Answer:
1) 392 joules
2) 625,000 joules
3) 156,800 joules
Explanation:
Gravitational potential energy = mgh. m = mass in kg, g = acceleration due to gravity and h = height in meters.
Kinetic energy = 1/2(m)(v)^2, m = mass in kg, v = velocity in meters per second
1) P.E = 2 x 9.8 x 20 = 392 joules
2) K.E = 1/2 x 2000 x (25)^2 = 625,000 joules
3) P.E = 80 x 9.8 x 200 = 156,800 joules
Answer:
[tex]1)\:392\:\text{J}\:(400\:\text{J with one significant figure)},\\2)\:625,000\:\text{J}\:(600,000\:\text{J with one significant figure)},\\3)\:156,800\:\text{J}\:(200,000\:\text{J with one significant figure)},[/tex]
Explanation:
1. The potential energy of an object is given by [tex]PE=mgh[/tex]. Substituting given values, we have:
[tex]PE=2\cdot 9.8\cdot 20=\boxed{392\:\text{J}}[/tex]
2. The kinetic energy of an object is given by [tex]KE=\frac{1}{2}mv^2[/tex]. Substituting given values, we have:
[tex]KE=\frac{1}{2}\cdot 2000\cdot 25^2 =\boxed{625,000\: \text{J}}[/tex]
3. 1. The potential energy of an object is given by [tex]PE=mgh[/tex]. Substituting given values, we have:
[tex]PE=80\cdot 9.8\cdot 200=\boxed{156,800\:\text{J}}[/tex]
180 J of work is done when lifting a box up to a shelf that is 3 m high. What is the mass of the box?
Explanation:
Work done= MGH
180=m×10×3
180/30=m
m=6kg
what's the temperature 32°F in degrees Celsius
Answer:
0 degrees Celsius
Explanation:
Please please help me please please help
Answer:
Materials like air, water, and clear glass are called transparent. When light encounters transparent materials, almost all of it passes directly through them. ... When light strikes translucent materials, only some of the light passes through them. The light does not pass directly through the materials.
Explanation:
P Flag question
Matt, shown below, is able to move
the large truck because
Please help I’ll mark you brainliest
Answer:
Percentage:
Rr = 50% because it's 2/4 (for both or 25% each since you have them separate)
rr = also 50%, because it's also 2/4.
Phenotype:
Rr = heterozygous
rr = "hozygous" recessive
In addition, RR is "hozygous" dominant
Explanation:
They said the hozygous is a swearword LOL.
P Flag question
Matt, shown below, is able to move
the large truck because
Answer:
he has more pushing force than the truck there for pushing it forword.
Explanation:
Please help!!!!!! Motion and Forces
Why does one side of the Moon’s surface always remain much colder than the other side?
A) The colder side of the Moon has a cloud cover over it.
B) The colder side of the Moon is entirely covered with ice.
C) The colder side of the Moon always faces away from the Sun.
D) The colder side of the Moon has many high-altitude mountains.
Answer:
it's C
Explanation:
The colder side of the Moon always faces away from the Sun.
A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.400 rev/s. What is its angular velocity (in rev/s) after a 22.0 kg child gets onto it by grabbing its outer edge
Answer:
The final angular velocity is rev/s is 0.293 rev/s.
Explanation:
Given;
mass of the merry-go-round, m₁ = 120 kg
radius of the merry-go-round, r = 1.8 m
initial angular velocity, ω = 0.4 rev/s
mass of the child, m₂ = 22 kg
Apply the principle of conservation angular momentum to determine the final angular velocity;
[tex]I_i= I_f\\\\\frac{1}{2} m_1r^2 \omega _i = \frac{1}{2} m_1r^2 \omega _f + m_2r^2 \omega _f\\\\ \frac{1}{2} m_1r^2 \omega _i =( \frac{1}{2} m_1r^2 + m_2r^2 )\omega _f\\\\\omega _f = \frac{ \frac{1}{2} m_1r^2 \omega _i}{\frac{1}{2} m_1r^2 + m_2r^2} \\\\\omega _f = \frac{ \frac{1}{2} m_1 \omega _i}{\frac{1}{2} m_1 + m_2}\\\\\omega _f = \frac{0.5 \ \times \ 120\ kg \ \times \ 0.4\ rev/s}{0.5 \ \times 120\ kg \ \ + \ \ 22 \ kg} \\\\\omega _f = 0.293 \ rev/s\\[/tex]
Therefore, the final angular velocity is rev/s is 0.293 rev/s.
