Answer:
The answer is 120lbs
Explanation:
because the scale exerts enough force to equal out to 0 and since the person is putting 120lbs onto the scale it then pushes back enough force to keep them up
The upward force acting on the body is 534 N which is equal to 240 lbs in the upward direction, hence, option d is correct.
What is force?Force is an external agent acting on a body to change it from the state of motion or rest. There are various kind of forces namely, gravitational force, magnetic force, nuclear force etc.
Gravitational force is the force by which an object attracts other objects to its center of mass. Gravitational force depends on the mass of the object and the distance from the surface of earth.
The weight of the person is 120 lbs.
1 Kg = 2.2 lbs
120 lbs = 54.5 Kg.
The force acting on the body by their weight = mg = 54.5 Kg × 9. 8 m/s².
= 534 N.
Hence, 534 N is 240 lbs (534 /2.2 ) of force upward.
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which statement is correct about the effectiveness of carbon dating
Answer:
b
Explanation:
Statement is correct about the effectiveness of carbon dating is that It only works for organisms that died less than about 60,000 years ago.
What is carbon dating?Even though the plant or animal stops absorbing when it dies, the radioactive carbon it has stored keeps on degrading. Estimating how much is left over allows one to determine how long something has been dead.
The moss was determined to have been frozen for more than 1,500 years based on carbon dating. Now, if other evolutionary ways of dating are consistent with carbon dating, the scientists may have made a significant discovery. However, when used in isolation, carbon dating is at best unreliable and at worst, blatantly wrong.
Statement is correct about the effectiveness of carbon dating is that It only works for organisms that died less than about 60,000 years ago.
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Which choice is not an example of a molecule? O3 NCl3 F H2O2
Answer:
The answer is F
Explanation:
F stands for Fluorine, which is an element and consists of one atom.
Answer:
f
Explanation:
i took quiz
PLEASE HELP!!!!!!!!
Answer:
the is D
Explanation:
An action-reaction force pair
Answer:
An action-reaction force pair
On top of a 3 m tall shelf sits a lonely 4.5 kg toy snake. How much GPE does this snake have if the shelf is on Earth? (g = 9.8 m/s2
Answer:
hi
Explanation:
how r u
To crack a pecan, you apply a force of 55 N to the nutcracker. The nutcracker applies a force of 740 N to the pecan. What is the mechanical advantage of the nutcracker?
Answer:
Explanation:
mechanical advantage = output force / input force
= 740 N / 55 N
= 13.45
El extremo de una cuerda se mueve de tal manera que las partículas de la cuerda emplean 0.25 segundos para producir una vibración. ¿Cuál es el periodo? Y ¿Cuál es la frecuencia de la vibración producida
Responder:
T = 0.25 segundos
f = 4 Hz
Explicación:
Paso uno:
datos dados
se nos dice que las partículas tardan 0,25 segundos en completar una vibración
por lo tanto, el período es de 0,25 segundos
¿Qué es un período de vibración?
Un período T es el tiempo necesario para que un ciclo completo de vibración pase por un punto determinado.
la expresión para el período se da a continuación.
T = 1 / f
¿Cuál es la frecuencia de vibración?
Básicamente, se refiere a la frecuencia con la que ocurren las vibraciones.
la frecuencia es una tasa, se expresa como la inversa del período
f = 1 / T
t = 1 / 0.25
f = 4 Hz
Please help ill give you 30 points
Answer: 14 inches.
Explanation: The radius of this circle is 7 inches, so the diameter is 2(7) = 14 inches. The diameter is 14 inches.
which event is an example of melting?
Answer:
welding metal
Explanation:
what is a science book
Answer:
A book containing information on various types of science related topics.
Answer: a science book is a textbook you use for science.
I need help on this question
Answer:
the 3rd one im pretty sure
Explanation:
Answer:the answer is answer 3
Explanation:
Calculate the power of a crane if it lifts a load of 2400N through a height of 10m in 15 seconds.Also express the power in horse power.
Answer:
2.08 hpExplanation:
The power of the crane can be found by using the formula
[tex]p = \frac{f \times d}{t} \\ [/tex]
f is the Force
d is the distance
t is the time taken
From the question we have
[tex]p = \frac{2400 \times 10}{15} = \frac{24000}{15} \\ [/tex]
We have
power = 1600 W
But 1 W = 0.0013 hp
So 1600 = 2.08 hp
We have the final answer as
2.08 hpHope this helps you
surface?
