El. A horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. How much work is done by the 40 - N force?

E2. A woman does 160 J of work to move a table 4 m across the floor. What is the magnitude of the force that the woman applied to the table if this force is applied in the horizontal direction?

E3. A force of 60 N used to push a chair across a room does 300 J of work. How far does the chair move in this process?

E4. A rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. A frictional force of 120 N opposes this motion.

a. What is the work done by the force applied by the rope?

b. What is the work done by the frictional force?

c. What is the total work done on the crate?​

El. A Horizontally Directed Force Of 40 N Is Used To Pull A Box A Distance Of 2.5 M Across A Tabletop.

Answers

Answer 1

The same formula of work can be applied to all the questions. The answers are:

E1. 100J

E2. 40N

E3. 5m

E4. a.) 360 J           b.) 240 J               c.) 120 J

El. If a horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. The formula to get the much work that will be done by the 40 - N force will be

Work done = force x distance

Work done = 40 x 2.5

Work done = 100 J

E2. If a woman does 160 J of work to move a table 4 m across the floor. We will use the same formula to calculate the magnitude of the force that the woman applied to the table assuming the force is applied in the horizontal direction.

Work done = force x distance

160 = 4F

F = 160/4

Force F = 40 N

E3. Given that a force of 60 N used to push a chair across a room does 300 J of work. Same formula to get how far the chair move in this process.

Work done = force x distance

300 = 60 x distance

distance = 300/60

Distance = 5 m

Therefore, the chair moved 5m away.

E4. Given that a rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. And a frictional force of 120 N opposes this motion.

a. The work done by the force applied by the rope can  be found by

W = F x S

W = 180 x 2

W = 360 J

b. What is the work done by the frictional force?

W = [tex]F_{r}[/tex] x s

W = 120 x 2

W = 240 J

c. What is the total work done on the crate?

W = (F - [tex]F_{r}[/tex]) x distance

Where  [tex]F_{r}[/tex]  = frictional force

Substitute all the parameters

W = (180 - 120) x 2

W = 60 x 2

W = 120 J

Learn more about work here: https://brainly.com/question/8119756


Related Questions

how to find velocity of center of mass before and after the collision

Answers

Hey there! I'll try to provide you with my best answer.

Answer: In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

the smallest division value of electronic balance​

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Answer:

0.1g to 0.0000001g hope it helps uu

what depth would a submarine have to submerge so that it would not be swayed by surface waves wwith a wavelength of 30 meters

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Answer:

Explanation:

ello

What is the difference between folk dance and ballroom dance

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Answer:

folk dancing is old music and ball room is young dancing

A passenger of mass 90kg is involved in a minor car crash. The car approaches a solid barrier at 32m/s. It crashes into the barrer and stops in 0.2s. Determine the impulse that must be applied to the car to bring it to rest

Answers

Answer:

I hope this helps:)

Explanation:

good luck:)

Help it’s multiple choice 11 through 15 please!

Answers

1. • Here, force of gravity on the block = 20 N.

• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]

• The coefficient

[tex] u_{k} = 0.4[/tex]

• Force of friction =

[tex]u_{k} \times \: normal \: \: \: force \\ = 0.4 \times 20N \\ = 8N[/tex]

• Hence, the force of sliding friction between the block and the ground is 8 N.

• So, it is option c. 8 N

2. The answer is option d. continue in the same direction with no change in speed.

We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.

3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.

Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.

So, 1 N = 1 Kg × 1 m/s^2.

4. It is d. not zero.

Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.

5. Force = 2 N

Acceleration of the object A = 2 m/s^2.

Acceleration of the object B = 1 m/s^2.

Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg

And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg

So, the mass of object B is greater than that of object A.

Hence, the answer is option c. Object B has more mass.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Which type of border shows the division between Sonora and Chihuahua?

National border
State border
Physical boundary
Natural boundary

Answers

The answer is the national border

A 78 N block is supported by a spring whose constant is 12 N/m. Calculate the elongation of the spring under this load.

a. 6.5 m

b. 1.5 m

c. 8.2 m

d. 7.2 m

Answers

Answer:

a 6.5 m

Explanation:

[tex]f = kx = > x = \frac{f}{k} = \frac{78}{12} = 6.5 m[/tex]

A hockey player hits a rubber puck from one side of the rink to the other. It has a mass of .170 kg, and is hit at an initial speed of 6 m/s. If the rink is 61 meters long, how fast is the puck moving when it hits the far wall?

Answers

By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s

Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:

mass m =  0.170 kg

initial speed u = 6 m/s.

Distance covered s = 61 m

To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V

To do this, let us first calculate the kinetic energy at which the ball move.

K.E = 1/2m[tex]U^{2}[/tex]

K.E = 1/2 x 0.17 x [tex]6^{2}[/tex]

K.E = 3.06 J

The work done on the ball is equal to the kinetic energy. That is,

W = K.E

But work done = Force x distance

F x S = K.E

F x 61 = 3.06

F = 3.06/61

F = 0.05 N

From here, we can calculate the acceleration of the ball from Newton second law

F = ma

0.05 = 0.17a

a = 0.05/0.17

a = 0.3 m/[tex]s^{2}[/tex]

To calculate the final velocity, let us use third equation of motion.

