Answer:
B line graph
Explanation:
sorry if I am wrong
Answer:
b
Explanation:
3kg ball traveling at 10 m/s east collides with 5 kg ball traveling at 2m/s east after the collision the balls stick together what is the final velocity of the 3kg ball ?
Answer:
Explanation:
The formula for this is designed around the fact that momentum must be conserved:
[tex][(m_{ball1}*v_{ball1})+(m_{ball2}*v_{ball2})]_b=[(m_{ball1}+m_{ball2})v_{both}]_a[/tex]
This is because they sitck together after they collide. Filling in:
[(3*10)+(5*2)] = [3 + 5]v and
30 + 10 = 8v so
40 = 8v and
v = 5
They are both moving east at a velocity of 5 m/s since they stuck together.
How are galaxies named?
Answer:
Some galaxies are given descriptive names (e.g. "Andromeda", "Whirlpool") if they are particularly distinctive in location or appearance. But most galaxies are known from their designation in a catalogue. One of the earliest catalogues of objects in the sky was made by Charles Messier.
what is the momentum of an object weighing 7.5 kg moving at 1.6 m/s?
Answer:
[tex]momentum = mass \times velocity \\ = 7.5 \times 1.6 \\ = 12 \: kg {ms}^{ - 1} [/tex]
Mass is 7.5 kg
Velocity is 1.6 m/s
we know that,
momentum = mass × velocity
or; momentum =7. 5 kg × 1. 6 m/s
or; momentum = 12 kgms^1
what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees
Answer:
The horizontal component of the vector ≈ -16.06
The vertical component of the vector ≈ 19.15
Explanation:
The magnitude of the vector, [tex]\left | R \right |[/tex] = 25 units
The direction of the vector, θ = 130°
Therefore, we have;
The horizontal component of the vector, Rₓ = [tex]\left | R \right |[/tex] × cos(θ)
∴ Rₓ = 25 × cos(130°) ≈ -16.06
The horizontal component of the vector, Rₓ ≈ -16.06
The vertical component of the vector, R[tex]_y[/tex] = [tex]\left | R \right |[/tex] × sin(θ)
∴ R[tex]_y[/tex] = 25 × sin(130°) ≈ 19.15
The vertical component of the vector, R[tex]_y[/tex] ≈ 19.15
(The vector, R = Rₓ + R[tex]_y[/tex]
[tex]\underset{R}{\rightarrow}[/tex] = Rₓ·i + R[tex]_y[/tex]·j
∴ [tex]\underset{R}{\rightarrow}[/tex] ≈ -16.07·i + 19.15j)
What is the value of x in the triangle? a 45-45-90 triangle with leg length x and hypotenuse length 4
Answer:
[tex]x = 2\sqrt 2[/tex]
Explanation:
Given
[tex]Hypotenuse = 4[/tex]
Required
Find x
Since the triangle is a 45-45-90 triangle, the following relationship exists
[tex]x^2 + x^2 = 4^2[/tex] --- i.e. the other legs are equal
So, we have:
[tex]2x^2 = 16[/tex]
Divide both sides by 2
[tex]x^2=8[/tex]
Take square roots of both sides
[tex]x = \sqrt 8[/tex]
Simplify
[tex]x = 2\sqrt 2[/tex]
Answer:
7√2
Explanation:
Derive the relation between wavelength, frequency and speed of sound.
Explanation:
sorry I need some points foe this
How much power is required to do 180 J of work in 2.4s?
The power required to do 180 J of work in 2.4 s is 75 W.
What is power?Power can be defined as the rate at which work is done.
To calculate the power, we use the formula below
Formula:
P = E/t............. Equation 1Where:
P = PowerE = Energy or workt = Time.From the question,
Given:
E = 180 Jt = 2.4 sSubstitute these values into equation 1
P = 180/2.4P = 75 W.Hence, the power required to do 180 J of work in 2.4 s is 75 W.