What is the mass of an object that experiences a gravitational force of 700 N near the Earth's surface
Answer:
70kg
Explanation:
Given parameters:
Gravitational force = 700N
Unknown:
Mass of the person = ?
Solution:
The weight is gravitational force on the person and can be expressed as;
W = mg
m is the mass
g is the acceleration due to gravity = 10m/s²
So;
700 = m x 10
m = 70kg
how do pteropods get energy
Answer:
Pteropods are little mollusks (related to snails, slugs and squid) that drift around in ocean currents, feeding on nutrient-rich plankton. Their rich diet makes them delicious to many fish. Seals eat many fish, and sharks eat seals and fish, so there it is: not even 6 degrees of shark separation.
Explanation:
You are an astronomer on planet tirth, which orbits a distant star. it has recently been accepted that tirth is spherical in shape, though no one knows its size. one day, you learn that on the equinox your sun is directly overhead in the city of tyene, located 750 kilometers due north of you. on the equinox, you go outside in alectown and observe that the altitude of your sun is 87.0 ∘.
Answer:
The circumference of planet tirth is [tex]C = 90000 \ km[/tex]
Explanation:
From the question we are told that
The distance of tyene from the observer is [tex]d = 750 \ km[/tex]
The altitude of the sun from the equinox is [tex]\theta_s = 87.0^o[/tex]
Generally given that on the equinox your sun is directly overhead in the city of tyene , then the altitude of the tyene from the equinox is [tex]\theta_e = 90 ^o[/tex]
Generally the angular distance between tyene and the sun as observed from the equinox is mathematically represented as
[tex]\theta _d = \theta_e - \theta_s[/tex]
=> [tex]\theta _d = 90 -87[/tex]
=> [tex]\theta _d =3^o[/tex]
Generally the ratio of [tex]\theta _d =3^o[/tex] to [tex]360^o[/tex] which is the total angle in a circle is equal to the ratio of [tex]d = 750 \ km[/tex] to the circumference of the planet
So
[tex]\frac{\theta_d}{360} = \frac{750}{C}[/tex]
=> [tex]\frac{3}{360} = \frac{750}{C}[/tex]
=> [tex]C = 90000 \ km[/tex]
A 100 Watt lightbulb uses 360000 Joules ever hour. How many lightbulbs could be powered for one hour by the energy from the Hiroshima bomb?
Answer:
200 million electric light bulbs.
Explanation:
First, we must calculate the power of the electric bulb, for this, we use the following equation that relates the energy as a function of time.
[tex]P=E/t[/tex]
where:
P = power [W] (units of watts)
E = energy = 360000 [J] (units of Joules)
t = time = 1 [h] = 3600 [s]
[tex]P = 360000/3600\\P= 100[W][/tex]
In 1 hour 1 electric lightbulb produces 100 [W], now we need to know the amount of energy produced by the Hiroshima bomb. A search made by the internet give us the data of 20 [GW] or [Gigawatts].
We need to remember that 1 Giga = 1 x10⁹
Energy Hiroshima explosion= 20*10⁹[W]
Amount = (20x10⁹)/100
Amount = 200 x10⁶ [bulbs]
That is, we would need an amount of 200 million electric light bulbs.
a small asteroid of mass 125 kg is orbiting a planet that has a mass of 3.52x 10^13 what is the radial distance between the asteroid and the planet of the tangential velocity of the asteroid is 0.034m/s
Answer:
r = 2.031 x 10⁶ m = 2031 km
Explanation:
In order for the asteroid to orbit the planet, the centripetal force must be equal to the gravitational force between asteroid and planet:
Centripetal Force = Gravitational Force
mv²/r = GmM/r²
v² = GM/r
r = GM/v²
where,
r = radial distance = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Planet = 3.52 x 10¹³ kg
v = tangential speed = 0.034 m/s
Therefore,
r = (6.67 x 10⁻¹¹ N.m²/kg²)(3.52 x 10¹³ kg)/(0.034 m/s)²
r = 2.031 x 10⁶ m = 2031 km
Si unit of thermal conductivity is
Answer: Watts
Explanation: In the International System of Units (SI), thermal conductivity is measured in watts per meter-kelvin (W/(m•k)).
