Answer:
0.32 mole
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) = 0.31 mole
Initial pressure (P₁) = 742 torr
Final pressure (P₂) = 759 torr
Final mole (n₂) =?
The final mole of the gas in the drum can be obtained as follow:
P₁/n₁ = P₂/n₂
742 / 0.31 = 759 / n₂
Cross multiply
742 × n₂ = 0.31 × 759
742 × n₂ = 235.29
Divide both side by 742
n₂ = 235.29 / 742
n₂ = 0.32 mole
Thus, the final mole of the gas in the drum is 0.32 mole
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Classify the following alcohol as primary,
secondary or tertiary.
OH
A. primary
B. secondary
C. tertiary
Answer:
The correct answer is C, tertiary.
The following alcohol is a tertiary alcohol. Hence, option C is correct.
What is primary alcohol?A primary alcohol is a compound in which a hydroxy group, ‒OH, is attached to a saturated carbon atom which has either three hydrogen atoms attached to it or only one other carbon atom and two hydrogen atoms attached to it.
Here, the carbon atom holding the OH group is attached directly to three alkyl groups.
Hence, the following alcohol is a tertiary alcohol.
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What chemical test to differentiate propane and propene
Answer:
If you add bromine water, an aqueous solution of bromine, to the test tubes, you can tell which is propene, the alkene. The bromine reacts with and saturates the double bonds in alkenes, and so decolourises.
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The following substances dissolve when added to water. Classify the substances according to the strongest solute-solvent interaction that will occur between the given substances and water during dissolution. Drag the appropriate items to their respective bins. Not all bins may contain an item and some bins may contain multiple items.NH3 AlBr3 CH3OH AlCl
Answer:
NH3 ------dipole - dipole forces
CH3OH ------ dipole - dipole forces
AlBr3 ------- ion - dipole forces
AlCl3 ------- ion - dipole forces
Explanation:
Let us recall that water is a polar molecule. This means that water has a positive as well as a negative end. NH3 also has a dipole. The interaction between solute and solvent dipoles leads to the dissolution of NH3 in water. Hence the strongest intermolecular force here is dipole - dipole forces.
Similarly, CH3OH possesses a polar -O-H group which can interact with water via dipole - dipole interaction as its strongest intermolecular force.
As for AlBr3 and AlCl3, the two substances dissociate into ions in solution and these ions interact with the dipole in water via ion - dipole interaction as its strongest intermolecular interaction.
Answer:
Dipole -dipole forces :Ammonia [tex]NH_3[/tex]
Aluminium Chloride [tex]AlCl[/tex]
Methanol [tex]CH_3OH[/tex]
Ion dipole forces :Aluminium bromide [tex]AlBr_3[/tex]
Explanation:
Because water is not in ionic form it can only forms dipole forces which are strongest. Methanol, Ammonia and AlCl are also dipoles not ions . Thus dipole dipole forces exist.
On the other hand, aluminium bromide are ionic and it can forms ion dipole bonds with water.
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James made a poster showing the two body systems that regulate a person's pulse. Which two systems did james represent on his poster? F nervous and circulatory G resiratoty and endocrine systems H circular and digestive system I digestive and nervous system
Answer:
F
Explanation:
An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its
final volume is 1.75 L. What was the initial temperature?
Answer:
[tex]T_1=-91.18\°C[/tex]
Explanation:
Hello there!
In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:
[tex]\frac{T_1}{V_1}= \frac{T_2}{V_2}[/tex]
Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:
[tex]T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C[/tex]
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I have to make question longer this question
(Answer the question all the way at the bottom)
\
Do you breathe air?
Answer:
Of course I breathe air.
Explanation:
I'm not a fish.
Answer:
[tex]ummmmmmm \: yes \: [/tex]
plz, help me I'm so confused!
(this is also science)
Answer:
Well, there is no photo...
Explanation:
A diver takes a balloon with a volume of 2.5Lfrom the surface, where the pressure is 1.0 atm, to a depth of 20m, where the pressure is 3.0 atm. What happen to the volume of the balloon? What if the end of the subnerged balloon is on a long pipe that goes to the surface and is attached to another balloon?
Answer:
The explanation is given below:
Explanation:
As we know that the volume is inversely proportional to the volume. If the pressure is rising from 1 atm to 3 atm so the volume of the ballon would decrease
P_1V_1 = P_2V_2
1.0 × 2.5L = 3 × V_2
V_2 = 0.833L
Since the air is moving from high pressure to low pressure and the two ballons are interconnected via a long pipe so the movement of the air is from bottom to top
Aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce
a precipitate of copper (II) phosphate and aqueous potassium sulfate.
Answer:
CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄
Explanation:
The question is missing but I think it must be about writing and balancing the equation.
Let's consider the unbalanced equation for the reaction that occurs when aqueous copper (II) sulfate reacts with aqueous potassium fluoride to produce a precipitate of copper (II) fluoride (I fixed a mistake here) and aqueous potassium sulfate. This is a double displacement reaction.
CuSO₄(aq) + KF(aq) = CuF₂ + K₂SO₄
Since only K and F atoms are not balanced, we will get the balanced equation by multiplying KF by 2.
