Answer:
Explanation:
Equipment manufactured by LECO(8 Corporation, St. Joseph, Michigan is warranted free from defect in material
and workmanship for a period of six months from the date of purchase. Equipment not manufactured by LECO is
covered to the extent of warranty provided by the original manufacturer and this warranty does not cover any
equipment, new or used, purchased from anyone other than the LECO Corporation. All replacement parts shall
be covered under warranty for a period of thirt days from date of purchase. LECO MAKES NO OTHER
REPRESENTATION OR WARRANTY OF ANY OTHER KIND, EXPRESSED OR IMPLIED, WITH RESPECT TO
THE GOODS SOLD HEREUNDER, WHETHER AS TO MERCHANTABILITY, FITNESS FOR PURPOSE, OR
OTHERWISE.
Expendable items such as crucibles, combustion tubes, chemicals and items of like nature are not covered by
this warranty.
LECO's sole obligation under this warranty shall be to repair or replace any part or parts which, to our
satisfaction, prove to be defective upon return prepaid to LECO Corporation, St. Joseph, Michigan. This
obligation does not include labor to install replacement parts, nor does it cover any failure due to accident, abuse,
neglect, or use in disregard of instructions furnished by LECO. In no event shall damages for defective goods
exceed the purchase price of the goods, and LECO SHALL NOT BE LIABLE FOR INCIDENTAL OR
CONSEQUENTIAL DAMAGES WHATSOEVER.
All claims in regard to the parts or equipment must be made within ten (10) days after Purchaser learns of the
facts upon which the claim is based. Authorization must be obtained from LECO prior to returning any other
parts. This warranty is voided by failure to comply with these notice requirements.
NOTICE
The warranty on LECO equipment remains valid only when genuine LECO replacernent parts are employed.
Since LECO has no control over the quality or purity of consumable products not manufactured by LECO, the
specifications for accuracy of results using LECO instruments are not guaranteed unless genuine LECO
consumables are employed in conjunction with LECO instruments. If purchaser defaults in making payment for
any parts or equipment, this warranty shall be void and shall not apply to such parts and equipment. No late
payment or cure of default in payment shall extend the warranty period provided herein.
LECO Corporation is not responsible for damage to any associated instruments, equipment or apparatus nor wil
LECO be held liable for loss of profit or other special damages resulting from abuse, neglect, or use in disregard
of instructions. The Buyer, their employees, agents and successors in interest assume all risks and liabilities for
the operation, use and/or misuse of the product(s) described herein and agree to indemnify, hold harmless and
defend the seller from any and all claims and actions arising from any cause whatsoever, including seller's
negligence for personal injury incurred in connection with the use of said product(s) and any and all damages
proximately resulting therefrom.
CAUTION
The instrument should be operated only by technically qualified individuals who have fully read and understand
these instructions. The instrument should be operated only in accordance with these instructions.
The operator should follow all ,of the warnings and cautions set forth in the manual and the operator should follow
and employ all applicable standard laboratory safety procedures.
LECO'" is a registered trademark of the LECO Corporatio
Please answer the following question!
What is the momentum of a 750-kg Volkswagen Beetle when at rest?
Please give the value and momentum!
Answer:
0
Explanation:
the momentum will always be 0 when it is at rest because the object isnt moving!
Hope this helped!
Learning Task 1: Define or describe the following words relat are not familiar with the word, you may ask assistance from y your answer in your notebook. 1. table 2. tennis C 3. ping-pong 4. net 5. ball 6. racket
Answer:
1.) TABLE = The table is 2.74 m (9.0 ft) long, 1.525 m (5.0 ft) wide, and 76 cm (2.5 ft) high with any continuous material so long as the table yields a uniform bounce of about 23 cm (9.1 in) when a standard ball is dropped onto it from a height of 30 cm (11.8 in), or about 77%.
2.) TENNIS = Tennis is a racket sport that can be played individually against a single opponent (singles) or between two teams of two players each (doubles). Each player uses a tennis racket that is strung with cord to strike a hollow rubber ball covered with felt over or around a net and into the opponent's court.
3.) PING-PONG = Table tennis, also known as ping-pong and whiff-whaff, is a sport in which two or four players hit a lightweight ball, also known as the ping-pong ball, back and forth across a table using small rackets. ... Spinning the ball alters its trajectory and limits an opponent's options, giving the hitter a great advantage.
