which best represents the number of moles in exactly 130 grams of potassium metal?

Answers

Answer 1

Answer:

if by EXACTLY means 130.0000, then the answer is 3.3250

by EXACTLY means 1.299 <Kmass<1.301 then the answer is 3.33

EXPLANATION

which best represents the number of moles in exactly 130 grams of potassium metal?

the elemental mass of K is 39.098

so exactly 130 divided by 39.098 = 3.3250

Answer 2

if by EXACTLY means 130.0000, then the solution is 3.3250 by EXACTLY means 1.299 <Kmass<1.301 is 3.33

What is Potassium Metal?

Potassium metal responds rapidly with atmospheric oxygen to create flaky white potassium peroxide in exclusively moments of exposure.

It stood preferably isolated from potash, the ashes of plants, from which its appellation derives.

In the systematic table, potassium is one of the alkali metals, all of which have a single valence electron in the outermost electron shell,

That is easily drawn to produce an ion with a positive charge a cation, that connects with anions to form salts. Potassium in disposition materializes only in ionic salts.

When the elementary mass of K is 39.098

Therefore, exactly 130 divided by 39.098 is = 3.3250

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Answer:

Explanation:

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Answer:

Explanation:

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Answer:

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Answer:

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You have a sealed 2 liter flask that contains nothing but water and carbon dioxide. The flask is half-filled with liquid water, has a temperature of 25°c, and the overall pressure within the flask is 0. 1 atm. How many moles of co2 are in the flask? at this temperature, you may take the kh value for co2 as 0. 033 m / atm.

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In this exercise we want to calculate the amount of moles, so this is going to be:

[tex](4.6)(10^{-3}) \ mols \ CO_2[/tex]

Knowing that Henry's law is given by:

[tex]C = KHP[/tex]

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C = Concentration  KH = Henry's law constant = [tex]0.033 m/atm[/tex]P = partial pressure = [tex]0.07 atm[/tex]

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[tex]CO_2 = 0.1 \ atm - 0.03 \ atm = 0.07 \ atm[/tex]

Now using Henry's law, we find the concentration:

[tex]C = (0.033)*( 0.07) = (2.31)*(10^{-3})[/tex]

Converting to moles of CO2, we have:

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Answers

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Trust me on this :)

3 sentances
Heat can be lost from the body in the same way that heat is lost from Earth's surface. Based on what you know about heat transfer from Earth's surface to the atmosphere, describe how the body can lose heat in each of these ways (radiation, conduction, convection).

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the body can losse heat through Radiation,since Radiation does not involve the direct contact of two mediums

Guys I need help please! Do not scam me ok? Thanks:). Please take a screenshot and send thanks.

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Answer:

thx for the points

Explanation:

no need brainliest

ΕΛΑ
1
a
C
Copper(II) nitrate decomposes on heating. The reaction is endothermic.
2Cu(NO),(s) → 2CuO(s) + 4NO2(g) + 0,(9)
Sketch a reaction pathway diagram for this reaction to include the
activation energy
[3]
b Draw an energy cycle to calculate the standard enthalpy change for
this reaction, using enthalpy changes of formation.
[3]
Calculate the enthalpy change for this reaction using the following
enthalpy changes of formation.
AH, [Cu(NO, ),(s)] = -302.9 kJ mol-'
AH, [CuO(s)] =-157.3 kJ mol-!
AH [NO,(g)] = +33.2 kJ mol-!
[3]
d Copper(II) sulfate is soluble in water. A student dissolved 25.0 g of
copper(II) sulfate in 100 cm of water in a polystyrene beaker stirring
all the time. The temperature of the water fell by 2.9 °C.
i Calculate the enthalpy change of solution of copper(II) sulfate.
(specific heat capacity of water = 4.18 Jg1 °C ; relative
molecular mass of copper(II) sulfate = 249.7 g mol-')
[3]
ii Suggest one source of error in this experiment and explain how
the error affects the results.
[2]
[Total: 14]

Answers

This problem provides information about the decomposition of copper(II) nitrate to copper(II) oxide and dinitrogen monoxide; for example, it is endothermic, the enthalpies of formation and the chemical reaction, as well as copper (II) sulfate which when dissolved in water, exhibits a temperature decrease:

[tex]2Cu(NO_3)_2(s) \rightarrow 2CuO(s) + 4NO_2(g) + O_2(g)[/tex]

First of all, we can draw the reaction pathway as shown on the attached figure, by taking into account the positive enthalpy change as it is endothermic, so that the products turn out with higher energy than the reactants, for it to be positive. In addition, keep in mind that top point is the activation energy the reaction needs to take place.

Next, we calculate the enthalpy change for this reaction by using the general formula which subtracts the enthalpy of formation of products and reactants with each species' correct stoichiometric coefficient:

[tex]\Delta H=2\Delta _fH_{CuO}+4\Delta _fH_{NO_2}+\Delta _fH_{O_2}-2\Delta _fH_{Cu(NO_3)_2}[/tex]

So we plug in the given enthalpies of formation:

[tex]\Delta H=2(-157.3)+4(33.2)+(0)-2(-302.9)=424.0 kJ/mol[/tex]

Finally, we go over the calorimetry experiment, whereby the total heat absorbed by the copper(II) sulfate is calculated via the general heat equation, which includes the heat loss from the solution of water and the salt:

[tex]Q_{rxn}=-mC_w\Delta T\\\\Q_{rxn}=-(100+25)g*4.18\frac{J}{g\°C}*-2.9\°C=1515.25J[/tex]

By dividing the previous answer by the moles of salt:

[tex]n=25.0g*\frac{1mol}{249.7g}=0.100mol[/tex]

We can obtain the enthalpy change of solution of the copper salt:

[tex]\Delta _{dissolution}H=\frac{1,515.25J}{0.100mol} \\\\\Delta _{dissolution}H=15,134J/mol=15.1kJ/mol[/tex]

To conclude, it is important to note that one possible source of error is we are assuming the solution has the same specific heat to that of water and that is not necessarily true. Also, we are neglecting any heat transfer to and from the surroundings despite the polystyrene beaker is considered a heat isolator, which means the results cannot necesarilly be accurate and the enthalpy change could have turned out higher or lower in a rigoruous experiment.

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