CuSO₄(aq) + 2 KF(aq) = CuF₂ + K₂SO₄
A solution has a
pH of 2.5.
Answer the following questions.
pOH =
[H]=
[OH]=
Answer:
pOH = 11.5
[H⁺] = 0.003 M
[OH⁻] = 3 × 10⁻¹² M
Explanation:
The computation is shown below:
Given that
pH = 2.5
Based on the above information
We know that
pH + pOH = 14 ⇒ pOH = 14 - pH
pOH = 14 - 2.5
pOH = 11.5
[H⁺] = 10^(-pH) = 10^(-2.5)
[H⁺] = 0.003 M
[OH⁻] = 10^(-pOH)
= 10^(-11.5)
= 3 × 10⁻¹² M
[OH⁻] = 3 × 10⁻¹² M
Hence, the above represents the answer
Atoms are the smallest unit of an element that holds the physical identity of that element. T or F
Answer:
True
Explanation:
How many moles would be present in a gas contained in a 100.0 mL vessel at 25.0oC at a pressure of 2.50 atm?
Answer:
n = 0.0102 mol.
Explanation:
Hello there!
In this case, according to the ideal gas law, which allows us to set up a relationship among volume, pressure, temperature and moles, we can define it as:
[tex]PV=nRT[/tex]
Thus, given the volume in liters (0.1000 L), temperature in kelvins (298.15 K) and pressure in atmospheres (2.50 atm), we can solve for moles as shown below:
[tex]n=\frac{PV}{RT}[/tex]
Thereafter, we plug in the aforementioned values to obtain:
[tex]n=\frac{2.50atm*0.1000L}{0.08206\frac{atm*L}{mol*K}*298.15K}\\\\n=0.0102mol[/tex]
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There are 3 gases in a container, methane has a partial pressure of 1.23 atm, ethane's partial pressure is 1.48 atm and an unknown pressure of propane. The pressure in the container was measure to be 4.43 atm. What is the partial pressure of propane?
A) 1.72
B) 1.35
C) 1.69
D) 1.53
Answer:
A) 1.72 atm
Explanation:
Dalton's Law of Partial Pressures
[tex]P_{t} = P_{1} + P_{2} + P_{3} ....[/tex]
4.43 atm = 1.23 atm + 1.48 atm + x
x = 4.43 atm - (1.23 atm + 1.48 atm)
x = 1.72 atm
Explain why a city that receives 10 hours more light each day has colder average temperatures. Explain
Explanation:
This would be similar to how the poles work in the North and South. Due to their placement, they recieve much more sun light than the rest of the Earth since we rotate horizontally. However, their placement also makes them farther from the sun than the rest of Earth, therefore not receiving as much heat.
how many atoms of carbon are in a diamond with a mass of 0.568 g?
Answer:
There are 2.85 x 10^22 atoms of carbon in a diamond with a mass of 0.568 g.
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Sally rides her bike to the store to get some Skittles. The store is 5 km
away. If it takes her 10 minutes to get to the store what is her average
speed?
0.5 km/hr
0.5 mph
0.5 km/min
5 km/min
Answer:
Sally's average speed is 0.5 km/min
Explanation:
speed=distance/time
so, 5km/10min=0.5 km/min
what do protons determine about an element
Answer:
The number of protons in one atom of an element determines the atom's identity, and the number of electrons determines its electrical charge. The atomic number tells you the number of protons in one atom of an element. It also tells you the number of electrons in a neutral atom of that element.
Explanation:
USA test prep wave 1 performance task
Answer:
Performance Tasks 188; Instructional Videos 75
Explanation:
How many moles of solute are in 53.1 mL of 12.5M HCI?
PLEASE HELP
How many chlorine atoms are needed to satisfy the octet rule when forming an ionic compound with a cation of charge 3+?
Answer:
not the right answer but I need this for the answer the question thing
How is gravity an attractive force?
A dilute solution of hydrofluoric acid has a volume of 3.0 L and a molarity of 3.0
M. If the original solution had a volume of 2.0L, what was the initial molarity?
Answer:
4.5M
Explanation:
The solution was diluted from 2.0L to 3.0L, the dilution factor was:
3.0L / 2.0L = 1.5.
That means the solution was diluted 1.5 times.
As the final molarity of the diluted solution is 3.0M, the initial molarity of the solution was:
3.0M * 1.5 =
4.5M is the molarity of the original solutionCalculate the number of copper atoms in a 63.55 g
sample of copper.
Answer:
there are N_A, "Avogadro's number" of copper atoms in a 63.55*g mass of copper wire. And N_A, "Avogadro's number" = 6.022xx10^23 individual copper atoms. I look on the Periodic Table, and at Z=29, i.e. copper, the quoted atomic mass is 63.55*g.
Explanation:
One mole of every substance contains 6.022×10²³ atoms. The atomic mass of copper is 63.55 g. Thus it is one mole of copper which contains copper 6.022×10²³ atoms.
What is copper?Copper is 29th element in periodic table. It is a transition metal classified into d-block. Transition metals are named so because they in between the metals and non-metals in periodic table.
