You have an assignment due in 2 hours, 30 minutes (150 minutes total). The assignment has 25 problems for you to complete. If you have not started yet and spend the same amount of time on each problem, how much time can you spend on each problem and complete all 25 problems in time?

Create and solve a linear inequality to determine how much time you can spend on each problem.

What does your solution from part (a) represent/mean?

PLEASE HELP !!!!!!!!!!!!!!!!!!!

Answer:

43.

Step-by-step explanation:

Follow PEMDAS (Parentheses, exponents, multiply, divide, add, subtract). First you do 8-4 which is 4, then you multiply 4 by 4 which is 16 since you multiply next, then you add 27 to 16 which then gets you to 43.

Answer:

32 cartons

Step-by-step explanation:

Total sets needed

48 + 43 + 46 + 50 = 187

Cartons needed

187 / 6 = 31 1/6

need 32 cartons

Answer:

32 cartons

Step-by-step explanation:

add up all of the students = 187

divide by 6 = 187/6 = 31.16

round = 32 cartons

Answer:

sub duplicate ratio of

hope it helps

Answer:

4.5 cm

Step-by-step explanation:

KL = LM as triangle is isosceles

LM = KM as LF = FM = KN = NM, so the triangle is equilateral

EF ║ NM as LE⊥EF and LN⊥NM

EF is half the midsegment as ∠KLN ≅ ∠MLN, and LN is angle bisector of ∠KLM

Midsegment is half the side length, and all sides are 18 cm.

EF = 1/2(1/2*18) = 4.5 cm

Answer:

OA. 81

Step-by-step explanation:

A composite number is a positive integer that can be formed by multiplying two smaller positive integers.

81 = 9 x 9

81 = 3 x 27

Answer:

300 watermelons

Step-by-step explanation:

3:2 ratio

3 is water melons and 2 is mangoes.

200 mangoes were purchased.

200/2=100

The unit rate is 100, so multiply 3 by 100, which is 300.

So Jack bought 300 watermelons, and 298 of which will be devoured by yours truly.

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hope it helps

Answer:

The mass of Element X will reach 62 grams in 7.0 years.

Step-by-step explanation:

We can find the time of decay of Element X by using the exponential decay equation:

[tex] \frac{dm}{dt} = -\lambda t [/tex]

The solution of the above equation is:

[tex]m_{(t)} = m_{0}e^{-\lambda t}[/tex]     (1)

Where:  

t: is the time =?

λ: is the decay constant                                                                                        

[tex]m_{(t)}[/tex]: is the mass at time t = 62 grams

[tex]m_{0}[/tex]: is the initial mass = 90 grams

First, we need to calculate λ

[tex] \lambda = \frac{ln(2)}{t_{1/2}} [/tex]   (2)    

Where [tex]t_{1/2}[/tex] is the half-life = 13 years

By entering equation (2) into (1) and solving for "t" we have:

[tex]\frac{m_{(t)}}{m_{0}} = e^{-\frac{ln(2)}{t_{1/2}}*t}[/tex]    

[tex]ln(\frac{m_{(t)}}{m_{0}}) = -\frac{ln(2)}{t_{1/2}}*t[/tex]      

[tex]t = -ln(\frac{m_{(t)}}{m_{0}})(\frac{t_{1/2}}{ln(2)}) = -ln(\frac{62}{90})(\frac{13}{ln(2)}) = 7.0 y[/tex]  

Therefore, the mass of Element X will reach 62 grams in 7.0 years.

I hope it helps you!

Answer:

88

Step-by-step explanation:

10a-9=14a-25

10a-14a=-25+9

-4a=-16

a=4

10(4)-9+14(4)-25+6(4)+2

40-9+56-25+24+2

88

Answer: 8 feet below sea level is higher

Step-by-step explanation:

Answer: 13/4

Step-by-step explanation: it was 3.25 and that as a fraction is 13/4

3/4 + ( 1/3 × 6 ) + 1/2 =

3/4 + 2/4 + ( 2 ) =

3 + 2/4 + 8/4 =

5/4 + 8/4 =

5 + 8/4 =

13/4

Answer:

c

Step-by-step explanation:

Interquartile range or IQR is the range of the "box" in the graph. So we have 54 and 36 so we subtract 54-36.

