Compare and contrast the applications and benefits of circle graphs and bar charts. Explain

Answer:

B) 1st C sp3 ; 2nd C sp3 ; O sp3

Explanation:

Both carbons in ethanol have an sp³ configuration of their orbitals, given that each carbon atom binds to four other atoms, as can be seen on the extended formula in the attachment.

In these carbons (1st and 2nd) one s orbital and three p orbitals are hybridized to form four hybrid orbitals sp³. These orbitals form four bonds and their bond angles are close to the tetrahedral value of 109.5º,as can be seen for methanol which also has an sp³ configuration.

The oxygen atom can also be described as having sp³ hybrid orbitals. Two of the four hybrid sp³ orbitals in oxygen are occupied by lone electron pairs, and two are used to form bonds with other atoms (in this case the oxygen is bonded to a carbon atom and a hydrogen atom).

Therefore, the three central atoms have an sp³ configuration.

Answer:

If an object has a higher density than the fluid it is in (fluid can mean liquid or gas), it will sink. If it has a lower density, it will float. Density is determined by an object's mass and volume. If two objects take up the same volume, but have one has more mass, then it also has a higher density.

Explanation:

Answer:

slower

Explanation:

NBS is used in place of Br2 during bromination because the use of Br2 tends to result in the formation of a large concentration of the addition product.  This is because, the Br2 interacts with the double bond to yield only the dibromide (addition product).

The usefulness of NBS lies in the fact that it provides a lower concentration of Br2, and such that the rate addition is slower than the chain propagation steps. Only the monobromination product is observed

The low concentration of Br2 allows the free-radical reaction to out-compete the alkene addition reaction.

Answer:+178

Explanation:

The heat of the reaction for the following reactions is 178 kJ. the correct option is D.

The heat that is added or removed during a chemical reaction is called the heat of reaction.

It is also called the enthalpy of the reaction.

The heat is absorbed or released to maintain the temperature of the reaction.

The enthalpy can be calculated by subtracting the enthalpy of the product from the enthalpy of the reactant.

Thus, the correct option is D.

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Answer:

Explanation:  check my paage

Answer:

1) 1.4 × 10³ mL

2) 0.913 kg

3) 1.1 g

Explanation:

1)

Step 1: Calculate the volume of 1.3 kg of olive oil

The density of olive oil is 0.917 kg/L.

1.3 kg × (1 L/0.917 kg) = 1.4 L

Step 2: Convert the volume to mL

We will use the relationship 1 L = 10³ mL.

1.4 L × (10³ mL/1 L) = 1.4 × 10³ mL

2)

Step 1: Calculate the mass of the cannon ball

The density of iron is 7.87 g/cm³.

116 cm³ × 7.87 g/cm³ = 913 g

Step 2: Convert the mass to kg

We will use the relationship 1 kg = 10³ g.

913 g × (1 kg / 10³ g) = 0.913 kg

3)

Step 1: Calculate the mass of the helium in the balloon

The density of balloon is 0.18 g/L.

6.1 L × 0.18 g/L = 1.1 g

Answer:

c. Voltmeter

Explanation:

PLATO LIVES MATTER

Answer:

The immune system responds to antigens by producing cells that directly attack the pathogen, or by producing special proteins called antibodies. Antibodies attach to an antigen and attract cells that will engulf and destroy the pathogen. The main cells of the immune system are lymphocytes known as B cells and T cells.

Answer:

AlCl3 and Ag

Explanation:

Edge 2020

The products formed when aluminum is added to a silver chloride solution are "AlCl3 and Ag".

The reaction of aluminum and silver chloride is a single substitution type of reaction that is expressed as follows: Al (s) + 3AgCl (aq) = AlCl3 (aq) + 3Ag (s)When aluminum is added to the silver chloride solution, the cations are exchanged in the process forming AlCl3 and Ag.

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#SPJ2

Answer:

3.44 × 10⁻²⁰ g Na

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

900 atoms Na

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Na - 22.99 g/mol

Step 3: Convert

[tex]900 \ atoms \ Na(\frac{1 \ mol \ Na}{6.022 \cdot 10^{23} \ atoms \ Na} )(\frac{22.99 \ g \ Na}{1 \ mol \ Na} )[/tex] = 3.4359 × 10⁻²⁰ g Na

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

3.4359 × 10⁻²⁰ g Na ≈ 3.44 × 10⁻²⁰ g Na

Answer:

B. the atmosphere

Explanation:

hope it helps

Answer:

Point F

Explanation:

Point F is the maximum potential energy.

Point G is lots of kinetic energy.

Point H is low potenital energy and low kinetic energy.

