The largest pieces being dragged along the streambed are undergoing the process called ________. pushing saltation traction suspension solution

Answer:

they have the same molar solubility at 44.5 degrees celsius

Answer: D.Solar power produces no carbon dioxide

Explanation:

Solar power produces no carbon dioxide. The solar panel's carbon footprint is roughly 20 times less than the carbon output of coal-powered electricity sources. Hence, option D is correct.

A solar power plant uses sunlight to get energy. As the sunlight is ample and renewable, one can use it to power up the home and business premises.

Biomass energy is an energy source that comes from plant materials such as wood, corn, sugarcane, and grasses, etc.

However, it needs less capital investment than setting up a solar power plant.

Solar Energy: The major advantage of solar is that the source of energy (sun) is free.

Hence, option D is correct.

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Molar mass of CH2NH2COOH - 75

Given mass of CH2NH2COOH - 30

Moles of CH2NH2COOH = Given mass/ Molar mass

moles of CH2NH2COOH = 30/75 = 0.4 mol

One mole of CH2NH2COOH contains 32 gram of oxygen

0.4 mole of CH2NH2COOH will contain = 0.4 × 32= 12.8 g of oxygen

Answer- the mass of oxygen in 30 g of CH2NH2COOH is 12.8 gram!

The mass of oxygen in 30 g of CH₂NH₂COOH is 12.8 g.

We'll begin by calculating the mass of 1 mole of CH₂NH₂COOH and the mass of oxygen in the compound.

1 mole of CH₂NH₂COOH = 12 + (2×1) + 14 + (2×1) + 12 + 16 + 16 + 1 = 75 g

Mass of oxygen in CH₂NH₂COOH = 16 + 16 = 32 g

Thus,

75 g of CH₂NH₂COOH contains 32 g of Oxygen.

With the above information, we can obtain the mass of oxygen in 30 g of CH₂NH₂COOH. This can be obtained as follow:

75 g of CH₂NH₂COOH contains 32 g of Oxygen.

Therefore,

30 g of CH₂NH₂COOH will contain = (30 × 32) / 75 = 12.8 g of Oxygen.

Thus, 12.8 g of Oxygen is present in 30 g of CH₂NH₂COOH

Calculate the mass of oxygen in 30 g of CH₂NH₂COOH.

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Answer:

Dispersion forces

that is the answer

Answer:

Green

Explanation:

pH : < 3 = Red

pH : 3 - 6 = Orange or yellow

pH : 7 = Green

pH : 8 - 11 = Blue

Answer:

76.0 g

Explanation:

Step 1: Write the balanced equation

2 HCl + Ca(OH)₂ ⇒ CaCl₂ + 2 H₂O

Step 2: Calculate the moles corresponding to 50.0 g of HCl

The molar mass of HCl is 36.46 g/mol.

50.0 g × 1 mol/36.46 g = 1.37 mol

Step 3: Calculate the number of moles of CaCl₂ produced from 1.37 moles of HCl

The molar ratio of HCl to CaCl₂ is 2:1. The moles of CaCl₂ produced are 1/2 × 1.37 mol = 0.685 mol.

Step 4: Calculate the mass corresponding to 0.685 moles of CaCl₂

The molar mass of CaCl₂ is 110.98 g/mol.

0.685 mol × 110.98 g/mol = 76.0 g

Answer:

10.65 moles

Explanation:

O2:H2O

8:6

14.2:x

x= 10.65 moles

Answer:

5.56g of FeCl2 can be produced

Explanation:

To solve this question we must find the moles of each reactant. With the moles and the chemical equation we can find limiting reactant. With limiting reactant we can find the moles of FeCl2 and its mass as follows:

Moles HCl:

1.5L * (0.25mol / L) = 0.375 moles HCl

Moles Fe -Molar mass: 55.845g/mol-

2.45g * (1mol / 55.845g) = 0.0439 moles Fe

For a complete reaction of 0.375 moles HCl are needed:

0.375 moles HCl * (1mol Fe / 2mol HCl) = 0.1875 moles Fe

As there are just 0.0439 moles Fe, Fe is limiting reactant

1mol of Fe produce 1 mole of FeCl2, 0.0439 moles Fe produce 0.0439 moles of FeCl2. The mass is:

Mass FeCl2 -Molar mass: 126.751g/mol:

0.0439 moles Fe * (126.751g / mol) =

Answer:

The minimum mass of ethylene glycol = 6.641 Kg

Explanation:

