A student needs to dilute a 0.25 M Pb(NO3)2 solution to make 73.0 mL of 0.13 M Pb(NO3)2 . Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.25 M Pb(NO3)2 solution that is needed.

Answer:

B

Explanation:

Answer:

In an uncharged atom, the number of protons is always equal to the number of electrons. Apr 24, 2017

Explanation:

Neutron: An uncharged particle found in the nucleus of an atom.

There is only one stable atom that does not have neutrons. It is an isotope of the element hydrogen called protium. Protium, which contains a single proton and a single electron, is the simplest atom.

Explanation:

Cu + 2 AgNO3 → Cu(NO3)2 + 2 Ag

Cu is oxidized

Ag+ is reduced

Cu is the reducing agent

To solve such this we must know the concept of displacement reaction. The balanced reaction of silver nitrate with copper is of  displacement type of reaction.

AgNO[tex]_3[/tex] + Cu [tex]\rightarrow[/tex] Cu(NO[tex]_3[/tex])[tex]_2[/tex] + Ag

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, displacement reaction.

The reaction between silver nitrate and copper is example of displacement reaction. Copper displaces silver from silver nitrate. to form copper nitrate.

Therefore, the balanced equation is of displacement type of reaction.

AgNO[tex]_3[/tex] + Cu [tex]\rightarrow[/tex] Cu(NO[tex]_3[/tex])[tex]_2[/tex] + Ag

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Answer: I believe the answer is A. The order of amino acids in the protein.

Explanation:

Answer:

C(btw this could be wrong)

Explanation:

Answer:

B is the answer

Explanation:

Answer:What is the volume of 37% HCl?

If however you meant to say 0.025M and assuming you want to prepare 1L solution then the volume of 37% HCl needed should be= (1000 X 0.025X 36.5)/ (37X1.19X10)=2.07 mL diluted to 1 L using DI water. Good day. If you want 0.025 mole HCl solution, you should take a 2.09 ml of your acid.

Explanation:To prepare 5% solution from this acid; simply take 5 ml. of the acid and add it to 95 ml of distilled water.You get a 5%HCl solution. By the way, Hydrogen Chloride is the name designated to the gas evolved from HCl acid

To determine the volume of a 5% solution that can be made from 25 mL of HCl, we need to use the equation: C1V1 = C2V2

Where:

C1 = Initial concentration of HCl

V1 = Initial volume of HCl

C2 = Final concentration of the solution (5% or 0.05 in decimal form)

V2 = Final volume of the solution (unknown)

HCl stands for hydrochloric acid. It is a strong, highly corrosive acid that is commonly used in various industrial, laboratory, and chemical applications. In its pure form, hydrochloric acid is a colorless liquid with a pungent odor. It is composed of hydrogen (H) and chlorine (Cl) and is known for its acidic properties.

Let's plug in the known values:

C1 = 100% (since the initial HCl is undiluted)

V1 = 25 mL

C2 = 5% or 0.05

V2 = Unknown

Solving for V2:

C1V1 = C2V2

(1)(25 mL) = (0.05)(V2)

25 mL = 0.05V2

Divide both sides by 0.05 to isolate V2:

V2 = 25 mL / 0.05

V2 = 500 mL

Therefore, from 25 mL of HCl, you can make a 500 mL solution with a concentration of 5%.

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Answer:

Assuming that all of the oxygen is used up, 1.53×4111.53×411 or 0.556 moles of C2H3Br3 are required. Because there are only 0.286 moles of C2H3Br3 available, C2H3Br3 is the limiting reagent.

Limiting Reagent What is the limiting reagent if 76.4 grams of C2H3Br3 were reacted with 49.1 grams of O2? C2H3Br3 + 11O2 → 8CO2 + 6H2O + 6Br2 SOLUTION Using Approach 1: A. 76.4g × (1 mol/ 266.72 g) = 0.286 moles C2H3Br3 49.1g × (1 mole/ 32 g) = 1.53 moles O2 B.

Explanation:

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https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Map%3A_Introductory_Chemistry_(Tro)/08%3A_Quantities_in_Chemical_Reactions/8.04%3A_Limiting_Reactant_and_Theoretical_Yield

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Answer:

P₄ + 6 H₂ ⇒ 4 PH₃

Explanation:

Let's consider the unbalanced reaction that takes place when phosphorus reacts with hydrogen to form phosphine. This is a synthesis reaction.

P₄ + H₂ ⇒ PH₃

We will balance this reaction using the trial and error method. First, we will balance P atoms by multiplying PH₃ by 4.

P₄ + H₂ ⇒ 4 PH₃

Finally, we get the balanced equation by multiplying H₂ by 6.

P₄ + 6 H₂ ⇒ 4 PH₃

Answer:

strong Base Dissociation

Explanation:

Answer:

0.20 moles of Pb(CH3COO)4

Explanation:

89g Pb(CH3COO)4 x 1 mol Pb(CH3COO)4 / 443.376 g Pb(CH3COO)4

= 0.20 moles of Pb(CH3COO)4

One mole of lead acetate weighs 443.29 g. Then, 89 grams of lead acetate contains 0.20 moles of Pb (CH₃COO)₄.

One mole of a substance is its amount containing 6.02 × 10²³  atoms or molecules. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.

Similarly one mole of every compound contains 6.02 × 10²³  molecules. The mass of one mole of compound is called its molar mass. The number  of moles of the compound can be determined by dividing the given mass by molar mass.

