How many grams of barium chloride are produced when 1.25 x 1023 molecules of HCl reacts with barium?

Answers

Answer 1

Considering the reaction stoichiometry and Avogadro's Number, the mass of barium chloride produced is 21.6 grams.

Balanced reaction

The balanced reaction is

2 HCl + Ba → BaCl₂ + H₂

Moles of HCl that react

Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of HCl, then 1.25×10²³ molecules are contained in how many moles of HCl?

amount of moles of HCl= (1.25×10²³ molecules × 1 mole)÷ 6.023×10²³ atoms

amount of moles of HCl= 0.2075 moles

Then, 0.2075 moles of HCl react.

Reaction stoichiometry

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HCl: 2 moles Ba: 1 mole BaCl₂: 1 mole H₂: 1 mole

Mass of barium chloride produced

Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl produce 1 mole of BaCl₂, 0.2075 moles of HCl will produce how many moles of BaCl₂?

[tex]amount of moles of BaCl_{2} =\frac{0.2075 moles of HCl x 1 mole of BaCl_{2} }{ 2moles of HCl}[/tex]

amount of moles of BaCl₂= 0.10375 moles

Being the molar mass of BaCl₂ 208.24 g/mole, then the mass of barium chloride produced is calculated as:

[tex]0.10375 molesx\frac{208.24 grams}{1 mole} =21.6 grams[/tex]

Finally, the mass of barium chloride produced is 21.6 grams.

Learn more about:

Avogadro's Numberbrainly.com/question/11907018?referrer=searchResults brainly.com/question/1445383?referrer=searchResults brainly.com/question/1528951?referrer=searchResultsReaction stoichiometry brainly.com/question/16487206?referrer=searchResults brainly.com/question/14446695?referrer=searchResults brainly.com/question/11564309?referrer=searchResults brainly.com/question/4025026?referrer=searchResults brainly.com/question/18650135?referrer=searchResults

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Answer:

In the Lewis structure for IF5 you'll need to put a total of 12 valence electrons on the Iodine atom in order to draw the Lewis structure. Remember that Iodine (I) can hold more than eight valence electrons. For the IF5 Lewis structure, calculate the total number of valence electrons for the IF5 molecule

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The lack of accuracy and underestimation of absorbance readings obtained from the colorimeter can be contributed to many experimental factors. One plausible error is from the imperfection of the absorber, in that it may not completely absorb the stray light passing by the perimeters of the photoresistor.

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if a substance has a normal boiling point of 50 °c, what can you state about the vapor pressure of the same substance at 40 0 °c?

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It will be less because pressure is directly proportional to temperature

Astatine-218 has a half-life of 1.6 seconds. If you begin with a 1.7 g sample of astatine-218, how much of the sample remains after 3.2 seconds?​

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Answer:

do you still need help on this question

Explanation:

Will give 10 points.
Why does an atom have a neutral charge?
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Answer:

option A it has equal numbers of electrons and protons

Explanation:

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Answer:

A. it has equal numbers of electrons and protons

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The overall charge of every atoms is neutral because the number of electrons and protons is the same. Protons are positively charged while electrons are negatively charged and so they cancel out.

Calculate the minimum volume of oxygen gas, at room temperature and pressure(r.t.p). required to completely burn 56g of methane gas. Give your answer to two significant figures. (1 mole of any gas occupies 24 dm³ at r.t.p,Ar:C=12,H=1)


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CH₄+2O₂→CO₂+2H₂O

Answers

Answer:

170 dm³ (2 significant figures)

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CH₄ + 2O₂ → CO₂ + 2H₂O

We need to find how much 'volume' of O₂ is required to burn 56 g of CH₄.

Let's take the ratios of the two gases only.

CH₄ : 2O₂ (in terms of moles the ratio is 1:2)

56g : x dm³

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State the given:

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Moles = Mass/Molar Mass

Rearrange the equation:

Mass = Moles x Molar mass

Plug in your given:

5 moles Sulfur   x   32.06g

                                 1 mol

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Explanation:

took the test

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Answer:

The wavelength is 0.02 m.

Step-by-step explanation:

Given :

[tex]\green\star[/tex] Velocity = 12 m/s[tex]\green\star[/tex] Frequency = 600 Hz

To Find :

[tex]\green\star[/tex] Wavelength

Using Formula :

Apply Wavelength formula :

[tex]\star{\small{\underline{\boxed{\sf{\purple{\lambda = \dfrac{v}{f}}}}}}}[/tex]

[tex]\pink\star[/tex] λ = Wavelength [tex]\pink\star[/tex] v = Velocity [tex]\pink\star[/tex] f = Frequency

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[tex]{\longrightarrow{\sf{\lambda = \dfrac{12}{600}}}}[/tex]

[tex]{\longrightarrow{\sf{\lambda = \dfrac{\cancel{12}}{\cancel{600}}}}}[/tex]

[tex]{\longrightarrow{\sf{\lambda = \dfrac{2}{100}}}}[/tex]

[tex]{\longrightarrow{\sf{\lambda = \cancel{\dfrac{2}{100}}}}}[/tex]

[tex]{\longrightarrow{\sf{\lambda = 0.02}}}[/tex]

[tex]\star{\underline{\boxed{\tt{\red{\lambda = 0.02 \: m}}}}}[/tex]

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Answer:

75%

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In order to find the percent yield, you need to figure out how many moles of ammonia are actually produced for every 100 moles of ammonia that could theoretically be produced.

You know that 0.667 moles will produce 0.50 moles, so you can say that

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Answer:

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