[tex]\Delta T_f= T_f-T_f'\\T_f'=T_f-\Delta T_f[/tex]

Where T_f = freezing point of pure solvent water, 0°C

T_f'= Freezing point of solvent after mixture

K_f = Freezing point depression constant = 1.86 °C/m

Moecular weight of ethylene glycol = 60 g/mol

Weight of ethylene glycol = 14.5 Kg= 14.5×10^3 g

molality of ethylene glycol

[tex]m = \frac{weight}{mol.wt} \times\frac{1000}{V}[/tex]

Substitute the values to calculate m

[tex]m = \frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]

by formula

[tex]0-(-14.2) =1.86\frac{w}{60} \times\frac{1000}{14.5\times1000}[/tex]

calculating we get w = 6641.93 g

Therefore, The minimum mass of ethylene glycol = 6.641 Kg

Answer:

11 grams of atoms are in 0.35 moles of oxygen.

Answer:

the chemical name for soap is a lot, for example there is Sodium Talowate, Sodium Palmate, and even Sodium Cocoate, but there is more

Explanation:

the chemical formula for it is RCOO-Na+ it has 12 - 18 carbon atoms.

Answer:1.12 g

Explanation:Molar mass of compound ​FeSO4(NH4)2SO4.6H2O = 392.14 g mol-1

Number of moles of compound in 7.84g sample = 7.84 g/ 392.14 g mol-1

                                                                       = 0.02 mole

1 mole of sample contain 1 mole of Fe

So, 0.02 mole of sample would contain 0.02 moles of Fe.

Mass of Fe equivalent to 0.02 mole = 0.02 mol x molar mass of Fe

                                                    = 0.02 mol x 55.84 g mol-1

                                                   = 1.12 g

Answer:

methyl ethanoate

Explanation:

To name the compound given above, the following must be obtained:

1. Determine the functional group of the compound.

In this case, the functional group is R–COOR' where R and R' are alkyl groups. Thus, the compound is an ester.

2. Determine the longest chain before the functional group and the compound after the functional group.

In this case, the longest chain before the functional group is carbon 2 i.e ethane and the compound after the functional group is methyl.

3. Name the compound by naming the compound after the functional group first, followed by the compound before the functional group and ending it with –oate.

This is illustrated below:

After the functional group => methyl

Before the functional group => ethane

Name of the compound => methyl ethanoate

Answer:

From the diagram above...

its explicitly show a compound that's dissociating or Decomposing into its Constituents.

Answer ....OPTION C.

Answer:

The correct answer is "142 g".

Explanation:

According to the question,

⇒ [tex]Cu^2+(aq)+2e^ ------> Cu(s)[/tex]

where,

Z = 2

F = 96500c

C = 30 A

t = 4h

 = [tex]4\times 60\times 60[/tex]

 = [tex]14400 \ sec[/tex]

We know that,

Atomic mass of Cu(M) = 63.5 g/mole

Now,

⇒ [tex]W=\frac{Mct}{ZF}[/tex]

On putting the values, we get

        [tex]=\frac{63.5\times 30\times 14400}{2\times 96500}[/tex]

        [tex]=\frac{27432000}{193000}[/tex]

        [tex]=142 \ g[/tex]

Answer:

B. Ultraviolet

Explanation:

UV has a higher frequency and shorter wavelength than visible light

Answer:

D0wnload Phot0Math......................

Explanation:

Answer:

Increasing its mass to twice its original value

Explanation:

Pls mark me brainliest

Answer:

Explanation:

Given that:

The mass of sodium crystal = 4.14 g

As a result, the number of atoms in the sodium crystal is:

[tex]=4.14 \g \times \dfrac{ 1 \ mol}{23.0 \ g }\times \dfrac{6.023 \times 10^{23} \ atoms}{1 \ mol}[/tex]

= 1.084 × 10²³ atoms

In the valence orbital of the sodium atom, there is just one electron.

As a result, the number of molecular orbitals produced by these atoms is= 1.084 × 10²³ molecular orbital

Because valence bands are created from occupied molecular orbitals, the number of valence bands created from the aforementioned molecular orbitals is:

[tex]= \dfrac{ 1.084 \times 10^{23}}{2}[/tex]

= 5.420 × 10²² orbitals.

Answer:

17188 years

Explanation:

Recall the formula;

0.693/t1/2 = 2.303/t log(No/N)

t1/2 = half life of 14C

No = initial activity of 14C

N = activity of 14C at time t

t = age of the sample

Substituting values

0.693/5730= 2.303/t log(160/ 20)

1.21 * 10^-4= 2.0798/t

t = 2.0798/1.21 * 10^-4

t = 17188 years

Answer:

The explanation according to the given question is summarized below.

