Devon has $900 in a savings account. The interest rate is 7% per year and is not
compounded. How much interest will she earn in 2 years?
Use the formula i = prt, where i is the interest earned, p is the principal (starting amount),
is the interest rate expressed as a decimal, and t is the time in years.
=

Answer:

Hey mate....

Step-by-step explanation:

This is ur answer....

an attribute of a shape or relation; exact reflection of form on opposite sides of a dividing line or plane.

Hope it helps!

Brainliest pls!

Follow me! :)

Answer:

The definition of correspondence is the act of conforming or agreeing with someone or something else. An example of correspondence is when a person acts in the same way she appears to think.

In simple terms, it means communication, generally looking at two things and identifying stuff about them

Hope that helps. x

Answer:

f(0) = 3

f(-2) = -15

Step-by-step explanation:

You just have to plug in the value in f(b) into the b of the equation.

So for f(0) --> 2(0)^3 - |0-4| + 7

2(0) - |-4| + 7

0 - 4 + 7 = 3

------------

for f(-2)

2(-2)^3 -|-2-4| + 7

2(-8) - 6 + 7

-16 -6 + 7 = -15

Answer:

Step-by-step explanation:

[tex]x - 0.20x \: = 1480[/tex]

[tex]0.8x = 1480[/tex]

[tex]x = 1480 \div 0.8[/tex]

I'm not sure if this is correct, but I got this

Last year’s computer models are discounted 20%. If a computer is on sale for $1,480, what is the original price of the computer rounded to the nearest dollar?

20% = 0.2

1,480 x 0.2 = 296

1,480 + 296 = 1,776

Answer: 1,776

Again, I don't know if this is correct, so don't be 100% sure with my response.

Answer:

He save 55$+50$ which is 105$

Step-by-step explanation:

total for iguana is 135$ and parakeet is 90$

= 225$

Answer:

the answers are <1 = 118°, <2 = 62°

Answer:

∠ 1 = 118° , ∠ 2 = 62°

Step-by-step explanation:

∠ 1 and 118° are corresponding angles and are congruent, then

∠ 1 = 118°

∠ 1 and ∠ 2 are adjacent angles on a straight line and sum to 180°

∠ 2 + 118° = 180° ( subtract 118° from both sides )

∠ 2 = 62°

Answer:

n(E) = 6

Step-by-step explanation:

That's to say that there are 6 five-digit numbers with 7 in the first place and 8 in the last place, using the digits 2, 3, 4, 7 and 8. Therefore n(E) = 6.

Answer:

112+24x

Step-by-step explanation:

2(16+(10*4)+(x*12))

solve the inner bracket

2(16+40+12x)

solve this bracket

2(56+12x)

solve this now

112+24x

Answer:

[tex]24x+112[/tex]

Step-by-step explanation:

First of all we will start with the brackets inside the equation,

1. [tex]2[16+40+12x][/tex]

Now we can multiply 2 by all the values inside the parentheses

2. [tex]32+80+24x[/tex]

I just wanted to confirm that the big X is a variable?

Fact: Did you know that there are about 4 types of parenthese: ( ) - round brackets, [ ] - square brackets, { } - curly brackets, and < > - angle bracket.

Answer:

one solution

Step-by-step explanation:

Since both are y-isolated equation, we can write as:

[tex]\displaystyle \large{6x-2=4x-2}[/tex]

Solve for x, first move 4x to subtract with 6x and -2 to add with -2

[tex]\displaystyle \large{6x-4x=-2+2}\\\displaystyle \large{2x=0}\\\displaystyle \large{x=0}[/tex]

Then substitute x = 0 in any of these equations which we receive y = -2.

And the solution is (0,-2) which only has one solution.

Answer:

-1.4 m/sec  [backwards]

Step-by-step explanation:

The energy of the cannon moving should be equal to the energy contained in the cannonball.  Kinetic energy for each is calculated using KE = (1/2)m[tex]v^{2}[/tex]

Let x be the speed of the cannon.

Cannonball:  

KE = (1/2)m[tex]v^{2}[/tex]

KE = (1/2)(1kg)(45 m/sec)^2

KE = 22.5   kg*m/sec^2

Cannon:      [The cannon will have the reverse energy]

KE = - (1/2)m[tex]v^{2}[/tex]

22.5 kg*m/sec^2 = -(1/2)(67 kg)x^2

22.5 kg*m/sec^2 = -(33.5 kg)x^2

x^2 = (33.5 kg)/(22.5 kg*m/sec^2)

x^2 = -1.4 m/sec  [backwards]

Answer: The blue dot's value on the number line is 1.

Step-by-step explanation: Each two-skip interval from -7 to -3 is a skip of 4. Therefore, -3 skipped two times is -3 + 4, which equals 1, therefore the blue dot's value on the number line is 1.

Answer:

x=3, y=-6

Step-by-step explanation:

As you know there are many ways to solve this question! First is Subsitutuion, Second is Elimination, and Third is Graphing!

