A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?
Answers
Answer:
35N
Explanation:
force=mass×gravity
the mass is 5 and the gravity is 7 therefore:
force=7×5
=35N
I hope this helps
Related Questions
Wire coils spinning between two magnets will produce …?
A: cold
B : electricity
C: chemicals
D: Steam
Answers
Answer:
B
Explanation:
I don't know but its b
Magnetic fields can be used to make electricity
Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current. Electricity generators essentially convert kinetic energy (the energy of motion) into electrical energy.
What would be the acceleration of a block sliding down an inclined plane that makes an angle of 45° with the horizontal if the coefficient of sliding friction between two surfaces in 0.3? 141
Ans: 4.95 m/sec?
Answers
Answer:
unfortunately we have not received a reply to the park yet but
Explanation:
mohamedz and he had killed him
An object weighs 15 N in air and 13 N when submerged in mineral spirits, which has a density of 788 kg/m3. Determine the density of the object
Answers
The density of the object is 5911.94 kg/m³
An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.
The buoyancy = weight of the object - weight in water
= 15 N - 13N
= 2 N
The buoyancy force can also be determined by using the expressed:
[tex]\mathbf{F_B = Volume (V) \times density ( \rho) \times g}[/tex]
[tex]\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }[/tex]
[tex]\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}[/tex]
volume (v) = 2.589 × 10⁻⁴m³
Recall that:
The mass of an object can be estimated by using the formula:
Weight = mass × gravity
mass = Weight / gravity
mass = 15/9.8
mass = 1.5306 kg
The density of the object can now be calculated using the relation
Density = mass/volume
Density = 1.5306 kg / 2.589 × 10⁻⁴m³
Density = 5911.94 kg/m³
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Please help! Question is attached.
Answers
Answer:
a. 6
b. 6 m/s²
c. 300 m to the right
d. 30 secs
Explanation:
slope = rise /run
60-0/10-0
= 6
b. slope = acceleration = 6 m/s²
c. d=ut+1/2at²
t=10 (segment A last for 10 secs)
u - initial velocity = 0
so d = 0(10)+1/2*6*10²
=300 m
What is the difference between a low tide and a high tide
Answers
Answer:
High water level during a tide is called High tide.
Low water level during a tide is called Low tide.
In a car race, the average speed of the car was 90 km/hr where the total
covered distance was 450 km.
1. Calculate the average speed of the car in SI unit.
Answers
Explanation:
The speedometer of a motor car showed the following speeds in km per hour at the ends of successive intervals of 3 secs. 38.9, 52.8, 64.4. 73.6, 80.9, 86.1, 90.0, 92.5 Plot the velocity – time graph in convenient units and find from the graph, (a) The distance covered while the speed increased from 80
State a hypothesis about your estimated daily water use.
Answers
Answer
Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.
Explanation:
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Answers
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
[tex]dl'=3.621*10^{-4}m[/tex]
From the question we are told
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Generally the equation for copper cylinder is mathematically given as
[tex]dl=\frac{Flo}{yA}[/tex]
[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=1.19064778*10^-^4[/tex]
Generally the equation for brass cylinder is mathematically given as
[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=2.43*10^{-4}[/tex]
Therefore Total change in length
[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]
[tex]dl'=3.621*10^{-4}m[/tex]
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A 0.5kg ball falls from a building that Is 50m high. how much kinetic energy will it have when it has fallen half way to the ground?
Answers
vfinal = root 2ad
v = root (2*9.81m/s^2*25)
v = 69.367175234 m/s
Kinetic energy = 1/2mv^2
Kinetic energy = 1/2 * (69.367175234 m/s^s^2
Ek = 2405.9025 Joules
The horizontal movement of air from an area of high pressure to an area of lower pressure
options:
wind
weather
heat
conduction
Answers
Answer:
Explanation:
A wind is the horizontal movement of air from an area of high pressure to an area of lower pressure. Winds are caused by differences in air pressure. Most differences in air pressure are caused by unequal heating of the atmosphere
Football players boots have spikes at their sole
Give reason
Answers
Answer:
it prevents slipping on the grass while playing
Answer:
to keep their grip on the ground so they won't fall
using the methos of dimensions derive an expression for the centripetal force f acting on a particle of mass m mivingv with velocity v in a circle of radius r?