Explanation:

Given:

Tris,

= 250 mM

Glycine,

= 1.92 M

According to the solution,

For the dilution pf 10X to 1X buffer, we get

= [tex]1 \ ml \ of \ 10X \ buffer +9 \ ml \ of \ distilled \ water[/tex]

= [tex]10[/tex]

i.e.,

⇒ [tex]10X \ to \ 1X=1:10 \ dilution[/tex]

Now,

⇒ [tex]10X (250 \ mM\ Tris \ HCl, 1.92M\ Glycine, and\ 1 \ percent (\frac{w}{v} ) SDS) ---->1X(25 \ mM \ Tris \ HCl,0.193 M\ Glycine, and \ 0.1 \ percent(\frac{w}{v} )SDS)[/tex]

Answer:

~69.744 moles of Ca

Explanation:

Using Avogadro's constant , we know that:

1 mole = 6.022 x 10^23 atoms

S0, the number of moles in 4.20 x 10^25 atoms of Ca:

=(4.20 x 10^25 x 1 )/(6.022 x 10^23)

~69.744 moles of Ca

Q2:How many atoms are in 0.35 moles of oxygen?

1 mole = 6.022 x 10^23 atoms

S0, the number of atoms in 0.35 moles of  oxygen:

=[0.35 x (6.022 x 10^23)]

=2.1077 x 10^23 atoms of Oxygen

Hope it helps:)

Answer:

Respiration

Explanation:

Energy, steam and carbondioxide formed.

The question is incomplete, the complete question is;

Which produces the greatest number of ions when one mole dissolves in water? a. NaCl b. NH4Cl c. NH4NO3 d. Na2SO4

Answer:

Na2SO4

Explanation:

If we consider the compounds listed in the options one after the other;

NaCl produces two moles of ions in solution

NH4Cl produces two moles of ions in solution

NH4NO3  produces two moles of ions in solution

Na2SO4 produces three moles of ions in solution

We can see that Na2SO4 produces the greatest number of ions when one mole of the substance  is dissolved in water, hence the answer above.

Answer:

Fusion has powered the sun for billions of years.Yet despite decades of effort, scientists and engineers have been unable to generate sustained nuclear fusion here on Earth. In fact, it's long been joked that fusion is 50 years away, and will always be.

Answer:

HNO3 is a potent acid, a base, a nitrating agent and a heavy oxidising agent at times. In the presence of a stronger acid, it serves as a base.

Explanation:

Answer:

It is a strong acid

Explanation:

Answer:

Linear

Explanation:

Answer:

The molality is "6.86 m".

Explanation:

Given:

Mass of of HCL,

= 25 g

Mass of water,

= 100 g

Density,

= 1.19 g/mL

Total mass of solution,

= 125 g

Now,

The number of moles of HCl will be:

= [tex]\frac{25}{36.458}[/tex]

= [tex]0.6857[/tex]

The solution volume will be:

= [tex]\frac{125}{1.19}[/tex]

= [tex]105.04 \ mL[/tex]

hence,

The molality will be:

= [tex]\frac{No. \ of \ moles \ of \ solute}{Mass \ of \ solvent (Kg)}[/tex]

= [tex]\frac{0.6857}{0.1}[/tex]

= [tex]6.857 \ m[/tex]

or,

= [tex]6.86 \ m[/tex]

Answer:

The entropy change in the environment is 3.62x10²⁶.

Explanation:

The entropy change can be calculated using the following equation:

[tex]\Delta S = \frac{Q}{k_{B}}(\frac{1}{T_{f}} - \frac{1}{T_{i}})[/tex]

Where:

Q: is the energy transferred = 5.0 MJ

[tex]k_{B}[/tex]: is the Boltzmann constant = 1.38x10⁻²³ J/K  

[tex]T_{i}[/tex]: is the initial temperature = 1000 K

[tex]T_{f}[/tex]: is the final temperature = 500 K

Hence, the entropy change is:

[tex] \Delta S = \frac{5.0 \cdot 10^{6} J}{1.38 \cdot 10^{-23} J/K}(\frac{1}{500 K} - \frac{1}{1000 K}) = 3.62 \cdot 10^{26} [/tex]                                    

Therefore, the entropy change in the environment is 3.62x10²⁶.

I hope it helps you!