Mathematics High School

f(1)=−6
f(2)=−4
f(n)=f(n−2)+f(n−1)
​

f(3)=f(3)=f, left parenthesis, 3, right parenthesis, equals

HURRY!!!!

Answers

Answer 1
f(3) = f(3-2) + f(3-1)
f(3) = f(1) + f(2)

then substitute using the values given so
f(3) = -6 + -4
so f(3) = -10
Answer 2

the value of function at n = 3 is  f( 3 ) is - 10.

To find the value of f( 3 ), we can use the given recursive formula:

f(n) = f( n - 2 ) + f( n - 1 )

We already have the values of f(1) and f(2):

f(1) = - 6

f(2) = - 4

Now, let's apply the recursive formula to find f(3):

f(3) = f( 3 - 2 ) + f( 3 - 1 )

f(3) = f(1) + f(2)

f(3) = - 6 + (- 4)

f(3) = - 10

So, the value of f(3) is - 10.

Learn more about recursive formula here

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Question :

[tex] \dashrightarrow{5 \dfrac{2}{12} \times \dfrac{10}{11}}[/tex]

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Performing multiplication :

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[tex] \dashrightarrow{\dfrac{620}{132}}[/tex]

Cutting the fraction into simplest form :

[tex] \dashrightarrow{ \cancel{\dfrac{620}{132}}}[/tex]

[tex] \dashrightarrow{ \dfrac{155}{33}}[/tex]

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--------------

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Answers

Answer:

-49

Step-by-step explanation:

Make sure you understand the difference between

-3² and (-3)²

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