What is the light speed formula?
If ' c ' is the speed of light, then the formula for it is . . .
c = 299,792,458 meters per second
A force is described as?
Explanation:
A push or pull of an objecr
[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]
A force is described as push or pull on an object.
ThanksHope it helps.What is the length of a string with a mass of 2.5 kg, with a
tension of 20 N, if the speed of wave on the string is 2 m/s?
a 0.8 m
b 0.4 m
C 0.5 m
d 1.0 m
e 0.1 m
The chart lists the masses of four planets.
Planetary Masses
Planet
Mass
Neptune
1.02 x 1026
Uranus
8.68 x 1025
Mars
6.42 x 1023
Venus
4.87 X 1024
According to evidence that supports Einstein's general
theory of relativity, which list shows the planets that
would cause curvature in space-time from the least
amount of curvature to the greatest?
O Mars, Venus, Uranus, Neptune
O Neptune, Uranus, Venus, Mars
O Neptune, Uranus, Mars, Venus
O Venus, Mars, Uranus, Neptune
Answer:
I think it's A
Explanation:
It's definitely not B on edge
The correct option for the given question about Einstein's general
theory of relativity is Option A) Mars, Venus, Uranus, Neptune.
What is the Einstein's general theory of relativity?Albert Einstein established that the rules of physics apply to all non-accelerating observers in his theory of special relativity.He also demonstrated that the speed of light in a vacuum remains constant regardless of the velocity of an observer.The theory may be used to anticipate everything and describes how objects behave in space and time. For instance: that if there are black holes or not, if Gravity can causes light to bend, The way Mercury behaves when it is in orbit and many more interesting things.As a Conclusion, we can state that the planets who would cause curvature in space time from the least amount of curvature to the greatest will be in order Mars, Venus, Uranus, Neptune.
Learn more about Einstein's general theory of relativity here:
https://brainly.com/question/13311063
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What is the answer to this problem
Answer:
Material that allow the electrons to move freely in order to produce a current
Please mark as brainliest if answer is right
Have a great day, be safe and healthy
Thank u
XD
A soccer ball with mass 0.450 kg is initially moving with speed 2.20 m/s. A soccer player kicks the ball, exerting a constant force of magnitude 38.0 N in the same direction as the ball's motion. Over what distance must her foot be in contact with the ball to increase the ball's speed to 6.00m/s?
Answer:
0.187 m
Explanation:
We'll begin by calculating the acceleration of the ball. This can be obtained as follow:
Mass (m) = 0.450 Kg
Force (F) = 38 N
Acceleration (a) =?
F = m × a
38 = 0.450 × a
Divide both side by 0.450
a = 38 / 0.450
a = 84.44 m/s²
Finally, we shall determine the distance. This can be obtained as follow:
Initial velocity (u) = 2.20 m/s.
Final velocity (v) = 6 m/s
Acceleration (a) = 84.44 m/s²
Distance (s) =?
v² = u² + 2as
6² = 2.2² + (2 × 84.44 × s)
36 = 4.4 + 168.88s
Collect like terms
36 – 4.84 = 168.88s
31.52 = 168.88s
Divide both side by 168.88
s = 31.52 / 168.88
s = 0.187 m
Thus, the distance is 0.187 m
plz help.me guys
6xy – 12x y + 15x3y? – 3x?y? by 3x²y
Answer:
2xy-12xy+15x3y?-3x?y?by3l 3x2y
What is the answer to question 4
In order to make it all the way from the opening to the detector, a wave has to travel through air, glass, water, plastic, and vacuum.
-- The siren and the tuning fork are sounds.
-- Sound cannot travel through vacuum.
-- That knocks out choices B, C, and D.
The answer is A.
Note: Making a big exception here. We don't do test questions on Brainly. That would be cheating. Don't let me catch you doing it again.
how does light travel across the universe to earth?
