Answer:
Test statistic = 1.1508
Step-by-step explanation:
Given the data provided
We have to make a table and find d and d²
From the calculations I did in the attachment
n = 5
d² = 1.81
d = 1.5
The t test statistic = 1.5/1.3038 = 1.1505
B. No the new stadium may not have caused the attendance t decrease in this case. Other factors could be responsible for the low attendance.
if sinθ =1/3 what are the values of cosθ and tanθ
solution in attachment
hope it helps
can you guys. guy's. Help me pls
Answer:
J) [tex]\frac{17}{24}[/tex]
Step-by-step explanation:
[tex]\frac{3}{8} +\frac{1}{3} \\\\\frac{9}{24} +\frac{8}{24} = \frac{17}{24}[/tex]
Find the common denominator ^^
Answer:
17/24
Step-by-step explanation:
3/8× 3/3=9/24
1/3×8/8=8/24
8/24 +9/24= 17/24
Find the exact value of the expression cos-1(1/2)
Answer:
60
Step-by-step explanation:
Plug it into the calculator
The new floor in the school cafeteria is
going to be constructed of square tiles that
are either gray or white and in the pattern
that appears below. What is the ratio of
Answer:
Step-by-step explanation:
18 tiles and 10 shaded in
Katie worked 40.5 hours this week. She makes $8 per hour. How much money did she earn this week?
Answer:
$324
Step-by-step explanation:
if
=> 1hr = $8
then,
=> 40.5 x 8 = 324
=> 40.5 hr = $324
She earned $324 this week.
hope this helps and is right :)
Answer:
$324
Step-by-step explanation:
So, First we have to establish what we are solving for, in this equation we are solving for how much money Katie made this week after working 40.5 hours at a salary of $8 per hour.
To find how much Katie made we have to multiply 40.5 and 8!
Let's make it easier by splitting 40.5 into 40 and 0.5
40 × 8 = 320
0.5 × 8 = 4
320 + 4 = 324
Katie made $324 this week!
Hope this Helps! :)
Have any questions? Ask below in the comments and I will try my best to answer.
-SGO
When a new highway is formed, the smoothness of the surface must be verified. A contractor is making a bid for this job and has a truck with the relevant detector. This detector must meet minimum standards for detecting irregularities in the road surface. If there is a roadway irregularity, there is a probability of 0.99 the detector will detect it. If there is no irregularity, there is a 0.06 probability detector will identify it as irregular (a false positive). It is known through experience that 3 miles out of 100 miles actually contain irregularities.
a. What is the probability the detector will identify a random mile of roadway as irregular? Give your answer to four decimal places.
b. Given a randomly selected miles has been identified as irregular by the detector, what is the probability it actually is irregular? Give your answer to four decimal places.
Answer:
a) 0.0879 = 8.79% probability the detector will identify a random mile of roadway as irregular.
b) 0.3379 = 33.79% probability it actually is irregular
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
a. What is the probability the detector will identify a random mile of roadway as irregular?
99% of 3%(it is irregular).
6% of 97%(false positive). So
[tex]p = 0.99*0.03 + 0.06*0.97 = 0.0879[/tex]
0.0879 = 8.79% probability the detector will identify a random mile of roadway as irregular.
b. Given a randomly selected miles has been identified as irregular by the detector, what is the probability it actually is irregular? Give your answer to four decimal places.
Conditional probability:
Event A: Identified as irregular
Event B: It is irregular.
0.0879 = 8.79% probability the detector will identify a random mile of roadway as irregular, which means that [tex]P(A) = 0.0879[/tex]
99% of 3% arre irregulars identified as, which means that [tex]P(A \cap B) = 0.03*0.99 = 0.0297[/tex]
The desired probability is:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0297}{0.0879} = 0.3379[/tex]
0.3379 = 33.79% probability it actually is irregular
7000×3
help me plssßsssssssssssssssss
Answer: 21000
its 21000 hope this helps have a good rest of day/night :D <3
Step-by-step explanation:
In triangle ABC, the measure of angle B is 50 degrees.
Give possible values for the measures of angles A and C if ABC is an acute triangle.
I need help!! thnaks
Answer:
7a + 2b
Step-by-step explanation:
Given
4a + 3b + 3a - b ← collect like terms
4a + 3a + 3b - b
= 7a + 2b
Y = 5x + 2
6y = 18x + 12
What is the value of X?
Step-by-step explanation:
x= 0, y = 2
have a great day
Krissi has $14 in the bank and earns $8 a day. John has 35$ and earns $5 a day when will krissi have more money?
