Solve the trigonometric equation over the interval [0, 2π)
[tex] \large{ {cos}^{2} \theta + \sqrt{3} sin \theta cos \theta = 1}[/tex]
Show your work, thanks!​

Answers

Answer 1

Answer:

θ = 0° , 60°

Step-by-step explanation:

[tex]\cos^2\theta + \sqrt{3}\sin \theta \cos \theta = 1[/tex]

Substract both the sides from 1.

[tex]=> \cos^2\theta + \sqrt{3}\sin \theta \cos \theta - 1 = 1 - 1[/tex]

[tex]=> \cos^2\theta + \sqrt{3}\sin \theta \cos \theta - 1 = 0[/tex]

Rearrange the terms in L.H.S.

[tex]=> (\cos^2 \theta - 1 )+ \sqrt{3} \sin \theta \cos \theta = 0[/tex]

Replace the terms in brackets with '-sin²θ' by using the identity (sin²θ + cos²θ = 1).

[tex]=> -\sin^2 \theta + \sqrt{3} \sin \theta \cos \theta = 0[/tex]

Take 'sinθ' common from the whole expression in L.H.S.

[tex]=> \sin \theta(- \sin \theta + \sqrt{3}\cos \theta) = 0[/tex]

Now solve each part separately :-

1) [tex]\sin \theta = 0[/tex]

[tex]=> \theta = \sin^{-1}0 = 0[/tex]

2) [tex]-\sin \theta + \sqrt{3} \cos \theta = 0[/tex]

Divide both the sides by 'cosθ'.

[tex]=> \frac{-\sin \theta + \sqrt{3}\cos \theta }{\cos \theta} = \frac{0}{\cos \theta}[/tex]

[tex]=> \frac{-sin \theta}{\cos \theta} + \frac{\sqrt{3} \cos \theta}{\cos \theta} = 0[/tex]

[tex]=> -\tan \theta + \sqrt{3} = 0[/tex]

Add both the sides with 'tanθ'.

[tex]=> -\tan \theta + \sqrt{3} + \tan \theta = 0 + \tan \theta[/tex]

[tex]=> \tan \theta = \sqrt{3}[/tex]

[tex]=> \theta = \tan^{-1}\sqrt{3} = 60[/tex]

∴ θ = 0° , 60°

Answer 2

Answer:

Solution given:

[tex] \large{ {cos}^{2} \theta + \sqrt{3} sin \theta cos \theta = 1}[/tex]

[tex] 1-sin^{2} \theta+\sqrt{3} sin \theta cos \theta = 1[/tex]

[tex] 1-1 +sin^{2}\theta=\sqrt{3} sin \theta cos \theta = 1[/tex]

[tex] Sin\theta(sin\theta -\sqrt{3}cos\theta)[/tex]

Either

[tex] sin\theta=\sqrt{3} cos \theta [/tex]

[tex] \sqrt{sin\theta}{cos \theta}=\sqrt{3} [/tex]

[tex] Tan \theta =\sqrt{3}[/tex]

[tex] Tan \theta =Tan 60,Tan(180+60),Tan (360+60)[/tex]

[tex] \theta =60°,240°,420°[/tex]

in terms of π is

[tex] \theta =⅓π,\frac{4}{3}π,[/tex]

Or

[tex] Sin\theta=1[/tex]

[tex]Sin\theta=Sin0° ,Sin180°[/tex]

In terms of π is

[tex]\theta=0π,π[/tex]

so

[tex]\theta=0π,⅓π,π,\frac{4}{3}π,[/tex]


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Answers

Answer:

There won't be enough arrangement

Step-by-step explanation:

Given

[tex]Letters = 2[/tex]

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Required

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[tex]Total = 676000[/tex]

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[tex]676000 < 800000[/tex]

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

take  angle A as reference angle

using sec rule

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Answers

Answer:

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Step-by-step explanation:

-3(-7) = -3 * -7

Multiply

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Mr. Carr is hiring a plumber to repair his sink. The cost of Plumber T is shown in the table.

A table titled Plumber T Costs is shown. It has three columns and two rows. Row one is labeled Hours, h. Row two is labeled Cost, c. One hour, one hundred twenty-eight dollars. Two hours, two hundred fifteen dollars. Three hours, three hundred two dollars.

Part A. What is the initial cost and hourly rate of Plumber T?

Part B. Write an equation to represent the function shown in the table.

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The hourly rate of plumber T is $87 per hour and have an initial cost of $41.

Linear equation

Linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial amount.

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Answers

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Answers

Answer:

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Step-by-step explanation:

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x = 30

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x = 30

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25

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Answer:

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Answers

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Item 3
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143 ft²

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Answers

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Step-by-step explanation:

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Answers

Answer:

$48

Step-by-step explanation:

Cora earns $20 for each lawn

She gives her father $12 EACH DAY for his lawn mower

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Answers

Answer:

D

Step-by-step explanation:

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Answers

Step-by-step explanation:

Given :-

4x + 8y = 20 -4x + 2y = -30

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[tex]: \implies[/tex] y = -1

Put it (i) :-

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[tex]: \implies[/tex] 4x = 20 + 8

[tex]: \implies[/tex] 4x = 28

[tex]: \implies[/tex] x = 28/4

[tex]: \implies[/tex] x = 7

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