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To clean the floor, David exerts a 40 N force on a broom handle to push it 2 m. If the broom handle makes a 40° angle with the floor, what is the work done by David on the broom? If the broom handle were angled at 65° would David do more or less work? Explain your answer. Use the Guess method.
Answer:
Explanation:
Work done = Force * Displacement
There is no displacement vertical so only the horizontal part of force did work.
The horizontal force = Force * cos(angle with floor)
Work done = 40*cos(40°)*2
= 61.28 J
As cos(65°) is less than cos(40°), work done will be less at 65°.
Explique cómo es que las estrellas emiten una radiación, específicamente qué es lo que sucede a nivel atómico
Answer:
Las estrellas se forman debido a la unión de pequeños elementos y partículas como el hidrógeno y el helio que experimentan una fusión nuclear en el núcleo debido a la intensa presión para formar un nuevo átomo (como dos hidrógeno que se combinan para formar un átomo de helio) que es un proceso. que requiere una gran cantidad de energía para comenzar, por lo que cada reacción de fusión produce una gran cantidad de energía que puede mantener la reacción y equilibra la fuerza gravitacional que atrae las masas de las partículas hacia el centro de la estrella
A medida que la energía de la estrella se irradia, la superficie de la estrella cede la energía en forma de calor y luz de manera que debido a la alta temperatura de las partículas de los átomos de los elementos se mueven muy rápida y energéticamente para emitir fotones rápidamente. (alta frecuencia) que se ve como el alto brillo de la estrella
Explanation:
You can do only number 1 only
For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C
Transforma las siguientes unidades utilizando factores de conversión (no vale poner el número solo) a. 85 atm a mmHg b. 60 Pa a atm c. 780 mmHg a Pa d. 740 mmHg a atm
Answer:
a. 6.5 × 10⁴ mmHg
b. 5.9 × 10⁻⁴ atm
c. 1.0 × 10⁵ Pa
d. 0.97 atm
Explanation:
Transformaremos las siguientes unidades utilizando factores de conversión.
a. 85 atm a mmHg
Usaremos el factor de conversion 1 atm = 760 mmHg.
85 atm × 760 mmHg/1 atm = 6.5 × 10⁴ mmHg
b. 60 Pa a atm
Usaremos el factor de conversion 1 atm = 101325 Pa.
60 Pa × 1 atm/101325 Pa = 5.9 × 10⁻⁴ atm
c. 780 mmHg a Pa
Usaremos el factor de conversion 760 mmHg = 101325 Pa.
780 mmHg × 101325 Pa/760 mmHg = 1.0 × 10⁵ Pa
d. 740 mmHg a atm
Usaremos el factor de conversion 1 atm = 760 mmHg.
740 mmHg × 1 atm/760 mmHg = 0.97 atm
A cubic box has a 0.8 meter side. Find the volume of air in the box in cubic meter?
Answer:
[tex]V=0.512\ m^3[/tex]
Explanation:
Given that,
The side of a cubic box, s = 0.8 m
We need to find the volume of air in the box.
We know that,
The volume of a cube is given by :
[tex]V=s^3[/tex]
So,
[tex]V=0.8^3\\\\V=0.8\times 0.8\times 0.8\\\\=0.512\ m^3[/tex]
So, the volume of air in the box is [tex]0.512\ m^3[/tex].
A 1.50 kg ball moving at 4.50 m/s is caught by a 60.0 kg man while the man is standing on ice. How fast will the man / ball combination be moving after the ball is caught by the man?
Answer:
Explanation:
The Law of Momentum Conservation applies, and the formula for us here specific to this problem is:
[tex][(m_bv_b)+(m_mv_m)]_b=[(m_b+m_m)v_{both}]_a[/tex] and filling in:
[(1.50*4.50)+60.0*0)] = [(1.50 + 60.0)v] and
6.75 + 0 = 61.5v so
v = .110 m/s in the same direction as the ball
The absorption of a photon causes a hydrogen atom
to change from the n = 2 to the n = 3 energy state.