Answer: 8 days
Step-by-step explanation:
K=14+8x
J=35+5x
when K=J they will have the same amount
14+8x=35+5x
8x=21+5x
3x=21
x=7 days until they have the same amount- 8 days until she has more
What is the value of the digit 4 in 149,832?
Answer:
40,000
Step-by-step explanation:
Answer:
It would be 40,000
Explanation:
It is in the ten thousands digit.
(12+9i)+(10+25i)
Simplify?
Answer:
22+34i
Step-by-step explanation:
Brainliest?
Answer:
22+34i
Step-by-step explanation:
(12+9i)+(10+25i)
12+9i+10+25i
12+10+9i+25i
22+34i
I WILL GIVE BRAINLIEST!!! In ABC, m∠A=10 and m∠B=145. Select the triangles that are similar to ABC.
Answer:
See Explanation
Step-by-step explanation:
Given
[tex]\triangle ABC[/tex]
[tex]\angle A = 10[/tex]
[tex]\angle B = 145[/tex]
Required
Similar [tex]\triangle[/tex] to [tex]\triangle ABC[/tex]
The question is incomplete as the other triangles to make comparison from, are not given.
However, general information that could help you are as follows.
The given parameters show that we have to consider AA criterion for selecting similar triangles.
So, you need to check the [missing] given triangles, and pick any that have 10 and 145 (in that particular order) as measures of two of its angles.
Take for instance.
[tex]\triangle DE\ F[/tex]
Where
[tex]\angle D = 10[/tex]
[tex]\angle E = 145[/tex]
See that:
[tex]\angle D = 10[/tex] is similar to [tex]\angle A = 10[/tex]
[tex]\angle E = 145[/tex] is similar to [tex]\angle B = 145[/tex]
This means that:
[tex]\triangle DE\ F[/tex] is similar to [tex]\triangle ABC[/tex] by AA
Answer:
The answer is the 10 degrees on and 25 degreees
Step-by-step explanation:
AP EX
Look at this triangle.
B
8 cm
A А
22 cm
С
Work out length AB.
Answer:
AB=23.40cm
Step-by-step explanation:
(AB)²=(AB)²+(BC)²
(AB)²=22×22+8×8
=484+64
(AB)²=548
AB=23.40 cm
hope it helps...
have a great day!!
PLEASE HELP ILL MARK BRAINLIST The drama club is going on a trip to Brenau University's theatre. The trip costs each member $65. Included in that price is $10 for the cost of renting a charter bus and the cost of 2 plays. Each play costs the same price.
Write an equation representing the cost of the trip for each member. Let x represent the cost of each play.
Determine the price of one play. Solve your equation by showing your work and steps. (10 points)
9514 404 393
Answer:
65 = 10 + 2x . . . equation for trip costx = 27.50 . . . cost of playStep-by-step explanation:
We are told that the costs add up this way:
trip cost = bus rental + 2 × (cost of play)
Given that ...
trip cost = $65bus rental = $10cost of play = xThe above equation can be rewritten as ...
65 = 10 + 2x . . . . . . the desired equation
__
Solving for x, we have ...
55 = 2x . . . . subtract 10
27.50 = x . . . . divide by 2
The cost of one play is $27.50.
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!
Camille is saving for a laptop that costs about $850. To model her savings plan and determine how many more months it will take her to reach her goal, she recently created this equation, where y represents the total amount saved and x represents the number of months. Which statement about her work is true?'
A. Camille used the associative property in step 3.
B. Camille used the multiplication property of equality in step 4.
C. Camille used the subtraction property of equality in step 5.
D. Camille used the substitution property in step 6.
Find the value of x in the triangle shown below.
a.164
b.2
c.6
d.80
Answer:
[tex] \huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{➔}\ [/tex]
by using Pythagoras law:
h²=p²+b²
10²=z²+8²
z²=100-64
z=√36=6
z=6 units.
The height of a triangle is 7 inches greater than the base. The area of the triangle is 225 square inches. Find the length of the base and the height of the triangle.
Answer:
Height is 25in
Base is 18in
Step-by-step explanation:
225=[x*(x+7)]/2=[x^2+7x]/2
450=x^2+7x
x^2+7x-450=0
(x+25)(x-18)=0
Carlos worked at a farmer's market on 4 summer weekends. He worked 5 hours on Saturdays and 4 hours on Sundays. How many hours did Carlos work in all at the farmer's market?
Answer:
36
Step-by-step explanation:
5x4=20
4×4=16
16+20=36
You have
A square piece of confetti has a perimeter of 24 millimeters. How long is each side of the
piece of confetti?
Please no links and please explain!!!
Answer:
6 millimeters
Step-by-step explanation:
All the sides on a square are equal and a square has four sides. For perimeter you add up all the sides which in this case have to add up to 24.