Un automóvil se mueve hacia el norte siguiendo una trayectoria rectilínea con una velocidad constante, recorre 195 Km cada 1.3 h. ¿Calcula la velocidad con que se mueve?
Answer:
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
Explanation:
La velocidad es una magnitud que expresa la relación entre el espacio recorrido por un objeto, el tiempo empleado para ello y su dirección.
Es decir, la velocidad se define como la relación que se establece entre la distancia recorrida y el tiempo transcurrido en el movimiento de un móvil.
Se puede calcular la magnitud de la velocidad utilizando la siguiente expresión:
[tex]velocidad=\frac{distancia}{tiempo}[/tex]
En este caso:
distancia= 195 kmtiempo= 1.3 hReemplazando:
[tex]velocidad=\frac{195 km}{1.3 h}[/tex]
Resolviendo:
velocidad=150 [tex]\frac{km}{h}[/tex]
La velocidad con la que se mueve el automóvil es 150 [tex]\frac{km}{h}[/tex]
Planet X has a magnetic field with strength 0.70 G in the southern direction. When a probe is placed 50 mm east of a vertical wire it measures a field of 0.50 G in the southern direction. What would a probe read if placed 20 mm east of the vertical wire?
Answer:
0.20 G
Explanation:
The given parameters are;
The magnetic field strength of planet X = 0.70 G
The location of a probe in relation to the vertical wire = 50 m
The measurement of a probe placed 50 mm east of a vertical wire = 0.50 G
The location of the probe = 20 mm east of the vertical wire
Based on the given parameter, the wire is a current carrying conductor with a magnetic field acting tangent to the magnetic field lines.
Given that the measured Earth magnetic field reduces, we have that the magnetic field of the wire cancels the magnetic field of the Earth
As the probe moves closer to the wire the measured magnetic field in the southern direction reduces
When the probe is placed 20 mm from the wire, the magnetic field reduces to 20/50 × 0.50 G = 0.20G
If you committed a crime, would it be easy for investigators to match this print to your records? Why or why not? Hint: how’s the quality of the lifted print? How rare is your pattern? (At least two sentences)
Answer:
This question is incomplete
Explanation:
This question is incomplete because of the absence of the picture of the print in question. However, when the quality of the print obtained from a crime scene is high/good, then this is a good/positive step in identification of a suspect. However, if the quality is bad, other options might need to be explored in addendum to the print obtained in identifying a suspect.
If the quality of the print is good enough to make a pattern, then another factor comes into play. If the pattern is a rare pattern or is not common, then it becomes easier to identify the suspect because there would be fewer people having that fingerprint and fewer people to deal with. Of the three major patterns of fingerprints (whorl, loop and arch), arch fingerprints are the least common.
different types of families and describe each
Answer:
there are many types of family but main is 2
Explanation:
1). joint family 2). nucleic family joint family has mother father grandfather grandmother uncle aunty children. and nucliec family has mother father and childrens
Answer: Childless family, Extended family, Step family, Grandparent family, Single parent family, and Nuclear family.
Explanation:
A rock is thrown upwards at 13.5 m/s. How long does it take to fall back to the ground?
What is the formula of Acceleration for mass and time
Answer:
a = m/t²
Explanation:
The Formula of Acceleration for mass and time
a = m/t²
where,
m = meter
t = time in (seconds)
The SI unit of acceleration is m/s² or ms⁻²
-TheUnknownScientist
Un auto se mueve con velocidad constante de 20 m/s y la mantiene durante 20 s. Después se le aplica una aceleración constante y aumenta su velocidad a 40 m/s, recorriendo durante el cambio de velocidad una distancia de 200 m ¿Cuál es el tiempo empleado en el recorrido total?