Transition metals have varying oxidation state. Copper exists in +1, +2 and +3 oxidation states.
Any substance containing 6.022×10²³ atoms is called one mole of that substance. This number is called Avogadro number. Hence one mole of each element contains avogadro number of its atoms.
Similarly one mole of each compound contains 6.022×10²³ number of molecules. Here, the atomic mass of copper is 63.55 g. That is one mole of copper weighs 63.55 g. Hence, number of atoms in 63.55 g of copper is 6.022×10²³ atoms.
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1.1
Which of these is NOT an intermolecular force?
A
Covalent bonding
B
Hydrogen bonding
с
London / dispersion forces
Dipole - dipole forces
1.2
London forces are found between ...
A two polar molecules.
B two non-polar molecules.
C a polar molecule and a non-polar molecule.
Da polar molecule and an ionic substance.
(2
1.3 Which of the following compounds have a shape that can be described as
trigonal bipyramidal?
A
CH4
B
PCL5
с
SF6
D
BF3
(2)
1.4
Which of the following have the same molecular geometry?
CO2, H20, BeCl2 and N20
A
CO2, BeCl2 and N2O
B
H20 and N20 only
C
H20, BeCl2 and CO2
CO2 and N20 only
(2)
Answer:
1.1) Covalent bonding
Explanation:
All of the above are intermolecular forces except covalent, which is intramolecular.
If a sample of oxygen gas has a pressure of 810 torr at 298 K, what will be its pressure if its temperature is raised to 330K?
Answer:
The pressure is = 897 torr
Explanation:
We use Gay Lussac's Law.
A percent composition analysis yields
22.6% phosphorus (P) and 77.4%
chlorine (CI). What is the empirical
formula for the compound?
А
B
P2C17
PCI:
Answer:
PCl₃
Explanation:
To determine the empirical formula of a compound, we need to follow a series of steps.
Step 1: Divide each percent composition by the atomic mass of the element
P: 22.6/30.97 = 0.729
Cl: 77.4/35.45 = 2.18
Step 2: Divide all the numbers by the smallest one, i.e. 0.729
P: 0.729/0.729 = 1
Cl: 2.18/0.729 ≈ 3
The empirical formula of the compound is PCl₃.
In the hydrogenation of ethylene using a nickel catalyst, the initial concentration of ethylene is 1.65 mol⋅L−1 and its rate constant (k) is 0.0014 mol⋅L−1⋅s−1 . Determine the rate of reaction if it follows a zero-order reaction mechanism.
Answer:
.0014 M/s ( (mol*L^-1 / s) )
Explanation:
Since the rate law of a zero order reaction is Rate = k[A]^0, the rate is .0014 * (1.65)^0 = .0014
Meat-eating animals are:
decomposers
second-order consumers
producers
first-order consumers
HELP
Answer:
decomposers
Explanation:
Is carbonic acid (H2CO3) soluble in water?
Answer:
it is soluble in water
Explanation:
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Determine the enthalpy of neutralization in Joules/mmol for a solution resulting from 19 mL of 1 M NaOH solution and 19 mL of a HCl with the same molarity. If separately, each had a temperature of 28.6 degrees Celsius, and upon addition, the highest temperature reached by the solution was graphically determined to be 37.3 degrees Celsius. Round to the nearest whole number.
Answer:
[tex]\Delta _{neutralization}H=-73\frac{J}{mmol}[/tex]
Explanation:
Hello there!
In this case, by considering this calorimetry problem, it is possible to realize that the heat released by the reaction between HCl and NaOH is absorbed by the reaction mixture, which can be assumed to have the same density and specific heat of pure water; thus, we calculate this heat as a function of the specified temperature change:
[tex]Q_{rxn}=-Q_{solution}\\\\Q_{rxn}=-m_{solution}C_{solution}(T_2-T_1)[/tex]
Thus, we plug in the data, by also considering that the total volume of solution is 19mL+19mL=38mL:
[tex]Q_{rxn}=-(38mL*\frac{1g}{1mL} )(4.184\frac{J}{g\°C}) (37.3\°C-28.6\°C)\\\\Q_{rxn}=-1383.2J[/tex]
Next, since the reaction between NaOH and HCl is:
[tex]NaOH+HCl\rightarrow NaCl+H_2O[/tex]
Whereas there is 1:1 mole ratio of NaOH to HCl, we infer they both react with the same moles, defined by the volume and molarity:
[tex]n_{rxn}=0.019L*1mol/L\\\\n_{rxn}=0.019mol[/tex]
Finally, to compute the enthalpy of neutralization we divide the total heat due to the reaction by the reaction moles to obtain:
[tex]\Delta _{neutralization}H=\frac{Q_{rxn}}{n_{rxn}=}\\\\ \Delta _{neutralization}H=\frac{-1383.23J}{0.019mol}\\\\\Delta _{neutralization}H=-72801.6\frac{J}{mol}*\frac{1mol}{1000mmol}\\\\\Delta _{neutralization}H=-73\frac{J}{mmol}[/tex]
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