So, 6 + 6 + 6 + 6 = 24
The bell on the clock tower rings every 15 minutes. If the bell has rung 24 times, how many minutes have passed?
Amber chose A. How did she get that answer?
someone please help me with this please
Hi there!
[tex]\large\boxed{P = 22 cm}[/tex]
To find the perimeter, we must find the length of the rectangle.
We know the area is 24, thus:
A = l × w
24 = l × 3
24/3 = l = 8 cm
Find the perimeter using the formula:
P = 2l + 2w
Plug in the solved length and width:
P = 2(8) + 2(3) = 16 + 6 = 22 cm.
Express -36/78 as a rational number with numerator 6:
Answer:
6/9
Step-by-step explanation:
Answer:
6/9 I think that's the answer
On Friday,
1
6
of band practice was spent trying on uniforms. The band spent
1
8
of practice on marching. The remaining practice time was spent playing music.
What fraction of practice time was spent playing music?
Answer:
[tex]\frac{17}{24}[/tex]
Step-by-step explanation:
First, you have to make all of the fractions have a common denominator. You can find the LCM (least common multiple) of 6 and 8.
6, 12, 18, 24 . . .
8, 16, 24 . . .
Their LCM is 24.
So now, change the fractions:
1 4
---- = -----
6 24
Remember, whatever you multiply the bottom by to get to 24 is what you multiply the top number by. You have the make sure the fractions are equivalent.
1 3
---- = -----
8 24
Remember, whatever you multiply the bottom by to get to 24 is what you multiply the top number by. You have the make sure the fractions are equivalent.
So if we have 1 band practice, we know that
24 1
---- = ---- = 1
24 1
So the fraction of practice time spent playing music is:
[tex]\frac{24}{24}-\frac{3}{24} -\frac{4}{24}=\frac{17}{24}[/tex]
HELP ASAP oooooooooooooooooooooooooo
Answer:
The answer is b Maria will run 1.75 miles more than her goal.
Step-by-step explanation:
For this you take the total number of miles divided by miles per day. 17.5 divided by 2.75 is approximately six slightly over. That remaining time is less than 1 day so she can’t do 2.75 over her goal and the other options talk about going under so that leaves us with option two.
Hope this helps.
Suppose the sample space for a probability experiment has 8 elements. If elements from the sample are selected
without replacement, how many different ways can you select all of them?
55
Drive
Remember that "without replacement" means that the items are not returned to the sample space after they are chosen.
Recording
Write your answer in factorial notation.
Answer:
You can select all of them is 40320 ways.
Step-by-step explanation:
Number of arrangements of n elements:
The number of arrangements of n elements, that is, the number of ways in which n elements can be chosen without replacement, is given by:
[tex]A_{n} = n![/tex]
In this question:
8 elements, so:
[tex]A_{8} = 8! = 40320[/tex]
You can select all of them is 40320 ways.
What is the probability of rolling a 2 or a 3 on a regular fair die
Answer:
The possibility of rolling a
3
on a fair die and getting tails on a coil is
1
12
. Based on this probability, there are
12
possible outcomes. As only 1 out of 12 possiblities would get this outcome, it is not a likely outcome.
Step-by-step explanation:
The probability of rolling a
3
on a fair die is
1
6
because there is only one
3
out of
6
numbers. The probability of getting tails on a coin is
1
2
because there are
2
possibilities and tails is one of them. To get the probability of rolling a
3
on a fair die and getting tails on a coil, we multiply their probabilities:
1
6
⋅
1
2
=
1
12
There are
12
possiblities because for each of the
6
possibilites for rolling a die, there are
2
possibilites for flipping a coin.
Surface Area Homework (Help)
Baseball statisticians studied how often triples (a certain event in a baseball game) occurred in professional games played between 1947 and 2017. A 98 percent confidence interval to estimate the slope of the linear regression line relating the year, x, and the mean number of triples per game, y, yielded (−0.006,−0.002). A check shows that the conditions necessary for inference for the slope of the regression line are met.
Based on the confidence interval, which of the following claims is supported?
A. The mean number of triples per game is between 0.002 and 0.006.
B. The number of triples per game has increased, on average, per year.
C. There is no linear relationship between the mean number of triples per game and year.
D. There is a negative linear relationship between the mean number of triples per game and year.
E. A conclusion cannot be made about the relationship between year and mean number of triples per game because the values are close to 0.
Answer: D. There is a negative linear relationship between the mean number of triples per game and year.
Step-by-step explanation: This claim is supported by the interval. The interval contains plausible values for the slope of the linear regression line relating year and mean number of triples per game. Since all the values in the interval are negative, the interval supports the claim that increases in the year are associated with decreases in the mean number of triples per game.