Let’s begin with our detailed answer:

As you know subsitution is solving for a variable and then it can be used as a variable substitution to figure out x and y.

So in our system of equations:

[tex]\left \ {3x+2y=-3}} \atop {9x+4y=3}} \right.[/tex]

I will just take one equation and solve for x but it actually dosent matter which variable you subsitutue and solve for.

[tex]\left \ {3x+2y=-3}} \atop {9x+4y=3}} \right.[/tex]

To eliminate this question we can divide the top part by -3:

[tex]\left \ {-9x-6y=9}} \atop {9x+4y=3}} \right.[/tex]

Let‘s sum these system of equation and we get: [tex]y=-6[/tex]

We can now insert y as -6 and solve for x:

[tex]3x-12=-3[/tex]

[tex]x=3[/tex]

So, [tex]x=3, y = -6[/tex]

Answer:

(3, - 6 )

Step-by-step explanation:

3x + 2y = - 3 → (1)

9x + 4y = 3 → (2)

Multiplying (1) by - 3 and adding to (2) will eliminate the x- term

- 9x - 6y = 9 → (3)

Add (2) and (3) term by term to eliminate x

0 - 2y = 12

- 2y = 12 ( divide both sides by - 2 )

y = - 6

Substitute y = - 6 into either of the 2 equations and solve for x

Substituting into (1)

3x + 2(- 6) = - 3

3x - 12 = - 3 ( add 12 to both sides )

3x = 9 ( divide both sides by 3 )

x = 3

solution is (3, - 6 )

Jake's Argument is correct, adding zero (0) to an addend does not change a sum.

Addend is number which is added to another number.

For example:

y + 5 = 8

where;

Adding zero (0) to an addend does not change a sum. An example is present below;

5 + 3 = 8

add zero (0) to 3 and check if the final result will change;

5 + (3 + 0) = 5 + 3 = 8

Thus, Jake's Argument is correct, adding zero (0) to an addend does not change a sum.

Learn more about addend number here: https://brainly.com/question/654494

[tex]3x-5 +x = 31\\\\\implies 4x -5 = 31\\\\\implies 4x = 31 +5\\\\\implies 4x = 36 \\\\\implies x =\dfrac{36}4\\\\\implies x = 9[/tex]

Answer:

C. A rate with one (1) in the denominator

A unit rate is basically a ratio of something to one.

example:

if 10 bananas costs ten dollars then one banana would cost one dollar.

Step-by-step explanation:

Answer:

A.  A rate with one in the numerator

Step-by-step explanation:

We can find the unit rate when given a rate by dividing the unit in the numerator by the quantity in the denominator. For example, if we are given the rate $4.50/5 gallons of milk, we can divide 4.50 by 5 to find the unit price, which is dollars per one gallon of milk. A unit rate means a rate for one of something. We write this as a ratio with a denominator of one. For example, if you ran 70 yards in 10 seconds, you ran on average 7 yards in 1 second. Both of the ratios, 70 yards in 10 seconds and 7 yards in 1 second, are rates, but the 7 yards in 1 second is a unit rate.

Answer:

4 burgers

Step-by-step explanation:

four burgers

If you're making the patties yourself (to save money or because you love making burgers), assume four burgers per pound of meat

Answer:

1,2,4,5,8,10,20,40

Step-by-step explanation:

Have a nice day

Answer:

55.56%

Step-by-step explanation:

55/99=.5555555...

.55555...*100=55.555...%

55.56%

Answer:

7308 / 18

= 406

B is the answer.

Answer:

x = -2.

y = 3.

Step-by-step explanation:

If y = 3x + 9

Substitute this value for y in the first equation.

4x + 5(3x + 9) = 7

4x + 15x + 45 = 7

19x = 7 - 45

19x = -38

x = -38/19

x = -2.

with this value of x, substitute -2 in the second equation

y = 3(-2) + 9

y = -6+9

y = 3.

check if your values are all correct

4(-2) + 5(3) = 7

-8 + 15 = 15 - 8 = 7

Correct!

Answer:

D: {-2, 0, 2}

R: {-1, 1, 3

Answer:

true

Step-by-step explanation:

Answer:

-5.

Step-by-step explanation:

5 + -5 = 0, so i's -5.

Answer:

70% right, 30% wrong

Step-by-step explanation:

3 is 30% of 10

Answer:

A. 10/14

and

C. 15/21

Step-by-step explanation:

A. 10/14

and

C. 15/21

[tex]\mathfrak{ x ^ { 2 } + b x - 4 = 0} [/tex]

[tex]\mathfrak{bx-4=-x^{2} } [/tex]

[tex]\mathfrak{bx=-x^{2}+4 } [/tex]

[tex]\mathfrak{xb=4-x^{2} } [/tex]

[tex]\mathfrak{\frac{xb}{x}=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{ b=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{b=-x+\frac{4}{x} } [/tex]

AnSwEr

[tex]\boxed{\mathfrak{b=-x+\frac{4}{x},x\neq 0 } }[/tex]

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