So we get 18.

Answer:

Right skewed

Step-by-step explanation:

The shape of a distribution could be classed based on the position of the peak and position of the tails formed by the distribution. A distribution is described as being Symmetric if the peak is situated at the middle of the distribution with the tails being evenly spread to the right and left of the peak.

When the peak of the distribution shifts either to the left of right, then we have a skewed distribution. A distribution is said to be right skewed if it has a longer tail to the right while it is left skewed if the loner tail is to the left of the distribution.

The distribution Given above, the tail is longer to the right with the peak in the left. Hence we have a right skewed or positively skewed distribution

Answer:

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55

55 divided by 10 = 5.5 around 5

Add all your numbers

Divide by the many numbers there are, go by the exact value or estimate if needed.

Answer:

x=110˚

Step-by-step explanation:

We need to first find the other degree inside the triangle

first add 45˚ and 65˚

which is 110˚

subtract 110˚ with 180˚

which is 70˚

So we find x since a straight line is 180˚

subtract 70 and 180

which is 110˚

Hoped I helped!

Answer:

110 degrees

Step-by-step explanation:

A triangle is 180 degrees. So if the missing angle is 70, and 70+x=180 then x=110

[tex]1\frac{1}{2}[/tex] [tex]batches[/tex]

➛➛➛➛➛

[tex]\frac{1/2}{1} =\frac{3/4}{x}[/tex]

[tex]\frac{1}{2} =\frac{3}{4x}[/tex]

[tex]cross~multiply[/tex]

[tex]4x=2(3)[/tex]

[tex]\frac{4x}{4} =\frac{6}{4}[/tex]

[tex]x=\frac{3}{2} =1\frac{1}{2}[/tex]

Answer:

[tex](g + f)(2) = \sqrt 3 - 3[/tex]

[tex](\frac{f}{g})(-1) = 0[/tex]

[tex](g + f)(-1) = \sqrt{15}[/tex]

[tex](g * f)(2) = -3\sqrt 3[/tex]

Step-by-step explanation:

Given

[tex]f(x) =1 - x^2[/tex]

[tex]g(x) = \sqrt{11 - 4x[/tex]

See attachment

Solving (a): (g + f)(2)

This is calculated as:

[tex](g + f)(2) = g(2) + f(2)[/tex]

Calculate g(2) and f(2)

[tex]g(2) \to \sqrt{11 - 4 * 2} = \sqrt{3}[/tex]

[tex]f(2) = 1 - 2^2 = -3[/tex]

So:

[tex](g + f)(2) = g(2) + f(2)[/tex]

[tex](g + f)(2) = \sqrt 3 - 3[/tex]

Solving (b): [tex](\frac{f}{g})(-1)[/tex]

This is calculated as:

[tex](\frac{f}{g})(-1) = \frac{f(-1)}{g(-1)}[/tex]

Calculate f(-1) and g(-1)

[tex]f(-1) = 1 - (-1)^2 = 0[/tex]

So:

[tex](\frac{f}{g})(-1) = \frac{f(-1)}{g(-1)}[/tex]

[tex](\frac{f}{g})(-1) = \frac{0}{g(-1)}[/tex]

[tex](\frac{f}{g})(-1) = 0[/tex]

Solving (c): (g - f)(-1)

This is calculated as:

[tex](g + f)(-1) = g(-1) - f(-1)[/tex]

Calculate g(-1) and f(-1)

[tex]g(-1) = \sqrt{11 - 4 * -1} = \sqrt{15}[/tex]

[tex]f(-1) = 1 - (-1)^2 = 0[/tex]

So:

[tex](g + f)(-1) = g(-1) - f(-1)[/tex]

[tex](g + f)(-1) = \sqrt{15} - 0[/tex]

