|x-(-12)| if x>-12


ill give brainlyest if corect

Answer:

x=6

Step-by-step explanation:

Answer:

x=6

Step-by-step explanation:

[tex]{3}^{4x} = {3}^{3( x+ 2)} [/tex]

4x = 3(x + 2)

4x = 3x + 6

4x - 3x = 6

x = 6

I don't think its possible to do this... you have to have 2 equations

Answer:

the distance between the points is 9.84885780 and so on so if you round to the nearest tenth it would be 9.8 :)

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

the y axis is the axis going up and down, so the reflection would be on the other side of the axis.

Answer:

Step-by-step explanation:

6) Number of sides = n = 7

Sum of all the sides of the mentioned polygon = (n - 2)*180 = (7-2)*180 = 5 *180

                            = 900

x + 125 + 119 + 117 +145+133 +140 = 900

x + 779 = 900

      x = 900 - 779

      x = 121

7) Number of sides = n = 5

Sum of all the sides of the mentioned polygon = (n - 2)*180

     = 3 *180 = 540

90 + 9x - 6 + 3x +23 + 95 + 7x- 4 = 540

90 - 6 + 23 + 95 - 4 + 9x + 3x + 7x = 540

198 + 19x = 540

         19x = 540 - 198

        19x = 342

            x = 342/19

          x = 18

8) Number of sides = n = 8

Sum of all the sides of the mentioned polygon = (n - 2)*180

    = 6*180

    = 1080

This is a regular polygon (All sides are equal). so all the angles are equal.

One angle = 1080 ÷ 8 = 135

16x +23 = 135

       16x = 135 - 23

      16x = 112

         x = 112/16

     x  = 7

Answer:

Lateral area:

Surface area:

Answer:  498.96 cm³

Lateral area:

Surface area:

A = πr(r + l) = 3.24*7(7 + 15) = 498.96 cm³

Answer:

8x+2

Step-by-step explanation:

I think that's right I hope it is

The area of the quadrilateral is (x² + 9x + 14).

Given is a quadrilateral with height equal to (x+7) and the base is (x+2), we need to find the area of the quadrilateral,

So, to find the area of a quadrilateral, we need to know the lengths of both the height and the base.

In this case, the height is given as (x+7) and the base is given as (x+2).

The formula to find the area of a quadrilateral is:

Area = (base × height)

Let's substitute the given values into the formula and solve for the area:

Area = [(x+2) × (x+7)]

To simplify the expression, let's expand the brackets:

Area = (x² + 7x + 2x + 14)

= (x² + 9x + 14)

So, the area of the quadrilateral is (x² + 9x + 14).

Learn more about Areas click;

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#SPJ6

Answer:

it is 24inches

Step-by-step explanation:

33/11=3

3x8=24

Answer:

a₃₁

Step-by-step explanation:

The terms have a common difference between consecutive terms, that is

d = 84 - 87 = 81 - 84 = - 3

This indicates the sequence is arithmetic with nth term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 87 and d = - 3 , then

[tex]a_{n}[/tex] = 87 - 3(n - 1) = 87 - 3n + 3 = 90 - 3n

To find when [tex]a_{n}[/tex] < 0 , solve

90 - 3n < 0 ( subtract 90 from both sides )

- 3n < - 90

Divide both sides by - 3, reversing the symbol as a result of dividing by a negative quantity, then

n > 30

Thus the 31st term will be the first negative term

Answer:

C=25 (vertically opposite angle)

b=150 (linear pair)

d=150(vertically opposite angle)

Step-by-step explanation:

pls mark BRAINLIEST

Answer:

The rotation is 270 degrees counterclockwise

Step-by-step explanation:

Given

See attachment

Required

Degrees of rotation

From the question, the rotation is counterclockwise

Using point B and B' as points of reference.

[tex]B =(2,5)[/tex]

[tex]B' =(5,-2)[/tex]

The rule that supports the above is: rotation by 270 degrees counterclockwise.

Because the rule is:

[tex](x,y) ==>(y,-x)[/tex]

Answer: 91

is that a x or multiply?