[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2as

[tex]V^{2}[/tex]  = [tex]6^{2}[/tex] + 2 x 0.3 x 61

[tex]V^{2}[/tex] = 36 + 36

[tex]V^{2}[/tex] = 72

V = [tex]\sqrt{72}[/tex]

V = 8.485 m/s

Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.

Learn more about dynamics here: https://brainly.com/question/402617

NEED HELP ASAP PLEASE
The drop time can be calculated as follows t = sqrt((2y)/g) where y is the vertical height of the table and g is the acceleration due to gravity (9.80 m/)How did the calculated drop time compare to the average of your measured drop times? Find the percent error using the following equation measured drop time - calculated drop time % 100 calculated drop time What factors might cause the differences?

Answers

did you end up getting the answer- im struggling

Answer:

I would think human error could cause differences like not pressing the stop watch on time.

Explanation:

A ball falling from a height of 5 m was caught at some height after being reflected off the floor. Find the magnitude of the movement of the ball. If the distance traveled is equal to 7 meters.

Answers

Answer:

3m

Explanation:

I can't make a drawing right know, but it's all around vectors. First of all the ball travels down 5 meters, so we have a vector pointing down, then it is reflected and travels 2 meters up. You have to sum the vectors so you obtain that the distance traveled is: 5-2 meters = 3m

assume that the hubble constant is 72 km/s/mpc. if a galaxy is 100mpc away, how fast is it moving away from us?

Answers

The galaxy is 7200 km/s moving away from us.

A Hubble is a large telescope in space.

The question can be solved using the formula below

⇒ Formula

v = Cd........................ Equation 1

⇒ Where:

v = Speed of the galaxyC = Hubble constantd = Galaxy's distance

⇒ Given:

C = 72 km/s/mpcd = 100 mpc

⇒ Substitute these values into equation 1

v = 72(100)v = 7200 km/s.

Hence, the galaxy is 7200 km/s moving away from us.

Learn more about Hubble here: https://brainly.com/question/14615983

The gravitational force between two asteroids is 6.2 × 108 N. Asteroid Y has three times the mass of asteroid Z.

If the distance between the asteroids is 2100 kilometers, what is the mass of asteroid Y?

Answers

Answer:

1.1x10¹⁶ kg

Explanation:

Let m =  mass of asteroid y.

Because asteroid y has three times the mass of asteroid z, the mass of asteroid z is m/3.

Given:

F = 6.2x10⁸ N

d = 2100 km = 2.1x10⁶ m

Note that

G = 6.67408x10⁻¹¹ m³/(kg-s²)

The gravitational force between the asteroids is

F = (G*m*(m/3))/d² = (Gm²)/(3d²)

or

m² = (3Fd²)/G

    = [(3*(6.2x10⁸ N)*(2.1x10⁶ m)²]/(6.67408x10⁻¹¹ m³/(kg-s²))

   = 1.229x10³² kg²

m = 1.1086x10¹⁶ kg = 1.1x10¹⁶ kg (approx)

Which model below shows the positions of the Sun, Moon, and Earth that have the greatest effect on ocean tides?

Answers

Answer:

Below!

Explanation:

Referring to the picture, we can conclude that the picture J will have the most effect on ocean tides.

Whichever model is similar to model J in the picture will be your answer.

Hoped this helped.

Which of the following statements cannot be supported by Kepler's laws of planetary motion?


A planet's distance from the sun will not be the same in six months.


A planet's speed as it moves around the sun will not be the same in six months.


The rotational speed of the four smallest planets can be determined using the rotational speeds of the four largest planets and their orbital periods.


The average distance of Saturn can be calculated using the average distance of Neptune and the orbital period of both planets.

Answers

the second
option is the answer

please help me! i’ll mark brainliest if you’re correct!

Answers

The answer is that the resultant force is the vector sum of the component forces. In your simple example, where the component forces (F1 and F2) are at right angles to one another, as illustrated below, then the resultant force (r) is given by:

[tex]r= \sqrt{(f_{1}) {}^{2} +( f_{2})^{2} + 2f_{1}f_{2}. cos \: Θ, } \\ where \\ \: Θ, = angle \: between \: f_{1} \: and \: f_{2} \\ r = \sqrt{(2) {}^{2} + (5) {}^{2} + 2 \times 2 \times 5 \times cos90 } \\ \sqrt{4 + 25} = \sqrt{29} = 5.385 \\ nearest \: hundred = 5.39[/tex]

Answer: 3N to the right

Explanation: 2N- 5N= 3N

I don't understand when to use the formule with the constant k, and when to use the formula without it.

In the exercise that i sent here, they use the formule with a constant but I don't get why.

Can someone help me out please?
Thanks.