Answers
According to the Question:
[tex]\footnotesize\implies F \propto [m]^x [v]^y [r]^z[/tex]
[tex]\footnotesize\implies F =k [m]^x [v]^y [r]^z \:...(i)[/tex]
K = Dimensionless ConstantNow, substituting Dimensions of each physical quantity in equation (I):
[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M^1L^0T^0]^x [M^0L^1T^{-1}]^y [M^0L^1T^0]^z[/tex]
[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M]^x [L]^{y + z} [T]^{ - y}[/tex]
On comparing the powers of LHS and RHS:
[tex]\implies \bf x = 1[/tex]
[tex]\implies - y = - 2[/tex]
[tex] \implies \bf y = 2[/tex]
[tex]\implies y + z = 1[/tex]
[tex]\implies z = 1 - 2[/tex]
[tex]\implies \bf z = - 1[/tex]
[tex]\footnotesize\implies F = [m]^x [v]^y [r]^z[/tex]
[tex]\footnotesize\implies F = [m]^1 [v]^2 [r]^{ - 1}[/tex]
[tex]\implies\footnotesize \underline{ \boxed{ \bf \red{ F = \frac{m {v}^{2} }{r} }}}[/tex]
A girl pushes her little brother on his sled with a force of 300 N for 750 m.
Answers
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
If force F, volume V and density D are taken as fundamental quantities, then the representation of pressure P will be
Answers
Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]
Pressure is related to Force, Volume and Density thus :
[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]
Using dimensional analysis :
Pressure, P = ML¯¹T¯²Substituting the dimension into the relation :
[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]
[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]
Equating the power ;
a + c = 1 - - - (1)
a + 3b - 3c = - 1 - - - (2)
-2a = - 2
a = - 2/-2
a = 1
From (1)
1 + c = 1
c = 1 - 1 = 0
c = 0
From (2) :
1 + 3b - 3(0) = - 1
1 + 3b = - 1
3b = - 2
b = - 2/3
Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]
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The representation of pressure is:
[tex]P=FV^{-\frac{2}{3} }[/tex]
Given that:
Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:
[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]
Hence:-
2 = -2a
a = 1
a + c = 1
1 + c = 1
c = 0
a + 3b - 3c = -1
1 + 3b - 3(0) = -1
3b = -2b = -2/3
Hence the representation of pressure is:
[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]
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6. Explain the importance of the law of conservation of mass.
Answers
Answer:
According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.
Explanation:
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NO LINKS! What are the definitions of initial horizontal velocity and initial vertical velocity? Please help! This like is my 10th time asking this question because many people have been scamming me...
Answers
Answer:
Additionally, the initial horizontal velocity may be calculated by measuring the diameter d of the ball and dividing the result by the amount of time t required for the ball to pass across the photogate. Vo = d/t is the formula.
Initial vertical velocity is the vertical component of the initial velocity: v 0 y = sin 0 sin 0 = (30.0 m/s) sin 45° = 21.2 m/s
Explanation:
Hope it helps:)
given. force of 88N and an acceleration of 4 m/s 2 what is the mass?
Answers
It is given that Force, F = 88N
Acceleration, a=4 m/s 2
28
If it takes 1,697 m to stop a car initially moving at 46 m/s, what distance is required to stop a car moving at a quarter
of the initial speed under the same conditions?
Answers
Answer:
Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.
Explanation:
Let [tex]v[/tex] and [tex]u[/tex] denote the final and initial velocity of the vehicle ([tex]v = 0\; \rm m \cdot s^{-1}[/tex] since this vehicle has come to a stop.)Let [tex]a[/tex] denote the acceleration of the vehicle (a constant under the assumption.) Let [tex]x[/tex] denote the displacement of the vehicle.If the acceleration on this vehicle is constant, the SUVAT equations would apply:
[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].
Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:
[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].
Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.
If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:
[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].
A state government wants to increase the taxes on cigarettes to increase tax revenue. Because cigarettes are addictive, we would expect its demand to be: ______________
a. Elastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
b. Elastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
c. Inelastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
d. Inelastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
Answers
The demand of cigarette is elastic so the government's cigarette-tax revenues would rise with a tax increase.
