - inside = 10 squares

Answer:

Step-by-step explanation:

Answer:

  see the attachment for a graph

Step-by-step explanation:

You seem to want a graph of the inequalities ...

The equations of the boundary lines are given by replacing the inequality symbol with an equal sign:

These are graphed in the usual way. It is often convenient to find the y-intercept, then use the slope to locate other points on the line.

y = -3/2x -2

  The y-intercept is (0, -2). The line has a rise/run of -3/2, so goes down 3 units for each 2 to the right. Another point on the line is (2, -5).

y = 1/2x +6

  The y-intercept is (0, 6). The line has a rise/run of 1/2, so goes up 1 unit for each 2 to the right. Another point on the line is (2, 7).

When the "or equal to" symbol (≤ or ≥) is used, the boundary line is solid. When the "or equal to" case is not part of the solution, the boundary line is dashed.

The line with negative slope through (0, -2) is solid; the line with positive slope through (0, 6) is dashed.

All you need to determine shading is a variable with a positive coefficient, and the inequality symbol.

  y ≤ . . . . . tells you shading is below the solid line

  y > . . . . . tells you shading is above the dashed line

We notice x has a positive coefficient in the second inequality, so we could determine shading from ...

  > x . . . . . tells you shading is left of the line (where x values are less than those on the line)

Of course, you can rearrange the inequality so a variable of interest has a positive coefficient. For example, we could add 3/2x to the first inequality to get ...

  3/2x + y ≤ -2

Then, looking at the x-variable, we see ...

  x ≤ . . . . . tells you shading is to the left of the line

Answer:

See attachment.

Step-by-step explanation:

When graphing inequalities:

Treat the inequalities as equations (swap the inequality sign for an equals sign) to find two points on the line to help draw the lines.

Inequality 1

[tex]y \leq -\dfrac{3}{2}x-2[/tex]

[tex]\begin{aligned}x=0 \implies y&=-\dfrac{3}{2}(0)-2\\y&=-2\end{aligned}[/tex]

[tex]\begin{aligned}x=2 \implies y&=-\dfrac{3}{2}(2)-2\\y&=-5\end{aligned}[/tex]

Plot the points (0, -2) and (2, -5).

Draw a solid straight line through the points.

Shade under the line.

Inequality 2

[tex]y > \dfrac{1}{2}x+6[/tex]

[tex]\begin{aligned}x=0 \implies y&=\dfrac{1}{2}(0)+6\\y&=6\end{aligned}[/tex]

[tex]\begin{aligned}x=4 \implies y&=\dfrac{1}{2}(4)+6\\y&=8\end{aligned}[/tex]

Plot the points (0, 6) and (4, 8).

Draw a dashed straight line through the points.

Shade above the line.

The solution to the two inequalities is the overlap of the shaded parts.