Answer:  \(\left( \ce{F} \right)\), chlorine \(\left( \ce{Cl} \right)\), bromine \(\left( \ce{Cl} \right)\), iodine \(\left( \ce{I} \right)\), and astatine \(\left( \ce{At} \right)\)

Explanation:

Answer:

453.031g

Explanation:

atomic mass (molar mass)- 196.97g/m

2.3(196.97)=453.031

actual yield = 0.182 mole

theoretical yield : 0.484 mole

percentage mole(% yield)=37.6%

Percent yield is the comparison of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

Fe₂O₃+3C⟶2Fe+3CO

a. actual yield of Fe mole

10.2 g produced

[tex]\tt mol~Fe=\dfrac{10.2}{56}=0.182[/tex]

b. percentage mole and theoretical yield

0.242 mol Fe₂O₃ = 2 x 0.242 mol Fe = 0.484 mol (theoretical yield)

percentage yieldpercentage mole)

[tex]\tt \dfrac{0.182}{0.484}=0.376=37.6\%[/tex]

Answer:

695.8kJ/mol = Enthalpy of combustion

Final temperature = 407.4°C

Explanation:

Taken the reaction:

2CH₃NO₂ + 3/2 O₂ → 2CO₂ + 3H₂O + N₂

The enthalpy of the reaction is the heat released when 1 mole of nitromethane are in combustion.

We need to find the moles presents in 121L of nitromethane using its density and molar mass (61.04g/mol). As these moles releases 1.6x10⁶kJ, we need to find heat released per mole of nitromethane

Mass nitromethane:

121L = 121000cm³ * (1.16g/cm³) = 140360g

Moles:

140360g * (1mol / 61.04g) = 2299.5 moles of nitromethane

Heat released per mole of nitromethane:

1.6x10⁶kJ / 2299.5 mol = 695.8kJ/mol = Enthalpy of combustion

The symbol - is because the heat is released, a + symbol is when the heat is absorbed.

Using:

Q = m×C×ΔT

Where Q is heat (1.6x10⁶kJ = 1.6x10⁹J)

m is mass of water:

1kL = 1000L = 1x10⁶mL = 1x10⁶g

C is specific heat of water: 4.184J/g°C

And ΔT is change in temperature.

Solving for ΔT:

1.6x10⁹J = 1x10⁶g * 4.184J/g°C * ΔT

ΔT = 382.4°C

As initial temperature was 25°C, final temperature is:

382.4°C + 25°C =

407.4°C

Answer:

C

Explanation:

Answer:

Electron cloud

Explanation:

If you were to scale the size of the atom up to have the nucleus be about the size of a basket ball, then the placement of the actual electrons (about the size of a large marble at this scale) throughout the cloud would be many yards away from the nucleus.

Answer:

C. Bases are found in the pH range of 1-7 on the pH scale.

Explanation:

Acids are less than 7 on the pH scale, so 1-7. Bases are more than 7 on the pH scale, so 7-14. That's why C is incorrect, hope this helps!

Answer:

B

Explanation:

i hope this helps

Answer:

- 278.85 J  

Explanation:

Given that:

Pressure = 1.1 atm

The initial volume V₁ = 0.0 L

The final volume V₂ = 2.5 L

The work that takes place in a reaction at constant pressure can be expressed by using the equation:

W = P(V₂ - V₁ )

Since the volume of the gas is expanded from 0 to 2.5 L when 1.1 atm pressure is applied. Then, the work can be given by the expression:

W = - P(V₂ - V₁ )

W = -1.1 atm ( 2.5 - 0.0) L

W = -1.1 atm (2.5 L)

W = -2.75 atm L

Recall that:

1 atm L = 101.4 J

Therefore;

-2.75 atm L = ( -2.75 × 101.4 )J

= -278.85 J  

Thus, the work required at the chemical reaction when the pressure applied is 1.1 atm  = - 278.85 J  

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question we have

[tex]volume = \frac{3.50}{5.61} \\ = 0.6238859...[/tex]

We have the final answer as

Hope this helps you

Answer:

Gas (B)

Explanation:

Answer:

D

Explanation:

Answer:

A molecular compound.

Explanation:

Ice, H2O(s), is classified as ; ( B ) A molecular compound

Given that Ice and H₂O are the same element but in different forms therefore we can classify Ice, H₂O as been a molecular compound.

Ice and H₂O are not ionic compounds because ionic compounds are formed between metal and non-metal elements while H₂O and Ice are neither metals but are both Nonmetals

Hence we can conclude that Ice, H2O(s), is classified as A molecular compound

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Answer:

2) (s)

3) PbBr2

Explanation:

2) This is a precipitation rxn which means if forms a solid, We use (s) for solid.

3) Refer to solubility table