4.) NET = This is stretched across the centter of the table by a cord attached to a post at either end. It measures 6ft long and the ball must pass over it for a rally to continue.
5.) BALL = The ball, which is spherical and hollow, was once made of white celluloid. Since 1969 a plastic similar to celluloid has been used. The ball, which may be coloured white, yellow, or orange, weighs about 0.09 ounce (2.7 grams) and has a diameter of about 1.6 inches (4 cm).
6.) RACKET = A table tennis racket is made up of two distinct parts - a wooden blade which incorporates the handle together with table tennis rubbers affixed to each side of the blade using water-based glue.
Explanation:
All my answers are
about the tools of the
game of tennis
4 What type of circuit is described by each of the following statements?
Answer series or parallel
a All components are connected end-to-end.
b. The current in the circuit divides so that some flows through one component
and the rest through another component
Two lamps are connected side by side so that each lights brightly
d The current has the same valur everywhere in the circuit
C
Two spherical balloons are filled with water. The first balloon has a radius of 3 cm, and the second has a radius of 6 cm. How much greater is the volume of water in the larger balloon than in the smaller balloon? Use 3. 14 to approximate pi. Round to the nearest hundredth if necessary. Enter your answer as a decimal in the box.
Answer:
V = 4/3 R^3
V2 / V1 = (R2 / R1)^3 = 2^3 = 8
8.00
The volume of water in the larger balloon is 8 times greater than in the smaller balloon
We'll begin by calculating the volume of each balloon.
For smaller balloon:Radius (r) = 3 cmPi (π) = 3.14Volume (V) =?V = 4/3 πr³
V = 4/3 × 3.14 × 3³
V = 113.04 cm³For larger balloon:Radius (r) = 6 cmPi (π) = 3.14Volume (V) =?V = 4/3 πr³
V = 4/3 × 3.14 × 6³
V = 904.32 cm³Finally, we shall determine how much greater the larger balloon is to the smaller balloon
Volume of smaller balloon = 113.04 cm³Volume of larger balloon = 904.32 cm³Greatness =?Greatness => large / small
Large / small = 904.32 / 113.04
Large / small = 8
Cross multiply
Large = 8 × smallTherefore, the larger balloon is 8 times greater than the smaller balloon.
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which constellation is in contrast with ursa major
Answer: Ursa Major (/ˈɜːrsə ˈmeɪdʒər/; also known as the Great Bear) is a constellation in the northern sky, whose associated mythology likely dates back into prehistory. Its Latin name means "greater (or larger) she-bear," referring to and contrasting it with nearby Ursa Minor, the lesser bear.
Bordering constellations: Draco; Cameloparda...
Brightest star: ε UMa (Alioth) (1.76m)
Meteor showers: Alpha Ursa Majorids; Leonid...
Symbolism: the Great Bear
can you fit all the planets between earth and moon
Answer: No, planets of our solar system, with or without Pluto, cannot fit within the mean lunar distance. An additional 3,500 km is needed to squeeze in Neptune
An instrument made of brass is an example of which of these?
solid–liquid solution
solid solution
liquid–liquid solution
gas–liquid solution
Answer:
a solid made of liquid solution
Explanation:
a trumpet for example has intrcuite valves , the only way to do this is by creating a liquid form of the metal to be able to create the solid formed instrument.
Answer:
a solid made of liquid solution
Explanation:
domne
The expression below was formed by combining different gas laws. V is proportional to StartFraction n T over P EndFraction. Which law was used to determine the relationship between the volume and the number of moles in this equation? Boyle’s law Charles’s law Avogadro’s law Gay-Lussac’s law.
The relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
Avogadro's law:
It states that at constant temperature and pressure, gases with same volume has the same number of molecules.
For an ideal gas with with constant temperature and pressure, the volume of the gas is directly proportional to the amount or number of molecules.
Charle's law states that at constant pressure, volume (V) and temperature (T) are directly proportional.Boyle's law states that at constant temperature, the volume of gas is inversely proportional to the gas pressure.Gay-Lussac's law states that pressure (P) and absolute temperature (T) of the gas are directly proportional.Therefore, the relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
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Answer:
Avogadro's law
Explanation:
a water balloon is thrown a target at 18 m/s. if the water balloon has a mass of 0.4 kg, what is the momentum?
The momentum of the water balloon at the given speed is 7.2 kgm/s.