A flat circular coil of wire having 400 turns and diameter 6.0 cm carries a current of 7.0 A. It is placed in a magnetic field of with the plane of the coil making an angle of 30° with the magnetic field. What is the magnitude of the magnetic torque on the coil?
Answer:
6.8 N.m
Explanation:
The computation of the magnitude of the magnetic torque on the coil is given below:
Given that
n = 400
d = 6.0 cm
Current is I = 7.0 A
Angle is [tex]\theta[/tex] = 30 degree
Now
We know that
the magnitude of the magnetic torque is
= nIABsin[tex]\theta[/tex]
= (400) (7.0) π ÷ 4 (0.06m)^2 sin(90° - 30°)
As
[tex]\theta[/tex] = (90° - Ф)
= (400) (7.0) π ÷ 4 (0.06m)^2 sin 60°
= 6.8 N.m
You are asked to design a spring that will give a 1070 kg satellite a speed of 3.75 m/s relative to an orbiting space shuttle. Your spring is to give the satellite a maximum acceleration of 5.00g. The spring's mass, the recoil kinetic energy of the shuttle, and changes in gravitational potential energy will all be negligible.
(a) What must the force constant of the spring be?
(b) What distance must the spring be compressed?
Answer:
[tex]380697.33\ \text{N/m}[/tex]
[tex]0.138\ \text{m}[/tex]
Explanation:
m = Mass rocket = 1070 kg
v = Velocity of rocket = 3.75 m/s
a = Acceleration of rocket = 5g
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
The energy balance of the system is given by
[tex]\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\Rightarrow kx=\dfrac{mv^2}{x}\\\Rightarrow kx=\dfrac{1070\times 3.75^2}{x}\\\Rightarrow kx=\dfrac{7250}{x}[/tex]
The force balance of the system is given by
[tex]ma=kx\\\Rightarrow m5g=\dfrac{7250}{x}\\\Rightarrow x=\dfrac{7250}{1070\times 5\times 9.81}\\\Rightarrow x=0.138\ \text{m}[/tex]
The distance the spring must be compressed is [tex]0.138\ \text{m}[/tex]
[tex]k=\dfrac{7250}{x^2}\\\Rightarrow k=\dfrac{7250}{0.138^2}\\\Rightarrow k=380697.33\ \text{N/m}[/tex]
The force constant of the spring is [tex]380697.33\ \text{N/m}[/tex].
A wall in a house contains a single window. The window consists of a single pane of glass whose area is 0.10 m2 and whose thickness is 8 mm. Treat the wall as a slab of the insulating material Styrofoam whose area and thickness are 11 m2 and 0.15 m, respectively. Heat is lost via conduction through the wall and the window. The temperature difference between the inside and outside is the same for the wall and the window. Of the total heat lost by the wall and the window, what is the percentage lost by the window
Answer:
the percentage of heat lost by the window is 93.18%
Explanation:
Given the data in the question;
Area of glass [tex]A_{glass[/tex] = 0.10 m²
Thickness of glass [tex]t_{glass[/tex] = 8 mm = 0.008 m
Area of Styrofoam [tex]A_{styrofoam[/tex] = 11 m²
Thickness of Styrofoam [tex]t_{styrofoam[/tex] = 0.15 m
we know that;
Thermal conductivity of glass [tex]k_{glass[/tex] = 0.80 J/smC°
Thermal conductivity of Styrofoam [tex]k_{styrofoam[/tex] = 0.010 J/smC°
Now, temperature difference between outside and inside the walls and window is ΔT
So, In time t, heat lost due to conduction in the window will be;
[tex]Q_{glass[/tex] = [[tex]k_{glass[/tex] × [tex]A_{glass[/tex] × ΔTt] / [tex]t_{glass[/tex]
we substitute
[tex]Q_{glass[/tex] = [ 0.80 × 0.10 × (ΔT)t] / 0.008
[tex]Q_{glass[/tex] = [ 0.80 × 0.10 × (ΔT)t] / 0.008
[tex]Q_{glass[/tex] = 10(ΔT)t J
Also, the heat lost due to conduction in the wall be;