What is the energy of the absorbed photon?
A) 4.9 eV
C) 1.9 eV
B) 3.4 eV
D) 10.2 eV
4.9 eV is the correct answer
Hope it helps you ^ _ ^
A man who weighs 75kg on the surface of the earth whose mass is 6*10^24kg. If the radius of earth is 6480km ,calculate the force of attraction between them.
Answer:
718.02N is the answer to the question
A cheerleader jumps off from the shoulders of two of her teammates. They all fell at the same rate, as a result. This type of collision is...?
Answer:
elastic collision
Explanation:
A 350 kilogram car is traveling at a constant velocity of 15 m/s. What is the net force acting on the car?
Answer:
The net force acting on the car is zero.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 350 Kg
Velocity (v) = constant = 15 m/s
Net Force (F) =?
An object moving with a constant velocity is not accelerating. The acceleration of such object is zero. Thus, the net force acting on the object is also zero. This can further be explained as shown below:
Mass (m) = 350 Kg
Acceleration = 0 (since the velocity is constant)
Net Force (F) =?
Force (F) = mass (m) × Acceleration (a)
F = m × a
F = 350 × 0
F = 0
Thus, the net force acting on the car is zero.
A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains in static equilibrium. What is the mass of the meterstick
An ohmic dipole of resistance 100 ohm is crossed by a current of intensity 120 ma. Calculates the voltage across this chemical dipole
Answer:
12.0 Volt
Explanation:
Step 1: Given data
Resistance of the ohmic dipole (R): 100 Ohm
Intensity of current (I): 120 mA (0.120 A)
Step 2: Calculate the voltage (V) across this chemical dipole
To calculate the voltage across the ohmic dipole, we will use Ohm's law.
I = V/R
V = I × R
V = 0.120 A × 100 Ohm = 12.0 V
HELP ME ILL MARK U THE BRAINLIEST
the crane takes 2.5s to raise the box 3.0 m. Calculate the power output of the crane
Answer:
Power = 1800 W
Explanation:
Power = work / time
Power = 4500 / 2.5
Power = 1800 W
Can anybody answer ??
Answer:
C. Electromagnetic wave
Explanation:
Please give me brainliest
Answer:
C. electromagnetic
Explanation:
because 5g uses higher frequency radio waves a type of electromagnetic radiation which are within the spectrum considered safe.
Do solar panels create enough energy to power the car throughout the day?
Answer:
Yes, but only if it's sunny.
Explanation:
As you know, solar panels generate energy through the sun's rays of light (better known as sunlight). Therefore, as long as the sun is shining high in the sky, the car will generate electricity and be able to function. If this vehicle was only powered by solar panels, it would not function during the night, in cloudy areas, and/or in dark places (such as parking garages or home garages).
Hope this helps!
Do only number 3 and thank
Charge = 0.2 Ah is the correct answer...
31) A box is pushed, up a ramp, at constant velocity with a force of 14 N.
What is the magnitude of the friction force working on the box? *
The magnitude of the frictional force working on the box is 14 N.
According to Newtons's first law, an object will continue in its state of rest or state of uniform motion unless it is acted upon by an unbalanced force. This means that motion or acceleration is caused by an unbalanced force.
Since the box is moving at constant velocity, the frictional force on the box and the force that moves the box forward are exactly equal in magnitude but opposite in direction.
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Craig is modeling the discovery of electromagnetism. Which procedure should he use?
A. moving a magnet into a coil of wire in a closed circuit
B. moving a magnet into a coil of wire in an open circuit
C. bringing a compass near a wire that has no electric current
D. bringing a compass near a wire that has an electric current
Answer:
A
Explanation:
moving a magnet into a coil of wire in a closed circuit
Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism. Option A is correct.
What is electromagnetism ?The physical interplay of electric charges, magnetic moments, and the electromagnetic field is known as electromagnetism.