The given parameters:
Speed of the water balloon, v = 18 m/sMass of the balloon, m = 0.4 kgThe momentum of the water balloon is calculated as follows;
P = mv
Substitute the given values of mass and velocity as follows;
P = 0.4 x 18
P = 7.2 kg m/s.
Thus, the momentum of the water balloon at the given speed is 7.2 kgm/s.
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Describe the direction in which each object will accelerate. If the object won't accelerate, write "no acceleration." Explain what might be happening to each object in terms of its overall motion.
You are trying to find the amount of heat transferred between two substances. In order to do this, you plan
to place both substances in a thermally isolated container and wait until the system reaches thermal
equilibrium. You need to decide what measurements you should take.
Remember that heat transfer is described by the equation Q =mcAT where m is the mass, c is the
specific heat, and AT is the change in temperature. Assume you are able to look up the specific heat
capacities of both substances.
Which of the following sets of measurements would best allow you to determine the heat transfer
between the two substances?
The mass, the initial and the final temperature would let you determine the heat transfer between two substances.
What is meant by heat transfer?Heat transfer refers to the movement of thermal energy from one location or substance to another as a result of a difference in temperature. There are three primary mechanisms for heat transfer: conduction, convection, and radiation.
Conduction is the transfer of heat through direct contact of substances, such as when heat travels from a hot pan to your hand through the handle.
Convection is the transfer of heat through the movement of a fluid, such as when hot air rises and cool air sinks.
To determine the heat transfer between two substances, you need to measure their mass, initial temperature, and final temperature. With these measurements, you can calculate the change in temperature (AT) and use the equation Q = mcAT to determine the heat transfer. The specific heat capacities of both substances can be looked up.
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“Applications of thermal expansion in solids, liquids and gases.”
(Two for each states of matter)
Thermal expansion is the tendency of matter to change its shape dimensions, density in response to a change in temperature.
The following are applications of thermal expansion in various matter.SolidsThe principle of thermal expansion is used in thermostat to regulate the temperature of heating device e.g Electric pressing Iron.Rivets are used to hold steel plates together very tightly.
2. Gases
Hot-air balloons are an application of thermal expansionGases turbine3. Liquids
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a truck in a traffic circle travels in a circular path at constant speed v0 while passing through region x of the circle, as shown in figure 1 above. a diagram representing the forces exerted on the truck in region x is shown in figure 2. at a later time a car with less mass than the truck passes through region x at the same speed and the same distance from the center of the traffic circle as the truck. the coefficient of friction between the car’s tires and the ground is the same as that for the truck’s tires and the ground. which of the following diagrams could represent the forces exerted on the car in region x compared to the truck in region x ? assume that the length of each arrow is proportional to the magnitude of the force represented by the arrow.
The Diagram that represents the forces exerted on the car in region x when compared to the truck in region X is : Diagram C
Given that the mass of the car is less than the mass of the truck the force due to gravity will be greater on the truck than it could be on the car
i.e. | Fg |car < | Fg | truck
also : | Fₙ | car < | Fₙ | truck
Since the gravitational force on the car is less than the gravitational force on the truck
| Ff | car < | Ff | truck
where : Ff = frictional force
Fg = force due to gravity
Fn normal force
Therefore from the diagrams attached below the correct diagram that represents the forces exerted on the car in region x when compared to the truck in region X is : Diagram C.
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Attached below is the missing data related to your question
The instant before a batter hits a 0.14-kilogram baseball, the velocity of the ball is 45 meters per second west. The instant after the batter hits the ball, the ball's velocity is 35 meters per second east. The bat and ball are in contact for 1.0 x 10-2 second.
1. find the magnitude and direction of the average acceleration of the baseball while it is in contact with the bat.
2. calculate the magnitude of the average force the Bat exerts on the ball while they are in contact.
(1) The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is 8,000 m/s² east.
(2) The magnitude of the average force the Bat exerts on the ball while they are in contact is 1,120 N.
The given parameters:
Mass of the baseball, m = 0.14 kgInitial velocity of the baseball, u = 45 m/s west (negative direction)Final velocity of the baseball, v = 35 m/s east (positive direction)Time of contact, t = 0.01 sThe magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is calculated as follows:
[tex]a = \frac{v- u}{t} \\\\a = \frac{35 - (-45)}{0.01} \\\\a = \frac{80}{0.01} \\\\a = 8,000 \ m/s^2[/tex]
The magnitude of the average force the Bat exerts on the ball while they are in contact is calculated as follows;
[tex]F = ma\\\\F = 0.14 \times 8,000\\\\F = 1,120 \ N[/tex]
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A roller coaster goes from 2.00 m/s [forward] to 10.0 m/s [forward) in 4.50 s. What is its acceleration?