The demand of cigarette is elastic because of the addiction the people can buy the cigarette even at high prices and the government's cigarette-tax revenues would rise.
The demand for cigarettes is unitary elastic (−1.06) means that a 1% increase in the price of cigarette would reduce its consumption by 1.06% so we can conclude that the demand of the cigarette is elastic and the government revenues increases.
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Guys plz i need those answers as soon as possible
Answers
9) a) formula = h(ρ)g by default g=9.8m/s²
Pressure = 2×1000×9.8 = 19600Pa
b)
I will give 100 Points, 5-stars, and Brainliest
Direct contact is necessary for which type of energy transfer?
A. Conduction
B. Sound Waves
C. Conduction
D. Convection
Answers
Answer:
Conduction
Explanation:
Because when a molecule is transferred to another molecule then this in going into direct contact
For example if we have a pan and it is boiling well the heat that is on the pan holder that stays in place and it won`t move anywhere else like there is Radiation and Convection but for this question the answer would be Conduction
A child sits on a rotating merry-go-round, 2.1 m from its center. If the speed of the child is 2.2 m/s, what is the minimum coefficient of static friction between the child and the merry-go-round that will prevent the child from slipping?
Answers
We have that the the minimum coefficient of static friction is mathematically given as
[tex]\mu= 0.235[/tex]
ForceGenerally the equation for the Force is mathematically given as
[tex]F=n\mu\\\\Where\\\\n = mg\\\\Given\\\\Fc = m(vt2/R)\\\\Therefore\\\\\mu = vt2/gR\\\\\mu = 2.22/(9.8(2.1)) \\\\[/tex]
[tex]\mu= 0.235[/tex]
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Hello everyone, I just want to know the formula to solve this problem:
What is the speed of sound at 62°C?
and how to solve this kind of problem? My brain isn't working.. :)
Answers
Answer:
367 m/sExplanation:
Use simplified formula:
[tex]v=331.3\sqrt{1+T/273.15}[/tex] , where T- temperature in Celsiusb. Ron bicycles forward with an acceleration of 2.1 m/s2. If he is applying a forward force of 195 N, what is his mass?
Answers
Answer:
92.86 kgExplanation:
lThe mass of an object given only it's force and acceleration can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question
f = 195 N
a = 2.1 m/s
We have
[tex]m = \frac{195}{2.1 } = 92.857142... \\ [/tex]
We have the final answer as
92.86 kgHope this helps you
what is potentiometer
Answers
Answer:
potentiometer is a device used to measure potential difference across the circuit
What is the centripetal force acting on a 1.5 kg mass moving in a circular path with a centripetal
acceleration of 18 m/s2
Answers
The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N
A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.
According to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.
The centripetal force is the external force at work here and It's the net force that propels the object in a circular motion.
Using the formula for calculating centripetal force:
[tex]\mathbf{F_c = mass (m) \times acceleration (a)}[/tex]
[tex]\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}[/tex]
[tex]\mathbf{F_c = 27 \ N}[/tex]
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In fish BB-blue, BW-blue with white stripes, WW-white. Cross a white fish with a fish with blue and white stripes. What is the probability of having white fish offspring?
Answers
Answer: Juvenile fish go through various stages between birth and adulthood. When they have developed to the point where they are capable of feeding themselves, the fish are called fry. When, in addition, they have developed scales and working fins, the transition to a juvenile fish is complete and it is called a fingerling.
If 40 N force is exerted by a box covering 2 metre square area, calculate pressure.
Answers
[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]
[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]
[tex] \sf \huge \red {\dag} Given[/tex]
[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]
[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]
We know that the formula of Pressure is
[tex]\sf \longmapsto \: Force/Area[/tex]
Let's start.
Put the values[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]
[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]
[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]
A 30 kg boy stands on rough horizontal ground. The coefficient of
static friction,
us is 0.8. The present static friction between the boy and the ground is
?
Answers
Answer:
0n
Explanation:
Of the Three elements listed, which element is NOT present in the mixture?
Element D
Element A
Element Z
Answers
Answer:
element ammmkkkv was a very good