The electromagnetic field can be static, moving slowly, or forming waves.
Craig, move a magnet into a coil of wire in a closed circuit for the discovery of electromagnetism.
Hence, option A is correct.
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Which one of the patterns is the quietest?
Answer:
A
Explanation:
Explain concept of donor levels and accepter levels in extrinsic semiconductors and How can Fermi level be defined for conductors , insulators and semiconductors when temperature increases above zero Kelvin.
Answer:
DONORS: If the material for which it substitutes has more electrons than the original
ACCEPTORS: If the replacement material has fewer electrons than the original material
Fermi level: the point where the probability of finding the last electron is ½
Explanation:
When in a semiconductor material a small fraction of an element is replaced by another with different valences, an excess charge is created.
If the material for which it substitutes has more electrons than the original, there is an excess of electrons, these excess electrons are weakly bound in the material and their orbits are large, in an energy versus moment diagram their energy places them a little more below the conduction band, these materials are called DONORS.
If the replacement material has fewer electrons than the original material, one electron is missing to complete the bonds, so there is a movement of the other electrons, an easier way to analyze this movement of the (n-1) electrons is to suppose that The missing charge has a positive charge and to study its movement, this positive charge is called a hole, its binding energy is small so the orbit of the hole is large, in an energy diagram it is located a little above the band of valence, these are called ACCEPTORS
The Fermi level is defined as the point where the probability of finding the last electron is ½, when the temperature is changed the density of states of the bands changes, therefore the location point moves, but its [probability remains ½
please helpppp... thank u ❤️
Answer:
For Ryan:
[tex]at \: highest \: point : v = 0 \\ velocity = 0 \: {ms}^{ - 1} [/tex]
For the football kicked:
[tex]s = ut - \frac{1}{2} g {t}^{2} \\ for \: range : s = 0 \\ u \sin( \theta) = \frac{gt}{2} \\ t = \frac{2u \sin(\theta) }{g} \\ range(x) = ut \\ x = \frac{ {2u {}^{2} \sin(\theta) }^{} }{g} \\ \frac{50 \times 9.8}{ {2318.9}^{} } = \sin(\theta) \\ \\but \: 0 = u \sin(25) - 2 \times 9.8 \times 50 \\ u = 2318.9 \: {ms}^{ - 1} \\ \theta = 12.2 \degree[/tex]
Answer:
the highest point for the first question is 0 meters per second
the answer for question 2 is 45 degrees
Which situation results in the most attraction between two magnets?
A. The north pole of one magnet is near the south pole of the other
magnet
B. The north pole of one magnet is far away from the north pole of
the other magnet.
C. The north pole of one magnet is far away from the south pole of
the other magnet.
D. The south pole of one magnet is near the south pole of the other
magnet
what are the horizontal and vertical components of a vector that is 25units long with an angle of 130 degrees
Answer:
The horizontal component of the vector is approximately -16.07
The vertical component of the vector is approximately 19.15
Explanation:
A vector quantity is a quantity that posses both magnitude and direction specifications
The magnitude of the given vector, R = 25 units
The direction of the vector, θ = 130°
Therefore the location of the vector, starting from the origin of the Cartesian plane, is in the second quadrant having an angle of 180° - 130° = 50° to the horizontal
Given that the x-coordinate is negative in the second quadrant, we have;
The horizontal component of the vector, Rₓ = The x-coordinate of the vector = R×cos(θ)
∴ The horizontal component of the vector, Rₓ = 25 × cos(130°) = -25 × cos(50°) ≈ -16.07
The horizontal component of the vector, Rₓ ≈ -16.07
The vertical component of the vector, [tex]R_y[/tex] = The y-coordinate of the vector = R×sin(θ)
∴ The vertical component of the vector, [tex]R_y[/tex] = 25 × sin(130°) ≈ 19.15
The vertical component of the vector, [tex]R_y[/tex] ≈ 19.15
The vector can be resolved as R = -16.07·i + 19.15·j