A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
The final speed of the combined masses is 0.186m/s
According to the law of collision, the sum of the momentum of the bodies before the collision is equal to the momentum after the collision.
Mathematically;
m1u1 - m2u2 = (m1+m1)v
v is the final speed of the combined masses.Substituting the given parameters;
0.24(0.6) - 0.26(0.2) = (0.24+0.26)v
0.144 - 0.052 = 0.5v
0.092 = 0.5v
v = 0.092/0.5
v = 0.184m/s
Hence the final speed of the combined masses is 0.186m/s
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how far will an object fall in 3 seconds
Answer:
144.7832 ft
Explanation:
heres the formula i found to solve
v = v₀ + gt
where:
v₀ is the initial velocity (measured in m/s or ft/s);
t stands for the fall time (measured in seconds); and
g is the free fall acceleration (expressed in m/s² or ft/s²).
Without the effect of air resistance, each object in free fall would keep accelerating by 9.80665 m/s (approximately equal to 32.17405 ft/s) every second. In reality, though, a falling object's velocity is constrained by a value called the terminal velocity.
im sorry i couldnt provide more information, but there was not much info provided in the question itself
What part of the reactor is used to control the speed of the nuclear reaction? How does it work?
Control rods
____________________
Control rods are inserted into the core of a nuclear reactor and adjusted in order to control the rate of the nuclear chain reaction
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A racing car has a mass of 750 kg. It undergoes an acceleration of 4.00 m/s2. What is the net force acting on the car?
Answer:
3000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 750 × 4 = 3000
We have the final answer as
3000 NHope this helps you
Which is a possible food chain in the ocean from start to finish?
a.phytoplankton, zooplankton, small fish, large fish, large shark
b.phytoplankton, large shark, zooplankton, large fish, small fish
c.large shark, large fish, small fish, zooplankton, phytoplankton
d.zooplankton, phytoplankton, large fish, small fish, large shark
Answer:
a.phytoplankton, zooplankton, small fish, large fish, large shark
Explanation:
The bottom level of the ocean's food chain is made up of one-celled organisms called phytoplankton. These tiny organisms are microscopic. They are so small they cannot be seen without a microscope. Billions of phytoplankton live in the upper part of the ocean. They take in the sun's light.
Phytoplankton, or plant plankton, is the first link in the food chain in the ocean. They require sunlight for photosynthesis, which they must perform. They therefore reside higher up in the shallow sunlight. Furthermore, they transform themselves into an ocean animal that can eat the “food” from the sun. Thus, option A is correct.
What food chain in the ocean from start to finish?One-celled organisms known as phytoplankton make up the base of the ocean's food chain. These microscopic organisms are quite small. Without a microscope, they are invisible due to their small size. In the upper ocean, there are billions of phytoplanktons. They absorb the light from the sun.
Aquatic food webs are built on phytoplankton and algae. They are consumed by zooplankton, tiny fish, and crustaceans, which are the main consumers. Fish, tiny sharks, corals, and baleen whales all devour the primary consumers after them.
Therefore, phytoplankton, zooplankton, small fish, large fish, large shark is a possible food chain in the ocean from start to finish.
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1)A chocolate bar measures 10 cm long by 2 cm wide and is 2 cm thick
a)Calculate the volume of one bar.
b)How many bars each 2 cm long, 2 cm wide and 2cm thick have the same total volume?
c)A pendulum makes 10 complete oscillations in 8 seconds. Calculate the time period of the pendulum
Answer:
40cm³
Explanation:
I only have an answer to 1a
Volume = Length X breadth X height
where;
length = 10cm
breadth = 2cm and;
width = 2cm
*Find*
V = ?
V = L X B X H
V = 10 X 2 X 2
= 40cm³✓
What is number 10 for this?
Answer:
The wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Given data in the question;
Speed of wave;
Frequency of wave;
wavelength;
To determine the wavelength of the radio wave, we use the expression for the relations between wavelength, frequency and speed.
Where is wavelength, f is frequency and c is the speed.