Answer:

4,52

Step-by-step explanation:

32+5x=y

pls let me know is it was right

if it was pls give brainlest

Answer:

[tex]ED = 26[/tex]

[tex]CF = 13[/tex]

[tex]m \overset{\huge\frown}{ED} = 136[/tex]

[tex]m \overset{\huge\frown}{HD} = 68[/tex]

[tex]m \overset{\huge\frown}{CE} =88[/tex]

Step-by-step explanation:

Given

[tex]JG = JF[/tex]

[tex]GD = 13[/tex]

[tex]m \overset{\huge\frown}{CD} = 136[/tex]

See attachment for circle

Solving (a): Length ED

Line JD divides ED into two equal parts, EG and DG.

So:

[tex]ED = EG + GD[/tex]

[tex]ED = GD + GD[/tex]

[tex]ED = 13 + 13[/tex]

[tex]ED = 26[/tex]

Solving (b): Length CF

CF is a reflection of EG.

So:

[tex]CF = EG[/tex]

[tex]EG = GD = 13[/tex]

So:

[tex]CF = 13[/tex]

Solving (c): [tex]m \overset{\huge\frown}{ED}[/tex]

Since ED = CD;

Then:

[tex]m \overset{\huge\frown}{ED} = m \overset{\huge\frown}{CD}[/tex]

So:

[tex]m \overset{\huge\frown}{ED} = 136[/tex]

Solving (d): [tex]m \overset{\huge\frown}{HD}[/tex]

Line HF divides CD to 2 equal parts

So:

[tex]m \overset{\huge\frown}{HD} = \frac{1}{2} * m \overset{\huge\frown}{CD}[/tex]

[tex]m \overset{\huge\frown}{HD} = \frac{1}{2} * 136[/tex]

[tex]m \overset{\huge\frown}{HD} = 68[/tex]

Solving (e): [tex]m \overset{\huge\frown}{CE}[/tex]

[tex]m \overset{\huge\frown}{CE}[/tex] is a minor arc while [tex]m \overset{\huge\frown}{ED} = 136[/tex] + [tex]m \overset{\huge\frown}{CD} = 136[/tex] are the major arcs.

So:

[tex]m \overset{\huge\frown}{CE} + m \overset{\huge\frown}{ED} + m \overset{\huge\frown}{CD}= 360[/tex]

[tex]m \overset{\huge\frown}{CE} + 136+136= 360[/tex]

Collect like terms

[tex]m \overset{\huge\frown}{CE} =- 136-136+ 360[/tex]

[tex]m \overset{\huge\frown}{CE} =88[/tex]

Following are the calculated value " [tex]ED=26, CF=13\ , m \widehat{ED}=136^{\circ}\ , m \widehat{HD}=68^{\circ}\ , m \widehat{CE}=88^{\circ}\\\\[/tex]", and its complete calculation can be defined as follows:

[tex]\bold{JG=JF,GD=13,} \\\\ m \widehat{CD}=136^{\circ}\\\\[/tex]

When

[tex]m \widehat{CD}= m \widehat{ED}\\\\m \widehat{ED} = 136^{\circ}[/tex]

[tex]HJ \perp CD \\\\IJ \perp ED\\\\[/tex]

SO,

[tex]CF = FD \\\\EG=ED \\\\[/tex]

[tex]m \widehat{HD} = m \widehat{CH} = \frac{1}{2} m \widehat{CD}\\\\[/tex]

[tex]CF=13\\\\ ED = 13 \times 2 =26 \\\\ m \widehat{HD} = \frac{1}{2}\ m \widehat{CD} = 136^{\circ} \div 2 = 68^{\circ}\\\\m \widehat{CE} = 360^{\circ} -136^{\circ} - 136^{\circ} = 88^{\circ}\\\\[/tex]

Using the Vertical theorem and Theorem of the length of tangent to calculate the value:

[tex]ED=26\\\\CF=13\\\\m \widehat{ED}=136^{\circ}\\\\m \widehat{HD}=68^{\circ}\\\\m \widehat{CE}=88^{\circ}\\\\[/tex]

Note:

The given question is incomplete that's why we defined the question in the attached file and then solve it.

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Answer:

‏‏‎ ‎

Step-by-step explanation:

#1 - they look cool

#2 - they can swim

#3 - they eat fish

Answer:

None. There can't be any dirt in it because it's a hole.