Answer:
26.67 s
Explanation:
v = Velocidad final = 40 m/s
u = Velocidad inicial = 20 m/s
[tex]t_1[/tex] = Tiempo inicial = 20 s
[tex]t_2[/tex] = Tiempo empleado durante la aceleración
a = Aceleración
s = Desplazamiento del automóvil durante la aceleración = 200 m
De las ecuaciones lineales de movimiento tenemos
[tex]v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{40^2-20^2}{2\times 200}\\\Rightarrow a=3\ \text{m/s}^2[/tex]
[tex]v=u+at_2\\\Rightarrow t_2=\dfrac{v-u}{a}\\\Rightarrow t_2=\dfrac{40-20}{3}\\\Rightarrow t_2=6.67\ \text{s}[/tex]
El tiempo necesario para acelerar es 6.67 s
El tiempo total necesario para toda la ruta es [tex]t=t_1+t_2=20+6.67=26.67\ \text{s}[/tex].
Which describes the positions on a horizontal number line?
Answer:
All points to the left of zero are negative numbers. All points to the right of the zero are positive numbers. Zero is generally considered the center of the number line since both positive and negative numbers (more specifically integers) are considered to go to infinity. (Negative infinity or positive infinity)
Explanation:
Whoops sorry I accidentally commented the first time
The diagram below shows a force of 5N acting on an object P at an angle of 30° to the horizontal.
By drawing appropriate lines on the diagram using a ruler to determine:
a.)The horizontal component of the 5N force.
b.)The vertical component of the 5N force .
Given :
The diagram below shows a force of 5N acting on an object P at an angle of 30° to the horizontal.
To Find :
By drawing appropriate lines on the diagram using a ruler to determine:
a.)The horizontal component of the 5N force.
b.)The vertical component of the 5N force.
Solution :
Horizontal component is given by :
=F cos θ
=5 cos 30°
= 5×0.866
= 4.33 N
Vertical component is given by :
= F sin θ
= 5 sin 30°
= 5×0.5
= 2.5 N
Therefore, horizontal and vertical component are 4.33 N and 2.5 N.
Hence, this is the required solution.
How does the law of conservation of mass apply to this reaction: C2H4 + O2 → 2H2O + 2CO2?
Answer:
The equation needs to be balanced. There are fewer oxygen atoms in the equation than hydrogen or carbon. ... There is an equal number of each element on both sides of the equation.
Explanation:
Which has the most momentum?
Select one:
A. 100 kg at rest
B. 20 kg at 2 m/s
C. 5 kg at 50 m/s
D. 10 kg at 5 m/s
Answer: C
Explanation:
A: 100kg*0m/s (obviously not answer)
B: 20kg*2m/s (=40)
C: 5kg*50m/s (=250, safe bet this one is it)
D: 10kg*5m/s (=50)
5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
To calculate momentum, we use the formula:
Momentum (p) = Mass (m) × Velocity (v)
Let's calculate the momentum for each option:
A. 100 kg at rest
Momentum = 100 kg × 0 m/s = 0 kg m/s
B. 20 kg at 2 m/s
Momentum = 20 kg × 2 m/s = 40 kg m/s
C. 5 kg at 50 m/s
Momentum = 5 kg × 50 m/s = 250 kg m/s
D. 10 kg at 5 m/s
Momentum = 10 kg × 5 m/s = 50 kg m/s
Therefore, 5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
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Zero is the freezing temperature of water on which temperature scale?
Kelvin
Fahrenheit
Pascal
Celsius
Answer:
Celsius. i think! I might be wrong
In the diagram below, a 10-kilogram ball is fired with a
velocity of 500 meters per second from a 1,000 kilogram
cannon. What is the recoil velocity of the cannon?
A. 5 m/s
B. B) 2 m/s
C. C) 10 m/s
D. D) 500 m/s
Answer:
A) 5m/s
Explanation:
Momentum of ball in one direction=momentum of cannon in other direction
mv = mv
(10)(500)=(1000)v
5000=1000v
∴v=5m/s
When a ball is fired with a velocity its momentum remains conserved. The recoil velocity of the cannon is 5m/s.
The velocity with which the cannon is pushed backwards after firing is called the recoil velocity.
The momentum remains conserved . So, according to the momentum conservation principle, initial momentum is equal to the final momentum.
Mu +mu=Mv +mv
where, M is the mass of cannon and m is the mass of ball.
u is the initial velocity and v is the final velocity.
10 kg ball is fired with a velocity of 500 meters per second from a 1,000 kg cannon.
mu = Mv
(10)(500)=(1000)v
5000=1000v
v=5m/s
Thus, the recoil velocity of the cannon is 5 m/s.
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