We substitute our given values into the equation
Therefore, the wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Explanation:
Which image shows an example of the electromagnetic force in action?
Answer:
Where are the images?
Explanation:
I can't help if there is no image(s) to this question.
jamal is playing with magnetic toy vehicles. He has two identical magnetic vehicles (purple and green) on different sides of a center magnet that cannot move. His friend Simone challenges him to move one vehicle one space to the left or the right in order to get the largest increase in potential energy. That means Jamal can move the purple car to point A or point B, or he can move the green car to point C or point D. Explain which movement Jamal should make (which car and which point), and why that movement will result in the largest increase in potential energy. Describe the magnetic force that will act on the vehicle he moves.
Answer:
Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance. The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.
Explanation:
Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance.The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.
A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
The final speed of the combined masses is 0.21 m/s
Applying the law of conservation of momentum:
Total momentum before collision = Total momentum after collision.
⇒ Formula:
MU+mu = V(M+m).................. Equation 1
⇒ Where:
M = mass of the first bodym = mass of the second bodyU = Initial speed of the first bodyu = Initial speed of the second bodyV = common final speed.From the question,
⇒ Given:
M = 0.24 kgU = 0.60 m/sm = 0.26 kgu = -0.20 m/s (traveling in opposite direction)⇒ Substitute these values into equation 1
0.24(0.6)+0.26(-0.20) = V(0.24+0.2)⇒ Solve for V
0.144-0.052 = 0.44V0.44V = 0.092V = 0.092/0.44V = 0.209V ≈ 0.21 m/sHence the final speed of the combined masses is 0.21 m/s
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Stewart (70 Kg) is attracted to Ms. Little (60 Kg) who sits 2 m away. What is the gravitational attraction between them? G=6.67×10^-11 (-11 is an exponent)
Happy Holidays!
We can use the following equation to solve for the gravitational force:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]
Fg = force due to gravity (N)
G = Gravitational constant
m1,m2 = masses of the objects (kg)
r = distance between the objects (m)
Plug in the given values into the equation:
[tex]F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}[/tex]
The Earth currently has an orbital period of 1 year and a semi-major
axis length of 1 AU. If the Earth's orbit changed and the semi-major
axis length increased to 1.1 AU, how would the Earth's orbital period change?
A: It would increase by 0.15 years
B: It would increase by 0.032 years
C: It would decrease by 0.15 years
D: It would decrease by 0.032 years
The Earth's orbital period change is A: It would increase by 0.15 years
Using Kepler's third law which states that the square of the orbital period of the planet is directly proportional to the cube of its distance from the sun.
So, T² ∝ R³
T'²/T² = R'³/R³ where
T = orbital period at R = 1 yearR = initial axis length = 1 AUT' = orbital period at R'R' = final axis length = 1.1 AU.So, making T' subject of the formula, we have
T' = [√(R'/R)³]T
T' = [√(1.1 AU/1 AU)³] × 1 year
T' = [√(1.1)³] × 1 year
T' = √1.331 × 1 year
T' = 1.15 × 1 year
T' = 1.15 years.
So, the change in the Earth's orbital period ΔT = T' - T
= 1.15 years - 1 year
= 0.15 years
Since this is positive, the orbital period increases by 0.15 years.
So, the Earth's orbital period change is A: It would increase by 0.15 years
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A car has a kinetic energy of 4.33x10^5 J when traveling a speed of 25 m/s. What is the mass ?
1. Which of the following types of energy is
potential energy? More than one answer is
possible,
A kinetic energy
B.thermal energy
C.sound energy
D.gravitational energy
Answer:
Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.
Tim is pushing a heavy box across the floor. He is using 300N of force and can accelerate at 2m/s/s. What is the mass of the box?
-298 kg
-600 kg
-0.006 kg
-150 kg
Using Newton's second law
[tex]\\ \sf\Rrightarrow F=ma[/tex]
[tex]\\ \sf\Rrightarrow 300=2m[/tex]
[tex]\\ \sf\Rrightarrow m=150kg[/tex]
Hey there!
The formula of “mass” in physics is:
m = F/a
Whereas “f” is ‘force’, “a” is ‘acceleration’, & “m” is your ‘mass’ of course.
mass = 300 Net force/2 acceleration
300 Net force/2 acceleration = m
mass = 150
Therefore, your answer is: 150 kg
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)