Step-by-step explanation:

Answer:

1) Part A

The function that models the situation is P = 8,300·(1 - 0.12)ⁿ

Part B

2626 people

Part C

1575 people

2) Part A

The function that models the situation is A = 342.000·(1 - 0.06)ⁿ

Part B

The value of the hose in 2025 is approximately $208,472.6

Part C

The value of the hose in 2032 is approximately $135,189.8

Step-by-step explanation:

1) Part A

The given parameters are;

Martianville population in 2012, P₀ = 8,300 people

The percentage annual decrease in the population, r = -12% = -0.12

The formula for the growth of a population is presented as follows;

P = P₀·(1 + r)ⁿ

Where;

P = The population amount at a later time

P₀ = The initial amount of the population

r = The rate of the population growth

n = The number of years

Therefore;

The function that models the situation is P = 8,300·(1 - 0.12)ⁿ

Part B

The population that will attend Martianville in 9 years is given as follows;

P₉ = 8,300 × (1 + (-0.12))⁹ = 8,300 × (1 - 0.12)⁹ ≈ 2626.77

Therefore, by rounding down to the next whole person, the population that will attend Martianville in 9 years, P₉ = 2626 people

Part C

The population that will attend Martianville in 13 years is given as follows;

P₁₃ = 8,300 × (1 - 0.12)¹³ ≈ 1575 people

2) Part A

The price at which the house was bought, A₀ = $342,000

The rate of decrease of the value of the house = 6% therefore, r = -0.06

The function that models the situation is presented as follows;

A = A₀·(1 + r)ⁿ

Therefore;

The function that models the situation is A = 342.000·(1 - 0.06)ⁿ

Part B

The number of years between 2025 and 2017 = 2025 - 2017 = 8 years

The value of the hose in 2025, A₂₀₂₅ = 342.000·(1 - 0.06)⁸ = 208,472.576981

The value of the hose in 2025, A₂₀₂₅ ≈ $208,472.6

Part C

The number of years between 2032 and 2017 = 2032 - 2017 = 15 years

The value of the hose in 2032, A₂₀₃₂ = 342.000·(1 - 0.06)¹⁵ = 135,189.795176

The value of the hose in 2025, A₂₀₃₂ ≈ $135,189.8

Step-by-step explanation:

m = y2-y1/X2-X1

slope intercept equation is: y=Mx+b

The slope is based on the formula m and from there pick any points then do the forumla m to find the slope. Anything that have 0 as the X is b which is the y intercept.

Your answer would be

Slope: 2

y-intercept: 7

Answer: y=2x+7

Answer:

B. C. E.

Explanation:

In answer B, 4b means four of that variable, so you would add them all together, same goes with answer C. In answer E, you would use the "multiply by the reciprocal" rule, which basically means to keep the b as it is, change division to multiplication, and flip [tex]\frac{1}{4}[/tex].

Answer:

C

Step-by-step explanation:

p-2>6

add 2 both sides

p >8

p can only be greater than 8, and not equal to it, so the circle is open

Answer:

M = 12.5

Step-by-step explanation:

Simple,

2 times 12.5 is 25

4 times 12.5 is 50

6 times 12.5 is 75

8 times 12.5 is 100

The "m" is just a variable. Kinda like a question mark.

Answer:

D. x = 7

Step-by-step explanation:

Midsegment of a trapezium = ½(sum of the lengths of the parallel bases) => Trapezoid midsegment theorem

Thus:

QR = ½(NO + MP)

QR = 14

NO = 8

MP = 2x + 6

Plug in the values into the equation

14 = ½(8 + 2x + 6)

14 × 2 = ½(8 + 2x + 6)×2

28 = 8 + 2x + 6

28 = 14 + 2x

28 - 14 = 14 + 2x - 14

14 = 2x

14/2 = 2x/2

7 = x

x = 7

Answer:

x ≈ 2879.4 m

Step-by-step explanation:

Measure of ∠DAC = 10°

Measure of ∠DAB = 90°

Measure of ∠BAC = 90° - 10° = 80°

By applying cosine rule in ΔABC,

cos(80°) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

              = [tex]\frac{AB}{AC}[/tex]

0.17365 = [tex]\frac{500}{x}[/tex]

x = [tex]\frac{500}{0.17365}[/tex]

x = 2879.36

x ≈ 2879.4 m

Answer:

I drew the graph

I hope this helps you