[tex]Q_{styrofoam[/tex] = [[tex]k_{styrofoam[/tex] × [tex]A_{styrofoam[/tex] × ΔTt] / [tex]t_{styrofoam[/tex]
we substitute
[tex]Q_{styrofoam[/tex] = [ 0.010 × 11 × ΔTt] / 0.15
[tex]Q_{styrofoam[/tex] = 0.7333(ΔT)t J
Now, Net heat lost in the wall and window is;
Q = [tex]Q_{glass[/tex] + [tex]Q_{styrofoam[/tex]
Q = 10(ΔT)t J + 0.7333(ΔT)t J
Q = 10.7333(ΔT)t J
So, the percentage of heat lost by the windows will be;
% of heat lost = [tex]Q_{glass[/tex] / Q
= 10(ΔT)t J / 10.7333(ΔT)t J
= 0.93167
= ( 0.93167 × 100 )%
= 93.18%
Therefore, the percentage of heat lost by the window is 93.18%
HELP PLEASEEEEEEEEEEEE
If a magnet can cut into a small piece , each piece will remain a magnet ? Explain this phenomenon
yes ,each piece will remain a magnet because the small pieces will cut into north and south
A playground merry-go-round with a radius of 2.0 m and a rotational inertia of 100 kg m2 is rotating at 3.0 rad/s. A child with a mass of 22 kg jumps onto the edge of the merry-go-round, traveling radially inward. What is the new angular speed of the merry-go-round
Answer:
The new angular speed of the merry-go-round = [tex]1.6rad/sec[/tex]
Explanation:
From angular momentum conservation
[tex]Iw_1 = (I + mr^2)w_2\\\\3*100 = (100 + 22*2^2)w_2\\\\300 = (100 + 88)w_2\\\\w_2 = \frac{300}{188}\\\\w_2 = 1.6rad/sec[/tex]
For more information on angular momentum, visit
https://brainly.com/subject/physics
Which of the following is an example
of a measure of the
mass of an object?
A. 65 centimeters
B. 65 grams
C. 65 light-years
D. 65 feet
Answer:
Grams
Explanation:
Because that is the definition
Answer:
65 grams
Explanation:
4. A girl sits on a tire that is attached to a tree limb by a rope 2.10 m in length. The girl's father pushes her with a tangential speed of 2.50 m/s. If the magnitude of the force that maintains her is 88.0 N, What is the girl's mass? Predictions On JOT 自 DLL Fa F11
Answer:
the answer is M=29.6kg
Explanation:
your welcome:)
What happens when sulfur reacts with potassium?
O A. Electrons move from the sulfur atoms to the potassium atoms.
B. Electrons become delocalized among the atoms.
O C. Electrons are shared between the potassium atoms and the sulfur
atoms.
O D. Electrons move from the potassium atoms to the sulfur atoms.
Answer: Electrons move from the potassium atoms to the sulfur atoms.
Explanation: 2 K + S ⇒ 2 K^+ + S^2- . Usually metals donor electrons to non-metals
What is the correct calculation for voltage if the resistance is 3 ohms and the current is 4 amps?
3 x 4 = 12 volts
3 + 4 = 7 volts
4= 3 = 1.33 volts
4-3 = 1 volt
Answer:
iek
Explanation:
Answer:
the answer to your questions above is 3 x 4 = 12 volts
Explanation:
Voltage = Current × Resistance
what heat transfer occurs when warm air rises
Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where low frequency sound is originating from. (a) Suppose a low-frequency sound source is placed to the right of a person, whose ears are approximately 18 cm apart, and the speed of sound generated is 340 m/s. How long is the interval between when the sound arrives at the right ear and the sound arrives at the left ear
Answer:
Δt = 5.29 x 10⁻⁴ s = 0.529 ms
Explanation:
The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.
[tex]\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}[/tex]
where,
Δt = required time interval = ?
Δs = distance between ears = 18 cm = 0.18 m
v = speed of sound = 340 m/s
Therefore,
[tex]\Delta t = \frac{0.18\ m}{340\ m/s}[/tex]
Δt = 5.29 x 10⁻⁴ s = 0.529 ms