Answers

Answer:

This appears to be the formula for the electrical force between 2 objects.

You need this constant to calculate the electrical force between 2 charged objects.

Note that k = (1 / 4 * π ∈0)

∈0 is called the permittivity constant and ∈0 = 8.85E-12 farad/m

k = ( 1 / (4 * 3.28 * 8.85E-12) = 8.99E9

This makes F reasonably easy to remember as

F = 9E9 Q1 * Q2 / R^2 Newtons for the electrical force between Q! and Q2 separated by R

If the mass of a substance having its volume 80 cm is 68 g. Calculate the density of the substance​

Answers

[tex]\text{Given that,}\\\\\text{Mass}~ m = 68 ~\text{g} = 68 \times 10^{-3}~ \text{kg}\\\\\text{Volume}~ V = 80 ~ \text{cm}^3 = 80 \times 10^{-6}~ \text{m}^3 = 8\times 10^{-5}~ \text{m}^3\\\\\\\text{Density} ~\rho = \dfrac mV = \dfrac{68\times 10^{-3}}{8 \times 10^{-5}} = 8.5 \times 10^2 = 850 ~ \text{kg}~\text{m}^{-3}[/tex]

What is the boiling point of water?

Group of answer choices

373.15 degrees Fahrenheit

373.15 degrees Celsius

373.15 Kelvin

Answers

Answer:

373.15 Kelvin

Explanation:

Boiling Point of water

= 100 degree Celsius

= (100 + 273.15) Kelvin

= 373.15 Kelvin

Which branch of science deals with the study of the structures shown here?

FISH
AMPHIBIAN
REPTILE
BIRD?

Answers

Vertebrate Zoology, I’m pretty sure

Answer:

Vertebrate zoology

Explanation:

Have a great day!

how can I make a square fit in a triangle hole

Answers

cut the square and make it a triangle

which of the following are features of the nucleus of an atom
finding evidence to support or dispove is how science advanes

Answers

We r made of atom so v can’t touch anything hehe I just joking

A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what are the X AND Y components of the NORMAL FORCE?

Answers

Answer:

y-component = 45.75N

x-component = 0N

Explanation:

What does the Area under a Speed-time graph represent?
A. acceleration
B. average speed
C. deceleration
D. distance travelled

Answers

Answer:

d. distance travelled

Explanation:

answer

How much power is used in question #2 if the power time was 100secs
I really need the Formula, substitute & solve , answer with units.

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Answer:

I just put a random number for the work

Explanation:

I hope it is ok.

Please help is any one know Its correct answer ​

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Answer:

a=Head

b=Tip

c=South pole of the magnet

d=North pole of the magnet

Two sections of genetic material from a fruit fly are shown in the diagram.
X
-Eye color
-Wing shape
What does the diagram reveal about the inherited traits of fruit flies?
А Inherited traits are controlled by tissues, which are found in organs.
B
Inherited traits are controlled by organs, which are found in tissues.
с
Inherited traits are controlled by genes, which are found in chromosomes.
OD
Inherited traits are controlled by chromosomes, which are found in genes.

Answers

the answer is c, inherited traits are controlled by genes, which are found in chromosomes

how much force would be needed to push a box weighing 30 N up a ramp that ahas an ideal mechanical advantage of 3

Answers

Answer:

60n would be the needed force

The force needed to push a box weighing 30 N up a ramp that has an ideal mechanical advantage of 3 is equal to 10 N.

What is the mechanical advantage?

The mechanical advantage can be described as the ratio of the input force to the output force. The mechanical advantage of any machine can be determined by the ratio of the forces involved to do the work.

The ratio of the resistance force to the effort is called the actual mechanical advantage which will be comparatively less. The efficiency of a machine is always determined by equating the ratio of its output to its input.

The efficiency of the machine is equal to the ratio of the actual mechanical advantage (M.A.) and theoretical mechanical advantage. Mechanical advantage can be defined as the force produced by a machine to the force applied to it.

Given the load = 30 N and the ideal mechanical advantage = 3

Mechanical advantage = Load/ Effort

Input force or effort = Load/ M.A.

Force = 30/3

Input Force = 10 N

Learn more about the Mechanical advantage,  here:

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#SPJ2

what is the velocity of a 50 kg dog with 3000 j of kinetic energy

Answers

Answer:

KE = 225000000 J

Explanation:

Answer:

10.954. from equation. KE=1/2m(v^2)

2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50

(v^2)=120. square root for all v=10.954 m/s

What force is responsible for how magma flows and rocks stack up on top of one another?

Question 6 options:

Electroweak and Strong


Nuclear


Electromagnetic


Gravitational

Answers

Gravitational Force

Explanation:-

The magma flows through the gap between the rocks which are stacked up on top of one another.

The gravity attracts the magma to do that.

Also the rocks are stacked because of the gravitational force between them

Hence Option D is correct

Hope it helps

Answer:

pls mark me as brainliest

Explanation:

last one

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