Molar mass of lead acetate = 443.29 g/mol

given mass  = 89 grams

then , no.of moles = weight/molar mass

n = 89 g/ (443.29 g/mol) = 0.20 moles

Therefore, the number of moles of Pb (CH₃COO)₄ in 89 g is 0.20 moles.

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Answer:

Explanation:

correct me if im wrong

Answer:

There both true.

Explanation:

Hope this helps

Answer:

The first one is True

The second one is false

Explanation:

Answer:

See Explanation

Explanation:

When a constraint such as a change in temperature, concentration or pressure is imposed on a reaction system in equilibrium, the system will readjust itself in such a way as to annul the constraint. This readjustment occurs when the equilibrium position shifts towards the left or right in order to annul the constraint.

a. increasing the concentration of CO: When the concentration of CO is increased, the equilibrium position shifts to the right in order to annul the constraint. This means that more CO2 is produced in the system while the concentration of CO and O2 are decreased until equilibrium is reestablished.

b. decreasing the amount of O2: When the amount of O2 is decreased, the equilibrium position will shift to the left and more CO and O2 are produced while the concentration of CO2 decreases until equilibrium is reestablished.

c. decreasing the the volume of the system: When the volume of the system is decreased, the equilibrium position shifts towards the right hand side where there is less total volume. Hence the concentration of CO and O2 decreases while the concentration of CO2 increases.

Answer:

ch∪pαpi munαn0?

Explanation:

Answer:

E

Explanation:

The simple rule of thumb is that as the atomic or molar mass of an atom increases, the entropy increases. This means that more the mass more will be entropy.

The atomic mass of various elements is as follows

Ne = 20 g/mol

Xe = 131 g/mol

He = 4 g/mol

Ar = 40 g/mol

Kr = 84 g/mol

Therefore, the order of increasing entropy must be

He<Ne<Ar<Kr<Xe.

Hence, option E is the correct answer.

Explanation:

A matter can be present in different states like solid, liquid or gas. When we write a chemical equation then states of species involved are also mentioned.

This is because it tells in what state the reactants were present and in what state the products are then formed.

For example, [tex]H_{2}O_{2}(aq) \rightarrow H_{2}O(l) + O_{2}(g)[/tex]

Now here, (aq) means aqueous, (l) means liquid and (g) means gas.

So, these states denoted are necessary as it tells that [tex]H_{2}O_{2}[/tex] in aqueous state dissociates to give [tex]H_{2}O[/tex] in liquid state and [tex]O_{2}[/tex] in gaseous state.

Answer:

182

Explanation:

1 hectogram (hg) = 100 grams (g)

1.82 x 100 = 182

Answer: The mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.

Explanation:

Given: Mass of calcium carbonate = 45 g

Volume = [tex]100 cm^{3}[/tex]

Convert [tex]cm^{3}[/tex] into L as follows.

[tex]1 cm^{3} = 0.001 L\\100 cm^{3} = 100 cm^{3} \times \frac{0.001 L}{1 cm^{3}}\\= 0.1 L[/tex]

Moles of calcium carbonate (molar mass = 100 g/mol) is as follows.

[tex]No. of moles = \frac{45 g}{100 g/mol}\\= 0.45 mol[/tex]

Molarity is the number of moles of solute present in a liter of solution.

Hence, molarity (or mass concentration) of given solution is calculated as follows.

[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.45 mol}{0.1 L}\\= 0.045 M[/tex]

Thus, we can conclude that the mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.

Answer:

chlorine ~ 30%

zinc ~ 28%

oxygen ~ 41%

Explanation:

Answer:

Sis I think it happened with me but I am not able to remember if u want u can share if it happened with u

Answer:

???! huhhhjhhh no I speak English

Explanation:

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Answer:

vifucivud UKvi uiiijhhh

Answer: The new pressure is 1.34 atm.

Explanation:

Given: [tex]P_{1}[/tex] = 10.8 atm,         [tex]T_{1} = 118^{o}C[/tex]

[tex]P_{2}[/tex] = ?,                  [tex]T_{2} = 948^{o}C[/tex]

Formula used to calculate the new pressure is as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{10.8 atm}{118^{o}C} = \frac{P_{2}}{948^{o}C}\\P_{2} = 1.34 atm[/tex]

Thu, we can conclude that the new pressure is 1.34 atm.

Answer:

B. 50%

Explanation:

First we convert the given masses of the reactants into moles, using their respective molar masses:

0.893 moles of CO would react completely with (0.893 * 2) 1.786 moles of H₂. As there are more H₂ moles than that, H₂ is the reactant in excess and CO is the limiting reactant.

Now we calculate how many CH₃OH moles would have been formed if all CO would have been consumed:

Then we convert 0.893 moles of CH₃OH into grams, using its molar mass:

Finally we calculate the percent yield:

Answer:

0.0428 kg or 42.8 g

Explanation:

Applying,

Q = cmΔt.............. Equation 1

Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.

make m the subject of the equation above

m = Q/cΔt.................. Equation 2

From the question,

Given: Q = 428 J, Δt = 25 °C

Constant: c = 400 J/kg.°C

Substitute these values into equation 2

m = 428/(25×400)

m = 0.0428 kg

m = 42.8 g

Answer:

We often want to decrease the rates of certain reactions rather than speeding them up. For example, to prolong the shelf lives of certain foods, the chemical reactions by which they spoil must be slowed down.