[tex](g + f)(-1) = \sqrt{15}[/tex]

Solving (d): (g * f)(2)

This is calculated as:

[tex](g * f)(2) = g(2) * f(2)[/tex]

Calculate g(2) and f(2)

[tex]g(2) \to \sqrt{11 - 4 * 2} = \sqrt{3}[/tex]

[tex]f(2) = 1 - 2^2 = -3[/tex]

So:

[tex](g * f)(2) = g(2) * f(2)[/tex]

[tex](g * f)(2) = \sqrt 3 * -3[/tex]

[tex](g * f)(2) = -3\sqrt 3[/tex]

Answer: A would be your answer.

Step-by-step explanation: Internal conflict is when you have a problem with yourself and this means your not intercating with others.

Answer:

The 1st step in evaluating the expression is doing the equation in the paranthesis. PEMDAS states we do the paranthesis 1st.

Answer:

I'm not 100% sure but I think its A

Answer:

∆ADE ≈ ∆ DCF

I hope this helps

Answer: f(x)=x^(2)+14x+40

Answer:

x=9

Step-by-step explanation:

Pretty self explanatory.

Answer:

95 square units

Step-by-step explanation:

Area of a triangle formula:

A = 0.5bh

Given:

b = 19

h = 10

Work:

A = 0.5bh

A = 0.5(19)(10)

A = 9.5(10)

A = 95

Step-by-step explanation:

1*-2=-2, -2*-2=4, -2*4=-8, -8*-32=256

Answer:

AA

Step-by-step explanation:

AA

Answer:

15+ 8d

After d day,she has read 15 +8d pages

Answer:

150.8 m³

48π m³

Step-by-step explanation:

V = πr²h/3

V = π · 4² · 9/3

150.8 m³

Answer:

15, 96, 2, 9, 12.

Another accepted answer is -5-i, but if your teacher wants only one answer, then I'd go for 5+i

======================================================

Work Shown:

[tex]\sqrt{24+10i} = a+bi\\\\\left(\sqrt{24+10i}\right)^2 = (a+bi)^2\\\\24+10i = a^2+2abi+b^2i^2\\\\24+10i = a^2+2abi+b^2(-1)\\\\24+10i = a^2+2abi-b^2\\\\24+10i = (a^2-b^2)+(2ab)i\\\\[/tex]

Equating terms, we have this system

[tex]\begin{cases}24 = a^2-b^2\ \text{.... real terms}\\10 = 2ab\ \text{.... imaginary terms}\end{cases}[/tex]

Solve the second equation for b to get b = 5/a

Plug that into the first equation to solve for 'a'

[tex]24 = a^2-b^2\\\\24 = a^2-\left(\frac{5}{a}\right)^2\\\\24 = a^2-\frac{25}{a^2}\\\\24a^2 = a^4-25\\\\0 = a^4-24a^2-25\\\\a^4-24a^2-25 = 0\\\\(a^2-25)(a^2+1) = 0\\\\(a-5)(a+5)(a^2+1) = 0\\\\[/tex]

Setting each factor equal to zero would lead to...

We're told that 'a' is a real number, so we ignore the solutions "a = i and a = -i". The only possible solutions are a = 5 and a = -5

If a = 5, then,

b = 5/a = 5/5 = 1

So

[tex]\sqrt{24+10i} = a+bi = 5+1i = 5+i[/tex]

or in short,

[tex]\sqrt{24+10i} = 5+i[/tex]

-----------------

If a = -5, then b = 5/a = 5/(-5) = -1

So it's very possible that we could also say

[tex]\sqrt{24+10i} = -5-i\\\\[/tex]

If you wanted to combine the two we would use the plus/minus notation like so

[tex]\sqrt{24+10i} = \pm(5+i)\\\\[/tex]

This is due to (5+i)^2 and (-5-i)^2 both having the same result of 24+10i. Hence the plus/minus. If your teacher wants one answer only, then I'd go for 5+i, as we could consider it a "principal" square root in a sense.